DSLP(11.3m)

Subject:-

DSLP Design Calculation

Project:-

132/33kV KADUNA SUBSTATION

Location:-

KADUNA

Client:-

FEDERAL MINISTRY OF POWER

SYSTEM DATA Sl No.

DATE:- 15/5/2013

Description

1

Nominal System Voltage

2

System Frequency

3

Rated Impulse Withstand Vtg.

4

Limiting Corona Gradient Strikes On Shield Wire IEEE 998-1996)

5

(page 25-

132

Kv

50

Hz

Vc

650

Kv

E0

1500

Kv/mt

k=

1.2

d=

0.0395

n=

2

l=

0.25

mt

h=

8.3

mt

H=

15.3

mt

Conductor Data Type Of Conductor( Single AAAC 800-D2-61) Sl No. Description 1

Diameter OF Conductor

2

Number Of Conductors Sub Conductor Spacing

3

mt

Installation Data Description

Sl No. 1

Height Of Installation above FGL

2

Height of the Mast

Calculation The Equivalent Radius is given by (Rc) =Rcx ln(2 x h /R)-V/E=0

.

(EqnC.1-IEEE 998-1996)

By solving the equation for Rc, we have Rc= Rc= 0.081704552

mt

In Case Of A twin Conductor bundle ,the The Equivalent Radius is given by (R0) R0= √( r x l ) Ro= 0.070267347 The Radius of the bundle conductors under corona is= Rc'= Ro + Rc Rc'= 0.151971898 The surge impedace of conductors under corona is given as Zs= 60x√{ln(2xh/R)xln(2xh/r)} Zs= 337.3141969 The allowable stroke current is obtained by the equation is Is= 2.2BIL/Zs Is= 4.239370928 BIL=Rated Lightning impulse withstand voltage Zs=Surge impedance of current carrying conductor 0.65 S= 8xk x Is S= 24.54805877

(Eqn. C.7-IEEE 998-1996)

0.000848598

OBJECT TO BE PROTECTED Allowable Strike distance (S)=

24.5480588 m

Height of the shield wire (H)=

15.3

m

Height of the object to be protected(A)=

8.3

m

Elevation difference between Shield wire and the Object to be protected(D)= D=H-A D= 7

m

Elevation difference between Origin of Rolling Sphere & Shield wire(E)= S-D E= 17.5480588 m

Horizontal distance between Origin of the Rolling Sphere & Shield wire(L)= √( S2 x E2 ) L= 17.1660369 m

Maximum allowable horizontal separation of the shield wires ensuring protection of object at height(X)= 2xL X= 34.33207379 m

0.01975

Subject:-

DSLP Design Calculation

Project:-

330/132kV KADUNA SUBSTATION

Location:-

KADUNA

Client:-

FEDERAL MINISTRY OF POWER

SYSTEM DATA Sl No.

DATE:-

Description

1

Nominal System Voltage

2

System Frequency

3

Rated Impulse Withstand Vtg.

4

Limiting Corona Gradient

5

Strikes On Shield Wire IEEE 998-1996)

Vc E0

(page 25-

k=

Conductor Data Type Of Conductor( Single AAAC 800-D2-61) Sl No. Description 1 2 3

d=

Diameter OF Conductor Number Of Conductors Sub Conductor Spacing

n= l=

Installation Data Description

Sl No. 1

Height Of Installation above FGL

2

Height of the Mast

h= H=

Calculation The Equivalent Radius is given by (Rc) =Rcx ln(2 x h /R)-V/E=0 By solving the equation for Rc, we have Rc= Rc= 0.081704552

.

In Case Of A twin Conductor bundle ,the The Equivalent Radius is given by (R0) R0= √( r x l ) Ro= 0.070267347 The Radius of the bundle conductors under corona is= Rc'= Ro + Rc Rc'= 0.151971898 The surge impedace of conductors under corona is given as Zs= 60x√{ln(2xh/R)xln(2xh/r)} Zs= 337.3141969 The allowable stroke current is obtained by the equation is Is= 2.2BIL/Zs Is= 4.239370928 BIL=Rated Lightning impulse withstand voltage Zs=Surge impedance of current carrying conductor 0.65 S= 8xk x Is S= 24.54805877

OBJECT TO BE PROTECTED Allowable Strike distance (S)= Height of the shield wire (H)= Height of the object to be protected(A)= Elevation difference between Shield wire and the Object to be D= Elevation difference between Origin of Rolling Sphere & Shield Horizontal distance between Origin of the Rolling Sphere &E= Shield wire(L)= L= Maximum allowable horizontal separation of the shield wires X=

24.5480588 15.3 8.3 D=H-A 7 S-D 17.5480588 √( S2 x E2 ) 17.1660369 2xL 34.33207379

15/5/2013

132

Kv

50

Hz

650

Kv

1500

Kv/mt

1.2

0.0395

mt

2 0.25

mt

8.3

mt

15.3

mt

(EqnC.1-IEEE 998-1996)

mt

0.000848598

given by (R0)

(Eqn. C.7-IEEE 998-1996)

m m m m m m m

0.01975