ORG./INO. CHEMISTRY
TARGET : JEE (Main) 2017 NO. 09
Course : AADHAAR(EB) AADHAAR(EB)
This DPP is to be discussed in the week (13-07-2015 to 18-07-2015 )
DPP No. # 9 To ta l M a r k s : 60
M a x. T i m e : 40 m i n .
S i n g l e c h o i c e O b j e c t i v e ( ’– 1 ’ n e g a t i v e m a r k i n g ) Q . 1 t o Q . 2 0
1.
( 3 ma ma r k s , 2 m i n . )
[ 6 0 , 40 40 ]
Which of the following gives positive Baeyer’s test :
fuEu es a ls dkSulk ;kSfxd /kukRed cs ;j ijh{k.k ijh{k.k nsrk gS % (1) CH3 –CH2 –CH2 –CH –CH3 2.
(2) (CH3)3CH
(3)
(4*) CH3 –CH=C –CH=CH–C H–CH H3
Which of the following molecular formula cannot show Bromine water test :
fuEu esd a kSulk v.kqlw=k czksehu ty ijh{k.k ugha n'k’ k Zrk gS \ (1*) C6H14 3.
(2) C4H8
(3) C5H8
A compound (A) with with molecular formula C4H8O shows bromine water test. Compound (A) is : C4H8Ov .kqlw=k j[kus okyk ;kSfxd (A)c zksehu ty ijh{k.k n'k’ kZrk gSA vr% ;kSfxd (A) gS % O
O
–CH2 –CH –CH2 –C–H –C–H (3) CH3 –CH2 –C–CH3 (2) CH3 –CH
(1)
4.
(4) C2H4
(4*) CH2=CH–CH2 –CH2 –OH
Which of the following group can be identified by bromine water test :
fuEu esa ls fdl lewg dh igpku czksehu ty ijh{k.k }kjk }kjk fd;k tkrk gS % O –C–OH (1) –C–OH
5.
(2) –SO3H
(3) –NO2
(4*) –C C–
Which of the following compound gives bromine water test positive positive :
fuEu esl a s dkSulk ;kSfxd xd /kukRed czksehu ty ijh{k.k ijh{k.k n'k’ kZrk gS % (1*) CH3 – C CH
(2) CH3 –CH2 –CH3
(3) CH3
6.
CH3 | CH CH2
CH3
Baeyer’s reagent is : (1) Hot dil. alkaline alkaline KMnO KMnO4 (3) Cold dil. dil. acidic acidic KMnO4
(4)
(2*) Cold dil. dil. alkaline alkaline KMnO4 (4) Cold conc. conc. alkaline alkaline KMnO4
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PAGE NO.- 1
cs;j vfHkdeZ d gS : (1) xeZ ruq {kkjh; KMnO4 (3) B.Mk ruq vEyh; KMnO4 7.
(2*) B.Mk
ruq {kkjh; KMnO4 (4) B.Mk lkUnz {kkjh; KMnO4
Lucas reagent is : (1*) Anhydrous ZnCl2 and conc. HCl (3) Hydrous ZnCl2 and conc. HNO 3
(2) Anhydrous ZnCl2 and conc. HNO 3 (4) Hydrous ZnCl2 and conc. HCl
Y;wdkWl vfHkdZed gS % (1) futZ yh; ZnCl2 rFkk lkUnz HCl (3) tyh; ZnCl2 rFkk lkUnz HNO3 8.
(2) futZ yh; ZnCl2 rFkk lkUnz. HNO3 (4) tyh; ZnCl2 rFkk lkUnz. HCl
Primary, secondary and tertiary alcohols are distinguished by : (1) Ceric ammonium nitrate (2*) Victor Meyer’s test (3) FeCl3 test (4) Sodium metal test
izkFkfed]f}rh;d o r`rh;d ,YdksgkWy dk foHksnu fuUu esa ls fdlds }kjk fd;k tkrk gS \ (1) lsfjd veksfu;e ukbVªsV (2) foDVj es;j ijh{k.k (3) FeCl3 ijh{k.k (4) lksfM;e /kkrq ijh{k.k 9.
The group reagent for the test of alcohols is : (1) Baeyer’s reagent (2) FeCl3 (3*) Ceric ammonium nitrate (4) Na metal test
,YdksgkWy dsi jh{k.k ds fy, lewg vfHkdeZd gS % (1) cs;j vfHkdeZ d (3) lsfjd veksfu;e ukbVªsV 10.
(2) FeCl3 (4) Na /kkrq ijh{k.k
The compound which reacts fastest with Lucas reagent at room temperature : (1) Butan-1-ol (2) Butan-2-ol (3) 2-Methylpropan-1-ol (4*) 2-Methylpropan-2-ol
og ;kSfxd tks dejs ds rki ij Y;wdkWl vfHkdeZd ds lkFk rsth ls fØ;k djrk gS % s -1-vkW y kWy s us -1-vkW y (1) C;w V u (2) C;wVsu -2-v (3) 2- e fs Fkyiz k i 11.
fFkyiz k is su -2- vkWy
The long form of periodic table has (1) Eight horizontal rows and seven vertical columns (2*) Seven horizontal rows and eighteen vertical columns (3) Seven horizontal rows and seven vertical columns (4) Eight horizontal rows and eight vertical columns
vkorZ lkj.kh ds nh?kZ :i es gksrs gSa (1) vkB {kS frt iafä;k¡ ,oa lkr Å/okZ/kj LrEHk kr Å/okZ/kj LrEHk (3) lkr {kSfrt iafä;k¡ ,oal 12.
(4) 2-es
(2*) lkr
{kSfrt iafä;k¡ ,oa vBkgjg Å/okZ/kj LrEHk (4) vkB {kSfrt iafä;k¡ ,oa vkB Å/okZ/kj LrEHk
If an atom has electronic configuration 1s2 2s2 2p6 3s2 3p6 3d3 4s2, it will be placed in (1) II A group (2) III A group
(3*) V B group
(4) VI A group
;fn ,d ijek.kq dk bysDVªkWfud foU;kl 1s 2s 2p 3s 3p 3d 4s gS] rks bls j[kk tk,xk % ewg esa (1) II A lewg esa (2) III Al (3*) V Blew g esa (4) VI A lewg esa 2
13.
2
6
2
6
3
2
All the s-block element of the periodic table are placed in the group. (1*) IA and IIA (2) IIIA and IVA (3) B sub groups
lHkh
rRoksa dks vkorZ lkj.kh esja [kk x;k gS (1*) IA vkSj IIA lewgksa esa (2) IIIA vkSj IVA lew gksa esa
(4) VA to VIIA
s- CykWd
(3) B mi
lewgksa esa (4) VA ls
VIIA lewgks a
esa
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PAGE NO.- 2
14.
The electronic configuration of an element is 1s 2 2s2 2p6 3s2 3p3. What is the atomic number of the element which is just below the above element in the periodic table
,d rRo dk bys DVªkWfud foU;kl 1s2 2s2 2p6 3s2 3p3 gSA vkorZlkj.kh esa bl rRo ds lewg es a layXu uhps ds LFkku ds rRo dk ijek.kq Øaekd gksxk % (1*) 33 15.
(2) 34
(3) 31
(4) 49
Which of the following pairs has both members fr om the same period of the periodic table
fuEu esa ls rRoksa dk dkSu&lk ;qXe vkorZ lkj.kh ds, d gh vkorZ dk gS % (1) Na,Ca 16.
(2*) Na,Cl
(3) Ca,Cl
(4) Cl,Br
An element has electronic configuration 1s2 2s2 2p6 3s2 3p4. Predict their period, group and block (1*) Period = 3rd, block = p , group = 16 (2) Period = 5th, block = s , group = 1 (3) Period = 3rd, block = p , group = 10 (4) Period = 4th, block = d , group = 12
,d rRo dk bysDVª kWfud foU;kl 1s2 2s2 2p6 3s2 3p4. g S bls fdl vkorZ] lew g o CykWd esa j[kk x;k gS (1*) vkorZ = 3rd, CykWd = p , lewg = 16 (2) vkorZ = 5th, CykWd = s , lewg = 1 (3) vkorZ = 3rd, CykWd = p , lew g = 10 (4) vkorZ = 4th, CykWd= d , lew g = 12 17.
Electronic configuration of chalcogens in their outermost orbit is
psYdkstUl ds ckbjh d{kk dk bys DVªkWfud foU;kl gS (1) ns2np3 18.
(2*) ns2np4
(3) ns2 np5
(4) ns2 np6
Which configuration represents a noble gas
dkSulk bysDVªkWfud foU;kl mRÑ"V xSl dk gS (1) 1s2 2s2 2p6 3s2 3p6 3d10 4s2 (3) 1s2 2s2 2p6 3p6 19.
(2*) 1s2 2s2 2p6 3s2 3p6 (4) 1s2 2s2 2p6 3s2
Which is smallest in size
vkdkj esl a cls NksVk gS (1) O2– 20.
(2) C4–
(3*) F –
(4) N3–
(3) Mg+2
(4) Na+
Which one of the following is the biggest ion
fuEufyf[kr esa lcls cM+k vk;u dkS ulk gS (1) Al+3
(2*) Ba+2
Corporate Office : CG Tower, A-46 & 52, IPIA, Near City Mall, Jhalawar Road, Kota (Raj.)-324005 Website : www.resonance.ac.in | E-mail :
[email protected] Toll Free : 1800 200 2244 | 1800 258 5555| CIN: U80302RJ2007PTC024029
PAGE NO.- 3
