A react eactiion turb turbiine is supp suppllied ied wit with 100 100 cu m of wat water per per secon econd d and and work workss under under a maximum maximum head of 120 m at 350 rpm. Assuming Assuming plant’s plant’s overall efficien efficiency cy of 80% and water density of 1000 kg per cu m, calculate the power in kW.
2
(a) (a)
Calc Calcul ulat atee the the tot total al ener energy gy in kWh kWh whic which h can can be gene genera rate ted d from from a hyd hydro ro powe powerr sta stati tion on having the following data:
(b)
Reservoir area
= 2. 2.5 sq.km.
Capacity
= 5 x 106 m3
Net Net Head Head of wate waterr at at the the tur turbi bine ne
= 80 80 m
Turbine efficiency
= 80%
Generator efficiency
= 90%
Find Find by how how many many mete meters rs the the level level of the rese reservo rvoir ir will will fall fall if if a load load of 20,00 20,000 0
kW is supplied for 5 hours.
3
For For a hydr hydro o elec electr tric ic pow power er pla plant nt the the fol follo lowi wing ng annu annual al dat dataa is sup suppl plie ied: d: Annual rain fall
=
1000 mm
Catchment area
=
120 sq.km.
Effective Head
=
250 m
Load factor (λ )
=
40%
Yield factor (k) to allow for run off and evaporation loss k
=
50%
Efficiency of the plant
=
70%
Determ Determine ine the follow following ing::
4
(a)
Average Average power power produce produced d
(b) (b)
Capa Capaci city ty of the the pow power er plan plantt
Calcul Calculate ate the power power that that can can be be devel developed oped from from a HPS HPS havi having ng the follow following ing data: data: Catchment area
=
100 sq. km.
Average rain fall
=
120 cm
evaporation loss
=
20%
Available Head
=
300 m
Plant’s ov overall ef efficiency
=
75%
Kyaruzi
page 1
22/11/11
5
Determine the power that can be developed from a HPS with the following data: Area of reservoir
=
3 x 108 sq m
Mean Head
=
40 m
Annual average rain fall
=
110cm
Turbine efficiency
=
80%
Generator efficiency
=
85%
Assume that 25% of rain is lost due to evaporation and 4% head is lost in penstock.
6
For a hydro electric power plant the following data is supplied: reservoir area
=
2000 sq.km
capacity
=
2.0 x 109 m3
net head
=
200 m
Load factor (λ )
=
0.8
Yield factor (k) to allow for run off and evaporation loss k
=
25%
Turbine efficiency
=
90%
Generator efficiency
=
95%
If the density of water is taken as 1000 kg/m3 calculate: The change in level of the reservoir if the power station is to supply its rated capacity for 72 h ours.
7
Name various factors to be considered when selecting the site for the hydro power plant. The hydro-electric power station has the following data: Catchment area
300 sq. km.
total plant efficiency
80%
yield factor to allow for run off and evaporation loss load factor
50%
0.5
Plant capacity
20 MW
The dam level was 200 m at the beginning of the month of January and 202 m at the end of January of the same year. If the dam level is taken as the effective head of the plant and the average daily rainfall in January was 5 mm, find the reservoir area .
8
a)
A power station has a maximum demand of 80 MW and the daily load curve is defined as follows:
Kyaruzi
page 2
22/11/11
time in hours
0-6
load in MW
40
6-8
8-12
12-14
14-18
18-22
22-24
50
60
50
70
80
40
(i)
Determine the load factor of the power station.
(ii)
What is the load factor of the stand-by generator rated 25 MW that takes up all load in excess of 60 MW.
(b)
In a 60 MW steam power station working at 40% load factor the energy cost is found to be 1.50 shs/kWhr. Calculate the cost of energy if the power station load factor is improved to 50%, and due to increase in energy generation the fuel cost increases the annual generation cost by 6%.
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