Diseño de Escalera

November 18, 2022 | Author: Anonymous | Category: N/A
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DISEÑO DE ESCALERA

DATOS

f'c = 210.00 210.00 Kg/c Kg/cm² m² fy = 4200.0 4200.00 0 Kg/c Kg/cm² m² S/ S/C C = 500. 500.00 00 K Kg/ g/m² m²  Acabados = 100.00 Kg/m² b= 1 .3 0 m   Hentre!so=

C# =

  #or $orma C# = #= %ec&b =

)40

 C( = 2400.00 Kg/m3

0)2 5

0.25 m

1.60 m

3.10 m

1. PREDIMENSIONADO  Espesor de la escalera Primer tramo

2."0 m 0 .1 3 m 0.1" m 0 .3 1 m 3.00 cm

Segundo tramo

0.40 m

 

t = Ln Ln//20 t = Ln Ln//25 USAR t

= = =

0.24 m 0.19 m 0.20 m

t= t=

Ln/20 Ln/25 USAR t

= = =

0.24 m 0.19 m 0.20 m

 

2) DISEÑO PRIMER TRAMO hm



h

CP  

2

 

t  

(o*  

CP  

2

=/√(^2+ 〖 〖〗 〗 ^2 )

(o*θ hm

0.9251 0.31 m

2.1. METRADO DE CARGAS Wu2 Wu1

1.25 m

3.300 m !

R"

Wu1 TRAMO DESCANSO #arga $uerta P.P = 624.00 'g/m A(a)a A(a)ado* do* = 130.00 130.00 ' 'g/m g/m 54.00 'g/m W+1 = 1055.60 'g/m

#arga %i&a S/# = 650.00 'g/m 650.00 'g/m WL1 = 11 1105.00 'g/m

Wu1 = 21 21!. !.!! "#$% "#

%$Wu2 TRAMO PASOS #arga $uerta P.P = 955.34 'g/m A(a)a A(a)ado* do* = 130.00 130.00 ' 'g/m g/m 10,5.34 'g/m W+1 = 1519.4, 'g/m

#arga %i&a S/# = 650.00 'g/m 650.00 'g/m WL1 = 11 1105.00 'g/m

2.2. CA(C(O DE MOMENTO R* = 6456.66 'g - maimo *e dar!en +,momento =! = a *e((ion 2.46 ue m o*ea e (ortante igua a 0  $u $u ma = 942. 942.23 23 'g 'gm m  $ di*e7o = 14,.01 'gm $= 3.5 8m

=

.15 8m

Wu2 = 22 22&.& &.&'' "#$% "#

%$  

2.-. DISEÑO EN ACERO Acero /0eror A*umiendo &aria de a(ero  ) = 130.00 (m $d = 'u <
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