Design Calculation Anchor Flange - ASME VIII Div 1 App.2

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Design calculation Anchor Flanges

rimod

According ASME VIII div 1 appendix 2

bc

Customer: IV Oil & Gas Customer ref: OGPA080174-DS-L5400 Date: 10/7/2009 Description: Anchor flange 10" 900# A694 F65 PFF ref: 90753546/MV

Design data 273 247.4 12.8 545 70 470 39 8 270 368 75

description

mm mm mm mm mm mm mm

Outside diameter welding end Inside diameter Wall thickness welding end Flange blade outside diameter Flange blade thickness Diameter bolt circle Bolt holes diameter Number of bolts total hight Diameter conical hub Design temperature

mm mm °C

244

N/mm2

Rm ca milt TD pd

530 3 1

N/mm mm %

2

137

bar

Design pressure

dsf fe me

0.5 80 40.1

kN kNm

Design factor1) External axial force External moment

Rt

Yield at design temperature1)

df2 NB, equally spaced

de di

dfd

fd

de di dfd rimod fd bc df2 NB th x re

mm

th

figure

Tensile at 20° Corrosion allowance Mill tolerance

x

Calculated figures FEC = MEC = PDC = g0 = dimax = h= g1 = h0 =

80000 40100000 13.7 9.672 253.528 100 57.236 49.51891372

1) According NEN 3650

N N Mpa mm mm mm mm mm

[= fe x 1000] [= me *1000*1000] [= pd/10] [= dfd-dfd x milt / 100 - ca] [= di+dfd x milt / 100 + ca x 2] [= (th-fd)/2] [= (x - di)/2] [= √(dimax x g0)]

(minimum wall thickness) (Maximum ID) (Hight conical hub) (Average thickness conical hub) (Square root (max id x minimum WT))

PFF Europe B.V. Wielewaalweg 4 4791 PD Klundert The Netherlands

Tel. :+31 (0) 168 387410 Fax.:+31 (0) 168 387420 E-Mail : [email protected] Internet: www.pff-group.com

Calculation of value Sr, St, & Sh: Values F & v acc. ASME VIII, div 1, appendix 2 e= K= q= Z1=

0.009804187 2.149663942 1 0.332370572

[=F/h0] [=rimod/di] [=1/log(10)] [=log(K)]

t=

1.452567279

[=(K x (1+8,55246 x q x Z1)-1)/((1,0472 + 1,9448 x K ) x (K-1))

2

2

2

2

U=

2.956732956

[=K x (1 + 8,55246 x q x Z1)-1)/(1,36136 x (K -1) x (K-1)]

Y=

2.690633212

[=(1/(K - 1)) x (0,66845 + 5,7169 x (K2 x q x Z1/(K2 - 1)))]

Z=

1.55232521

[=(K2 + 1)/(K2 - 1)]

D=

16218117.02

[=(U/v) x h0 x g02]

L= B1= FT= R= M=

1.182054508 263.2 689422.4924 51 71286285.71

[=(fd x e + 1)/t + fd3/D] [=di + gi] [=FEC + 4 x MEC / (di + g0)] [=(bc-x)/2] [=FT*(R+g1-g2/2)]

Sr=

92.85583054

[=M*(1,33*fd*e+1)/(L*di*fd2)]

St= Sh= S1= S2= FB=

10.25441735 69.94296654 81.39939854 40.09869194 122

[=Y*M/(di*fd2)-Z*Sr] [=f*M/(L*B1*G1)] [=(Sh+Sr)/2)] [=(Sh+St)/2] [=dsf*Rt]

Results: Sr =

92.85583054 N/mm2

≤

FB =

122

St =

10.25441735 N/mm2

≤

FB =

122

Sh =

69.94296654 N/mm2

≤

Rt =

244

(Sh + Sr)/2 = 81.39939854 N/mm2

≤

FB =

122

(Sh + St)/2 = 40.09869194 N/mm2

≤

FB =

122

Conclusion: Accepetable

if f