Design and Sizing Wwtp

December 21, 2019 | Author: Anonymous | Category: Industrial Processes, Aquatic Ecology, Waste, Chemical Engineering, Sanitation
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Dr. S Biological Wastewater Treatment

Designed By: Advisor :

Ramy R. Salem Dr. Husam Al-Najar

Rights are not reserved ^_^

water Treatment

Designed by : Ramy R. Salem

Activated Sludge System

Advisor : Dr. Husam Alnajar INPUT DATA 3 12700 m /d 84 mg/L

Flow = BOD5 (soluble) = (BOD5)total = Suspended Solids(SS)= (BOD5)soluble in effluent =

30 mg/L 30 mg/L 11.1 mg/L

Micro-organism Growth Constant µm = Kd = Y= Ks=

-1 2.5 d -1 0.05 d 0.5

Concentration of Biomass(X mg VSS/mg BOD5 removed

100 mg BOD5/L

The Solid retension time θc (day) = Minimum Sludge retension time (day) = S/F = S min Hydranlic detension time θ (day ) = Volume of the tank (m3) =

5.0056319 0.9163347 day 5.4626679 OK 2.0408163 S>Smin OK 0.0486438 617.77605

Food to micro-organism ratio in the reactor (F/M) = 0.57561312 OK mg BOD5 / mg MLVSS .d Biomass production per day (Px) (Kg/d) = 461.79183 Waste Flow rate Qw (m3/d) = 3

Effluent Flow rate Qe (m /d) = 3

Recycle Flow Qr (m /d) = Oxygen reqirements =

46.179183 7257.1429 5442.8571 270.08559 kg O2/d

dge System BOD removal

Concentration of Biomass(X) =

3000 mg MLVSS/L

1600 4800

Xr =

10000 mg VSS/L

Q0(m3/d)=

12700

S0 (mg/L)=

84

Qe(m3/d)=

7257.143

Xe neigligable Sed tank

Areation tank

Qr(m3/d)= S (mg/L)=

5442.857 11.1

Qw(m3/d)= S (mg/L)= Xr =

46.17918 11.1 10000

Designed By : Ramy R. Salem

Activated Sludge System

Advisor : Dr. Husam Alnajar INPUT DATA Flow = BOD5 (soluble) =

3 12960 m /d 84 mg/L

(BOD5)total = Suspended Solids(SS)= (BOD5)soluble in effluent =

30 mg/L 30 mg/L 11.1 mg/L

Micro-organism (N) Growth Constant -1 0.25 d -1 0.04 d 0.2 mg VSS/mg NH4-N removed 0.4 mg/L

(µm)n = (Kd)n = (Y)n = (Ks)n=

Micro-organism Growth Constant -1

Kd = Y=

2.5 d -1 0.05 d 0.5

Ks=

100 mg BOD5/L

µm =

Concentration of Biomass(X mg VSS/mg BOD5 removed

The Solid retension time θc (day) = Minimum Sludge retension time (day) =

10 0.0761905 day

S/F =

2.1 OK

S min Hydranlic detension time θ (day ) =

0.0761905 S>Smin OK 0.0486438

Volume of the tank (m3) =

2437.1532

Food to micro-organism ratio in the reactor (F/M) = 0.16543892 OK mg BOD5 / mg MLVSS .d

Biomass production per day (Px) (Kg/d) =

408.42013

Waste Flow rate Qw (m3/d) =

110.37077

Effluent Flow rate Qe (m3/d) =

7765.7506

3

Recycle Flow Qr (m /d) = Oxygen reqirements =

5194.2494 2764.896 kg O2/d

udge System BOD Removal & Nitrification

40 mg/L 1 mg/L

TKN0 = TKN =

Concentration of Biomass(X) =

3000 mg MLVSS/L

1600 4800

Xr =

10000 mg MLVSS/L

Q0(m3/d)=

12960

S0 (mg/L)=

84

TKN0(mg/L) =

40

Qe(m3/d)= Xe neigligable

Areation tank

Sed tank

TKN0(mg/L) =

Qr(m3/d)=

5194.249

Qw(m3/d)=

S (mg/L)=

6.382979

S (mg/L)= Xr =

7765.751 0.509091

110.3708 6.382979 10000

Designed By : Ramy R. Salem

Activated Sludge System

Advisor : Dr. Husam Alnajar INPUT DATA Flow = BOD5 (soluble) =

3 12960 m /d 84 mg/L

(BOD5)total = Suspended Solids(SS)= (BOD5)soluble in effluent =

30 mg/L 30 mg/L 11.1 mg/L

Micro-organism (N) Growth Constant -1 0.25 d -1 0.04 d 0.2 mg VSS/mg NH4-N removed 0.4 mg/L

(µm)n = (Kd)n = (Y)n = (Ks)n=

Micro-organism Growth Constant -1

Kd = Y=

2.5 d -1 0.05 d 0.5

Ks=

100 mg BOD5/L

µm =

Concentration of Biomass(X mg VSS/mg BOD5 removed

BOD Removal The Solid retension time θc (day) =

5.0056319

Minimum Sludge retension time (day) =

0.9163347 day

S/F =

5.4626679 OK

S min

2.0408163 S>Smin OK

Hydranlic detension time θ (day ) =

0.0972876

Volume of the tank (m3) =

1260.8469

Food to micro-organism ratio in the reactor (F/M) =

0.57561312 OK

mg BOD5 / mg MLVSS .d Biomass production per day (Px) (Kg/d) = 470.10523 Waste Flow rate Qw (m3/d) = 3

Effluent Flow rate Qe (m /d) = 3

Recycle Flow Qr (m /d) =

47.010523 10739.981 2287.0588

Oxygen reqirements =

2764.896 kg O2/d

NH3 Removal (Nitrification) The Solid retension time θc (day) = Minimum Sludge retension time (day) = Hydranlic detension time θ (day ) = Volume of the tank (m3) =

54.054054 4.7619048 day 0.0888889 1147.8213

Food to micro-organism ratio in the reactor (F/M) = 0 Biomass production per day (Px) (Kg/d) = 31.852041 Waste Flow rate Qw (m3/d) = 3

Effluent Flow rate Qe (m /d) = 3

Recycle Flow Qr (m /d) =

3.1852041 10634.227 2278.7628

Oxygen reqirements (kg O2/d) = 3

Volume of air to be supplied(m /d) =

2301.4821 104643.27

0.3

mg TKN/mg Vss.d

udge System BOD Removal & Nitrification (Seperated processes)

40 mg/L 1 mg/L

TKN0 = TKN =

Concentration of Biomass(X) =

1500 mg MLVSS/L

1600 4800

Xr =

3

10000 mg MLVSS/L

3

Q0(m /d)=

12960

Qe(m /d)=

S0 (mg/L)=

84

Xe neigligable

TKN0(mg/L) =

40

TKN0(mg/L) =

Areation tank 1260.8

10672.94 40

Sed tank

Qr(m3/d)= S (mg/L)=

mg TKN/mg Vss.d

2287.059 11.1

Qw(m3/d)= S (mg/L)=

Qe(m3/d)= 12912.9895

Qe(m3/d)=

Nitrification 1147.82

Sed tank

TKN0(mg/L) =

12909.8 1

47.01052 11.1

Qw(m3/d)=

3.185204

Designed By : Ramy R. Salem

Activated Sludge System

Advisor : Dr. Husam Alnajar INPUT DATA Flow = BOD5 (soluble) =

3 12960 m /d 84 mg/L

(BOD5)total = Suspended Solids(SS)= (BOD5)soluble in effluent =

30 mg/L 30 mg/L 11.1 mg/L

The denitrifying bacteria (µm)d = (Kd) = (Y)d = Kdn=

-1 0.4 d -1 0.04 d 0.9 mg VSS/mg NO3-N 0.16 mg NO3-N

Micro-organism Growth Constant -1

Kd = Y=

2.5 d -1 0.05 d 0.5

Ks=

100 mg BOD5/L

µm =

Concentration of Biomass(X mg VSS/mg BOD5 removed

NH3 Removal (Denitrification) The Solid retension time θc (day) = Minimum Sludge retension time (day) =

5.271538462 2.51025641 day

Hydranlic detension time θ (day ) =

0.050654608

Volume of the tank (m3) =

652.2055178

Biomass production per day (Px) (Kg/d) =

363.6613402

Waste Flow rate Qw (m3/d) =

36.36613402

3

Effluent Flow rate Qe (m /d) =

12839.17567

3

Recycle Flow Qr (m /d) =

5.518089346

NH3 Removal (Nitrification) The Solid retension time θc (day) = Minimum Sludge retension time (day) = Hydranlic detension time θ (day ) = Volume of the tank (m3) =

4.4827586 2.7777778 day 0.0866667 1119.1258

Food to micro-organism ratio in the reactor (F/M) = Biomass production per day (Px) (Kg/d) =

374.47669

Waste Flow rate Qw (m3/d) =

37.447669

3

Effluent Flow rate Qe (m /d) = 3

Recycle Flow Qr (m /d) =

10634.227 2278.7628

Oxygen reqirements (kg O2/d) = 3

Volume of air to be supplied(m /d) =

2242.4698 101960.1

0.3

mg TKN/mg Vss.d

udge System Denitrification

39 mg/L 1 mg/L 3000 mg MLVSS/L

TKN0 = TKN = X

linked nitrification seperet value form this shee Concentration of Biomass(X) =

1500 mg MLVSS/L

1600 4800

Xr =

3

10000 mg MLVSS/L

Q0(m /d)=

12960

S0 (mg/L)=

84

TKN0(mg/L) =

39

3

Qe(m /d)=

10672.94

Xe neigligable TKN0(mg/L) =

Areation

tank(m3)

1260.8

39

Sed tank

Qr(m3/d)= S (mg/L)=

mg TKN/mg Vss.d

2287.059 11.1

Qw(m3/d)= S (mg/L)=

NOTE linked with the process of BOD removal and nitrification seperetly . You can change the value form this sheet.

Qe(m3/d)= 12912.9895

Nitrification(m3) 1119.13

Sed tank

Qe(m3/d)=

12875.54

TKN0(mg/L) =

1

Denitrificatio

47.01052 11.1

Qr(m3/d)= 2.278763

Qw(m3/d)=

37.448

Qe(m3/d)=

Denitrification (m3) 652.2055

Sed tank

12839.18

Qr(m3/d)= 5.518089

Qw(m3/d)= 36.36613

Designed by : Ramy R. Salem

OXIDATION DICHES

Advisor : Dr. Husam Alnajar INPUT DATA Flow = Influent BOD5 (soluble) =

3 20000 m /d 300 mg/L

(BOD5)total = Suspended Solids(SS)= (BOD5)soluble in effluent =

33.9 mg/L 30 mg/L 15 mg/L

Micro-organism Growth Constant -1 2.5 d -1 0.03 d 0.5

µm = Kd = Y=

mg VSS/mg BOD5 removed

30 mg BOD5/L

Ks=

No Sludge Production Allow Sludge Production

The Solid retension time θc (day) = Hydranlic detension time θ (hours ) =

S min

Volume of the tank (m3) = 20000 Concentration of Biomass(X) = 4750 mg MLVSS/L Food to micro-organism ratio in the reactor (F/M) = 0.063 Biomass production per day (Px) (Kg/d) =

0

Waste Flow rate Qw (m3/d) =

0

3

Effluent Flow rate Qe (m /d) = 3

Recycle Flow Qr (m /d) =

1904.7619 18095.238

Oxygen reqirements =

5700 kg O2/d

ATION DICHES BOD removal,Nitrification & denitrification

1600 4800 Xr =

10000 mg VSS/L

30 15 3

Q0(m /d)=

20000

S0 (mg/L)=

300

3

Qe(m /d)= Xe neigligable

OD

Sed tank

Tank(m3) 20000

OK OK

Qr(m3/d)= S (mg/L)=

18095.24 15

Qw(m3/d)= S (mg/L)= Xr =

1904.762

Xe neigligable

0 15 10000

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