Daniel Hart Power Electronics Chapter 1 Solutions

CHAPTER 1 SOLUTIONS (1-1)

(1-2)

25V

20V

15V

10V

5V

0V

-5V 0s

2us

4us

6us

8us

10us

12us

14us

16us

10us

12us

14us

16us

V(D1:2) Time 25V

(1.4333u,23.800)

20V

15V

10V

5V (4.0833u,-851.690m) 0V

-5V 0s

2us

4us

6us

8us

V(S1:4) Time

In part (b), the voltage across the current source is reduced from 24 V by the switch resistance and diode voltage drop.

(1-3)

40V

96.46n,23.94) 20V

(3.150u,-1.052)

0V

(3.150u,-1.052)

-20V 0s

5us

10us

V(V2:-) Time

15us

(1-4)

25V

20V

(800.000n,23.924)

15V

10V

5V (3.8333u,-1.0517) 0V

-5V 0s

2us

4us

6us

8us

V(V2:-) Time

10us

12us

14us

16us