An EULER CIRCUIT is a simple circuit that contains every vertex edge A connected graph has Euler circuit iff every vertex is of even deg
Binomial
if
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An EULER PATH is a simple path which is not a circuit and contains all the edges and vertices A graph has an Euler path iff it is connected
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Pascal’s Identity:
√ ,
Type Simple Graph Multigraph Pseudograph
Fundamental Theorem of Arithmetic: Every +ve integer > 1 has a divisor which is prime every +ve integer greater than 1 can be written uniquely as a product of primes. E.g. An integer ̅ s.t. ̿ The inverse of
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{ {
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Edges
Multiple Edges?
Loops?
Undirected Undirected Undirected
No Yes Yes
No No Yes
An
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Edges with
as terminal vertex
Edges with COMPLETE BIPARTITE GRAPH denoted
as initial vertex
Chapter 4: Mathematical Induction
Working here to prove that
A tree with vertices has at least two vertices of deg(1) A tree with vertices has edges A full -ary tree ́ internal vertex has vertices Suppose full -ary tree with vertices, internal vertices and leaves, then
-
A rooted -ary tree of height is BALANCED if all leaves are at level or In an -ary tree there are at most vertices at level . If the height is , there are at most leaves.
,
is true
Chapter 5: Counting
With Repetition:
-
are true. Then ….
Thus is true. Therefore, by Mathematical Induction, *proposition* for all *domain*
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-ary is FULL if every internal vertex has exactly m children.
An ORDERED ROOTED TREE is a rooted tree in which children of each vertex are ordered. E.g. for T2, the left subtree of is the subtree rooted at while the right subtree if a single vertex
}
is called an inverse of exists iff
Let be the proposition that … Basis Step: is true since… Inductive Step: Assumer that
graph with NO cycles
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Chapter 7: Graphs √ is prime
with
and all vertices, but two, have even degrees.
Chapter 8: Trees - A TREE is a connected
Prime Numbers and GCD A positive integer is: - PRIME if it has exactly 2 +ve divisors, 1 and itself; - COMPOSITE if it has more than 2 +ve divisors If is composite, then it has a divisor if does not have a divisor with
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