Ch. 13: Conjugation and Aromaticity Stability of Aromatic Compounds As a result of cyclic delocalization and resonance, most aromatic compounds are more stable and less reactive than alkenes.
Heats of Hydrogenation
H2 Pd
- 118 kJ/mol
3H2 Pd
- 206 kJ/mol
Benzene Molecular Orbitals Frost Circle: a method f or determining the relative order of pi MOs in planar, fully conjugated monocyclic compounds
Note: When inscribing the polygon, ensure that one of the vertices is placed at the bottom. Each point where one of the vertices touches the circle represents the location of one of the molecular orbitals.
Antibonding orbitals
Bonding orbitals Energy Determining Aromaticity
Example: Cyclooctatetraene
Four Conditions: 1. Must be cyclic 2. Must be planar 3. Must be f ully-conjugated 4. Must have 4n+2 number of pi electrons A molecule is anti-aromatic if it meets the f irst three conditions but only has 4n pi electrons.
This compound is not actually planar:
A molecule is non-aromatic if it does not meet any of the f irst three conditions.
Aromatic Ions Cations:
Non-aromatic (sp3 carbon)
Anions:
4e-
Aromatic (now sp2)
5e-
Heterocyclic Compounds sp2-hybridized Lone pair in sp2 orbital (orthogonal) N
6 pi electrons N
Aromatic 6e-
Lone pair in p orbital
NH
6 pi electrons
N H
sp2-hybridized
Lone pair in sp2 orbital (orthogonal) O
6 pi electrons
O
In general, heteroatoms that are double bonded will not contribute their lone pairs because their p orbitals are already being used for the double bond. Heteroatoms single bonded to other atoms can contribute one lone pair to the pi system (the other pair is perpendicular). Acid and Base Properties Stronger acids have more stable conjugate bases. H N
Aromatic
Not Aromatic pK a = 15
Aromatic pK a = 23
N
Aromatic
Pyrrole (right) is considered a weak acid compared to cyclopentadiene (left). To determine the strength of a base, one must look at the stability of the conjugate acid. H N
H N
Pyrrole is a weak base because protonation destroys aromaticity H
Aromatic
N
NH
Imidazole
Cl
Not Aromatic pK a = - 4
In this compound, the lone pair on the left nitrogen is in an sp2 orbital that does not interact with the pi system. As a result, this nitrogen is more basic than the other.
Chemistry of Benzene The most common reaction of aromatic compounds is electrophilic aromatic substitution. H H
H
H +
E
H
E
Base
E
H H
Deuterated Acid: H
D3O+/D2O
H D
D
H D
D2O
H
D
D
Birch Reduction Example: Na/NH3 Na/NH3
EtOH
EtOH
OEt
OEt
COOH
COOH
1. Na/NH3, EtOH
1. Na/NH3, EtOH
2. H2O/H3O+
2. H2O/H3O+
Electron-releasing groups end up attached to a double bond
Electron-withdrawing groups end up on the methylene positions
Benzyl Compounds An orbital at the benzylic position is stabilized by overlap with adjacent orbitals. The benzyl position is similar to the allylic position.
CH2
benzyl position H2C
allylic position
CH2
Benzyl compounds are very active f or SN1 and SN2 reactions. Cl
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