Circuitos de Ventilacion

May 20, 2019 | Author: adramp024046 | Category: Electrical Resistance And Conductance, Optics, Light, Electrical Engineering, Equations
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Esta guía ha sido elaborada por profesores que imparten la materia. Está diseñada y orientada en la preparación del exa...

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CIRCUITO DE VENTILACION

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Leyes de Kirchhoff Las dos leyes fundamentales administrada por la conducta de los circuitos eléctricos fueron desarrolladas por el físico alemán Gustav Robert Kirchhoff. Aunque estas leyes fueron desarrolladas con respecto a circuitos eléctricos, a estado siendo aplicado a circuitos de ventilación usando análisis de la analogía de H -Q 2. Primera ley de Kirchhoff  La figura figura es un segmento segmento de un circuit circuito o de ventilación ventilación donde se se encuentran encuentran cuatro ramas en un punto común o conjunción. Para este capitulo conjunción es específicamente definida como un punto donde tres o más ramas se encuentran.

Según la primera ley de kirchhoff, el caudal de salida de una conjunción será igual

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Segunda ley de kirchhoff  La segunda ley ley de kirchhoff kirchhoff dice que la suma suma de las caídas de presión presión en una malla cerrada deberá ser igual a cero, el cual puede ser expresada de la siguiente forma:

• H = 0

La figura está referida al orden adoptado aplicando la ecuación anterior. Una malla cerrada consiste de flujos a, b, c y d, indicado por la línea segmentada. Si se suman

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Circuitos series En un sistema de ventilación, dos combinaciones de flujos de aire son posibles: series o paralelos. Ocurren también combinaciones complejas, estas pueden ser reducidas usando algunas técnicas básicas. En la figura figura se puede definir un circuito circuito serie.

Resistencia equivalente en circuito serie La figura ilustr ilustra a un simple circuito circuito en serie. serie. El caudal de aire de cada cada rama rama es el

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Para este caso, la presión del ventilador H m es igual a la caída total (caída estática) para los puntos AB. Uno puede a menudo convenir no involucrar el ventilador, la expresión puede ser escrita de la siguiente forma: H = H1 + H2 + H3 + ............. Puede ser expre expresado sado en términos términos de caudal y resist resistencia encia para cada rama rama H = R1 |  |Q Q|Q + R2|Q|Q + R3|Q|Q + ...........

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Factor común en Q 2, H = ( R1 + R2 + R3 + .. .... ) Q 2 = Req Q 2 Donde Req  esta referido a la resistencia equivalente de los circuitos en serie, esto significa la suma individual de todas las resistencias. Entonces, la ecuación general de las resistencias en serie puede ser escrita de la siguiente forma: Req = H = R 1 + R2 + R3 + ......... Q 2

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Curva característica circuitos series Los cálculos de flujo en serie pueden ser resueltos gráficamente usando la curva característica, las curvas son visualizadas para cada condición de flujo. En este caso las caídas de presión son son acumulativas acumulativas para para un caudal dado.

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Circuitos paralelos Las ramas pueden ser conectadas en paralelo donde el flujo de aire es dividido. En ventilación de minas, es practicado en termino de ramales, y las mallas son referidas a las ramas. Hay dos formas de ramales, ramal natural ocurre cuando el caudal es dividido en mallas paralelas acordado por su propia regulación. Los

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Resistencia equivalente para circuitos paralelos Como para los circuitos en serie, la resistencia equivalente para ramales paralelos puede ser determinada aplicando la primera ley de Kirchhoff y la ecuación de

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La ecuación general para la resistencia equivalente puede ser escrita como sigue: 1 / (Req) ½ = 1 / (R1) ½ + 1 / (R2) ½ + 1 / (R3) ½ + .......

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Curva característica de circuitos paralelos Algunas soluciones se pueden obtener a través de la curva característica. La caída de presión en un punto sobre la curva es calculada, asumiendo un caudal. En este

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Q 3 = 25.000 Q 4 = 40.000 Q 5 = 10.000

Q 8 = 15.000 Q 9 = 35.000 Q 10 = 20.000

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Solución, el caudal de la mina es determinado aplicando la primera ley de Kirchhoff trabajando con los nodos internos y externos. Q 2 = Q 6 = 25.000 + 40.000 + 10.000 = 75.000 cfm Q 7 = Q 11 = 15.000 +35.000 + 20.000 = 70.000 cfm Q mina = Q 1 = Q 12 = 75.000 + 70.000 = 145.000 cfm La caída de presión de cada rama es calculada para los caudales designados como sigue: H1 = R1 Q 12 = (0.238x10-10) (145.000)2 = 0.5 in

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Si las mallas en la figura (c) son definidas, las siguientes ecuaciones pueden ser escritas para determinar la localización de los reguladores y la cantidad de reguladores. Malla 1 : 2.0 + Hx = 3.0 Malla 2 : 3.0 = 0.5 + Hx Malla 3 : 1.0 + Hx = 3.0 Malla 4 : 0.5 + Hx = 3.0 Malla 5 :2.0 + 3.0 + 1.0 + Hx = 3.0 + 3.0 +2.0

Hx = 1.0 Hx = 2.5 Hx = 2.0 Hx = 2.5 Hx = 2.0

(rama 3) (rama 5) (rama 9) (rama 8) (rama 2 o 6)

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Dado el esquema de un sistema de ventilación de minas mostrado en la figura, con caudales asignados y las caídas de presión calculadas, determine el caudal de la mina y la presión estática. Nivel superior: Q = 20.000 + 30.000 + 25.000 = 75.000 cfm Nivel inferio inferior: r: Q = 40.000 + 15.000 + 35.000 = 95.000 cfm cfm Caudal de la mina Q = 75.000 + 95.000 = 170.000 cfm Para Pa ra una parte parte de la red red B a J, la segunda segunda ley ley de Kirchho Kirchhoff ff debe debe ser satis satisfe fecha cha en

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Si las mallas de la figura 5 son definidas, se determinaran las siguientes ecuaciones:

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Método de transformación triangulo en estrella Por analogía por el cálculo de las redes eléctricas, en el cálculo de los sistemas de ventilación, para su simplificación, se utiliza la transformación del triángulo en estrella de tres rayos. Así, el triángulo ABC puede ser reemplazado por una

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R3,1 + R1,2 =

R1(R2 + R3) R1 + R2 + R3 + 2(R1(R2 +R3)) ½ Por analogía R  + R  =

R (R  + R )

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