Calculation API 650
March 14, 2017 | Author: jamil | Category: N/A
Short Description
Download Calculation API 650...
Description
ROOF THICKNESS VERIFICATION AS PER API 620 Contents: 1
Design Data
2
Roof Design
3
Shell Desin
4
Compression Area Design
5
Bottom Plate Design
6
Intermediate Wind Girder Calculations
7
Stabiltility Calculations Against Wind Load
8
Stabiltility Calculations Against Seismic Load 8.1
Resistance To Over Turning
8.2
Shell Compression For Unanchored Tanks
8.3
Maximum Allowable Shell Compression For Unanchored Tanks
8.4
Shell Compression For Anchored Tanks
8.5
Maximum Allowable Shell Compression For Anchored Tanks
9
Uplift Load Cases As Per API 650 Table 3-21a
10
Anchor Chair Calculations
11
Foundation Loading Data
12
Nozzle Reinforcement Calculations(LATER)
13
Nozzle Flexibility Analysis As Per Appendix P of API 650(LATER)
14
Venting Calculations As Per API 2000(LATER)
7.1)
Roof Thickness and Compression Area Verification As Per API 620 Nomenclature P
= =
Total pressure in lbs/ft2 acting at a given level of the tank under the particular condition of loading. P1 + Pg
P1
=
Pressure in lbs/ft2 resulting from the liquid head at the level under consideration in the tank.
Pg
=
Gas pressure in lbs/ft2 above the surface of the liquid. Thwe maximum gas pressure(not exceeding 15 lbs/ft2) is the nominal pressure rating of the tank. Pg is the positive except in computation used to investigate the ability of the tank to withstand a partial vacuum; in such computations its value is negative.
T1
=
Meridional unit force in lbs/inch of latitudinal arc, in the wall of the tank at the level of the tank under consideration. T1 is positive when in tension.
T2
=
Latitudinal unit force in lbs/in of maridional arc, in the wall of the tank under consideration. T2 is positive when in tension.(in cylinderical side walls the latitudinal unit forces are circumfrential unit forces)
R1
=
Radius of curvature of the tank side wall in inch in a meridional plane at the level under consideration. R1 is to be considered negative when it is on the side of the tank wall opposite from R2 except as provided in 5.10.2.6
R2
=
Length in inch of the normal to the tank wall at the level under consideration measured from the wall of the tank to the axis of the revolution. R2 is always positive except as provided in 5.10.2.6
W
=
Total weight in lbs of that portion of the tank and its contents(either above the level under consideration, as in figure 5-4 panel b, or below it, as in figure 5-4 panel a) that is treated as a free body on the computations for that level. Strictly speaking the total weight would
include the weight of all metal, gas and liquid in the portion of the tank treated as described; however the gas weight is negligible and the metal weight may be negligible compared with the liquid weight. W shall be given the same sign as P when it acts in the same direction as the pressure on the horizontal face of the free body; it shall be given the opposite sign when it acts in the opposite direction. At
=
Cross section area in in2 of the side walls, roof or bottom of the tank at the level under consideration.
t
=
Thickness in inch of the side walls, roof or bottom of the tank at the level under consideration.
c
=
Corrosion allowance in inch
E
=
Joint efficiency
Sts
=
Maximum allowable stress for simple tension in lbs/in2 as given in table 5-1
Sca
=
Allowable compresive stress in lbs/in2 established as prescribed in 5.5.4
Design Data : API 620 10TH Ed. ADD.01
Desig Code Client's Specs Fluid Material Design Density of Contents
= =
Density of water for hydrotest = Specific Gravity Of Contents Material Yield Strength Design Temperature Internal Pressure Extrenal Pressure Liquid Level
= = = = = =
Sulphuric Acid A36 1820 113.623 1000 62.43 1.82 248.21 36000 100 1.015 146.16 0.0725 4200 13.78
Design Liquid Level
= = =
Allowable Tensile Stress At Design Temperature
4200 14 110.32 16000
Corrosion Allowance Shell
6.4 0.25197 6.4 0.25197 6.4 0.25197
Bottom Roof
Inside Dia Of Tank
D
=
Height Of Shell
=
Weight Of Compression Ring IF applicable Weight Of Accessories Wind Velocity
= =
4000 13.12 4010 13.16 4020 13.19 158.27 4200 14 450 3000 96.31
Nominal Dia Of Tank
Dn
=
Outside Dia of tank
D0
=
Yield Strength Of Steel Structure Roof Angle
= =
36000 11.3
Roof Design
As Per API 620 B 5.10.2
Assumptions
Taking Thickness
t
Joint Efficiency
E
Radius Of Dome
rr
Height Of Cone Roof
One Half The included apex angle of the Conical roof or bottom . Radius Of Cone
= = = = =
14 mm 0.551 inch 0.7 1xD 13.12 ft
h
=
1.31 ft
a
=
78.7
L
=
6.69 ft
Angle b/w the normal to roof q and a vertical line at the roof to shell juncture
=
At'
Roof Area Roof Weight
= = W (Uncorroded) =
Roof Weight
W (corroded) = At
Cross sectional Area at roof to shell junction
11.30
20256 141 Density x t x Roof Area 3163 1719
= =
19478 135
As per API 620 5.10.2.5.a
For Conical Seg.
R1
=
Infinity
ft
As per API 620 5.10.2.5.a
R3 = D/2
Case I :
= =
6.562 ft 78.74 inch
Thickness At The Top Head Edge Against Internal Pressure
W/At W/At'
= =
-0.162 psi -0.156 psi (force acting in downward direction)
Now Calculating Meridional and Latitudinal Forces T1
=
{R3/(2Cosa)}*{P+W/At}
= T2
=
Equation 8 of 5.10.2.5
171 lbf/in {(P × R3)/(Cosa)} 408 lbf/in
Now As Per 5.10.3.2 If T1 and T2 both are +ve, then T
=
Max.(T1 and T2) 408 lbf/in
tcalc.
= =
T/(Sts.E) + C.A 0.288 inch
Equation 9 of 5.10.2.5
Provided Thickness is Ok
Case II :
Thickness At The Top Head Center Against Internal Pressure
T1 '
T2 '
=
Rs/2(P+W/At')
=
0 lbf/in
= =
Rs x (P+W/At') - T1 0 lbf/in
Now As Per 5.10.3.2 If T1 and T2 both are +ve, then T
= =
Max.(T1' and T2') 0 lbf/in
tcalc.
=
T/(Sts.E) + C.A 0.252 inch
As these thicknesses are calculated based on the internal pressure of = 1.015 psi Therefore, Back calculating the internal pressure limited by the actual provided thickness
tprov.
=
T/(Sts.E) + C.A
(tprov. - C.A) X Sts X E = = 3351 lbf/in Now putting this value of T in the equation of T2, where we find the maximum calculated thickness T
T2
=
Rs x (P+W/At x cos a) - T1
T
=
Rs x (P+W/At x cos a) - Rs/2(P+W/At) T2 = T
P
= =
(2 X T/Rs) - W/At(2*cos a -1) #DIV/0! #DIV/0!
As Per 7.18.3.2, our roof will be safe against the hydro test pressure of 1.25 x internal pressure i.e. 1.26875 psi
Case II :
Thickness At The Top Head Edge Against External Pressure
W = - (Live Load + Dead Load) x Roof Area -ve sign id due to the downward direction of load -(25 + weight of roof in lbs/ft2) x roof area
=
W/At W/At'
=
-4985 lbf
= =
-0.256 psi -0.246 psi
Now Calculating Meridional and Latitudinal Forces T1
= =
{R3/(2Cosa)}*{P+W/At} -66.0 lbf/in
Equation 8 of 5.10.2.5
T2
=
{(P × R3)/(Cosa)} -29.1 lbf/in
Equation 9 of 5.10.2.5
Now As Per 5.10.3.5 T'
= =
Max.{ABS(T1) , ABS(T2)} 66.0 lbf/in
T"
=
Min.{ABS(T1) , ABS(T2)} 29.1 lbf/in
R' R"
= =
Infinity
t18
= =
Sqrt{(T'+0.8 X T") X R'}/1342 +Solving C.A By Equation 18 of API 620 Infinity inch
t19
=
SQRT{T'' x R''}/1000 + CA 0.300 inch
Similarly, 78.74 inch
Now,
Now; As per 5.10.3.5.b Step-2 t18 - C.A R'
=
Infinity
< .0067
Solving By Equation 19 of API 620
t19 - C.A R'' treq treq tprovided
=
0.0006
< .0067
Max(t18 , t19) 0.300 inch
= = =
0.551 inch
As per 5.5.4.3 Allowable Compressive Stress; Sca
Provided thickness is O.K
Case IV :
Thickness At The Top Head Center Against External Pressure
T1 '
Rs/2(P+W/At' )
= =
0.00 lbf/in
T2 '
= = Now As Per 5.10.3.5
Rs(P+W/At' ) -T1' 0.00 lbf/in
T'
=
T"
=
Max.{ABS(T1' ) , ABS(T2' )} 0.00 lbf/in Min.{ABS(T1' ) , ABS(T2' )} 0.00 lbf/in
Similarly R' = R2 R" = R1
0.00 inch 0.00 inch
Now, t18
=
t19
=
Now; As per 5.10.3.5.b Step-2 t18 - C.A R' t19 - C.A R'' treq
=
treq
= =
tprovided
Sqrt{(T'-0.8 X T") X R'}/1342 + Solving C.A By Equation 18 of API 620 0.252 SQRT{T'' x R''}/1000 + CA Solving By Equation 19 of API 620 0.252
=
#DIV/0!
< .0067
=
#DIV/0!
< .0067
Max(t18 , t19) 0.252 inch 0.551 inch
As per 5.5.4.3 Allowable Compressive Stress; Sca Sca
=
= 106 x (t - C.A) R' #DIV/0!
As these thicknesses are calculated based on the external pressure of P = 0.0725 psi Therefore, Back calculating the external pressure limited by the actual provided thickness
Now; As per 5.10.3.5.a t19
=
SQRT{T'' x R''}/1000 + CA
tprovided
=
SQRT{T'' x R''}/1000 + CA
T''
=
[(tprovided-C.A) x 1000 ]2 / R''
T''
=
T''
=
-Rs/2(P+W/At' )
Pext
=
2/Rs x T'' - W/At' #DIV/0! Psi
#DIV/0!
lbs/in
NOTE:
As Per 32-SAMSS-006 Para 5.4.k, roof live loads shall not be less than concentrated load of 225 Kgs over 0.4 meter square area. for this purpose, by considering the roof segment of 700mm diamter which is equivelant to 0.4 meter squre area is to be analysed against these loading conditions #DIV/0! For result and methodolgy see ANNEXURE 1
3)
Shell Design Shell calculations are based on different assumed thicknesses, here we will perform the specimen calculations for 1st shell course and the others are given in the tabulated form which are mentioned below.
Case I :
Thickness of 1st shell course Against Internal Pressure
Joint Efficiency
E
Taking thickness of Ist Shell Course Total weight of shell of different
=
0.85
= =
0.630 inch 26004 lbs
=
3163 lbs
thicknesses. Total weight of roof
Total Weight; W W/At
(Roof Pl.+Shell).= =
29167 lbs 1.50 psi
Now Total Pressure Internal Pressure + Pressure due to liquid head
=
24.31 psi
Now calculating the latitudinal and maridianal forces As Per 5.10.2.5.c
T1
= =
Rc/2(P+W/At) equation 10 of 5.10.2.5 1,016 lbs/inch
T2
= =
Rc x P
Now As Per 5.10.3.2 If T1 and T2 both are +ve, then T = = tcalc.
= =
equation 11 of 5.10.2.5 1,915 lbs/inch
Max.(T1 and T2) 1,915
lbs/inch
T/(Sts.E) + C.A 0.39
inch
The same procedure is adopted while confirming the thickness during hydrotest
As this thickness is calculated based on the internal pressure of P = Internal Pressure + Pressure due to liquid head = 24.31 psi Back calculating the internal pressure limited by the actual provided thickness tprov. T/(Sts.E) + C.A = T
=
5,140 lbs/inch
Now putting this value of T in the equation of T2, where we find the maximum calculated thickness
Case II :
T2
=
Rc x P
Pmax.int
= =
T2/Rc
T2=T 65.28 psi
Thickness of 1st shell course Against External Pressure
= -(Weight Of Roof Plates + Weight Of shell + Live Load) = -32684 lbs Pext. = -0.0725 psi -ve sign id due to the downward direction of load W
Now calculating the latitudinal and maridianal forces As Per 5.10.2.5.c
T1
=
Rc/2(P+W/At) equation 10 of 5.10.2.5 -69 lbs/inch
T2
=
Rc x P
equation 11 of 5.10.2.5 -5.71 lbs/inch
Now As Per 5.10.3.5 T' T"
=
Max.{ABS(T1) , ABS(T2)}
=
69 lbs/inch Min.{ABS(T1) , ABS(T2)} 6 lbs/inch
similarly,
R' = Rc R" = Rc Now,
= =
78.74 inch 78.74 inch
t18
= = t19 = = Now; As per 5.10.3.5.b Step-2 t18 - C.A R' t19 - C.A R'' treq
= =
Sqrt{(T'+0.8 X T") X R'}/1342 + C.A 0.3087 inch SQRT{T'' x R''}/1000 + CA 0.2732 inch
=
0.0007
< .0067
=
0.0003
< .0067
Solving By Equation 18 of API 620 Solving By Equation 19 of API 620
Max(t18 , t19) 0.3087 inch
As per 5.5.4.3 Allowable Compressive Stress; Sca Sca
=
= 106 x (t - C.A) R' 0
Psi
Back calculating the external pressure limited by the actual provided thickness
Now; As per 5.10.3.5.a as the maximum thickness is obtained by equation 18, therefore back calculating the external pressure limited by tprov.
t18
=
{1342 x (tprov.-C.A)}2/R'
=
{1342 x (tprov.-C.A)}2/R'
=
Sqrt{(T'+0.8 X T") X R'}/1342 + C.A T'-0.8 X T" -Rc/2(P+W/At)- 0.8 x (Rc x P)
Now Putting the values in the above equation
Pmax.ext.
=
-31.27 Psi
-ve sign shows the vacuum condition. Assuming Thicknesses of Various Shell Courses and Calculate their Weights
Now following the above mentioned procedure for the calculation of remaining shell courses.
CASE 1. Table 1.
Internal Pressure With Full of Liquid
Shell
Thickness
Width
Weights
Coures #
mm
inch
mm
inch
1 2 3 4 5 6
16 14 12 10 0 0
0.630 0.551 0.472 0.394 0.000 0.000
2450 2450 2450 1650 0 0
96.46 96.46 96.46 64.96 0.00 0.00
Total Weight Of Shell
Kgs
3,863 3,380 2,897 1,626 =
Table 2.
Shell Coures #
1 2 3 4 5 6
Weight of Roof
Weight of Shell
lbs
lbs
3,163 3,163 3,163 3,163 3,163 3,163
26,004 17,467 9,997 3,594 -
Total Weight Total Weight WHydrotest W lbs
29,167 20,630 13,160 6,756 3,163 3,163
lbs
29,167 20,630 13,160 6,756 3,163 3,163
W/At Psi
1.50 1.06 0.68 0.35 0.16 0.16
Table 3.
Shell Coures #
1 2 3 4 5 6
Water Pressure Head Psi
Total Pressure PContents
Total Pressure PHydrotest
Psi
Contents Pressure head Psi
Psi
Psi
1.015 1.015 1.015 1.015 1.015 1.015
23.30 16.96 10.61 4.27 0.00 0.00
12.80 9.32 5.83 2.35 0.00 0.00
24.31 17.97 11.63 5.29 1.02 1.02
Internal Pressure
As Per 7.18.3.2 Internal Presssure for Hydrotest is 1.25 * Pint Now Calculating Meridianal and Latitudinal Forces aginst pressure and During Hydrotest Condition.
Shell Coures #
Pcon.+W/At internal Psi
Phydro+W/At Hydrotest Psi
T1
T1hydro
lbs/inch
lbs/inch
1 2 3 4
25.81 19.03 12.30 5.63
15.57 11.64 7.78 3.96
1,016.22 749.25 484.44 221.79
612.92 458.46 306.16 156.01
5 6
1.18 1.18
1.43 1.43
46.35 46.35
56.34 56.34
Shell Coures #
1 2 3 4 5 6
T2
T2hydro
lbs/inch
lbs/inch
1,914.53 1,415.11 915.69 416.27 79.92 79.92
1,107.93 833.52 559.11 284.71 99.90 99.90
T{Max.(T1,T2) T{Max.(T1hyd., T2hyd.)} } lbs/inch lbs/inch
1,914.53 1,415.11 915.69 416.27 79.92 79.92
1,107.93 833.52 559.11 284.71 99.90 99.90
Now Calculating the required thickness as Per 5.10.3.2 Shell Coures #
tcalc.
thydro
tcalc1.25GHD Therefore WL=1.25GHD
WL
8.2)
=
413.5 lbs/ft
Shell Compression For Unanchored Tanks Ms
=
0.39
Per API 620 Appendix. L.5.1
D2(Wt+WL)
=
0.39
Where, Wt
{Weight of Roof + Weight Of Shell}/p x D 704 lbs/ft
= =
As Ms/{D2*(Wt+WL)
View more...
Comments