BITS PILANI Test - 4 – Answer Key & Explanatory Answers

BITS PILANI Test - 4 – Answer Key & Explanatory Answers 1.By selling a tape - recorder for ₹ 1040 a man gains 4% . If he sells if for ₹ 950 , his loss will be 1) 5% 2) 4% 3) 4.5% 4) 9% 2.Every Sunday , Gin jogs3 miles . For the rest of the week , each day he jogs1 mile more than the previous day . How many miles Gin jogs in 2 weeks ? 1) 42 2) 63 3) 84 4) 98 3.A rectangle with one side of length 4 cm is inscribed in a circle of diameter 5 cm . Find area of the rectangle 1) 21 cm2 2) 12 cm2 3) 4 cm2 4) 3 cm2 4.The price of a shirt after 15% discount, is Rs.119. What was the marked price of the shirt before discount 1) Rs.129 2) Rs.140 3) Rs.150 4) Rs.160 5.The average of a,b,c is 20 and that of b,c,d is 25; if d=30, then the value of a is 1) 25 2) 45 3) 30 4) 15 6.The ratio of circumradius and radius of an equilateral triangle is 1) 1:2 2) 3:1 3) 2:1 4) 1:3 7.AB is a diameter of the circle with centre O , CD is chord of the circle , If ∠BOC = 120° , then the value of ∠ADC is 1) 42° 2) 30° 3) 60° 4) 35° 8.A straight tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle of 30° with the ground . The distance from the foot of the tree to the point , where the top touches the ground is 10 m. Find the total height of the tree? 1) 10√3 m 2) 10√3 /3 m 3) 10 ( √3 + 1) m 4) 10 ( √3 - 1) m 9.The compound interest on a certain sum for 2 yearsat 10% per annum isRs. 525 . The simple interest on the same sum for double the time at half the rate percent per annum is : 1) Rs.520 2) Rs.550 3) Rs. 500 4) Rs. 515 10.If tan θ = tan 30° . tan 60° and θ is an acute angle , then 2θ is equal to 1) 30° 2) 45° 3) 90° 4) 0° 11.Find the sum of the distinct roots of the equation: |x2 + x + 4| = 4x + 2? (1) -2 (2) 3 (3) -5 (4) 0

(5) None of these

Solution: Given equation: |x2 + x + 4| = 4x + 2. i) Consider |x2 + x + 4| = x2 + x + 4, then x2 + x + 4 = 4x + 2 → x2 – 3x + 2 = 0 → (x – 1)(x – 2) = 0 → x = 1 or 2. ii) Consider |x2 + x + 4| = -x2 – x – 4, then –x2 – x – 4 = 4x + 2 → –x2 – 5x – 6 = 0 → x2 + 5x + 6 = 0 → (x + 2)(x + 3) = 0 → x = -2 or -3. Thus, the sum of the distinct roots = 1 + 2 – 2 – 3 = -2. Hence, the correct answer is option 1. 12.Natural numbers starting from 1 are written one next to another as shown: 123456789101112... N is a number which contains the first 5555 digits (from left) of the above series. What is the remainder when N is divided by 5? (1) 4 (2) 2 (3) 1 (4) 3 (5) 0 Solution: N = 123456789101112 … (5555 digits). The 5555th digit is found out as follows: © 2017 ETHNUS

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BITS PILANI Test - 4 – Answer Key & Explanatory Answers In the above series, i) There are 9 single digit numbers, which would in all have 9 × 1 = 9 digits. ii) There are 90 double digit numbers, which would in all have 90 × 2 = 180 digits. iii) There are 900 triple digit numbers, which would in all have 900 × 3 = 2700 digits. So, until now there are 2700 + 180 + 9 = 2889 digits. Till 5555th digit, there are (5555 – 2889) = 2666 digits more. Since these are all 4 digit numbers, there would be (2666/4) = 666.5 numbers or 666 numbers followed by 2 more digits OR it would be the 2nd digit of the 667th four digit number, which is the 2nd digit of (999 + 667 = 1666) = 6. Thus, when N (which ends in 6) is divided by 5, the remainder would be 1. Hence, the correct answer is option 3. 13.Given that: f(x) = 3x2 + 12, g(x) = 5x – 6 and h(x) = 4; what is the value of (fogoh)100(x), where (fogoh)n(x) indicates (fogoh)o...(fogoh)o(fogoh)(x) ‘n’ times? (1) 4100 (2) 4 (3) 14 (4) 600 (5) None of these Solution: Given: f(x) = 3x2 + 12, g(x) = 5x – 6 and h(x) = 4. (fogoh)(x) = (f(g(h(x)))) = (f(g(h(1)))) = (f(g(4))) = (f(5 × 4 – 6)) = f(14) = (3 × 142 + 12) = 600. Now, (fogoh)2(x) = (fogoh)o((fogoh)(x)) = (fogoh)o(600) = (f(g(h(600)))) = (f(g(4))) = f(14) = (3 × 142 + 12) = 600. Thus, this cycle would repeat for any positive value of n. Hence, (fogoh)n(x) = (fogoh)100(x) = 600. Hence, the correct answer is option 4. 14.Given f [(2n)/(1 + n2)] = 2 f(n), where n is a positive integer, then which of the following expressions could f(n) always be equal to? (1) log[(1 + n)/(1 – n)] (2) log(1/n) (3) log[(1 – n)/(1 + n)] (4) log[(1 + n2)/(n)] (5) More than one of these Solution: Given: f [(2n)/(1 + n2)] = 2 f(n). i) Consider f(n) = log[(1 + n)/(1 – n)], then f [(2n)/(1 + n2)] = log({1 + [(2n)/(1 + n2)]}/{1 – [(2n)/(1 + n2)]}) → f [(2n)/(1 + n2)] = log{[(1 + n)2]/ [(1 – n)2]} → f [(2n)/(1 + n2)] = 2 × log[(1 + n)/ (1 – n)] = 2 × f(n). ii) Consider f(n) = log(1/n), then f [(2n)/(1 + n2)] = log[(1 + n2)/ (2n)] ≠ 2 × f(n). iii) Consider f(n) = log[(1 – n)/(1 + n)], then f [(2n)/(1 + n2)] = log({1 – [(2n)/(1 + n2)]}/{1 + [(2n)/(1 + n2)]}) → f [(2n)/(1 + n2)] = log{[(1 – n)2]/ [(1 + n)2]} → f [(2n)/(1 + n2)] = 2 × log[(1 – n)/ (1 + n)] = 2 × f(n). iv) Consider f(n) = log[(1 + n2)/(n)], then f [(2n)/(1 + n2)] = log({[2(1 + n2)/(n)]/{1 + [(1 + n2)/(n)]2}) ≠ 2 × f(n). Hence, f [(2n)/(1 + n2)] = 2 f(n) for more than one of the above cases. Hence, the correct answer is option 5. 15.Danny Ocean and Willy Bank travel separately from Las Vegas to Grand Canyon. The way they travel is as described below: (i) Ocean travels at a speed of ‘3v’ for the 1st one-fourth of the time, at a speed of ‘5v’ for the 2nd one-fourth of the time, at a speed of ‘v’ for the 3rd one-fourth of the time and at a speed of ‘11v’ for the last one-fourth of the total journey time. (ii) Bank travels the 1st one-fourth of the distance at a speed of ‘4v’, the 2nd one-fourth of the distance at a speed of ‘6v’, the 3rd one-fourth of the distance at a speed of ‘8v’ and the last one-fourth of the distance at a speed of ‘2v’. What is the ratio of the average total journey speeds of the slower to the faster of the two? (1) 2:3 (2) 3:4 (3) 4:5 (4) 19:25 (5) None of these Solution: Let the total distance from Las Vegas to Grand Canyon be denoted by D. © 2017 ETHNUS

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BITS PILANI Test - 4 – Answer Key & Explanatory Answers i) For Ocean, let the total journey time be denoted by T. Distance covered in the 1st 1/4th of the time = 3 × Tv/4 Distance covered in the 2nd 1/4th of the time = 5 × Tv/4 Distance covered in the 3rd 1/4th of the time = 1 × Tv/4 Distance covered in the 4th 1/4th of the time = 11 × Tv/4 Thus, total distance covered = (3 + 5 + 1 + 11) × Tv/4 = 5Tv = D. Thus, the total average speed = D/ T = 5Tv/ T = 5v. ii) For Bank: Time for the 1st 1/4th of the distance = (D/4)/4v = D/16v. Time for the 2nd 1/4th of the distance = (D/4)/6v = D/24v. Time for the 3rd 1/4th of the distance = (D/4)/8v = D/32v. Time for the 4th 1/4th of the distance = (D/4)/2v = D/8v. Thus, the total time = (25/96) × D/v. Thus, the total average speed = D/[(25/96) × D/v] = 96v/25. Thus, the ratio of the slower to the faster speed = (96/25): 5 = 96: 125. Hence, the correct answer is option 5. 16.When the graph of f(x) = x2 – 4x + 3 is reflected in a co-ordinate graph system along the line y = 3, the graph of g(x) is obtained. Find the value of the expression: f(5) – g(5)? (1) 6 (2) -6 (3) -10 (4) 10 (5) None of these Solution: When graph of f(x) is reflected along the line y = 3, the graph of g(x) is obtained. Thus, the two graphs are symmetric about the line y = 3. Hence, f(x) + g(x) = 3 + 3 = 6. → x2 – 4x + 3 + g(x) = 6 → g(x) = 3 + 4x – x2 → g(5) = 3 + 4 × 5 – 52 = 3 + 20 – 25 = -2. f(5) = 52 – (4 × 5) + 3 = 8. Hence, f(5) – g(5) = 8 – (-2) = 10. Hence, the correct answer is option 4. 17.A circle C1 is drawn such that it touches all the four corners of a square and another circle C2 is drawn such that it touches the mid-points of all the four sides of the same square? What is the ratio of the area of the larger circle that lies outside the smaller circle to that of the area of the smaller circle? (1) 1:√2 (2) 1:1 (3) √2:1 (4) 2:1 (5) (π – 1):1 Solution: Here, circle C1 would be the circumcircle to the given square while circle C2 would be the in-circle to the same square, whose side is denoted by 2a. Radius of the circumcircle C1 = (1/2) × Diagonal of the square = a√2. Thus, area of C1 (larger circle) = π × (a√2)2 = 2πa2 sq. units. Radius of the in-circle C2 = (2a /2) = a. Thus, area of C2 (smaller circle) = π × (a)2 = πa2 sq. units. Thus, area of C1 outside C2 = (2πa2 – πa2) = πa2 sq. units. Hence, the ratio of the area of C1 outside C2 to the area of C2 = πa2: πa2 = 1:1. Hence, the correct answer is option 2. 18. The ratio of the prices of a typical sports motorbike of Honda and Suzuki is the same as the ratio of the prices of a typical sedan car model of the same auto companies. The ratio of the sum of prices of the two sedan cars to the ratio of the sum of the prices of the two motorbikes is equal to 5:2. What is the ratio of the absolute value of the difference of the prices of the two motorbikes to the absolute value of the difference of the prices of the two sedan cars? (1) 1:2 (2) 2:3 (3) 2:5 (4) 5:2 (5) 5:3 Solution: Let the prices of the motorbike and car of the company Honda be denoted by hm and hc respectively. Also, let the prices of the motorbike and car of the company Suzuki be denoted by sm and sc respectively. By given data, it can be written that: © 2017 ETHNUS

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BITS PILANI Test - 4 – Answer Key & Explanatory Answers i) (hm /sm) = (hc /sc) (1) ii) (hc+ sc)/(hm+ sm) = 5/2 (2) From (2), we get (hm+ sm)/ (hc+ sc) = 2/5. According to componendo – dividendo rule: If a/b = c/d, then (a + b)/(a – b) = (c + d)/(c – d). Similarly, from (1), since (hm /sm) = (hc /sc), (hm+ sm)/ (hm– sm) = (hc+ sc)/ (hc – sc) → (hm+ sm)/ (hc+ sc) = (hm– sm)/ (hc – sc) = 2/5. Hence, the correct answer is option 3. 19.Rajeev buys a new model pen for a certain amount and sells it at a profit of 30%. If he had bought it at 20% less and sold it for Rs 21 less, he would still make a profit of 10%. At what price (in Rs) did he originally buy it for? (1) 42 (2) 50 (3) 40 (4) 65 (5) 210 Solution: Let the original cost price and the original selling price of the pen be denoted by c and s respectively. Since profit = 30%, s = 1.3c. Now, if the cost price was 20% less, new cost price = 0.8c. Also new selling price = s – 21 = 1.3c – 21. New profit = new selling price – new cost price = 1.3c – 21 – 0.8c = 0.5c – 21 Profit = 10% = 1/10 = (0.5c – 21)/ 0.8c → 5c – 0.8c = 4.2c = 210 → c = 210/4.2 = 50. Hence, the original price at which the pen was bought is Rs 50. Hence, the correct answer is option 2. 20. A particular locking mechanism has a five-digit lock code. This lock code contains only those digits which are either prime or even. How many such lock codes exist in all (assume that the digits can repeat)? (1) 34405 (2) 35560 (3) 45913 (4) 49000 (5) None of these Solution: Even or prime digits are 2, 3, 4, 5, 6, 7 and 8. Thus, digits which should not be present are 0, 1 and 9. Total number of five digit numbers are 10000 to 99999, a total of 90000 numbers. Among these, the numbers from 10000 to 19999 and 90000 to 99999 can be ignored since they begin with 1 and 9 respectively. Thus, there are 90000 – 20000 = 70000 numbers left. i) Consider the number series 20000 to 29999. Among these numbers mentioned above, the numbers which have the digits 0, 1 and/or 9 need to be ignored. Consider the numeral ‘0’ first. Then, the number of five digit numbers between 20000 and 29999 which have: a) Four 0’s = 4C4 × 70 = 1 × 1 = 1 (Since 0, 1 and 9 need to be ignored, hence 7 numerals are remaining which can be chosen). b) Three 0’s = 4C3 × 71 = 4 × 7 = 28. c) Two 0’s = 4C2 × 72 = 6 × 49 = 294. d) One 0 = 4C1 × 73 = 4 × 343 = 1372. Thus, all the above numbers = 1 + 28 + 294 + 1372 = 1695 numbers can be ignored. Similarly, we get 1695 distinct numbers between 20000 and 29999, which contain 1 in them. Similarly, we get 1695 distinct numbers between 20000 and 29999, which contain 9 in them. Thus, there a total of 1695 + 1695 + 1695 = 5085 numbers which contain 0, 1 and/or 9. Hence, the numbers between 20000 and 29999 which can be used for the lock code = 10000 – 5085 = 4915 such numbers. Similarly, between 30000 and 39999, … 80000 and 89999, for each set of 10000 numbers, 4915 numbers could be used as codes. In all, there are a total of 7 such sets, thus the total number of valid lock codes = 7 × 4915 = 34405. Hence, the correct answer is option 1. 21.Two years ago, Aadhya was three times as old as his son and two years hence, twice her age will be equal to five times that of her son. Find Aadhya's present age. 1) 38 years 2) 36 years 3) 34 years 4) 42 years © 2017 ETHNUS

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BITS PILANI Test - 4 – Answer Key & Explanatory Answers 22.From the given alternative words, select the word which cannot be formed using the letters of the given word: ADMINISTRATION 1) STRAIN 2) TRADITION 3) SITUATION 4) RATION 23.If MOTHER is coded as KMRFCP, then HOUSE is coded as 1) FMRPC 2) GNSQD 3) GNRQD

4) FMSQC

24.If D stands for x, S stands for +, A stands for - and M stands for ÷, what is the value of the given expression 1) 558 2) 3312 3) 137 4) 31 25.If 3 * 4 = 10, 5 * 8 = 18, 7 * 7 = ? 1) 26 2) 21

3) 28

26.Select the related word/letters/number from the given alternatives. Foot : Man :: Hoof : ? 1) Leg 2) Dog 3) Horse

4) 49

4) Shoe

27.Rahul starts and walks towards the south, he then turns to his right and walks 5 kms, then again turns left and walks 3 kms and then again turns left and walks 5 kms. In which direction is he from the starting point? 1) NORTH 2) SOUTH 3) EAST 4) WEST 28.Consider the given statement/s to be true and decide which of the given conclusions/assumptions can definitely be drawn from the given statement. Statements: a) Odisha is still an underdeveloped state. b) Problems like poverty, unemployment and illiteracy have not been solved. Conclusions: I) The administration of Orissa is not sensitive enough.II) It is the Will of God. 1) Only I follows 2) Only II follows 3) Both I and II follow 4) Neither I and II follows 29.Select the related word/letters/number from the given alternatives. ACEG : ZXVT :: IKMO : ? 1) MNOP 2) PQRS 3) RPNL

4) LNPR

30.Select the related word/letters/number from the given alternatives. 68 : 130 :: 222 : ? 1) 345 2) 365 3) 355

4) 350

Directions for Questions 31 to 35: Each question is followed by two statements A and B. Indicate your responses based on the following directives: Mark (1) if the question can be answered using A alone but not using B alone. Mark (2) if the question can be answered using B alone but not using A alone. Mark (3) if the question can be answered using A and B together, but not using either A or B alone Mark (4) if the question can be answered using either statement alone. Mark (5) if the question cannot be answered even using A and B together 31. There are 10 groups of students each group consisting 10 students in a park. The groups are named with the alphabets A, B, C, D…I, J. How many different heights of students are there? A: Any two consecutive alphabetical groups have exactly one student with the same height. B: Except any two consecutive alphabetical groups, no other pair of groups has any student with the same height. (1) if the question can be answered using A alone but not using B alone. (2) if the question can be answered using B alone but not using A alone. (3) if the question can be answered using A and B together, but not using either A or B alone (4) if the question can be answered using either statement alone. (5) if the question cannot be answered even using A and B together Solution: Either statement alone is not sufficient to find a unique answer. © 2017 ETHNUS

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BITS PILANI Test - 4 – Answer Key & Explanatory Answers From A & B, the total number of students with same heights = 9. The number of different heights of students = 100 – 9 = 91 Hence, the correct answer is option 3. 32.

How many 4-digit numbers “abcd” are there for which the number of factors is an odd number? A: ‘a’ = ‘b’ and ‘c’ = ‘d’ B: ‘d’ is an even number. (1) if the question can be answered using A alone but not using B alone. (2) if the question can be answered using B alone but not using A alone. (3) if the question can be answered using A and B together, but not using either A or B alone (4) if the question can be answered using either statement alone. (5) if the question cannot be answered even using A and B together Solution: The number has to be a perfect square because it has odd number of factors. From statement A alone, we have aacc = 1000a + 100a + 10c + c aacc = 1100a + 11c aacc = 11[100a + c] Since ‘aacc’ is a perfect square [100a + c] should be a multiple of 11, i.e., {[100a + c]/ 11}is an integer. [100a + c]/11 = 9a + (a + c)/11 We know that (a + c) should be a multiple of 11. The only possibility is a = 7 and c = 4. So, the number is 7744. Hence, the correct answer is option 1. 33. ‘y’?

Consider integers ‘x’, ‘y’ and ‘z’. If the value of x2 + y2 + z2 is minimum, then what is the difference between ‘x’ and

A: ‘y’ is greater than ‘x’. B: x + y + z = 79 (1) if the question can be answered using A alone but not using B alone. (2) if the question can be answered using B alone but not using A alone. (3) if the question can be answered using A and B together, but not using either A or B alone (4) if the question can be answered using either statement alone. (5) if the question cannot be answered even using A and B together Solution: From B, In the equation x + y + z = 79 when x, y and z have to be equal for the value of x2 + y2 + z2 is to be minimum, i.e. (x, y, z ) = (26, 26, 27). The difference between ‘x’ and ‘y’ could either be 0 or 1. So, combining A and B, we have y – x = 1. Hence, the correct answer is option 3. 34.

What is the distance between the points A and B given that C and D are points on the line AB? A: AC = BD = 8 units and CD = 5 units. B. The distance between A and B is more than 10 units. (1) if the question can be answered using A alone but not using B alone. (2) if the question can be answered using B alone but not using A alone. (3) if the question can be answered using A and B together, but not using either A or B alone (4) if the question can be answered using either statement alone. (5) if the question cannot be answered even using A and B together Solution: Given that Case I: A_______________C_______________D___________B Case II: A_______________D_______________C___________B From statement A, AC = 8 BD = 8 and CD = 5 AC + CD + BD = 21 and for case II © 2017 ETHNUS

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BITS PILANI Test - 4 – Answer Key & Explanatory Answers AC + BD – CD = 8 + 8 – 5 = 9 From this also we do not know whether it is case I or Case II. Now combining A and B, we have the answer as 21 units. Hence, the correct answer is option 3. 35. Kumari Sheela bought two different items from a store, item A and item B. What is the least number of items of A could she have been bought? A: The cost of an item A is Rs. 97 and an item B is Rs. 299. B: The amount that she spent in buying item A is Rs. 50 more than the amount that she spent in buying B. (1) if the question can be answered using A alone but not using B alone. (2) if the question can be answered using B alone but not using A alone. (3) if the question can be answered using A and B together, but not using either A or B alone (4) if the question can be answered using either statement alone. (5) if the question cannot be answered even using A and B together Solution: This question can be answered using statement A and B together. From statement A and B: Given that 97A = 299B + 50 97A – 299B = 50 97(A – 3B) = 8B + 50 To satisfy this equation above, 8B + 50 must be divisible by 97 and also it should be an even number. Hence the least possible value of 8B + 50 is 97 × 2 = 194 In this case B = 18 and the value of A is = 56. Hence, the correct answer is option 3. Directions for questions 36 to 38 : Refer the following data to answer the questions given below. There are thirty three states in a country. The following table gives the number of deaths in each of the thirty three states in a country. State Deaths Reported Deaths Reported Deaths Reported S1 1105 S2 31 S3 88 S4 45 S5 4 S6 228 S7 308 S8 227 S9 0 S10 560 S11 317 36.

State State S12 S13 S14 S15 S16 S17 S18 S19 S20 S21 S22

313 1053 0 2 59 0 1541 167 190 27 326

S23 S24 S25 S26 S27 S28 S29 S30 S31 S32 S33

0 227 327 46 57 1 10 1533 0 16 0

Which is the state that accounts for nearly 12.5% of the total deaths in the country? (1) S1 (2) S13 (3) S18 (4) S30

(5) None of these

Solution: Total number of deaths = 8808 12.5% of 8808 = One-eighth of 8808 =1101. Hence, the correct answer is option 1. 37.

How many states account less than five percent of the total deaths of the states S1, S13 and S18 put together? (1) 14 (2) 16 (3) 18 (4) 19 (5) 17

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BITS PILANI Test - 4 – Answer Key & Explanatory Answers Solution: The number of deaths of S1, S13 and S18 = 1105 + 1053 + 1541 = 3699 ≅ 3700 Five percent of it = (1/20) × 3700 = 185. The number of states with deaths less than 185 are 19. They are S2, S3, S4, S5, S9, S14, S15, S16, S17, S19, S21, S23, S26, S27, S28, S29, S31, S32 and S33. Hence, the correct answer is option 4. 38. If all the states with less than fifty deaths each are removed from the figure, what is the average number of deaths per state? (1) 325 (2) 420 (3) 400 (4) 360 (5) 480 Solution: There are 15 states that show their number of deaths less than 50. New total = 8808 – (31 + 45 + 4 + 2 + 27 + 46 + 1 + 10 + 16) = 8808 – 182 = 8626 ∴ Average = 8626/(33 – 15) = 479.22 ≅ 480. Hence, the correct answer is option 5. Directions for questions 39 and 40: Refer the following data to answer the questions given

below.

The distribution of the estimated number of man-hours required for a research project to be undertaken by two groups of students A, and B is given below. There are only three operations in the research. They are X, Y and Z. Operations Distribution of estimated man-hours Group A Group B Estimated X 110 20 130 140 Y 400 180 580 600 Z 270 160 430 460

Total Man-hours Actual

39. For operation X, if the entire estimated work for Group B has actually been outsourced and in addition, one-fifth of the estimated Group A man-hours has also been outsourced, then what is the total number of man-hours actually spent by Group A for the operation X? (1) 78 hrs (2) 128 hrs (3) 118 hrs (4) 98 hrs (5) None of these Solution: The number of man-hours that is outsourced = 20 + 20% of 110 = 42 man-hours The total number of man-hours to be spent by Group A = 140 – 42 = 98 man-hours Hence, the correct answer is option 4. 40. Which of the following account for approximately slightly more than 50% of the total estimated effort for the research? (1) The sum of estimated total man-hours on operation X and of Group A on Y (2) The sum of estimated man-hours for X and the estimated Group A man-hours on Z and estimated group B manhours on Y (3) The sum of estimated total hours on X and Z put together (4) The total estimated Group A man-hours. (5) The total estimated Group B man-hours. Solution: The total number of estimated man-hours = 1140 hrs. 50% of 1140 = 570 hrs Option [1] = 130 + 400 = 530 hrs Option [2] = 130 + 270 + 180 = 580 hrs Option [3] = 130 + 430 = 560 hrs Option [4] = 110 + 400 + 270 = 780 hrs Option [5] = 20 + 180 + 160 = 360 hrs Hence, the correct answer is option 2. © 2017 ETHNUS

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