Bio-ijso-DPP

CAREER POINT PRE-FOUNDATION COURSE IJSO SUMMER WORKSHOP Daily Practice Problem Sheet Subject : Biology

DPPS. NO. – 01 .

Topic : Photosynthesis Q.1

The enzyme phosphoenol pyruvate carboxylase catalyses the combination of CO2 and phosphoenol pyruvate to form oxaloacetic acid in – (A) Pea (B) Sugarcane (C) Pinus (D) Apple

Q.2

The energy in photosynthesis for attaching a phosphate group to ADP comes from – (A) Breaking down glucose (B) Protons moving from the thylakoid compartment (C) Taking a phosphate off of a sugar (D) All of the above

Q.3

When Rubisco acts as an oxygenase – (A) Phsophoglycerate and phosphoglycolate are produced (B) Phosphoenol pyruvate is oxidized (C) Net carbon fixation is enhanced (D) It must mean that the plant is deprived of CO2

Q.4

Calvin Cycle represents which of the following phenomenon – (A) Oxidative Carboxylation (B) Substrate level phosphorylation (C) Dark respiration (D) Reductive carboxylation

Q.5

The mechanisms of ATP formation both in chloroplast and mitochondria is explained by – (A) Relay pump theory of Godlewski (B) Cholodny Went's model (C) Chemiosmotic theory (D) Munch's pressure/mass flow model

Q.6

In which of the following cells of a C 3 leaf would you find the highest concentration of enzyme rubisco – (A) Epidermal cell (B) Mesophyll cell (C) Bundle sheat cell (D) (B) and (C)

Q.7

In C4 plant, during photosynthesis C4 acid undergoes decarboxylation in _________ to produce C3 acid (pyruvic acid) and __________. (A) Mesophyhll, O2 (B) Bundle sheath, CO2 (C) Grana, CO2 (D) Bundle sheat, CO2

Q.8

During photosynthesis C3 acid is transported from cells of bundle sheath where it is converted to – (A) Pyruvic acid (B) PEP (C) OAA (D) Malic acid

Q.9

Which one is correct for C 4-plants?

(A) (B) (C) (D)

Mesophyll C4-Cycle PEPCase PEPCase Calvin cycle RUBisCO C4-Cycle RUBisCO C2-Cycle

Bundle Sheath C3-Cycle RUBisCO C4-Cycle RUBisCO C3-Cycle PEPCase C3-Cycle PEPCase

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Q.10

Which one of the following correctly identifies X and Y and shows their functions?

X (A) (B) (C) (D) Q.11

Structure Grana Grana Stomata Grana

Y

Function Photolysis of water CO2 fixation Photolysis CO2 fixation

Function CO2fixation Photolysis of water CO2 fixation Photolysis of water

The diagram shows the ultrastructure of a chloroplast as seen in section.What are the fucntions of P, Q and R?

P

Q.12

Structure Stroma Stroma Grana Lamellae

Q

R

(A) Carbohydrate storage

Carbohydrate synthesis

Light reaction

(B) Light reaction

Carbohydrate synthesis

Carbohydrate storage

(C) Light reaction

Carbohydrate storage

Carbohydrate synthesis

(D) Light absorption

Carbohydrate synthesis

Carbohydrate storage

The diagram shows the movement of substances into in and out of a chloroplast – 2

4

Light dependent reaction

Light Independent reaction

1

3

The diagram shows the movement into in and out of a chloroplast

What do labels 1 to 4 represent?

1

2

3

4

(A)

CO2

ATP

H2O

Starch

(B)

CO2

H2O

Sugars

O2

(C)

H2O

O2

CO2

Sugar

(D)

Sugar

H2O

ATP

O2

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Q.13

All C4 plants show Kranz anatomy and it is – (A) Environmentally determined (C) Edaphically determined

(B) Non-gentically determined (D) Genetically determined

Q.14

The term Kranz (wreath) of Kranz-anatomy of leaf C4 plant refers to arrangement of cells. These cells are cells of – (A) Mesophyll (B) Spongyparenchyma (C) Bundle sheath (D) Both mesophyll and bundle sheath

Q.15

I. Photorespiration is favoured by high O2 low CO2, rise in temperature, high light intensity. II. Chloroplasts of cells of bundle sheath of C4 plants are granaless and have RUBisCO but noPEPCo. III. Chloroplasts of mesophyll cells of C4 plant are granale, have PEPCo PEPcase but no RUBisCo. IV. Maize and Sorghum are C4 plants Which of the above statement are true? (A) All are correct (B) I and IV are correct (C) II and III are correct (D) Only IV is correct

Q.16

Rate of photosynthesis is independent of – (A) Quality of light (C) duration of exposure to light

(B) Intensity of light (D) All

Q.17

At higher light insensities gradually photosynthesis rate does not show further increase - why? (A) Higher light intensity activate more chlorophylls (B) Higher light intensity causes more transpiration (C) No need of more sugar formation (D) Other factors become limiting

Q.18

Photosynthesis occurs maximum at – (A) Red light (B) Blue light

(C) Orange light

(D) White light

Q.19

Light is rarely a limiting factor in nature except in – (A) Maize (B) Sugarcane (C)Sorghum (D) Plants - plants growing in shade or in dense forests

Q.20

lncrease in light intensity beyond saturation point causes – (A) More photosynthesis (B) Less photosynthesis (C) Breakdown of the chlorophyll and a decrease in photosynthesis (D) Heliotropism

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CAREER POINT PRE-FOUNDATION COURSE IJSO Daily Practice Problem Sheet Subject : Biology

DPPS. NO. – 02 .

Topic : Control and Coordination in Plants Q.1

Q.2

Arithmetic growth includes all except – (A) constant growth rate (C) It is expressed as Lt = Lo + rt

(B) It is found in root and shoot cells (D) Its characteristic graph is sigmoid

Which one is the correct graph of arithmetic growth?

(A)

(B)

(C)

(D)

Q.3

Why a linear curve is obtained in arithmetic growth? (A) Because it has lag, log and stationary phase (B) Because on daughter cell remains meristematic while the other daughter cell differentiates and matures (C) Because of the effect of environment on mitosis (D) None

Q.4

Go through the following points – I. Slow growth, thereafter exponential group and then stationary phase II. Geometric and arithmetic phases III. Characteristic of all living organisms growing in natural environment IV. W1 = W0ert

Sigmoid curve

Exponential growth

Embryo development

(A)

II

I

III, IV

(B)

I, III

IV

III, IV

(C)

I

II, III

IV

(D)

III, IV

I

II

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Q.5

A-Leaf AGR RGR

Q.6

Q.7

B-Leaf AGR RGR

(A)

1%

1

2%

2

(B)

100%

5

10%

5

(C)

5

100%

5

10%

(D)

0.5

100%

1.5

100%

For growth which one(s) is essential – (A) Nutrients (B) H2O

(C) O2

(D) All

Water is needed for – (A) Cell-enlargement (C) Both

(B) Providing aqueous medium for enzymatic reactions (D) Oxidizing glucose to provide energy

Q.8

I. O2 helps in releasing metabolic energy essential for growth activities. II. Nutrients (Micro and Macromolecules) are required by plants for the synthesis of protoplasm as well as act as source energy. III. Optimum temperature for plant growth is needed IV. Environmental signal like light and gravity affect certain phases of growth. Which of the above statements are correct? (A) All are correct (B) All are incorrect (C) I, II and IV are correct (D) I and IV are corrct

Q.9

Under certain conditions regaining the lost capacity of division by living cells is called – (A) Dedifferentiation (B) Redifferentiation (C) Differentiation (D) Efficiency index

Q.10

Which one is the example of dedifferentiated cells? (A) Procambium + Vascular cambium (B) Vascular cambium + Interfascicular cambium (C) Phellogen + Procambium (D) Cork cambium + Interfascicular cambium

Q.11

Which one(s) is/are redifferentiated cell(s)? (A) Cork (B) Secondary cortex

(C) Both

Growth in plants is – (A) Only determinate (C) Mostly determinate

(B) Only indeterminate (D) Open (both determinate and indeterminate)

Q.12

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(D) None

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Q.13

Differentiation in plant is open because cells/tissues arising out of the same meristem – (A) have same structure at maturity (B) Have different structures at maturity (C) Have capacity to disappear their cell walls (D) Have same fate

Q.14

Column I I. IAA II. GA III. ABA IV. C2H4 V. Kinetin, (N6-furfuryl amino purin) The correct match is – (A) I-B, II-A, III-E, IV-D, V-C (C) I-E, II-D, III-A, IV-B, V-C

Q.15

Q.16

Column II A. Terpenes B. Indole compounds C. Adenine derivatives D. Gases E. Cerotenoid derivatives (B) I-A, II-B, III-C, IV-D, V-E (D) None

Which one includes growth promoters? (A) Auxin, Cytokinin, ABA (C) C2H4, ABA

(B) GA, Cytokinin, C2H4 (D) Auxin, Cytokinin, GA

Which one include growth inhibitors ? (A) ABA, Cytokinin (B) GA, IAA

(C) ABA, C2H4

(D) None

Q.17

PGRs include – (A) Only growth promoters (B) Only growth inhibitors (C) Both growth promoters and growth inhibitors (D) Only solid hormones, not gaseous hormones

Q.18

Which of the following growth regulators can fit either of the groups (promoter and inhibitor) – (A) C2H4 (B) ABA (C) GA (D) IAA

Q.19

I. Cell division II. Cell enlargement III. Pattern formation IV. Tropic growth V. Flowering VI. Fruiting VII. Seed germination VIII. Response to wound IX. Response to stresses of biotic and abiotic origin Which one is correct?

Functions of growth promoters

Functions of growth inhibitor

(A)

I, II, VII, IX

III, IV, V, VI, VIII

(B)

VIII, IX

I, II, III, IV, V, VI, VII

(C)

I, II, III, IV, V, VI, VII

VIII, IX

(D)

I, II, III, IV, V, VI, VII, IX

VIII

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Q.20

Column I I. C. Darwin and F. Darwin II. Miller and Skoog III. F. W Went IV. Kurosawa

Column II A. Cytokinin B. ABA C. C2H4 D. Auxin E. GA

Correct Match is –

Q.21

I

II

III

IV

(A)

D

A

D

E

(B)

D

A

C

B

(C)

C

A

B

D

(D)

E

D

B

A

Statement I - Confirmation of the release of volatile substances from ripened oranges that hastened the ripening of stored unripe bananas. Statement II - Callus formation from the internodal segments of tobacco stem with the Auxin and extracts of vascular tissues/yeast/coconut milk/DNA. Later, Cytokinesis promoting substance was identified, crystallized and named as KINETIN. Statement III - Reporting of appearance of symptoms of bakane/foolish seedling disease caused by fungus. Gibberella fujikuroi, in uninfected seedling when they were treated with sterile filtrates of the fungus. The active substances were later identified as GA. Choose the correct option –

I

II

III

(A)

Miller + Skoog

Cousins

Kurosawa

(B)

Kurosawa

Cousins

Miller + Skoog

(C)

Cousins

Kurosawa

Miller + Skoog

(D)

Cousins

Miller + Skoog

Kurosawa

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CAREER POINT PRE-FOUNDATION COURSE IJSO SUMMER WORKSHOP Daily Practice Problem Sheet Subject : Biology

DPPS. NO. – 03 .

Topic : Transportation in Plants

Q.1

After the system reaches equilibrium, what changes are observed? (A) The water level is higher in side A than in side B (B) The water level is higher in side B than in side A (C) No' Change is Observed (D) First the level of water is high in tube A and then water level is decreased Q.2

Water potential of plasmolysed cell will be – (A) w = –s + p (B) s = p

(C) w = 0

Q.3

When does a concentration gradient exist? (A) When solute concentrations are low (B) When membrane rupture (C) When solute concentration is high (D) When solute concentration differ on either side of a membrane

Q.4

What would be p of a fully flaccid cell? (A) +3 (B) +2

(C) –3

(D) w= –s – p

(D) 0

Q.5

During plasmolysis what occurs? (A) Movement of water occurs across the membrane from an area of higher water potential to lower water potential (B) Movement of water occurs across the membrane from an area of low water potential to high water potential (C) Water moves inside the cell until equilibrium is reached (D) O.P. of cell remains the same

Q.6

When a plasmolysed cell is placed in water or hypotonic solution, what happens? (A) T.P. of cell decreases (B) T.P. of cell becomes zero (C) T.P. increases (D) Water potential of cell decreases

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Q.7

As various ions from the soil are actively transported into vascular tissues of root, water follows and increases the pressure inside the xylem. This positive pressure is called – (A) Mass pressure (B) Root pressure (C) osmotic potential (D) None

Q.8

Attraction of water molecules to polar surface is known as : (A) Cohesion (B) Adhesion (C) Capillarity

(D) Tensile strength

Q.9

Go through the four statements given below – I. Root pressure provides a light push in the overall process of water transport II. Most plants meet their water need by transpiration pull III. The greatest of root pressure my be to re-establish the continuous chains of water molecules in the xylem vessel which often break under enormous tension created by transpiration IV. Guttation is the cause of transpiration pull The correct statement are – (A) I, II, III, IV (B) I, II, III (C) II, III, IV (D) II, III

Q.10

According to transpiration-cohesion theory water is pulled upward through the xylem. The cause of the pull is – (A) Guttation (B) Root pressure (C) transpiration (D) condensation

Q.11

The lowest water potentials in the xylem are in the – (A) root hairs (B) vascular cylinders of root (C) tracheids of the stem (D) leaves

Q.12

The energy source that drives the upward flow of water is – (A) light (B) sucrose (C) solar heat

(D) ATP

Q.13

Which of the following is not a major factor in the movement of xylem sap up in a tall tree? (A) Plasmodesmata (B) Cohesion and adhesion (C) Tension (D) Transpiration

Q.14

Adhesion is the result of – (A) hydrogen bonding between the water molecules (B) Transpiration pull (C) High surface tension (D) Attraction of water molecules to polar surface/hydrophilic wall of the xylem tube.

Q.15

Which of the following statement is correct concerning the flow of sap in xylem of trees? (A) In the morning sap begins to flow first in the twigs and later in the trunk (B) Flow is driven by high cone. of sugar in the vessel elements (C) Flow from the roots to the twigs would be accelerated if the leaves are removed (D) Rapid flow of water puts the xylem under a pressure much greater than atmospheric pressure.

Q.16

Which of the following is a difference between transport by xylem and transport by phloem? (A) Active transport moves xylem but not phloem sap (B) Transpiration moves phloem sap but not xylem sap (C) xylem sap moves up; phloem sap moves up and down (D) xylem moves from sugar source-to sink but phloem does not

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Q.17

What keeps the force of gravity from pulling water molecules out of the leaves ? (A) Upward pressure from root (B) High water pressure in leaves (C) Movement of water towards a sugar sink (D) Cohesion and adhesion of water molecules

Q.18

Which one is correct – (A) Unlike water all minerals cannot be passively absorbed by roots (B) Most of the minerals enter the root by active transport (C) Ions are absorbed from soil by both passive and active transport (D) All

Q.19

In root there is one way active transport of ions because of presence of – (A) Pericycle (B) Diffusion (C) ATP

Q.20

Ions from soil reach to xylem of root through – (A) Active uptake only (C) Only diffusion

(D) Endodermis

(B) Passive uptake only (D) Active or passive uptake or a combination of both

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CAREER POINT PRE-FOUNDATION COURSE IJSO SUMMER WORKSHOP Daily Practice Problem Sheet Subject : Biology

DPPS. NO. – 04 .

Topic : Genetics Q.1

Column A I. Sickel-cell anaemia II. Phenylketonuria III. Cystic fibrosis IV. Huntington's disease V. Colour blindness The correct match is – (A) I-B, II-A, III-D, IV-C, V-D (C) I-D, II-B, III-A, IV-C, V-D

Column B A. 7th chromosomes B. 4th chromosome C. 11th chromosome D. X-chromosome E. 12 th chromosome (B) I-D, II-A, III-B, IV-C, V-D (D) I-C, II-E, III-A, IV-B, V-D

Q.2

Column A Column B I. Autosomal linked recessive trait A. Down's syndrome II. Sex linked recessive disease B. Phenylketonuria III. Metabolic error linked to autosomal recessive trait C. Haemophilia st IV. Additioal 21 chromosome D. Sickle cell Anaemia The correct match is – (A) I-B, II-A, III-D, IV-C (B) I-D, II-A, III-B, IV-C (C) I-D, II-C, III-B, IV-A (D) I-C, II-D, III-A, IV-B

Q.3

The experiment shown in the figure has been carried out by Morgan to show the phenomenon of linkage and recombination. If in Cross I, genes are tightly linked and in Cross II, genes are loosely linked then what will be the percentage of recombinants produced in Cross I and Cross II respectively ?

(A) 98.7% and 62.8%

(B) 1.3% and 37.2%

(C) 37.2 and 1.3%

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(D) 62.8% and 98.7% Page # 1

Q.4

Observe the sex determination in the following I. Human males = XY III. Male Drosophila = XY V. Male birds = ZZ Male heterogamety = A Female heterogamety = B Male homogamety = C Which of the following combination is correctA B (A) I, III, IV II (B) II, IV I (C) III, IV, II (D) II, IV I

II. Female hen = ZW IV. Male grasshopper = XO

C V III I II

Q.5

Identify the steps in cross in pea. A. Removal of anthers B. Transfer of Pollen C. Raising the next generation (A) A - Pollination, B - Fertilisation, C - Fruit formation (B) A- Emasculation, B - Fertilisation, C - Endosperm formation (C) A Emasculation, B- Pollination, C – Hybridisation / Crossing (D) A- defeminization, B- Pollination, C – Hybridisation / Crossing

Q.6

The following table shows the genotypes for ABO blood grouping and their phenotypes. In which one of the four options the components of reaction labelled as W, X, Y and Z are identified correctly?

(A) (B) (C) (D) Q.7

W IAi IBi IBi IAi

X IBi IAi IBi IAi

Y AB B A O

Z ii ii ii ii

Match the statement with appropriate symbol

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A. Heterozygous individuals with autosomal recessive B. Diseased (or death) C. Female carrier of an X-linked recessive gene D. Individuals with normal trait 4. E. Consanguineous mating (marriage of blood relatives) F. Unknown sex G. Mating H. Male I. Female J. Affected individual K. Abortion or still birth B C E F (A) 12 11 16 7 (B) 9 8 10 6 (C) 2 1 10 4 (D) 9 1 10 4 Q.8

Q.9

Wife is PTC non taster and husband is PTC taster. Their son is taster but daughters are non tasters. This is not a sex linked trait. Which pedigree is correct?

(A)

(B)

(C)

(D)

Predict from the following chart

(A) character is dominant and carried by X chromosomes (B) character is carried by Y chromosomes (C) character is sex linked recessive (D) character is recessive autosomal Q.10

The daughter was married to a normal person and their daughter had the trait.

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It can be explained as

Q.11

(A)

(B)

(C)

(D)

In the given figure of human hand pedigree analysis given

In the above pedigree which character is represented and what is the probability of disease occurrence in fifth child? (A) Polydactyly (autosomal dominant disorder), 50% (B) Polydactyly (autosomal recessive disorder), 50% (C) Polydactyly (X-linked dominant disorder), 50% (D) Polydactyly (X-linked recessive disorder), 50% Q.12

Q.13

The diagram refer to the chromosome complement of each sex of fruit fly shown in the diagram.

By which number is a Y chromosome labeled? (A) 1 (B) 2 (C) 3 (D) 4 If a gamete mother cell of chromosome complement 44+ XY suffers a non-disjunction at the first meiotic division, which of the following sets of gametes could result ?

(A)

Q.14

(B)

Klinefelter's syndrome results from the fusion of (A) an X egg and a YY sperm (C) an XX egg and a Y sperm

(C)

(D)

(B) an XY egg and an X sperm (D) an XX egg and YY sperm

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Q.15

A species of plant is known to have a diploid chromosome number of 14 in each of its cells. Which of the following would be the number of chromosomes found in each cell of one of its polyploidy relatives ? (A) 7 (B) 14 (C) 15 (D) 25

Q.16

When a gene pair hides the effect of another, the phenomenon is called – (A) mutation (B) dominance (C) epistasis

Q.17

Q.18

Q.19

Q.20

(D) None of these

An allele is dominant, if it is expressed in (A) second generation (C) heterozygous combination

(B) homozygous combination (D) both homozygous and heterozygous condition

The ratio 9 : 7 is produced due to – (A) complementary genes (C) lethal genes

(B) supplementary genes (D) epistatic genes

How many contrasting characters were selected Mendel? (A) One (B) Two (C) Three

(D) Seven

Mendel's monohybrid ratio is – (A) 1 : 2 (B) 3 : 1

(D) 9 : 7

(C) 9 : 3 : 3 : 1

Q.21

A cross between F1 hybrid and a recessive parent (Tt x tt) gives a ratio of – (A) 1 : 1 (B) 2 : 1 (C) 3 : 1 (D) 4 : 1

Q.22

The different forms of a gene are called – (A) heterozygotes (B) alleles

(C) supplementary genes (D) complementary genes

Mendel's dihybrid ratio is – (A) 15 : 1 (B) 9 :3 : 3 : 1

(C) 1 : 2 : 1

Q.23

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(D) 9 : 6 : 6 :1

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