beton

dik: fy 230 fc' 28 tebal plat =

+ + 10

49 9 cm

= = =

279 37

27.9

Mpa Mpa

10 0 m m

syarat-syarat tumpuan tumpuan terjepit elastis, dengan jarak c.t.c di anggap sebagai bentang plat RK  Ly/L 4 : 4 = plat Koridor Ly/L 4 : 3 = plat Perpus Ly/L ! : 4 = plat Lab Ly/L ! : 4 = plat Gudang Ly/L ! : 4 =

hitungan beban-beban - beban mati (Wd a. be"at #e$di"i = 0.12  b. beba be ba$ $ ma mati ti %pe pe$& $&t& t&p p la la$t $tai aid d&c &cti ti$( $( )* pipa-pipa  = 200 k(/m

24

,d -

-

beban hidup (WL a. (ed&$( &$t&k "&a$( k&lia b. pe"alata$ ka$t"

kombinasi beban (beban ultimit,Wu & = 1.2 d + 1.! L = 1.2  2.88 + 1.! = 7.4! k/m

pe"it&$(a$ mme$  pelat RK  M5 6 = M5y = Mt6 = Mty = 

= =

=

2.88

k

= =

2. 0 0 4.88

k k

20 k(/m 10 k(/m ,L



= = =

2.0 1. 0 4.00

2.0

%de$(a$ tabel  1971 0.02 0.02 -0.01 -0.01

&.L6 &.L6 &.L6 &.L6

= = = =

0.02 0.02 -0.01 -0.01

   

7.4! 7.4! 7.4! 7.4!

pelat koridor M5 6 = 0.03!8

&.L6

=

0.03!8



9.8!

Mt6 Mty 





= =

-0.0!!1 -0.043

&.L6 &.L6

= =

-0.0!!1 -0.043

 

9.8! 9.8!

pelat perpus M5 6 = 0.04 M5y = 0.01! Mt6 = -0.07 Mty = -0.04

&.L6 &.L6 &.L6 &.L6

= = = =

0.04 0.01! -0.07 -0.04

   

9.8! 9.8! 9.8! 9.8!

pelat Lab M5 6 = M5y = Mt6 = Mty =

0.04 0.01! -0.07 -0.04

&.L6 &.L6 &.L6 &.L6

= = = =

0.04 0.01! -0.07 -0.04

   

9.8! 9.8! 9.8! 9.8!

pelat Gudang M5 6 = 0.04 M5y = 0.01! Mt6 = -0.07 Mty = -0.04

&.L6 &.L6 &.L6 &.L6

= = = =

0.04 0.01! -0.07 -0.04

   

9.8! 9.8! 9.8! 9.8!

kebutuhan tulangan lentur a. pelat RK   !ulangan Lapangan !inggi "# "#ekti# $e $eton  ika dipakai e$&t&p bet$ b diamete" t&la$(a$

%

= =

2 10

cm mm

=

 i$((i ;fektif et$ a"a d =

100

-

20

-

 i$((i ;fektif et$ a"a ydy =

100

-

20

-

tulangan lapangan arah &  b d 0.8  1000  ! 0.9

p

0.9

p

4.449

p

fy fc' 279 37 -

p

fy

+

k

=

0

p

27 9

+

0.882

=

0

279

p

+

0.882

=

0

p1 p2

= =

maka di dapat dipakai p = 0.0031! ceck te"adap pmi$ = ka"e$a p =

0.0031!

?

1.4 fy pm i $

!2.7087 0.0031! 1.4 279 0.0002

=

=

0.0

maka dipakai p

P%'-'' maka pe$&la$(a$ a"a y di pakai &(a ceck a"ak a$ta" t&la$(a$ 200 mm ? 3 ? 300mm A ? 00 mm k #iplaBB.CCC Pelat RK  tulangan tumpuan ) tin tinggi e# e#ekti# be beton  ika dipakai pe$&t&p bet$pb = diamete" t&la$(a$ =

2 10

cm mm

=

20

mm



 i$((i ;fektif et$ a"a tAtydt = 100 20 0. "a#i t&la$(a$ bet$ M& = !.08 km (untuk penulangan tumpuan dipakai *t& +*ty, M& !.08  10 k = = > b d 0.8  1 0 00  7  0.9

p

0.9

p

4.449

p

fy fc' 279 37 -

p

fy

+

k

=

0

p

279

+

1.31

=

0

279

p

+

1.31

=

0

p1 p2

= =

maka di dapat dipakai p = 0.00484 ceck te"adap pmi$ = ka"e$a p =

0.00484

1.4 fy pmi$

?

!2.7070 0.00484 1.4 = 0.0002 279 0.0002 maka dipakai p =

=

)luas tulangan perlu )# = p  b  d = 0.0002  1000  7 = 37!.34 mm dipakai t&la$(a$ diamete" 10 mm maka a"ak t&la$(a$$ya : 1/4DEb 1/4.D.10.1000 # = = )# 37!.34

=

208.8! mm

P%'-'  adi &$t&k t&la$(a$ t&mp&a$ a"a  di pakai ceck a"ak a$ta" t&la$(a$ 200 ? 3 = 300 mm A 00 mm )

luas tulangan susut pelat RK  0.2 )# = #&#&t

b 100



= =

ata& )#

#&#&t

=

20F



)# pkk

0.2



2 0

mm

=

7.2!88

mm

=

37

dipakai diamete" t&la$(a$ #&#&t = 8 mm 1/4DEb 1/4.D.8.1000 # = = )# 7.27

1 00 0 100



mm

momen

koe#.

ML Mly Mt Mty

3!.8 20.! !!.1 4.3

*u (km 3.2! 1.83 .87 4.82

ilai k   (*pa 0.724 0.40! 1.3039 1.0713 t&la$(a$

*u (km 7.18 2.!0 11.83 8.9

ilai k   (*pa 1.94 0.7!98 2.!283 1.9099 t&la$(a$

*u (km 7.18 2.!0 11.83 8.9

ilai k   (*pa 1.94 0.7!98 2.!283 1.9099 t&la$(a$

*u (km 7.18 2.!0 11.83 8.9

ilai k   (*pa 1.94 0.7!98 2.!283 1.9099 t&la$(a$

Pperlu

P

0.002!0 0.00194 0.004!7 0.00384 #&#&t

0.0 0.0 0.0 0.0

Pperlu

P

0.0072 0.00207 0.0124 0.00!8 #&#&t

0.0 0.0 0.0 0.0

Pperlu

P

0.0072 0.00207 0.0124 0.00!8 #&#&t

0.0 0.0 0.0 0.0

Pperlu

P

0.0072 0.00207 0.0124 0.00!8 #&#&t

0.0 0.0 0.0 0.0

t ty

b.

Pelat perpus momen

koe#.

ML Mly Mt Mty

4. 1!. 7 4.

t ty

b.

Pelat Lab momen

koe#.

ML Mly Mt Mty

4. 1!. 7 4.

t ty

b.

Pelat Gudang momen

koe#.

ML Mly Mt Mty

4. 1!. 7 4.

t ty

1 1.333 1. 1. 1.

m m m k/m k/m k/m

   

4 4 4 4

= = = =

2.98 2.98 -!.08 -!.08

k m k m k m k m



3

=

3.2!

k m

 

3 3

= =

-.87 -4.82

k m k m

   

4 4 4 4

= = = =

7.18 2.!0 -11.83 -8.9

k m k m k m k m

   

4 4 4 4

= = = =

7.1717 2.!0198 -11.827 -8.944

k k m k m k k m k m

   

4 4 4 4

= = = =

7.1717 2.!0198 -11.827 -8.944

k k m k m k k m k m

2 0 mm

0.



10

=

7

mm

10

-

0.



10

=

!

mm

!2



=

0.!!3

Mpa

%−GI(H2 J4/2 4.449 p 27 9 -

27 9

G

279 I

G

I

p + 279 H2 2 4.4489 7 78 4 1 8.898

de$(a$ "&m&# )*

=

8.8978 279 G

279.0 8.90

0.0002

.34

mm

!

$d= 

=

mm 0.882

Mpa

de$(a$ "&m&# )*

02 =

0.0002

4.449 -

p 279

G

-

279

G

-

27 9

=

279

G 8.8978 G 8.90

279 p 279 I 2 77 I 8.8978 7782 I 278.97



10

=

7

mm

karena momen tumpuan arah & + y sama maka penulangannya pun sa

=

1.31

Mpa 4.449 p 279

G

279 I

p 279 2

de$(a$ "&m&# )*

=

279 27 9

G

I

G I 8.898 279 G 278.9! 8.90

7 78 4 1 8.8978378 7781!.9!

+ 1.31 H2 4.449 -

0.00484

100

P-  adi &$t&k t&la$(a$ t&mp&a$ a"a  da$ y di pakai ceck a"ak a$ta" t&la$(a$ 400 ?  = 00 mm A ? 00 mm

in

/s (mm0

02 02 02 02

37!.344 32!.1! 30.0 249.!12

dipakai tulangan 10-220 10-20 10-230 10-330

70.110 49.922

!-430 !-00

in

/s (mm0

02 02 02 02

37!.344 32!.1! 940.82! 13.4!3

dipakai tulangan 10-220 10-20 10-89 10-1!0

188.1! 102.!93

8-280 8-00

in

/s (mm0

02 02 02 02

37!.344 32!.1! 940.82! 13.4!3

dipakai tulangan 10-220 10-20 10-89 10-1!0

188.1! 102.!93

8-280 8-00

in

/s (mm0

02 02 02 02

37!.344 32!.1! 940.82! 13.4!3

dipakai tulangan 10-220 10-20 10-89 10-1!0

188.1! 102.!93

8-280 8-00

K1 = =

0.8 0.7940

b

0.!!28 -

= 4

0 4.449 0.!!3

11.794

mi$ 

+ 0.882 H2 4.4 41 .298

= 4

0 4.449 0.8824

1.702

a

= 4 24.044

''

0 4.449 1.31

-

= = = = =

0.008  K1

%

08  fc'  K1 fy 0.8  24.9713 279 0.089 0.0!11

 

37

 37 279 !00 879 0.!8

-

30

!00 !00 + fy  0.7940





!00 ! 00

+

279

=  mak#

0.0002

?

0.0482

0.048

@N b d 279 G I G

I

279

=

0.8 p + 279 H2 2 4.4 77841 8.9 77817.79

G I 8.9 279 G 278.9! 8.90 =

1/4DEb )#

10  7  0 4.4 1.303949

!2.707

=

1/4.D.10.1000 37!.34

=

208.87 mm

#

#

=

1/4DEb )#

=

1/4.D.10.1000 32!.1!

=

240.!78 mm

#

=

1/4DEb )#

=

1/4.D.10.1000 30.

=

223.9338 mm

#

=

1/4DEb )#

=

1/4.D.10.1000 249.!1

=

314.4877 mm

#

ceck a"ak a$ta" t&la$(a$ 10 ? 3 = 300 mm A 00 mm

k

=

4.4 p 279 =

k

279

=

#

G

I

279

=

0.8 p + 279 H2 2 4.4 77841 8.9 77812.!2

7.18  1.94 -

 1000 = 4

10  7  0 4.4 1.94482

=

1.

=

0.

28.37

G I 8.9 279 G 278.9 8.90

=

4.4 p 279 -

M& > b d 279 G I

279

M& > b d 279 G I G

I

279

=

0.8 p + 279 H2 2 4.4 77841 8.9 77830.710

2.!0  0.78 -

 1000 = 4

10  7  0 4.4 0.78219

10.290

G I 8.9 279 G 278.98 8.90

=

1/4DEb )#

=

1/4.D.10.1000 37!.34

=

208.87 mm

#

=

1/4DEb )#

=

1/4.D.10.1000 32!.1!

=

240.!78 mm

#

=

1/4DEb )#

=

1/4.D.10.1000 940.83

=

83.43734 mm

#

=

1/4DEb )#

=

1/4.D.10.1000 13.4!

=

12.883 mm

= = =

4.00 1.0 .0

k/m k/m k/m

y 2

Mpa

k

=

4.4 p 279 =

04

Mpa

k

279

=

=

1/4DEb )#

=

G

I

279

=

0.8 p + 279 H2 2 4.448919 77841 8.9 77831.379

1.83  0.41 -

 1000 = 4

-

9.!21

4.82  1.071 -

 1000 = 4

-

19.0!

10  ! 0 4.4 0.4

G I 8.9 279 G 278.98 8.90

=

4.4 p 279 -

M& > b d 279 G I

279

M& > b d 279 G I G

I

279

=

0.8 p + 279 H2 2 4.448919 77841 8.9 77821.93

G I 8.9 279 G 278.97 8.90 1/4.D.10.1000 70.11

=

403.0809

mm

10  7 0 4.4 1.07

=

94

1/4DEb )#

Mpa

=

k

1/4.D.10.1000 49.92

=

4.4 p 279 =

78

Mpa

k

279

=

#

=

1/4DEb )#

G

I

279

!!.0779

=

0.8 p + 279 H2 2 4.448919 77841 8.9 77778.730

mm

11.83  3.499 -

 1000 = 4

-

!2.270

8.9  1.910 -

 1000 = 4

-

33.987

2!7 2!

mm

10  0 4.4

! 3.

G I 8.9 279 G 278.89 8.90

=

4.4 p 279 -

M& > b d 279 G I

=

279 279

M& > b d 279 G I G

I

=

0.8 p + 279 H2 2 4.448919 77841 8.9 77807.013

G I 8.9 279 G 278.94 8.90

=

1/4.D.10.1000 188.17

=

10  7 0 4.4 1.91

#

=

1/4DEb )#

=

1/4.D.10.1000 102.!9

=

489.2271

mm





=

0.41

Mpa

=

1.071

Mpa





=

3.499

Mpa

=

1.910

Mpa