Bab 5 Root Locus

July 5, 2019 | Author: Muhammad Irfan | Category: N/A
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Bab 5: Root Locus

EL303: Sistem Kendali

ROOT LOCUS

Ì Pendahuluan Ì Dasar Root Locus Ì Plot Root Locus Ì  Aturan-Aturan Penggambaran Root Locus Ì Root Locus Melalui MATLAB Ì Kasus Khusus Ì  Analisis Sistem Kendali Melalui Root Locus Ì Root

Locus

untuk

Sistem

dengan

Transport Lag

 __________________________________________________________________________  Teknik Elektro ITB [EYS-1998] hal 5-1

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Bab 5: Root Locus

EL303: Sistem Kendali

Ì PENDAHULUAN n

Karakteristik tanggapan transient sistem loop tertutup dapat ditentukan dari lokasi pole-pole (loop tertutupnya).

n

Bila K berubah, maka letak pole-pole nya juga berubah. Perlu pemahaman pola perpindahan letak pole-pole dalam bidang s. Desain sistem kendali melalui gain adjusment: pilih K sehingga pole-pole terletak ditempat yang diinginkan. Desain sistem kendali melalui kompensasi: memindahkan letak pole yang tak diinginkan melalui pole-zero cancellation. Mencari akar-akar persamaan karakteristik untuk  orde tinggi sulit, terlebih dengan K sebagai variabel. (Alternatif: gunakan MATLAB ?!) W.R. Evan mengembangkan metoda untuk mencari akar-akar persamaan orde tinggi : metoda Root Locus. Root Locus: tempat kedudukan akar-akar persamaan karakterstik dengan K = 0 sampai K = tak hingga.

n n n n n n

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Bab 5: Root Locus

EL303: Sistem Kendali

Ì DASAR ROOT LOCUS

Persamaan Karakteristik: s 2 + 2s + K =0

Akar-akar Persamaan Karakteristik : s=

K 0 1 2 10

− 2 ± 4 − 4 K  2

s1 0 -1 -1+j1 -1+j3

= −1 ± 1 − K 

s2 -2 -1 -1+j1 -1+j3

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Bab 5: Root Locus

EL303: Sistem Kendali

n

Root Locus mempunyai sifat simetri terhadap sumbu nyata.

n

Root Locus bermula dari pole-pole G(s)H(s) (untuk  K=0) dan berakhir di zero-zero G(s)H(s) (untuk  K→∞) termasuk zero-zero pada titik takhingga.

n

Root Locus cukup bermanfaat dalam desain sistem kendali linear karena Root Locus dapat menunjukkan pole-pole dan zero-zero loop terbuka mana yang harus diubah sehingga spesifikasi unjuk kerja sistem dapat dipenuhi.

n

Pendekatan desain melalui Root Locus sangat cocok  diterapkan untuk memperoleh hasil secara cepat.

n

Sistem kendali yang membutuhkan lebih dari 1 parameter untuk diatur masih dapat menggunakan pendekatan Root Locus dengan mengubah hanya 1 parameter pada satu saat.

n

Root Locus sangat memudahkan pengamatan pengaruh variasi suatu parameter (K) terhadap letak  pole-pole.

n

Sketsa Root Locus secara manual tetap dibutuhkan untuk dapat memahaminya dan untuk memperoleh idea dasar secara cepat, meskipun MATLAB dapat melakukannya secara cepat dan akurat.

n

Spesifikasi transient (koefisien redaman) dapat ditentukan dengan mengatur nilai K melalui Root

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Bab 5: Root Locus

EL303: Sistem Kendali

Ì PLOT ROOT LOCUS

Persamaan Karakteristik: 1 + G(s)H(s) G(s)H(s ) = 0 Atau: G(s)H(s) = -1, Sehingga: ⊃G(s)H(s) = ! 1800(2k+1); (syarat sudut) k = 0, 1, 2, …. | G(s)H(s)| = 1

(syarat magnitude)

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Bab 5: Root Locus

EL303: Sistem Kendali

Ì PROSEDUR PENGGAMBARAN ROOT LOCUS 1. Letakkan pole-pole pole-pole dan zero-zero loop terbuka pada bidang s.

2. Tentukan Root Locus pada sumbu nyata.

• Syarat Sudut: ⊃G(s)H(s) = ! 1800(2k+1); •

k = 0, 1, 2, …. Ambil titik test : bila jumlah total pole dan zero dikanan titik ini ganjil, maka titik tsb terletak di Root Locus.

3. Tentukan asimtot Root Locus:

• Banyaknya asimtot = n – m n = banyaknya pole loop terbuka m= banyaknya zero loop terbuka

± 1800 (2k + 1) • Sudut-sudut asimtot = n−m k=0, 1, 2, …

• Titik Potong asimtot-asimtot pada sumbu nyata: σa

(letak pole berhingga )− ∑ (letak zero berhingga ) ∑ =

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Bab 5: Root Locus

EL303: Sistem Kendali

4. Tentukan titik-titik break-away dan titik-titik titik-titik break-in: Untuk Persamaan Karakteristik: B(s) + KA(s) = 0, Maka titik-titik tsb harus berada di Root Locus dan memenuhi persamaan:

dK  ds

= −

 B ' ( s) A( s ) −  B ( s ) A' ( s ) 2

 A ( s )

=0

5. Tentukan sudut-sudut datang / sudut-sudut berangkat untuk pole-pole / zero-zero kompleks sekawan. • Sudut datang (dari suatu pole kompleks) = 180 0 – (jumlah sudut vektor-vektor dari pole-pole lain ke pole kompleks tsb) + ( jumlah sudut vektor-vektor vektor-vektor dari dari zerozero ke pole kompleks tsb). • Sudut pergi (ke suatu zero kompleks) = 180 0 – (jumlah sudut vektor-vektor dari zero-zero lain ke zero kompleks tsb) + ( jumlah sudut vektor-vektor vektor-vektor dari polepole ke zero kompleks tsb).

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Bab 5: Root Locus

EL303: Sistem Kendali

6. Tentukan batas kestabilan mutlak sistem (K):

• Melalui Kriteria Routh Hurwitz. • Secara analitis: memotong sumbu imajiner: s = j 7. Sketsa Root Locus secara lebih teliti pada daerahdaerah selain sumbu nyata dan asimtot. 8. Tentukan letak pole-pole pole-pole melalui nilai K yang memenuhi syarat magnitude. Sebalikya, bila letak polepole ditentukan (pada Root Locus), maka nilai K yang memenuhi dapat dihitung secara grafis atau secara analitis: Secara grafis: K=

perkalian panjang garis - garis dari titik s ke pole - pole perkalian panjang garis - garis dari titik s ke zero - zero

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Bab 5: Root Locus

EL303: Sistem Kendali

CONTOH : Gambarkan Root Locus sistem balikan satuan dengan G(s ) =

K  s ( s + 1)(s + 2)

Tentukan juga nilai K agar koefisien redaman pole-pole kompleks sekawan loop tertutup dominannya bernilai 0,5. Solusi :

1. Tentukan Root Locus pada sumbu nyata.  jω

Titik uji 2 -2

-1

Titik uji 1



0



σ

Untuk titik uji 1 : Syarat sudut : − ∠s − ∠(s + 1) − ∠( s + 2) = 0 0 + 0 0 + 0 0 = 0 0 (tak terpenuhi). Untuk titik uji 2 : 0 0 0 0 Syarat sudut : − ∠s − ∠(s + 1) − ∠( s + 2) = −180 − 0 − 0 = −180 (terpenuhi).

2. Penentuan asimtot Root Locus Banyaknya asimtot = banyaknya pole (n) – banyaknya zero (m) = 3 - 0 = 3

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Bab 5: Root Locus

K  s (s + 1)(s + 2) dK  ds

EL303: Sistem Kendali

+1 = 0

3 2 atau K  = −(s + 3s + 2 s ) , sehingga:

= −(3s 2 + 6 s + 2) = 0

Diperoleh s1 = −0,4226 (memenuhi) dan s 2 = −1,5774 (tak memenuhi) 4. Penentuan batas kestabilan sistem menggunakan kriteria Routh Hurwitz. s3 1 s2 3 6−K s1 3 s0 K

2 K

Syarat stabil tercapai bila 0 < K < 6. Bila dihitung, perpotongan Root Locus dengan sumbu khayal ini terjadi pada : s = ± j 2 . Cara lain untuk mengetahui titik potong ini adalah secara analisis: s = j ω (pada sumbu khayal). 5. Tentukan beberapa titik uji dekat titik pencar yang memenuhi syarat sudut Root Locus agar diperoleh plot Root Locus secara akurat.

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Bab 5: Root Locus

EL303: Sistem Kendali

6. Gambar Root Locus nya:

7. Penentuan letak pole-pole kompleks sekawan dominan yang memiliki koefisien 2 redaman 0,5. Anggap pole kompleks sekawan s = −ζω n ±  jω n 1 − ζ . Dengan

memperhatikan gambar dibawah ini, maka terlihat bahwa ζ = cos β . Untuk  

ζ = 0,5, maka β = 60 0 . Dengan menggunakan cara analitis akan diperoleh polepole dominan tersebut adalah : s = -0,3337 + j0,5780, dengan nilai K adalah: K  = s ( s +)(s + 2) s = −0 ,3337+ j 0,5780 = 1,0383

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Bab 5: Root Locus

EL303: Sistem Kendali

Ì BEBERAPA CATATAN • Konfigurasi pole-zero yang sedikit bergeser dapat mengubah total bentuk Root Locus.

• Orde sistem dapat berkurang akibat pole-pole G(s) di

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Bab 5: Root Locus

EL303: Sistem Kendali

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Bab 5: Root Locus

EL303: Sistem Kendali

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Bab 5: Root Locus

EL303: Sistem Kendali

Ì ROOT LOCUS MELALUI MATLAB Root Locus = persamaan karakteristiknya, dalam MATLAB: 1+ K

num den

=0

num = (s + z1 )(s + z 2 ) L (s + z m )

= s m + (z 1 + z 2 + L + z m )s m −1 + L z 1 z 2 L z m den = (s + p1 )(s + p 2 ) L (s + p n )

= s n + (p1 + p 2 + L + p n )s n −1 + L + p1 p 2 L p n Perintah MATLAB untuk menggambar Root Locus (Konsep Fungsi Alih):

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Bab 5: Root Locus

Cara

lain

EL303: Sistem Kendali

penggambaran

Root

Locus

adalah

dengan

menggunakan arguman berikut ini :

[r,K] = rlocus(num,den) rlocus(num,den) [r,K] = rlocus(num,den,K) rlocus(num,den,K) [r,K] = rlocus(A,B,C,D) rlocus(A,B,C,D) [r,K] = rlocus(A,B,C,D,K) rlocus(A,B,C,D,K) Pada layar akan tampil matriks r dan vektor penguatan K. Perintah :

r=rlocus(num,den) plot(r,'o')

atau,

plot(r,'x')

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Bab 5: Root Locus

EL303: Sistem Kendali

Contoh : Plot Root Locus menggunakan MATLAB suatu sistem kendali balikan satuan: G (s ) =

K (s 2 + 2s + 4) s (s + 4)(s + 6)(s 2 + 1,4s + 1)

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Bab 5: Root Locus

EL303: Sistem Kendali

Program MATLAB nya:

%------Root-Locus %------Root-Locus -------- ----num = [0

0

0

den = [1

11.4

1

2

39

rlocus(num,den) Warning:Divide by zero

4];

43.6

24

0];

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Bab 5: Root Locus

EL303: Sistem Kendali

Ì KASUS KHUSUS ] Parameter K bukan penguatan loop terbuka. ] Umpanbalik positif.

] Parameter K bukan Penguatan Loop Terbuka.

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Bab 5: Root Locus

EL303: Sistem Kendali

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Bab 5: Root Locus

] Umpanbalik Positif.

EL303: Sistem Kendali

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Bab 5: Root Locus

Contoh:

EL303: Sistem Kendali

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Bab 5: Root Locus

EL303: Sistem Kendali

Sistem tidak stabil untuk K > 3 (Gunakan metoda Root Hurwitz untuk  menghitungnya!). Sistem harus distabilkan dengan umpanbalik negatif diluarnya.

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Bab 5: Root Locus

EL303: Sistem Kendali

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Bab 5: Root Locus

EL303: Sistem Kendali

Ì ANALISIS SISTEM KENDALI • Ortogonalitas dan locus dengan penguatan konstan

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Bab 5: Root Locus

• Sistem Stabil Kondisional

EL303: Sistem Kendali

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