Armimi i Soletave Traveta

August 23, 2017 | Author: Livia15 | Category: N/A
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Projekt Konstrusione Bertoarme...

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Armimi i soletave me traveta Soleta S-5     Skema llogaritese

lx 500 = ly 560 =1.12llogaritet si solete kesone φx=22.122 φy=34.764     Seksion llogarites

1

1

h= 25 lsh= 25 500=20 cm pranoj h=30



pranoj d=15 cm Ngarkesat

1. PLLAKA 1.5 CM 2. LLAC 2 CM 3. IZOLBETON 4. SOLETA 5. SUVA

8 CM

30 CM

2 CM

Prej shtresave te soletes Pllaka 0.015 * 1 * 1 * 2700 = 40.5 daN/m Llac 0.02 * 1 * 1 * 2000 = 40 daN/m Izolbetoni 0.08 * 1 * 1 * 600 = 48 daN/m Soleta (pjesa e betonit) [0.05 * 1 * 1 + (0.2 * 1 * 0.25) * 2] * 2500 = 375 daN/m Soleta (pjesa e polistirenit) 0.8 * 0.8 * 0.25 * 50 = 8 daN/m Rrjete teli (20 * 1) * 2 * 0.0000126 * 7850 = 4 daN/m Suva 0.02 * 1 * 1 * 2000 = 40 daN/m2

200 daN/m2

Prej mureve

Ngarkesa e perhereshme e normuar: g n = 40.5 + 40 + 48 + 375 + 8 + 4 + 40 + 200= 755.5 daN/m Gjejme ngarkesat per travet 755.5 * 0.5= 377.75 daN/tv Ngarkesa e perkohshme pn=200 * 0.5 = 100 daN/tv Ngarkesa totale

q = 1.35*g + 1.5*p = 1.35*377.75 + 1.5*100 = 660 daN/tv

    Llogaritja e momenteve Mx=

q∗l x ² 660∗5² = 22.122 =745 daNxm φx

q∗l y ² 660∗5.6² My= = 34,764 = 595 daNxm φy

    Llogaritja e armatures Krahasojme momentin e jashtem me momentin qe mban pllaka Mpll=b’f*h’f*0.567*fck(d-0.4h’f)=50*30*0.567*300(28-0.4*5)=6633900 daNxcm Sipas x

Mx=74586 daNxcm < Mpll=6633900 daNxcm => seksioni (b’f*h)=(50*30)

K x=

[

Z=

M 74582 b d ² f cd = 50∗28²∗167 =0.01139 As=1.57

cm2

Sipas y

Mx= 59537daNxcm < Mpll=6633900 daNxcm => seksioni (b’f*h)=(50*30)

K y=

[

Z=

M 59534 b d ² f cd = 50∗28²∗167 =0.00909 As=1.57

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