Analisis Pinch con HYSYS.pdf

DISEÑO RED DE Design MethodDE forLA Heat Exchanger INTERCAMBIO Networks 2006

©2000 AspenTech. All Rights Reserved.

OC ES PR

S

SI

LATION ENV U I M

I know what is the

RO

Data Extraction

NM EN T

¿Cómo consigo potential for energy los objetivos demymínimo recovery in process. consumo energía? But, howde should I design a process that achieves the energy target ?

ANALYSIS

Ener

gy

  

Generate Evaluate Select Options

od

c Re

Pro s s M ce

SYNTHESIS

Network Design

THREE DAY COURSE

ROAD MAP Process Improvement Road Map

NT

AI

LD

N ENVIR ESIG O N M E ©2000 AspenTech. All Rights Reserved.

DE T

PROJECTS Project Selection for Implementation

2

Our Example Problem Para nuestro ejemplo:

Tmin = 20° QHmin = 1000, QCmin = 800 220°

RECYCLE STEAM

178°

1620

160°

880

CW 180°

60°

160° 2640 DIST VAP 130° 210°

REACTOR

REAC. OUT 270°

210°

160°

Distillation Column

149° STEAM FEED 50° = EXCHANGER DUTY, kW TEMPERATURE, ©2000 AspenTech. All Rights Reserved.

1220

1980 220°

PRODUCT

ºC 3

Diseñemos red Let’s design thelanetwork

Product

Reac. Out

220°

180°

180°

60°

270°

180°

180°

160°

210°

160°

160°

50° Feed

210°

160°

Recycle

¿Por dónde comenzar? Where should we start?

©2000 AspenTech. All Rights Reserved.

4

Identifique el Divide the problem punto corte at thede Pinch

Comience el Pinch punto de corte Start atenthe y luego hacia afuera andmuévase move away

T

Above

T

Pinch

PINCH

Below

Pinch

H

H

This will ensure no Cross Pinch heat transfer

©2000 AspenTech. All Rights Reserved.

5

¿Cómo definir intercambios entre How should welos match streams at the Pinch? corrientes en el punto de corte? T

T

Pinch

Pinch

H

eam r t ot S

tream Ho t S

tream Cold S

Co

ld

re St

am

H

H

Abajo Below

Arriba Above

CPcold CPhot

CPhot CPcold

CPIN CPOUT (The CP Rule) ©2000 AspenTech. All Rights Reserved.

6

¿Qué corrientes deben intercambiar Which Streamsse should we match first?primero? Examinemos las corrientes deOUT salida Let’s examine streams

Abajo Below

Arriba Above

1. Match con with una corriente 1. Match a stream de IN entrada Posible si Possible if CPIN  CPOUT

} Tmin

2.2.Match conwith unaa corriente Match stream lejos del punto corte away from thedePinch Posible Possible

Tmin { Hot Utility

3. 3. Match Matchcon withservicios utility auxiliares Posible Possible

Cold Utility

Encontrar los intercambios para las corrientes Finding partners for streams OUT of que salen del punto de corte es sencillo ©2000 AspenTech. All Rights Reserved.

the Pinch is easy

7

Veamos las corrientes Let’s examine streamsdeIN entrada

Below

Above 1. Match con una corriente de OUT salida 1. Match with a stream Possible Posible siif

CPIN  CPOUT

} Tmin

Hot Utility

2.2.Match con unaacorriente Match with Stream lejos del punto de corte away from the Pinch No Posible Not Possible (T violation)

Tmin {

3.3.Match con servicios Match with utility auxiliares No Posible Not Possible

(Cross-Pinch)

Cold Utility

Encontrar los intercambios las corrientes Finding partners forpara streams going que entranIN al corte es más the punto Pinch isde more difficult complicado

©2000 AspenTech. All Rights Reserved.

8

¿Qué cantidad dewe calor seeach debematch? intercambiar How big should make en cada match? H H = 100

100

H = 20

H

120

Lo máximo posible!!!!!

Try to maximize load to minimize number of matches (The “Tick Off” heuristic) ©2000 AspenTech. All Rights Reserved.

9

Apliquemos el procedimiento de diseño en nuestro ejemplo Above PC the Pinch Arriba 880 Product

H

CP

220°

180°

880

22

270°

180°

1620

18

210°

160°

Feed

1000

20

Recycle

2500

50

Reac. Out

210°

177.6°

160°

PRODUCTOis esthe la mayor corriente PRODUCT biggest stream IN entrante Apply the CP Rule and Tick Off heuristic ©2000 AspenTech. All Rights Reserved.

10

H

CP

180°

880

22

180°

1620

18

Feed

1000

20

Recycle

2500

50

880 Product

220°

270°

Reac. Out

235.6°

1000

210°

210°

160°

177.6°

160°

REACTOR OUT siguiente REAC. OUT is es thelanext biggest stream IN corriente entrante Again apply the CP Rule and Tick Off heuristic ©2000 AspenTech. All Rights Reserved.

11

H

CP

180°

880

22

180°

1620

18

Feed

1000

20

Recycle

2500

50

880 Product

220°

620

270°

Reac. Out

235.6°

1000

210°

210°

160°

190°

177.6°

160°

Now place the matches away from the Pinch Ahora ubique los matches lejos Follow Tick heuristic del punto deOff corte ©2000 AspenTech. All Rights Reserved.

12

H

CP

180°

880

22

180°

1620

18

Feed

1000

20

Recycle

2500

50

880 220°

Product

620 270°

235.6°

Reac. Out

1000

210°

210°

160°

H

190°

177.6°

160°

1000

Al último ubique servicios auxiliares Last placelosthe heaters ©2000 AspenTech. All Rights Reserved.

13

Next, below the Pinch Ahora, debajo del punto de corte

Product

H

CP

60°

2640

22

180°

160°

360

18

160°

50°

2200

20

180°

2200

80°

Reac. Out

Feed

FEED es única FEED is la the onlycorriente stream IN entrante Apply the CP rule and Tick Off heuristic ©2000 AspenTech. All Rights Reserved.

14

2200 Product

180°

H

CP

60°

2640

22

160°

360

18

2200

20

440 80°

C 360

180°

Reac. Out

160°

C

50°

Feed

No hay másare corrientes entrada, There no morede streams IN ahora podemos los the refrigeradores Now weubicar can place coolers ©2000 AspenTech. All Rights Reserved.

15

Linking Above and Below together Uniendo las dos partes... Product

180°

220° 270°

235.6°

Reac. Out

80°

C

440

180°

60°

C

160°

360 210°

160°

50° Feed

210°

190°

H

1000

177.6° 1000

620

QHmin = 1000

160°

2200 Recycle

880

QCmin = 800

Se consiguen Design is la onmetas Target de diseño!!!! ©2000 AspenTech. All Rights Reserved.

16

A veces, there se presentan problemas... Sometimes, are problems ….. ? CP HOT1

8

HOT2

4

COLD1

5

COLD2

1

COLD3

3

Falta una corriente de Missing a stream OUT salida!!!! ©2000 AspenTech. All Rights Reserved.

17

un problema más generally general Let’sMiremos look at the problem more Above No Cold Utility HOT1 HOT2

Below No Hot Utility 100°

100°

100°

100°

T >100°

?

100°

HOT3

?

90°

90°

COLD1

90°

90°

COLD2

T>90°

90° COLD3

Currently NIN> NOUT

Currently NIN> NOUT

For feasibility NIN  NOUT ©2000 AspenTech. All Rights Reserved.

18

SI If NIN > NOUT

CP = 2 CP CP = 6

HOT1

8 4

HOT2

1 3 2

COLD1

5

COLD2

1

COLD3

3

Divida una corriente de salida Splitdel a stream of the Pinch puntoOUT de corte ©2000 AspenTech. All Rights Reserved.

19

Otro ejemplo... Another Example CP 4

HOT1

9

HOT2

3

COLD1

8

COLD2

5

COLD3

?

There are enough streams OUT but Hay suficientes corrientes de salida pero... CPIN CPOUT not forpara every Pinch Match nopossible es posible cada match ©2000 AspenTech. All Rights Reserved.

20

do we do ? ¿Qué What debemos hacer?

CP 4

HOT1

9

HOT2

CP = 7

1

CP = 2 2 3

3

COLD1

8

COLD2

5

COLD3

Dividimos una entrante We splitcorriente a stream IN ©2000 AspenTech. All Rights Reserved.

21

Sin embargo, nofollow debemos seguir las….. reglas However do not the rules blindly ciegamente... Another Example 3

CP

CP 4

HOT1

10

HOT2

4

HOT1

10

HOT2

CP = 2 2

CP = 2 1

3

Splitting a stream IN causes the need to split a stream OUT COLD1

CP = 13

17

COLD2

CP = 4

3

COLD1

17

COLD2

CP 4

HOT1

10

HOT2

2 1

3 17

Splitting a stream OUT results in a simpler solution COLD1

CP = 12

COLD2

CP = 5

Alwaysintentemos try to minimize streamlas splits to reduce complexity Siempre minimizar bifurcaciones para reducir la complejidad ©2000 AspenTech. All Rights Reserved.

22

Resumen Ubique el punto de corte y divida el problema en dos partes

Realice los intercambios en el punto de corte

No Nin≤Nout

No CPin≤CPout

Ubique la mayor corriente de entrada Realice los intercambios remanentes CPin≤CPout Ubique los servicios auxiliares ©2000 AspenTech. All Rights Reserved.

Divida una corriente de salida

Divida una corriente de entrada

Para cada match

Maximice el intercambio 23