ALGEBRA LINEAL PC 2 Con Clave 2019-I
August 5, 2022 | Author: Anonymous | Category: N/A
Short Description
Download ALGEBRA LINEAL PC 2 Con Clave 2019-I...
Description
ZLKYJRXKFEF LEHKGLEA CE[GR FJ XEL CERHGX
(Zlkvjrskfef fja Pjrÿ, FJHELE FJ ECÄRKHE) IEHZAVEF FJ KLNJLKJRÃE JAJHVRØLKHE [ JAËHVRKHE Prehtkhe Heakikhefe 2 - 205;-K HZRXG PRGIJXGR
?
EANJBRE AKLJ AKLJEA EA Cn. LGAEL OERE OERE
?
EPJAAKFGX [ LGCBRJ? WWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWW Klstruhhkgljs? Ags jxåcjljs quj utkakzel aåpkz y/g akqukf pepjr lg tkjljl fjrjhdg e rjhaecg. Prjnultes? 5) Fjtjrcklj sk aes sknukjltjs prgpgskhkgl prgpgskhkgljs js sgl vjrfefjres g ieases, oustkikquj su rjspujste k) Xk ae cetrkz huefrefe B lg js klvjrtkbaj, jltglhjs Xgauhkøl.
30
js ul veagr prgpkg fj ae cetrkz B.Y B. Y
Xebjcgs quj ae cetrkz B lg js klvjrtkbaj hhuelfg uelfg fjt(B)30, pjrg? js ule , jltglhjs P(0)3fjt(B)30, ag huea qukjrj fjhkr quj reãz fja pgaklgckg herehtjrãstkhg, pgr ag teltg hglstktuyj ul veagr prgpkg fj B .
3 fjt2 5 0 30 3 ]80 20 06S 3 59 2 5 0 0 3 3 80 2 0 66 0 3 6 6 + 5 3 3 59 − 3 − − − − | 3 | | 3 | | 3 | | | | 3 | | 3 3 | 5 0 ; 4 3 000 500 5>0 9:5 5 0 ; 4 0 3 0 0 05 50> 95 : → 33 5 , 5 , jltglhjs
kk) Xk
js ul veagr prgpkg prgpkg fj ae Cet Cetrkz rkz B². Y
Xgauhkøl. Xgauhkøl.
Xebjcgs quj, sk js ul veagr prgpkg fj ae cetrkz B , jltglhjs js ul veagr prgpkg fj B² . Jstg lgs pjrcktj heahuaer fkrjhtecjltj ags veagrjs prgpkgs fj B y e pertkr fj jstgs veagrjs heahuaer ags veagrjs prgpkgs fj B² ?
, ,
ag teltg
6
js ul veagr prgpkg fj B, pgr
js ul veagr prgpkg fj B²
.
kkk) Xk E js sjcjoeltj e B, jltglhjs sus pgaklgckgs herehtjrãst herehtjrãstkhgs khgs sgl knueajs. Y Xgauhkøl.
Xk E js sjcjoeltj e B , jltglhjs jxkstj ule cetrkz P tea quj
, pgr ag teltg?
ku) Xje
, jltglhjs ags veagrjs herehtjrãstkhgs fj B sgl? 4, -4, 5 y -5. I
Xgauhkøl.
? ? → + ++ ² 3 8 2 + 8 2 +: + :²² 5 35 3 5 3 8+ 8 + 2 + :²:² ≠ 5 5
2) Xje
ule trelsigrcehkøl akljea fjiklkfe pgr Jltglhjs js hkjrtg quj? (oustkikquj su rjspujste) k) js ul vjhtgr prgpkg fj V hgrrjspglfkjltj ea veagr prgpkg
I
Xgauhkøl.
Xk fkhdg vjhtgr js herehtjrãstkhg, fjbjrãe hucpakrsj quj , pjrg? kk) Ae rjprjsjltehkøl cetrkhkea cetrkhkea fj V rjspjhtg e ae besj helølkhe js fkengleakzebaj. Y Xgauhkøl.
| 3 802 802 : 00 3 : ²5 3 ] 80 2 082 0:0S → 0 3 | 0 5 3 : → {(50 ) (05)}
= E js fkengleakzebaj.
kkk)
Ae cetrkz
Xgauhkøl.
5; ; 9 3 ]2:5> 55; 6;S
lg js fkengleakzebaj. fkengleakzebaj. Y
5; ; 9 2 3 5 → ]54]2:545> 352;; 52>:;9: ⋬⋬ 5500;S ~]005 6800; 5 60→ ⋬⋬3 005S →, 28 3 63 3 6 3 6 3 (86) 8 8 8
3 2 2=, 3 ]862]6 202 682S6S (0) ]6 2 6 ⋬ 0S3 ]52 5 2 ⋬ 0S 2 26 52 26 3 3 00 → 26 52 26 ⋬⋬ 00 ~ 00 00 00 ⋬⋬ 00 → 3 22 2 3 2 2 5 → 3 ]28 S ¸
kv)
Ja subjspehkg fj R¸
hgrrjspglfkjlt hgrrjspglfkjltjj ea ve veagr agr prgpkg
js ul jspehkg herehtjrãstkhg fj .Y
Xgauhkøl.
8) Hglskfërjsj ja gpjrefgr akljea V?R¸ R¸ tea quj V(T)3ET, fglfj
trjs vjhtgrjs prgpkgs fja gpjrefgr akljea sgl? u3(0,5,5)= v3(5,-5,0) y w3(5,0,-5) k) Fjtjrcklj ae rjnae fj hgrrjspglfjlhke fj V . kk) Gbtjlne ae fkcjlskøl fja Mjr(V) . Xgauhkøl.
yT
. Ags
0 5 + + 0 0 3 → ]28 S 55 3 55 → ( +++ ) 3 () 5 5 5 3 → ]28 S (50 ) 3 (50) → ( ) 3 ( ) 5 5 + 33→,, → → 3]8233, →→S 53++05 ,33 (→03) →,+ (3+)→ 3 (+,03+) 3 → 3 → 3 ,, 3 ,, 3 5,,5 3 5 → 3 ,, + 3 ,,+ 3 3 3 ]28 68 28S 3 3 ( ++ ++ )
k) k)
kk) kk)
+ + ) 3 () → 3 , 3 → ( ( ) = ∄ 3 3 () → ( + + + + +
View more...
Comments