April 7, 2017 | Author: M A Hossain Joe | Category: N/A
8086 Microprocessor Laboratory Experiments Manual Using MicroTalk-8086 and MDA-8086 Trainers MicroTalk-8086 ( Bangladesh )
MDA-8086 ( Korea )
Golam Mostafa
Ahsanullah University of Science and Technology
Preface
Dear Readers, First of all, you must say that you wish to learn ‘things’. And only then, we may tell you something like: “Look for the things that work and play with them”. This is one of the proven methods of ‘Self Learning’. This book is prepared for those who are willing to learn things by doing themselves. Take an experiment and “follow” every step. Be patient and keep waiting until you are rewarded with a result. Now, you have an experiment, which works. Repeatedly study and practice every step of the experiment. You will soon discover the reason for having a particular step included in the experiment. Try to build the experiment in your own way. Execute the program and monitor the result. Good Luck!
Golam Mostafa Segun Bagicha, Dhaka 6/1/2009
Contents Experiment – 1A Experiment – 1B
Familiarization with the Components Organization and the Operating Procedures of the MicroTalk-8086 Trainer 1/Expt-1A Familiarization with the Organization and the Operating Procedures of the MDA-8086 Trainer 1/Expt-1B.
Experiment – 2
Familiarization with the Assembly Instructions of 8086 Microprocessors by Adding Two 8-bit Unsigned Hexadecimal Numbers. 1/Expt-2
Experiment – 3
Familiarization with the Assembly Instructions of 8086 Microprocessors by Multiplying Two 8-bit Hex Numbers by Repetitive Additions. 1/Expt-3
Experiment – 4
Familiarization with the Procedures of Programming the 8255 Parallel IO Controller. 1/Expt-4
Experiment – 5A
Familiarization with the Procedures of Interfacing a Text Mode LCD Panel with MicroTalk-8086 Trainer. 1/Expt-5A Familiarization with the Procedures of Programming the Text Mode LCD Panel of the MDA-8086 Trainer. 1/Expt-
Experiment – 5B Experiment – 6A Experiment – 6B
Experiment – 7
Familiarization with the Functionality Check of the NMI-interrupt of 8086 using MicroTalk-8086 Trainer. 1/Expt-6A Familiarization with the Functionality Check of the NMI-interrupt of 8086 using MDA-8086 Trainer. 1/Expt-6B Task-7.1 [BCD-to-BINary] Conversion of 2-digit BCD Number (range: 00 – 99) into Equivalent BINary Number by Counting Method. 1/Expt-7 Task-7.2 [BCD-to-BINary] Conversion of 4-digit BCD Number into Equivalent BINary Number by Horner Method (Fast Method). 2/Expt-7
i
Experiment – 8
Task-8.1 [BINary-to-BCD] Conversion of Tw-digit BINary Number (range: 00h – 63h) into BCD Number by Counting Method. 1/Expt-8 Task-8.2 [BINary-to-BCD] Conversion of n-bit BINary Number into equivalent BCD Number by Horner Method (Fast Method) 2/Expt-8
Experiment – 9
[BINary Multiplication] Multiplication of two 16-bit unsigned BINary Numbers 1/Expt-9
Experiment – 10A Familiarization with the Procedures of Converting MicroTalk-8086 Trainer into a Digital Weighing Machine 1/Expt-10A Experiment – 10B Familiarization with the Procedures of Converting MDA-8086 Trainer into a Digital Weighing Machine 1/Expt-10B Experiment – 11A
Study of the Asynchronous Serial Communication Link Between IBMPC and MicroTalk-8086 Trainer. 1/Expt-11A Experiment – 11B Study of the Asynchronous Serial Communication Link Between IBMPC and MDA-8086 Trainer. 1/Expt-11B Experiment – 12
Programming of the 8279-Based Display Unit of the MicroTalk-8086 Learning System. 1/Expt-12
Experiment – 13A Programming of the 8279-Based Keyboard Unit of the MicroTalk-8086 Learning System. 1/Expt-13A Experiment – 13B Programming the Discrete Components-Based Keyboard Unit of the MDA8086 Learning System. 1/Expt-13B Experiment – 14A Converting MicroTalk-8086 Trainer into a 24-Hr Clock System
ii
Experiment – 8 Converting BINary Number into Equivalent BCD Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-8.1 Converting Two-digit BINary number (range: 00h – 63h) into equivalent BCD number (range: 00 – 99) using Counting Method (Slow Process). 1. Draw Input/Out Data Structure. Keep Input BIN at location 03010h and the Output BCD at location 04010h. 2. Convert the following conversion Pseudo Codes into 8086 ASM codes and save as: bin2bcdc..asm. MYCODE
START: L1: L2:
L3: L4: L5: L6: MYCODE
SEGMENT ASSUME cs:MYCODE ORG 1000h nop Bring BINary ah-register from location 03010h mov al, 00h ; IPBCD add al, 01h If ((al3 – al0) > 9) Goto L6 dec ah jnz L2 mov BYTE PTR [bx+1010h], al ; BCD result at location: 04010h hlt add al, 06h jmp L3 ENDS END START
4.
Assemble the above program and down load it.
5.
Enter the input BINary number as: 25h
6.
Execute the program:
7.
Open memory location 04010h and we must see 37 (the desired BCD number).
8.
Enter different values for the input Binary and check that the program produces correct BCD numbers.
1/Expt-8
Task-8.2 Converting 4-digit BINary number (range: (0000h – FFFFh) into equivalent BCD number (range: 0000h – 065535) using Horner Method (Fast Process). 1. Review the following Horner Rule foe conversion. BIN = b15b14, ………………………., b1b0 = b15x215 + b14 x 214 +, …………….., +b1 x 21 + b0 x20 = (……….(b15)2 + b14) 2 +, ………………………, + b1 ) 2 + b0
2.
3. 3.
BCD = (……….(b15)2 + b14) 2 +, ……………………., + b1 ) 2 + b0 = (……….(IPBCD x 2 + b15) 2 + b14) 2 +,………………..+ b1 ) 2 + b0 where: IPBCD = Initial Partial BCD = 000000 Computation Philosophy a. Extract b15 and compute: (IPBCD x 2 + b15) → IPBCD b. Carry out Step-a, for all the bits of the input BINary number. Draw DSM-based Data Structure for the Input/Output numbers. Draw the following Register-based Data Structure for the Input/Output Numbers. 15
0
23
(Six BCD Digits)
0 Cl, bh, bl = IPBCD
si = BIN cl
538
4.
bh
bl
Convert the following Pseudo Codes into ASM codes. Save as: bcd2binh.asm. Download and execute it. The DSM locations: 04011h and 04010h would contain the Binary number. L1:
L2:
L3: L4: L5:
000000 → cl, bh, bl (IPBCD) mov si, WORD PTR [di+10h] mov ah, 10h ; Extrcat b15 rcl si, 01h call BCDC dec ah Jnz L2 mov BYTE PTR [di+1012h], cl Mov WORD PTR [di+1010h], bx hlt
BCDC: mov adc daa mov
; getting the input BINary from DSM ; number of bits in the input Binary number ; b15 is in C-bit ; BCD Computation ; extract next bit (b14, …….b0) ; BCD at locations: 04012, 04011, 04010
al, bl al, al bl, al
mov adc daa mov
al, bh al, al
mov adc daa mov ret
al, cl al, al
bh, al
cl, al
2/Expt-8
3/Expt-8
Experiment – 1B
Familiarization with Components Organization and the Operating Procedures of the MDA-8086 Microprocessor Learning System Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-1B.1 Familiarization with the Components Layout In this task you will be locating and getting familiar with the following functional units of the MDA-8086 trainer. These units are considered as the Building Blocks of a microprocessor based system. The MDA-8086 is an 8086 microprocessor learning system made in Korea. i. 8086 Microprocessor ii. RAM (Random Access Read and Write Memory) iii. EPROM (Ultraviolet Erasable and Electrically Programmable Random Access Read Only Memory) iv. Input Device (The Keyboard) v. Keyboard Interface Controller (not visible) vi. Output Devices: a. Liquid Crystal Display Unit (LCD) b. Common Anode Type 7-Segment Display Device (CA7SDD) c. Light Emitting Diodes (LED11-LED14) d. 8x8 Bicolor Dot Matrix LED [DOTLED]. Each dot contains Red and Green LEDs. vii. Output Device Interface Controllers (not visible) viii. Primary Memory Decoder (not visible) ix. Primary Port Decoder (not visible)
Procedures: 1. 2. 3. 4. 5. 6.
Collect the MDA-8086 trainer from the lab attendant. Open the top cover of the trainer. Look at the PCB (Printed Circuit Board) of the trainer and the component layout of Fig-1B.8. Now, on the PCB, locate the circuit designation U1. This is the 8086 microprocessor chip. Look very carefully on the top of the U1-chip and you will find the inscription ‘8086’. Locate the keyboard on the trainer. The keyboard interface circuitry is there but is not obvious. 7. Locate the following output devices on the PCB of the trainer. a. The LCD unit. The interface controller of the LCD device is built-in within the LCD panel. b. The 7-segment display device, which has the circuit designation – FND in Fig-1B.8. This is a common-anode type display device. Let us agree to call it by the symbolic name CA7SD (Common Anode 7-Segment Display Device). A CA-type display device is opposite to CCtype display device. The interface controller for this device is the chip, U29 (8255). c. The LED assembly, LED11-LED13. The interface controller for these LEDs is the chip, U29. 8. Locate the RAM chips U9, U10 on the PCB. Bit capacity of each RAM is: 32x1024x8. 9. Locate the EPROM chips U7 and U8 on the PCB. These chips contain the Monitor Program of the MDA-8086 trainer. Bit capacity of each EPROM is: 32x1024x8.
1/Expt-1B
Task-1.2
Familiarization with the Hardware Block Diagram of MDA-8086
There are many more interface controllers on the PCB of the MDA-8086, which we could not describe in Task-1B.1. The following Hardware Block Diagram of Fig-1B.1 contains the total IO scenario of the trainer. For complete circuit diagram, consult user manual for MDA-8086 trainer. KBIC : 74244 :U24 NMI RES
G0 STP C D E
F
+ REG 8 - DA 4
9 5
A B 6 7
: AD 0 546
1
2
3
Users Interface Controller CA7SD
D7-D0
PB4-PB7 Step. Motor Int.
LM:U38
P8
VR2
DR
SIO: 8251:U14
CS/
D15-D8
D
PCR:1Dh
PIO:8255 U29
CR:1 Fh
CS/ D7-D0 PA:18h
CS/
CS/
D15-D8
0V
D7-D0
TC-0:09h
CK0 GT0 OT0
TC-1:0Bh
CK1 GT1 OT1
TC-2:0Dh
CK2 GT2 OT2
D7-D0
P6
PUT: U41 :8253
CR:0Fh
CR:18h
ADC: 0804 : U31
IN TA IN TR/
CS/ D
D8
D7-D0
DR: 11h
SPKIC: U25 F0001,...... ,FFFFF
RxRS
0V
CLK for 9600 Bd
Speaker
ODD: ROM:U8
TTL
CON: DB9
TxRDY
CR: 0Ah TxC,RxC
D7-D0
Out
TxRS
SR: 0Ah
D7-D0
DR:18h 0V
TTL
RxRDY
DR: 08h
CR:1Eh
DAC:U33 TH1
MIC
9600 Bd TxTTL D7-D0 9600 Bd RxTTL
D7-D0
PC:1Ch
DIP2
TTL RS232 : U15
CS/
PB:1Ah
Vin
16 Characters x 2 Lines
SR
CON10
PIO: 8255:U30
+5V
D7-D0
IR
20h, 22h, CS/ 24h, 26h
ADC:U31
8x8 Common Cathode Type Bi-color LED Array
CS/ D7-D0
DR:01h
PBR:1Bh
DAC U33
D15-D8
RS : 01h
PAR:19h
PB0-PB3 LED11-LED14
LCD
LCDIC
CPU : 8086 : U1
CS/
27256 CS/ D7-D0
PCLK: 2.4576MHz +5V
GATE1 0V
GATE2
INTA INT / CS/
(40h)IR0 (41h)IR1 IR2 IR3 IR4 D7-D0 IR5 DR:12h IR6 IPC IR7 U42 CR:10h
8259 D15-D8D15-D8
CS/ 62256 D7-D0
0V
IR2
ODD: RAM : U10 00001, ........ 0FFFF
NMI +5V
NMI
EVN: ROM:U7 F0000, ..... FFFFE
27256 CS/ D7-D0
D7-D0 D7-D0
CS/ 62256 D7-D0
EVN : RAM : U9 00000,......... 0FFFE
A,M-IO/,BHE/
Mem/Port Decoder : U16
Sx/
+5V
Sy/
0V GM: 547: 11/03:3 Hrs
Figure-1B.1: Hardware Block Diagram of MDA-8086 Trainer
2/Expt-1B
Task-1B.3
Getting Familiar with Keyboard Layout of MDA-8086 Trainer MON
RES
C
D
E
F
+
REG
8
9
A
B
-
DA
4
5
6
7
:
AD
0
1
2
3
G0
STP
546
Figure-1B.2: keyboard Layout of MDA-8086 Learning System
The 26 keys of the keypad may be classified into the following categories: A: CPU Control Key 1. RES (system RESet) : When this key is pressed down and then released, the 8086 is reset and starts from the cold state. The PC looks for a valid instruction at memory location: FFFF (CS):0000 (IP) = FFFF0h. Activation of the RES key displays the following message on the LCD monitor. Note that the jumper at P1 must be set to ‘Local Monitor (the left side)’ position. MDE – 8086 kit ! ! Midas 335-0964/5
2. MON (Monitor) /NMI (Non Maskable Interrupt): When pressed, the CPU is immediately interrupted B: Command Keys 1. AD (set memory ADdress) : This command key allows the user to set the 20-bit address of a memory location in the format of [Segment:Offset]. Press this key and we will see the following message on the LCD with the cursor blinking at the Segment Field. Seg.
Oset
data
xxxx yyyy zz a. ‘Seg.’ stands for ‘Memory Segment’, ‘Oset’ stands for ‘Memory Offset’ and ‘data’ refers to the 8-bit content of the memory location, xxxx:yyyy. b. Now, we can set the ‘Segment’ part of our desired memory location. Let us assume that we wish to examine the content of the memory location F000h (F000:0000) of the ROM area of Fig-11.1. We may use the data keys (0 to F) to change the segment into: F000h. c. Now is the turn to change the ‘Offset’. Press [:] key.
2. : (set the Offset) : This key allows editing the Offset part of a memory location. When this is pressed, the cursor moves to the Offset Field. And now, the user can use the data keys to set the offset to the desired value. 3. DA (update address and allow Data entry) : This key brings cursor to the Data Field. Now, the user may use the data key (0 to F) to enter new data (assume that the present memory location is a RAM location). 4. + (increment by One) : This key allows moving to the next memory location. 5. - (decrement by One): This key allows moving in the previous memory location. 6. GO (GO to the beginning point of the program to be executed): This key allows executing a program. 7. REG (examing and changing REGister contents): This key allows checking and editing the content of the internal registers of the 8086. 8. STP (Single STep): This key allows executing one instruction at a time. C: Data Keys Keys with labels: 0, 1,2,3,4,5,6,7,8,9,A,B,C,D,E,F are the hexadecimal data keys.
3/Expt-1B
Task-1B.4 Familiarization with the Operation of MDA-8086 Trainer by Blinking Character 3 on the CA7SDD. Brief Theory: The CA7SDD is connected with the 8086 CPU as per diagram depicted in Fig-1B.3. 8086 : U1
8255 : U29
CA7SD a
Port-A 19h D7-D0
PA7-PA0
CS/
D15-D8
ah
e
CR: 1Fh
(1)
f
(3) (3) (1)
MLoc
Content
Comment
03011 03010
FF B0
CA Code for Blank CA Code for 3
xxxxx 01000
TDELAY
PC = CS:IP
(2)
g d
al
Program Codes (4)
CA
+5V
b c p
DSM
CSM
RAM: U9, U10
548
Figure-1B.3: Connection Diagram between CA7SD and the CPU
To show character 3 on CA7SD (output device), we need to send code B0h (1011 0000) into Port-A register of U29. B0h is the 8-bit CA-code for character 3 (see Fig-1.4 for the internal structure of CA7SD). To blank (nothing) the output device, we need to send code FFh into Port-A. After sending B0h, we need to wait for sometimes (Time Delay) so that the character 3 remains visible for a while. Likewise, after sending code for blank, we also need to insert some time delay so that the display remains OFF for sometimes. To blink 3 on the CA7SD, we may follow the steps: A.
C.
Use keyboard and store data B0h (CA-code for 3) at memory location 03010h (0000:3010) of the DSM of Fig-1B.3. Keep data FFh (CA-code for) Blank) at memory location 03011h. Use keyboard and store Program Codes into the memory locations of the CSM of Fig-1B.3. The programs read the data for character 3 from DSM and send it to Port-A register. As a result, 3 appear on CA7SDD. The program inserts time delay. After that the data for blank is sent to Port-A to show nothing on the CA7SDD. Now, let us carry out the following:
1. 2. 3.
Power up the MDA-8086 trainer. Carry out the steps of Table-A to enter data into memory locations of DSM. Carry out the steps of Table-B to enter Program Codes into memory locations of CSM.
B.
Table-A Entry of Common Anode Code for Character 3 and Blank Sn: 1
Press Key RES
2
AD
3
0000
LCD Display MDE8086 Kit V9.5 Midas 935-0964/5 Seg. Oset Data xxxx yyyy zz Seg. Oset 0000 yyyy
Data zz
Remarks The trainer is ready to accept valid command The 20-bit address of an arbitrary memory location is opened in the format of: ‘Segment: Offset’. The present content of the memory location has also appeared in the data field. The segment part of the 20-bit address is set to 0000h. This is actually 00000h (the right most digit is understood to be 0). Now, set the offset part of the 20-bit address.
4/Expt-1B
4
:
Seg. 0000 Seg. 0000 Seg. 0000 Seg. 0000
Oset Data yyyy _ zz Oset Data 3010 _ zz Oset Data 3010 zz _ Oset Data 3010 B0 _
5
3010
6
DA
7
B0
8
+
Seg. Oset 0000 3011
9
FF
10
RESET
Seg. Oset Data 0000 3011 FF _ MDE8086 Kit V9.5 Midas 935-0964/5
Data zz _
The cursor has moved to the offset field and is blinking. Use the data keys (0 to F) to set the value of the offset. The 20-bit address, 03010 (0000:3010) is entered. Now, deposit the cacode data (B0h) for character ‘3’. The cursor has moved at the data field. Now, use data keys (0 to 9) to deposit the cacode, B0h at the indicated memory Location. The data value B0h is deposited at location, 0000:3010. Now, deposit cacode (FFh) for the ‘blank’ character at the memory location, 0000:3010. The next memory location is opened. Enter data, FFh at the indicated memory location using the data keys (0 to 9). To move to the previous memory location, use the ‘ – ‘ command. The CA-code for blank is entered at memory location: 03011 The trainer is ready to accept valid command
Table-B
Enter the Machine Codes of the following Program starting at location: 01000h (0000:1000) Label: START: L1:
Mem. Loc 0000:1000 – 0000:1001 -
Assembly Codes nop mov ax, 0000h mov ds, ax mov ax, 0000h mov ss, ax mov sp, 8FFEh
Machine Codes 90 B8 00 00 8E D8 B8 00 00 8E D0 BC FE 8F
L2:
0000:100E –
L2A:
0000:1015 -
0000:101D-
al, 80h CRU29(1Fh), al bx, 3000h al, BYTE PTR ds;[bx+10h] PARU29(19h), al cx, 0FFFFh HERE1
B0 80 E6 1F BB 00 30 8A 47 10 E6 19 B9 FF FF E2 FE
; bx-register to work as pointer ; reading cacode for ‘3’ ; sending cacode of ‘3’ to PAR ; Insert Time Delay
HERE1:
mov out mov mov out mov loop
L3:
0000:101F -
0000:1027 -
al, BYTE PTR ds:[bx+11h] PARU((19h), al cx, 0FFFFh HERE2
8A 47 11 E6 19 B9 FF FF E2 FE
; reading cacode for ‘blank’ ; sending cacode of ‘blank’ to PAR ; Insert Time Delay
HERE2:
mov out mov loop
L4:
0000:1029-
jmp
L2A
EA 15 10 00 00
; repeat the process
4.
Meaning ; 00000h = Base Add.of Data Seg. ; 00000h = Base Add of Stack Seg. ; Stack Pointer Reg. set to: 08FFEh ; Control Byte to set PAR as output
Carry out the steps of Table-C to execute the above program of Table-B. Table-C
Program Execution: Carry Out the following steps: Sn: 1
Press Key RESET
2
AD
3
:
4
GO
LCD Display MDE8086 Kit V9.5 Midas 935-0964/5 Seg. Ost Data xxxx yyyy zz Seg. Ost Data 0000 yyyy _ zz Statring Address 0000:1000
Remarks The trainer is ready The cursor blinks at the segment field. Use data keys to set the segment at: 0000h. The cursor blinks at the offset field. Use data key to set the address at : 1000h Program has been executed. Character ‘3’ should blink.
5/Expt-1B
Task-1B.5
Familiarization with Internal Structure of CA 7-Segment Display Device a
ca
10 g
9 f
8 ca
7 a
6 b
f 10 e 2
e 1
d 2
ca 3
c 4
g
d
7
ca
b 6
c
4
p 5
p 5 538
(a) Physical View
p(5)
g(10)
f(9) e(1) d(2) c(4) b(6) a(7)
538
(b) Internal LED Structure
538
(c) Electrical Equivalent
Figure-1B.4: Structure of Common Anode Type 7-Segment Display Device
Task-1B.6 Enter appropriate data at the appropriate memory locations of DSM to blink character A on the CA7SD. Make CA-code for A looking at the diagram of Fig-1B.3.
Task-1B.7 Learning How to Get Machine Codes of Character Blinking of Task-1B.4 In this task, we will get familiar with the procedures of getting the machine codes for the character-blinking program of Table-B of Task-1B.4. We shall use MASM (Macro Assembler) program and the IBM-PC to obtain the machine codes for the assembly instructions of Table-B of Task-1B.4. The procedures are: (a)
Create a directory named as MDA8086 in the hard drive C. And now accommodate the following program files under this directory. These programs may easily be collected from the CD that has been supplied with the MDA-8086 trainer. If the directory already exists and contains these files then go to step-b Sno. 1 2 3 4 5 6
(b)
(c) (d)
File Name COMM.EXE LINK.EXE LOD186.EXE MASM.EXE EDIT.EXE EXER
Purpose Serial Monitor of the MDA-8086 Trainer To create relocatable *.EXE file from *.OBJ file To create ‘Absolute (*.ABS)’ file from *.obj file To create *.LST and *.OBJ files form *.ASM file To create Assembly Program (Source Code) for 80x86 MPUs A Working Directory
Boot the IBMPC in Windows 98/XP and then go to DOS path using the Start Menu. The monitor would show as: c:\windows>_ Bring the IBM-PC in the following DOS path: c:\mda8086>-The procedures: 1. Type cd.. and then press enter key 2. Type mda8086 and then press enter key. Type EDIT at the cursor position of the above DOS prompt. Press Enter key. As a result, a screen appears called DOS Screen will appear. Type only the labels and the assembly instructions of Table-B of Task-1B.4.
6/Expt-1B
(e)
Save the screen (what you have typed in the screen) with the file name of: P1B.asm. Save the file as: c:\mda8086\P1B.asm The Procedures: 1. Press Alt key and then release. And then press Enter key.
(f)
2. Choose ‘Save As...’ from the menu using the arrow keys. 3. Now type the file name: P1B.asm and then press Enter key. Type the following lines (called Assembler Statements) at the top of your program. MYCODE
(g)
para public cs:MYCODE 1000h
‘code’
; declaring logical segment
Type the following assembler statements at the end of your assembly program. MYCODE
(h)
SEGMENT ASSUME ORG ENDS END
START
Update your file (P1B.asm) in the following ways: The Procedures: 1. Press Alt key and then release. And then press Enter key.
(i)
2. Choose ‘Save’ from the menu using the arrow keys. 3. Now press Enter key. Now leave the screen and come back to the DOS prompt in the following ways: The Procedures: 1. Press Alt key and then release. And then press Enter key.
(j) (k)
2. Choose ‘Exit’ from the menu using the arrow keys. 3. Now press Enter key. Type cls and press Enter key for clearing up the screen. Now, convert the source codes of your program c:\mda8086\P1B.asm into machine codes in the following ways: This is known as assembling. The Procedures: 1. Type MASM at the cursor position of the DOS prompt. Press Enter key. 2. Type P1B.asm (assembly) and press Enter key 3. Type P1B.obj (object) and then Press Enter key 4. Type P1B.lst (list) and press Enter key. 5. Press Enter key
(l)
(m)
You are back to the DOS prompt. Your assembly program has already been converted into machine codes and the codes have been saved in the path: c:\mda8086\P1B.lst. Show the error messages to the teacher if any. Remember that there should not be any error in the program. If there are errors, take help from the teacher to correct these errors and then and go to Step-k. After error free assembling go to Step-m. Open the P1B.lst file in the following ways to see its contents: The Procedures: 1. Type ‘EDIT’ at the DOS prompt. And then press Enter key.
(n) (o)
2. Press Alt key and then press Enter key. 3. Choose ‘Open...’ from the menu using the arrow keys. Press Enter key. 4. Use ‘tab’ key and ‘arrow’ key to choose the file, P1B.lst from the menu. Press Enter. 5. Now the machine codes of your program are in the screen. Look at the machine codes of your program on the screen. Compare these codes with the machine codes of Table-B of Task-1B.4. Write down the codes where they differ. Look for the jumper ‘P1’ (Fig-1B.5) or switch ‘KIT/PC’ of the MDA-8086 trainer. Bring the jumper at the ‘Local Monitor’ or KIT position.
7/Expt-1B
Jumper Position at: Serial Monitor
P1 GND
+5V
Jumper Position at: Local Monitor
538
Figure-1B.5: Jumper P1 is at Local Monitor Environment
(p) (q)
Power OFF and then ON of the MDA-8086 trainer and then press the RESET key. The LCD display of the trainer shows the following prompt message: MDE8086 Kit V9.5 Midas 335-0964/5
(r)
(s) (t) (u) (v)
Use keyboard of the trainer and enter the machine codes of Step-n in the CSM starting at memory location. 0000:1000. Take help of the lab teacher to know the ways of entering the differing codes in the CSM. For multi-byte data, the lower bytes should be entered first. Enter the data B0h (for character 3) at RAM location 0000:3010 and FFh (for Blank) at RAM location 0000:3011 of the data segment memory. Execute the program at location: 0000:1000 using the GO command. Observe that the device 3 is blinking on the CA7SD device. The Task-1B.7 is well done.
Task-1B.8 In this Task, we will learn how to transfer the machine codes of the Step-n of Task1B.7 from the IBMPC to the CSM of the MDA-8086 trainer. This method is known as Down Loading. To do it, we will be using the COM1 port of the IBMPC. This method saves a lot of time while developing a large program. We do not need to enter the data and codes manually in the memory locations. The procedures are: 1. Power down the MDA-8086 trainer. Bring P1 jumper (Switch) at the ‘Serial Monitor’/KIT position. Connect the serial cable of the trainer with the COM1 port of the IBMPC. 2. 3.
Bring the IBM-PC in the following DOS prompt: c:\mda8086> _ From the start icon of the IBMPC execute the WinComm and then goto Step-4 below. OR Type COMM at the cursor position and then press Enter key. A communication screen will appear. Press F5 function key and modify the screen as follows: Serial Port (1/2) Serial baud rate Set 1200 = 1 2400 = 2 4800 = 3 9600 = 4 19.2K = 5 38.4 = 6 Baud Rate Select (1 – 6) Parity bit NP =0, Po = 1, Pe = 2 Word Size 7-bit=2, 8-bit=3 Stop bit 1-bit=0, 2-bit=1 Change OK (Y/N) ? y
: [X]
==>1
press Enter key
: [X] : [X] : [X] : [X]
= = > 4 (always) ==>0 ==>3 ==>0
press Enter key press Enter key press Enter key press Enter key press Enter key
8/Expt-1B
4.
Power down and Power up the MDA-8086 trainer. Press the RESET key of the trainer to get the prompt message on the screen of the IBMPC. * * 8086 Monitor 9.5 * * * * Midas 335-0964/5 * * 8086> _
5. 6. 7.
To bring the IBMPC into DOS mode, press Alt and hold and then press X key. And then press the Enter key. The IBM-PC in the path: c:\mda8086> _ Now, convert the P1B.obj (object) file into P1B.abs (absolute) file for onward transmission to the trainer. Type LOD186 at the cursor position of the DOS prompt. And then press Enter key. Answer as follows: (a) Type T1B.obj (b) (c)
Type c:\mda8086\P1B.abs press Enter key
The conversion is completed with the message LOAD COMPLETED and the PC comes to the following DOS path: c:\mda8086> _ The converted file is located at: c:\mda8086\P1B.abs.
8. 9.
Type EDIT at the cursor position of the DOS prompt. Open the file P1B.abs The screen shows multiple lines, which are very similar to the following line. This particular format is known as Intel-hex Format. For details, see Page-12/Expt1A). : 0A 1000 00 90 B8 80 E6 1F B0 B0 E6 19 F4 46
Starting address of storage
10. 11. 12. 13. 14. 15. 16 17 18
Exit the screen and come to the DOS prompt of: c:\mda8086> _ Type COMM at the DOS prompt and press the Enter key OR click on the WinComm. Reset the MDA-8086 trainer to activate Serial Link with IBMPC. Type L at the cursor position. Press Enter key. And then press F3 key. Type c:\mda8086\P1B.abs and then press Enter key. The program codes have already been transferred into the trainer with the message ‘OK Completed’. Bring the jumper P1 (Switch) of the trainer into Local Monitor/KIT position. Enter B0h (CA code for 3) at memory location 03010h (0000:3010) and FFh (CA code for Blank) at memory location 03011h (0000:3011) of the DSM. Execute at 0000:1000 using the GO command of the trainer. The device CA7SD must blink the character ‘3’
Task-1B.9 Find the location of the file ‘fnd.abs’ in your computer and bring it under the directory of c:\mda8086. Down load the codes of the fnd.abs file in the trainer. Execute the program in the trainer at: 0000:1000. Observe that the device CA7SD shows: 0,1,2,3,4,5,6,7,8,9,0,1,2............ Task-1B.10 (P110.asm) Write an 8086-based assembly language program to display the characters: 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F,0,1,2,3...... cyclically on the device CA7SD. Get your program codes down loaded from the PC to the trainer. The offset of the 1st code byte must be at: 2000h.
9/Expt-1B
Task-1B.12 Introduction to MDA-8086 Trainer The MDA-8086 is a 16-bit microprocessor learning system using Intel’s 8086 architecture. The trainer has been designed, developed and built by the ‘MIDAS Engineering Co. of South Korea. The Address: Original Manufacturer:
ACE TechnoV, 906 19-7-22, Kuro-Gu, Seoul, South Korea. Fax: (02) 2109-5968. Web: www.midaseng.com.
Task-1B.13 Hardware Features of MDA-8086
A. Central Processing Unit Subsystem [see Fig-1.1] 1. 2. 3. 4.
8086 Microprocessor running in Minimum Mode Data Buffers for the data lines of the CPU Address Latches for the Multiplexed Address-Data Bus PAL-Based Composite Memory and Port Decoder
B. Memory Subsystem [see Fig-11.4] 1. 64 Kbytes of EPROM
2.
64 Kbytes of RAM
C: Interrupt Structure Subsystem [see Fig-1.1] 8259-Based 8-Channel Interrupt Priority Controller. It receives interrupt requests from the following devices and funnels them to the 8086. 1. IR0: From the Timer/Counter-1 of the 8253 (U41) 2. IR1: From the Timer/Counter-2 of the 8253 3. IR2: Hardware activation using onboard key: IR2 4. IR3: From Serial Communication Chip, U14 5. IR4-IR7: Available to user via ‘EXT CONNECTOR, SLOT’.
D: Input/Output Subsystem [see Fig-1.1] 1. Keyboard: 2. Display: 3. Parallel IO:
4. Serial IO: 5. ADC:
6. DAC:
7. Speaker:
Discrete IC-Based Keypad containing 24 Keys LCD-Based Display containing 16x2 Characters a: Onboard 8255 (U29), which is interfaced with the following onboard IO devices: i. FND (Common Anode Type 7-segment Display Device) ii. LED Assembly (LED11 – LED14) iii. Stepper Motor Driving Circuitry iv. Digital-to-Analog Converter (U33), which feds analog signal to either of: * Onboard Level Meter (U38, U39) * Onboard Analog-to-Digital Converter (U31) b: Onboard 8255 (U30), which is interfaced with the following onboard IO devices: 8x8 Bi-color Dot Matrix LED Assembly (DOT1) 8251-Based (U14) Serial Communication Scheme, which communicates with the IBMPC using RS-232 (U15) Link at a fixed Bd (Baud Rate) of: 9600 bps. ADC0804-Based Analog-to-Digital Converter. It takes analog signal either from: a. Onboard Potentio Meter (VR2) b. Onboard Thermostat (TH1) c. Onboard DAC (U33, U36) d. Onboard Microphone DAC0800 being driven by Port-C of the 8255 (U29). It feds analog signal either to: * Onboard Level Meter (U38, U39) * Onboard Analog-to-Digital Converter (U31) Externally installable Output device via socket ‘SPK’. The speaker is interfaced to the 8086 via (U25, TR4) at an port address: 11h and data line: D8.
10/Expt-1B
Task-1B.14 Software Features of MDA-8086 A: Resident Monitor Program 1. 2. 3. 4. 5.
Allows data entry, edit into RAM locations [Word operations are not available] Allows Program Execution Allows data entry, edit into Registers locations Allows Debugging a Faulty Program (Single Stepping) Does not contain any data conversion algorithms like: BCD-to-Binary, Binary-to-BCD, Multiplication, Division, BCD-to-ASCII
B: Serial Monitor Program Allows downloading program/data codes from the IMB-PC to the MDA-8086
C: Example Programs A disk accompanying the trainer contains a good number of example programs.
Taks-1B.15 Memory Space and Port Space Organization of MDA-8086
Reserved 4x 2KByres
0D000 0CFFF
Reserved 4x 4KByres
07000 06000
05000 04FFF 03000 02FFF
01000 00FFF 00F00 00EFF 00400 003FF 00000
FFFE
(00)26 (00)24 (00)22 (00)20
Space for Stack Segment Space for Extra Segment Space for Data Segment
IO CON10 IO CON10 IO CON10 IO CON10 ADC : DR/CR OR 8255 (U30):CR ADC : DR/CR OR 8255 (U30):PCR ADC : DR/CR OR 8255 (U30):PBR ADC : DR/CR OR 8255 (U30):PAR
(00)1F
8255 (U29): CR
(00)1E
(00)1D
8255 (U29): PCR
(00)1C
(00)1B
8255 (U29): PBR
(00)1A
(00)19
8255 (U29) PAR
(00)18
(00)11 (00)0F (00)0D (00)0B (00)09
SPEAKER: DR 8253: CR 8253: TC-2 8252: TC-1 8253: TC-0
(00)12 (00)10
8259: DR 8259: CR
(00)0A (00)08
8251: CR/SR 8251 : DR
KBD DR/FR
(00)04 (00)02 (00)00
LCDDR LCDSR LCDIR
RAM
09000 08000
FFFF
Useable after Decoding
User-3
10000 0FFFF
User-2
F0000 EFFFF
Start Up Location
User-1
FFFF:0000
ROM
FFFFF
Space for Code Segment Scratch Pad Data Structure Interrupt Vvector Table 545
Figure-1B.6: Memory Space of MDA-8086
(00)05 (00)03 (00)01
545
Figure-1B.7: Port Space Map of MDA-8086
11/Expt-1B
Task-1B.16 Component Layout of MDA-8086
12/Expt-1B
Figure-1B.8: Component Layout Diagram of the MDA-8086 System
Task-1.17 Schematics of the MDA-8086 Learning System
13/Expt-1B
14/Expt-1B
15/Expt-1B
16/Expt-1B
17/Expt-1B
18/Expt-1B
Experiment – 1B
Familiarization with Components Organization and the Operating Procedures of the MDA-8086 Microprocessor Learning System Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-1B.1 Familiarization with the Components Layout In this task you will be locating and getting familiar with the following functional units of the MDA-8086 trainer. These units are considered as the Building Blocks of a microprocessor based system. The MDA-8086 is an 8086 microprocessor learning system made in Korea. i. 8086 Microprocessor ii. RAM (Random Access Read and Write Memory) iii. EPROM (Ultraviolet Erasable and Electrically Programmable Random Access Read Only Memory) iv. Input Device (The Keyboard) v. Keyboard Interface Controller (not visible) vi. Output Devices: a. Liquid Crystal Display Unit (LCD) b. Common Anode Type 7-Segment Display Device (CA7SDD) c. Light Emitting Diodes (LED11-LED14) d. 8x8 Bicolor Dot Matrix LED [DOTLED]. Each dot contains Red and Green LEDs. vii. Output Device Interface Controllers (not visible) viii. Primary Memory Decoder (not visible) ix. Primary Port Decoder (not visible)
Procedures: 1. 2. 3. 4. 5. 6.
Collect the MDA-8086 trainer from the lab attendant. Open the top cover of the trainer. Look at the PCB (Printed Circuit Board) of the trainer and the component layout of Fig-1B.8. Now, on the PCB, locate the circuit designation U1. This is the 8086 microprocessor chip. Look very carefully on the top of the U1-chip and you will find the inscription ‘8086’. Locate the keyboard on the trainer. The keyboard interface circuitry is there but is not obvious. 7. Locate the following output devices on the PCB of the trainer. a. The LCD unit. The interface controller of the LCD device is built-in within the LCD panel. b. The 7-segment display device, which has the circuit designation – FND in Fig-1B.8. This is a common-anode type display device. Let us agree to call it by the symbolic name CA7SD (Common Anode 7-Segment Display Device). A CA-type display device is opposite to CCtype display device. The interface controller for this device is the chip, U29 (8255). c. The LED assembly, LED11-LED13. The interface controller for these LEDs is the chip, U29. 8. Locate the RAM chips U9, U10 on the PCB. Bit capacity of each RAM is: 32x1024x8. 9. Locate the EPROM chips U7 and U8 on the PCB. These chips contain the Monitor Program of the MDA-8086 trainer. Bit capacity of each EPROM is: 32x1024x8.
431
Task-1.2
Familiarization with the Hardware Block Diagram of MDA-8086
There are many more interface controllers on the PCB of the MDA-8086, which we could not describe in Task-1B.1. The following Hardware Block Diagram of Fig-1B.1 contains the total IO scenario of the trainer. For complete circuit diagram, consult user manual for MDA-8086 trainer. KBIC : 74244 :U24 NMI RES
G0 STP C D E
F
+ REG 8 - DA 4
9 5
A B 6 7
: AD 0 546
1
2
3
Users Interface Controller CA7SD
D7-D0
PB4-PB7 Step. Motor Int.
LM:U38
P8
VR2
DR
SIO: 8251:U14
CS/
D15-D8
D
PCR:1Dh
PIO:8255 U29
CR:1 Fh
CS/ D7-D0 PA:18h
CS/
CS/
D15-D8
0V
D7-D0
TC-0:09h
CK0 GT0 OT0
TC-1:0Bh
CK1 GT1 OT1
TC-2:0Dh
CK2 GT2 OT2
D7-D0
P6
PUT: U41 :8253
CR:0Fh
CR:18h
ADC: 0804 : U31
IN TA IN TR/
CS/ D
D8
D7-D0
DR: 11h
SPKIC: U25 F0001,...... ,FFFFF
RxRS
0V
CLK for 9600 Bd
Speaker
ODD: ROM:U8
TTL
CON: DB9
TxRDY
CR: 0Ah TxC,RxC
D7-D0
Out
TxRS
SR: 0Ah
D7-D0
DR:18h 0V
TTL
RxRDY
DR: 08h
CR:1Eh
DAC:U33 TH1
MIC
9600 Bd TxTTL D7-D0 9600 Bd RxTTL
D7-D0
PC:1Ch
DIP2
TTL RS232 : U15
CS/
PB:1Ah
Vin
16 Characters x 2 Lines
SR
CON10
PIO: 8255:U30
+5V
D7-D0
IR
20h, 22h, CS/ 24h, 26h
ADC:U31
8x8 Common Cathode Type Bi-color LED Array
CS/ D7-D0
DR:01h
PBR:1Bh
DAC U33
D15-D8
RS : 01h
PAR:19h
PB0-PB3 LED11-LED14
LCD
LCDIC
CPU : 8086 : U1
CS/
27256 CS/ D7-D0
GATE1 0V
GATE2
INTA INT / CS/
(40h)IR0 (41h)IR1 IR2 IR3 IR4 D7-D0 IR5 DR:12h IR6 IPC IR7 U42 CR:10h
8259 D15-D8D15-D8
PCLK: 2.4576MHz +5V
CS/ 62256 D7-D0
0V
IR2
ODD: RAM : U10 00001, ........ 0FFFF
NMI +5V
NMI
EVN: ROM:U7 F0000, ..... FFFFE
27256 CS/ D7-D0
D7-D0 D7-D0
CS/ 62256 D7-D0
EVN : RAM : U9 00000,......... 0FFFE
A,M-IO/,BHE/
Mem/Port Decoder : U16
Sx/
+5V
Sy/
0V GM: 547: 11/03:3 Hrs
Figure-1B.1: Hardware Block Diagram of MDA-8086 Trainer
432
Task-1B.3
Getting Familiar with Keyboard Layout of MDA-8086 Trainer MON
RES
C
D
E
F
+
REG
8
9
A
B
-
DA
4
5
6
7
:
AD
0
1
2
3
G0
STP
546
Figure-1B.2: keyboard Layout of MDA-8086 Learning System
The 26 keys of the keypad may be classified into the following categories: A: CPU Control Key 1. RES (system RESet) : When this key is pressed down and then released, the 8086 is reset and starts from the cold state. The PC looks for a valid instruction at memory location: FFFF (CS):0000 (IP) = FFFF0h. Activation of the RES key displays the following message on the LCD monitor. Note that the jumper at P1 must be set to ‘Local Monitor (the left side)’ position. MDE – 8086 kit ! ! Midas 335-0964/5
2. MON (Monitor) /NMI (Non Maskable Interrupt): When pressed, the CPU is immediately interrupted B: Command Keys 1. AD (set memory ADdress) : This command key allows the user to set the 20-bit address of a memory location in the format of [Segment:Offset]. Press this key and we will see the following message on the LCD with the cursor blinking at the Segment Field. Seg.
Oset
data
xxxx yyyy zz a. ‘Seg.’ stands for ‘Memory Segment’, ‘Oset’ stands for ‘Memory Offset’ and ‘data’ refers to the 8-bit content of the memory location, xxxx:yyyy. b. Now, we can set the ‘Segment’ part of our desired memory location. Let us assume that we wish to examine the content of the memory location F000h (F000:0000) of the ROM area of Fig-11.1. We may use the data keys (0 to F) to change the segment into: F000h. c. Now is the turn to change the ‘Offset’. Press [:] key.
2. : (set the Offset) : This key allows editing the Offset part of a memory location. When this is pressed, the cursor moves to the Offset Field. And now, the user can use the data keys to set the offset to the desired value. 3. DA (update address and allow Data entry) : This key brings cursor to the Data Field. Now, the user may use the data key (0 to F) to enter new data (assume that the present memory location is a RAM location). 4. + (increment by One) : This key allows moving to the next memory location. 5. - (decrement by One): This key allows moving in the previous memory location. 6. GO (GO to the beginning point of the program to be executed): This key allows executing a program. 7. REG (examing and changing REGister contents): This key allows checking and editing the content of the internal registers of the 8086. 8. STP (Single STep): This key allows executing one instruction at a time. C: Data Keys Keys with labels: 0, 1,2,3,4,5,6,7,8,9,A,B,C,D,E,F are the hexadecimal data keys.
433
Task-1B.4 Familiarization with the Operation of MDA-8086 Trainer by Blinking Character 3 on the CA7SDD. Brief Theory: The CA7SDD is connected with the 8086 CPU as per diagram depicted in Fig-1B.3. 8086 : U1
8255 : U29
CA7SD a
Port-A 19h D7-D0
PA7-PA0
CS/
D15-D8
ah
e
CR: 1Fh
(1)
f
(3) (3) (1)
MLoc
Content
Comment
03011 03010
FF B0
CA Code for Blank CA Code for 3
xxxxx 01000
TDELAY
PC = CS:IP
(2)
g d
al
Program Codes (4)
CA
+5V
b c p
DSM
CSM
RAM: U9, U10
548
Figure-1B.3: Connection Diagram between CA7SD and the CPU
To show character 3 on CA7SD (output device), we need to send code B0h (1011 0000) into Port-A register of U29. B0h is the 8-bit CA-code for character 3 (see Fig-1.4 for the internal structure of CA7SD). To blank (nothing) the output device, we need to send code FFh into Port-A. After sending B0h, we need to wait for sometimes (Time Delay) so that the character 3 remains visible for a while. Likewise, after sending code for blank, we also need to insert some time delay so that the display remains OFF for sometimes. To blink 3 on the CA7SD, we may follow the steps: A.
C.
Use keyboard and store data B0h (CA-code for 3) at memory location 03010h (0000:3010) of the DSM of Fig-1B.3. Keep data FFh (CA-code for) Blank) at memory location 03011h. Use keyboard and store Program Codes into the memory locations of the CSM of Fig-1B.3. The programs read the data for character 3 from DSM and send it to Port-A register. As a result, 3 appear on CA7SDD. The program inserts time delay. After that the data for blank is sent to Port-A to show nothing on the CA7SDD. Now, let us carry out the following:
1. 2. 3.
Power up the MDA-8086 trainer. Carry out the steps of Table-A to enter data into memory locations of DSM. Carry out the steps of Table-B to enter Program Codes into memory locations of CSM.
B.
Table-A Entry of Common Anode Code for Character 3 and Blank Sn: 1
Press Key RES
2
AD
3
0000
LCD Display MDE8086 Kit V9.5 Midas 935-0964/5 Seg. Oset Data xxxx yyyy zz Seg. Oset 0000 yyyy
Data zz
Remarks The trainer is ready to accept valid command The 20-bit address of an arbitrary memory location is opened in the format of: ‘Segment: Offset’. The present content of the memory location has also appeared in the data field. The segment part of the 20-bit address is set to 0000h. This is actually 00000h (the right most digit is understood to be 0). Now, set the offset part of the 20-bit address.
434
4
:
Seg. 0000 Seg. 0000 Seg. 0000 Seg. 0000
Oset Data yyyy _ zz Oset Data 3010 _ zz Oset Data 3010 zz _ Oset Data 3010 B0 _
5
3010
6
DA
7
B0
8
+
Seg. Oset 0000 3011
9
FF
10
RESET
Seg. Oset Data 0000 3011 FF _ MDE8086 Kit V9.5 Midas 935-0964/5
Data zz _
The cursor has moved to the offset field and is blinking. Use the data keys (0 to F) to set the value of the offset. The 20-bit address, 03010 (0000:3010) is entered. Now, deposit the cacode data (B0h) for character ‘3’. The cursor has moved at the data field. Now, use data keys (0 to 9) to deposit the cacode, B0h at the indicated memory Location. The data value B0h is deposited at location, 0000:3010. Now, deposit cacode (FFh) for the ‘blank’ character at the memory location, 0000:3010. The next memory location is opened. Enter data, FFh at the indicated memory location using the data keys (0 to 9). To move to the previous memory location, use the ‘ – ‘ command. The CA-code for blank is entered at memory location: 03011 The trainer is ready to accept valid command
Table-B
Enter the Machine Codes of the following Program starting at location: 01000h (0000:1000) Label: START: L1:
Mem. Loc 0000:1000 – 0000:1001 -
Assembly Codes nop mov ax, 0000h mov ds, ax mov ax, 0000h mov ss, ax mov sp, 8FFEh
Machine Codes 90 B8 00 00 8E D8 B8 00 00 8E D0 BC FE 8F
L2:
0000:100E –
L2A:
0000:1015 -
0000:101D-
al, 80h CRU29(1Fh), al bx, 3000h al, BYTE PTR ds;[bx+10h] PARU29(19h), al cx, 0FFFFh HERE1
B0 80 E6 1F BB 00 30 8A 47 10 E6 19 B9 FF FF E2 FE
; bx-register to work as pointer ; reading cacode for ‘3’ ; sending cacode of ‘3’ to PAR ; Insert Time Delay
HERE1:
mov out mov mov out mov loop
L3:
0000:101F -
0000:1027 -
al, BYTE PTR ds:[bx+11h] PARU((19h), al cx, 0FFFFh HERE2
8A 47 11 E6 19 B9 FF FF E2 FE
; reading cacode for ‘blank’ ; sending cacode of ‘blank’ to PAR ; Insert Time Delay
HERE2:
mov out mov loop
L4:
0000:1029-
jmp
L2A
EA 15 10 00 00
; repeat the process
4.
Meaning ; 00000h = Base Add.of Data Seg. ; 00000h = Base Add of Stack Seg. ; Stack Pointer Reg. set to: 08FFEh ; Control Byte to set PAR as output
Carry out the steps of Table-C to execute the above program of Table-B. Table-C
Program Execution: Carry Out the following steps: Sn: 1
Press Key RESET
2
AD
3
:
4
GO
LCD Display MDE8086 Kit V9.5 Midas 935-0964/5 Seg. Ost Data xxxx yyyy zz Seg. Ost Data 0000 yyyy _ zz Statring Address 0000:1000
Remarks The trainer is ready The cursor blinks at the segment field. Use data keys to set the segment at: 0000h. The cursor blinks at the offset field. Use data key to set the address at : 1000h Program has been executed. Character ‘3’ should blink.
435
Task-1B.5
Familiarization with Internal Structure of CA 7-Segment Display Device a
ca
10 g
9 f
8 ca
7 a
6 b
f 10 e
g
d
7
b 6
c
2
e 1
d 2
ca 3
c 4
ca
4
p 5
p 5
g(10)
f(9) e(1) d(2) c(4) b(6) a(7)
538
538
(a) Physical View
p(5)
(b) Internal LED Structure
538
(c) Electrical Equivalent
Figure-1B.4: Structure of Common Anode Type 7-Segment Display Device
Task-1B.6 Enter appropriate data at the appropriate memory locations of DSM to blink character A on the CA7SD. Make CA-code for A looking at the diagram of Fig-1B.3.
Task-1B.7 Learning How to Get Machine Codes of Character Blinking of Task-1B.4 In this task, we will get familiar with the procedures of getting the machine codes for the character-blinking program of Table-B of Task-1B.4. We shall use MASM (Macro Assembler) program and the IBM-PC to obtain the machine codes for the assembly instructions of Table-B of Task-1B.4. The procedures are: (a)
Create a directory named as MDA8086 in the hard drive C. And now accommodate the following program files under this directory. These programs may easily be collected from the CD that has been supplied with the MDA-8086 trainer. If the directory already exists and contains these files then go to step-b Sno. 1 2 3 4 5 6
(b)
(c) (d)
File Name COMM.EXE LINK.EXE LOD186.EXE MASM.EXE EDIT.EXE EXER
Purpose Serial Monitor of the MDA-8086 Trainer To create relocatable *.EXE file from *.OBJ file To create ‘Absolute (*.ABS)’ file from *.obj file To create *.LST and *.OBJ files form *.ASM file To create Assembly Program (Source Code) for 80x86 MPUs A Working Directory
Boot the IBMPC in Windows 98/XP and then go to DOS path using the Start Menu. The monitor would show as: c:\windows>_ Bring the IBM-PC in the following DOS path: c:\mda8086>-The procedures: 1. Type cd.. and then press enter key 2. Type mda8086 and then press enter key. Type EDIT at the cursor position of the above DOS prompt. Press Enter key. As a result, a screen appears called DOS Screen will appear. Type only the labels and the assembly instructions of Table-B of Task-1B.4.
436
(e)
Save the screen (what you have typed in the screen) with the file name of: P1B.asm. Save the file as: c:\mda8086\P1B.asm The Procedures: 1. Press Alt key and then release. And then press Enter key.
(f)
2. Choose ‘Save As...’ from the menu using the arrow keys. 3. Now type the file name: P1B.asm and then press Enter key. Type the following lines (called Assembler Statements) at the top of your program. MYCODE
(g)
para public cs:MYCODE 1000h
‘code’
; declaring logical segment
Type the following assembler statements at the end of your assembly program. MYCODE
(h)
SEGMENT ASSUME ORG ENDS END
START
Update your file (P1B.asm) in the following ways: The Procedures: 1. Press Alt key and then release. And then press Enter key.
(i)
2. Choose ‘Save’ from the menu using the arrow keys. 3. Now press Enter key. Now leave the screen and come back to the DOS prompt in the following ways: The Procedures: 1. Press Alt key and then release. And then press Enter key.
(j) (k)
2. Choose ‘Exit’ from the menu using the arrow keys. 3. Now press Enter key. Type cls and press Enter key for clearing up the screen. Now, convert the source codes of your program c:\mda8086\P1B.asm into machine codes in the following ways: This is known as assembling. The Procedures: 1. Type MASM at the cursor position of the DOS prompt. Press Enter key. 2. Type P1B.asm (assembly) and press Enter key 3. Type P1B.obj (object) and then Press Enter key 4. Type P1B.lst (list) and press Enter key. 5. Press Enter key
(l)
(m)
You are back to the DOS prompt. Your assembly program has already been converted into machine codes and the codes have been saved in the path: c:\mda8086\P1B.lst. Show the error messages to the teacher if any. Remember that there should not be any error in the program. If there are errors, take help from the teacher to correct these errors and then and go to Step-k. After error free assembling go to Step-m. Open the P1B.lst file in the following ways to see its contents: The Procedures: 1. Type ‘EDIT’ at the DOS prompt. And then press Enter key.
(n) (o)
2. Press Alt key and then press Enter key. 3. Choose ‘Open...’ from the menu using the arrow keys. Press Enter key. 4. Use ‘tab’ key and ‘arrow’ key to choose the file, P1B.lst from the menu. Press Enter. 5. Now the machine codes of your program are in the screen. Look at the machine codes of your program on the screen. Compare these codes with the machine codes of Table-B of Task-1B.4. Write down the codes where they differ. Look for the jumper ‘P1’ (Fig-1B.5) or switch ‘KIT/PC’ of the MDA-8086 trainer. Bring the jumper at the ‘Local Monitor’ or KIT position.
437
Jumper Position at: Serial Monitor
P1 GND
+5V
Jumper Position at: Local Monitor
538
Figure-1B.5: Jumper P1 is at Local Monitor Environment
(p) (q)
Power OFF and then ON of the MDA-8086 trainer and then press the RESET key. The LCD display of the trainer shows the following prompt message: MDE8086 Kit V9.5 Midas 335-0964/5
(r)
(s) (t) (u) (v)
Use keyboard of the trainer and enter the machine codes of Step-n in the CSM starting at memory location. 0000:1000. Take help of the lab teacher to know the ways of entering the differing codes in the CSM. For multi-byte data, the lower bytes should be entered first. Enter the data B0h (for character 3) at RAM location 0000:3010 and FFh (for Blank) at RAM location 0000:3011 of the data segment memory. Execute the program at location: 0000:1000 using the GO command. Observe that the device 3 is blinking on the CA7SD device. The Task-1B.7 is well done.
Task-1B.8 In this Task, we will learn how to transfer the machine codes of the Step-n of Task1B.7 from the IBMPC to the CSM of the MDA-8086 trainer. This method is known as Down Loading. To do it, we will be using the COM1 port of the IBMPC. This method saves a lot of time while developing a large program. We do not need to enter the data and codes manually in the memory locations. The procedures are: 1. Power down the MDA-8086 trainer. Bring P1 jumper (Switch) at the ‘Serial Monitor’/KIT position. Connect the serial cable of the trainer with the COM1 port of the IBMPC. 2. 3.
Bring the IBM-PC in the following DOS prompt: c:\mda8086> _ From the start icon of the IBMPC execute the WinComm and then goto Step-4 below. OR Type COMM at the cursor position and then press Enter key. A communication screen will appear. Press F5 function key and modify the screen as follows: Serial Port (1/2) Serial baud rate Set 1200 = 1 2400 = 2 4800 = 3 9600 = 4 19.2K = 5 38.4 = 6 Baud Rate Select (1 – 6) Parity bit NP =0, Po = 1, Pe = 2 Word Size 7-bit=2, 8-bit=3 Stop bit 1-bit=0, 2-bit=1 Change OK (Y/N) ? y
: [X]
==>1
press Enter key
: [X] : [X] : [X] : [X]
= = > 4 (always) ==>0 ==>3 ==>0
press Enter key press Enter key press Enter key press Enter key press Enter key
438
4.
Power down and Power up the MDA-8086 trainer. Press the RESET key of the trainer to get the prompt message on the screen of the IBMPC. * * 8086 Monitor 9.5 * * * * Midas 335-0964/5 * * 8086> _
5. 6. 7.
To bring the IBMPC into DOS mode, press Alt and hold and then press X key. And then press the Enter key. The IBM-PC in the path: c:\mda8086> _ Now, convert the P1B.obj (object) file into P1B.abs (absolute) file for onward transmission to the trainer. Type LOD186 at the cursor position of the DOS prompt. And then press Enter key. Answer as follows: (a) Type T1B.obj (b) (c)
Type c:\mda8086\P1B.abs press Enter key
The conversion is completed with the message LOAD COMPLETED and the PC comes to the following DOS path: c:\mda8086> _ The converted file is located at: c:\mda8086\P1B.abs.
8. 9.
Type EDIT at the cursor position of the DOS prompt. Open the file P1B.abs The screen shows multiple lines, which are very similar to the following line. This particular format is known as Intel-hex Format. For details, see Page-12/Expt1A). : 0A 1000 00 90 B8 80 E6 1F B0 B0 E6 19 F4 46
Starting address of storage
10. 11. 12. 13. 14. 15. 16 17 18
Exit the screen and come to the DOS prompt of: c:\mda8086> _ Type COMM at the DOS prompt and press the Enter key OR click on the WinComm. Reset the MDA-8086 trainer to activate Serial Link with IBMPC. Type L at the cursor position. Press Enter key. And then press F3 key. Type c:\mda8086\P1B.abs and then press Enter key. The program codes have already been transferred into the trainer with the message ‘OK Completed’. Bring the jumper P1 (Switch) of the trainer into Local Monitor/KIT position. Enter B0h (CA code for 3) at memory location 03010h (0000:3010) and FFh (CA code for Blank) at memory location 03011h (0000:3011) of the DSM. Execute at 0000:1000 using the GO command of the trainer. The device CA7SD must blink the character ‘3’
Task-1B.9 Find the location of the file ‘fnd.abs’ in your computer and bring it under the directory of c:\mda8086. Down load the codes of the fnd.abs file in the trainer. Execute the program in the trainer at: 0000:1000. Observe that the device CA7SD shows: 0,1,2,3,4,5,6,7,8,9,0,1,2............ Task-1B.10 (P110.asm) Write an 8086-based assembly language program to display the characters: 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F,0,1,2,3...... cyclically on the device CA7SD. Get your program codes down loaded from the PC to the trainer. The offset of the 1st code byte must be at: 2000h.
439
Task-1B.12 Introduction to MDA-8086 Trainer The MDA-8086 is a 16-bit microprocessor learning system using Intel’s 8086 architecture. The trainer has been designed, developed and built by the ‘MIDAS Engineering Co. of South Korea. The Address: Original Manufacturer:
ACE TechnoV, 906 19-7-22, Kuro-Gu, Seoul, South Korea. Fax: (02) 2109-5968. Web: www.midaseng.com.
Task-1B.13 Hardware Features of MDA-8086
A. Central Processing Unit Subsystem [see Fig-1.1] 1. 2. 3. 4.
8086 Microprocessor running in Minimum Mode Data Buffers for the data lines of the CPU Address Latches for the Multiplexed Address-Data Bus PAL-Based Composite Memory and Port Decoder
B. Memory Subsystem [see Fig-11.4] 1. 64 Kbytes of EPROM
2.
64 Kbytes of RAM
C: Interrupt Structure Subsystem [see Fig-1.1] 8259-Based 8-Channel Interrupt Priority Controller. It receives interrupt requests from the following devices and funnels them to the 8086. 1. IR0: From the Timer/Counter-1 of the 8253 (U41) 2. IR1: From the Timer/Counter-2 of the 8253 3. IR2: Hardware activation using onboard key: IR2 4. IR3: From Serial Communication Chip, U14 5. IR4-IR7: Available to user via ‘EXT CONNECTOR, SLOT’.
D: Input/Output Subsystem [see Fig-1.1] 1. Keyboard: 2. Display: 3. Parallel IO:
4. Serial IO: 5. ADC:
6. DAC:
7. Speaker:
Discrete IC-Based Keypad containing 24 Keys LCD-Based Display containing 16x2 Characters a: Onboard 8255 (U29), which is interfaced with the following onboard IO devices: i. FND (Common Anode Type 7-segment Display Device) ii. LED Assembly (LED11 – LED14) iii. Stepper Motor Driving Circuitry iv. Digital-to-Analog Converter (U33), which feds analog signal to either of: * Onboard Level Meter (U38, U39) * Onboard Analog-to-Digital Converter (U31) b: Onboard 8255 (U30), which is interfaced with the following onboard IO devices: 8x8 Bi-color Dot Matrix LED Assembly (DOT1) 8251-Based (U14) Serial Communication Scheme, which communicates with the IBMPC using RS-232 (U15) Link at a fixed Bd (Baud Rate) of: 9600 bps. ADC0804-Based Analog-to-Digital Converter. It takes analog signal either from: a. Onboard Potentio Meter (VR2) b. Onboard Thermostat (TH1) c. Onboard DAC (U33, U36) d. Onboard Microphone DAC0800 being driven by Port-C of the 8255 (U29). It feds analog signal either to: * Onboard Level Meter (U38, U39) * Onboard Analog-to-Digital Converter (U31) Externally installable Output device via socket ‘SPK’. The speaker is interfaced to the 8086 via (U25, TR4) at an port address: 11h and data line: D8.
440
Task-1B.14 Software Features of MDA-8086 A: Resident Monitor Program 1. 2. 3. 4. 5.
Allows data entry, edit into RAM locations [Word operations are not available] Allows Program Execution Allows data entry, edit into Registers locations Allows Debugging a Faulty Program (Single Stepping) Does not contain any data conversion algorithms like: BCD-to-Binary, Binary-to-BCD, Multiplication, Division, BCD-to-ASCII
B: Serial Monitor Program Allows downloading program/data codes from the IMB-PC to the MDA-8086
C: Example Programs A disk accompanying the trainer contains a good number of example programs.
Taks-1B.15 Memory Space and Port Space Organization of MDA-8086
Reserved 4x 2KByres
0D000 0CFFF
Reserved 4x 4KByres
07000 06000
05000 04FFF 03000 02FFF
01000 00FFF 00F00 00EFF 00400 003FF 00000
FFFE
(00)26 (00)24 (00)22 (00)20
Space for Stack Segment Space for Extra Segment Space for Data Segment
IO CON10 IO CON10 IO CON10 IO CON10 ADC : DR/CR OR 8255 (U30):CR ADC : DR/CR OR 8255 (U30):PCR ADC : DR/CR OR 8255 (U30):PBR ADC : DR/CR OR 8255 (U30):PAR
(00)1F
8255 (U29): CR
(00)1E
(00)1D
8255 (U29): PCR
(00)1C
(00)1B
8255 (U29): PBR
(00)1A
(00)19
8255 (U29) PAR
(00)18
(00)11 (00)0F (00)0D (00)0B (00)09
SPEAKER: DR 8253: CR 8253: TC-2 8252: TC-1 8253: TC-0
(00)12 (00)10
8259: DR 8259: CR
(00)0A (00)08
8251: CR/SR 8251 : DR
KBD DR/FR
(00)04 (00)02 (00)00
LCDDR LCDSR LCDIR
RAM
09000 08000
FFFF
Useable after Decoding
User-3
10000 0FFFF
User-2
F0000 EFFFF
Start Up Location
User-1
FFFF:0000
ROM
FFFFF
Space for Code Segment Scratch Pad Data Structure Interrupt Vvector Table 545
(00)05 (00)03 (00)01
Figure-1B.6: Memory Space of MDA-8086
545
Figure-1B.7: Port Space Map of MDA-8086
441
Task-1B.16 Component Layout of MDA-8086
442
Figure-1B.8: Component Layout Diagram of the MDA-8086 System
Task-1.17 Schematics of the MDA-8086 Learning System
443
444
445
446
447
448
Experiment – 2
Familiarization with Assembly Instructions of 8086 Microprocessors by Adding Two 8-bit Unsigned Hexadecimal Numbers Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-2.1 Theory When two 8-bit unsigned numbers are added, there may be a generation of carry, which is automatically stored into the C-bit (Carry Bit) of the flag register of the 8086. For example: addition of the numbers FFh and 10h produces the result ‘1 0Fh’. The upper part of the result is ‘Single Bit’, which is accommodated by the C-bit and the lower part ( 8-bit) of the result is in the al-register. Task-2.2 Data Structure A data structure clearly indicates the storage locations (memory locations or register locations) of the input data (input numbers) and the output data (result). A detailed and cleaned data structure helps a lot for writing error-free assembly instructions for the solution of a problem. The data structure for our present addition problem is given below in Fig-2.1. Here, we have assumed that: i. ii. iii.
The input numbers can have the range: 00h - FFh The 1st number (data1) is available via memory location 03010h and the 2nd number is available via memory location 03011h. The Lower part of the result in memory location 04000h and the Upper part (accumulated carries) of the result is in location 04001h. Expanded Data Segment Memory(DSM)
FFFFF = F000:FFFF Memory Location
Content
Table
seg:off (20-Bit) 04FFF = 0000:4FFF
Output 04001 = 0000:4001 04000 = 0000:4000 03FFF = 0000:3FFF
03012 = 0000:3012 03011 = 0000:3011 03010 = 0000:3010
Rubyte = 01 Rlbyte = 18
Data2=F7 Data1= 21
Inputs
03001 = 0000:3001 03000 =0000:3000 00000 = 0000:0000
608
Figure-2.1 : Memory Based Data Structure for Adding Two Unsigned Hexadecimal Numbers
1/Expt-2
Task-2.3
Pseudo Code for Addition
START:
nop
L1:
Initialize based address of DSM Initialize initial value for the bx-pointer to point locations in DSM 0000h → dsr 3000h → bx
L2:
Read data1 (say 21h) from the memory location 03010h of DSM Read data2 (say F7h) from the memory location 03011h of DSM al ← (03010h) ah ← (03011h)
L3:
Add the two numbers that have read from external memory locations al + ah → c, al ; result is C-bit and al-register
L4:
If (C-bit = LH) Gto L7 and save result as 01XX in locations 04000h and 04001h.
L5:
C-bit = LL, Save result as 00XX in locations 04000h and 04001h. al → 04000h ; lower 8-bit of result 00h → 04001h ; the C-bit as 00h
L6:
Halt
L7:
al → 04000h 01h → 04001h Goto L6
Task-2.4
Flow Chart for Adding Two Unsigned Numbers
; lower 8-bit of result ; the C-bit as 01h
10:GM:10-08 START:
Entry
L1: Initialize: Based Addr of DSM Pointer Register L2: (03010) --> al (03011) --> ah L3: al + ah --> c, al L4:
L5:
Y
Carry = 1 ? N
L 7: al ---- > 04000h 01 –Æ 04001h
al --- > 04000h 00 –Æ 04001h L6: Halt
Figure-2.2: Flow Chart for Adding Two 8-bit Numbers
2/Expt-2
Task-2.5
Write 8086 Assembly Codes for the Pseudo Codes of Task-2.3
MYCODE
SEGMENT ASSUME cs:MYCODE ORG 1000h
START:
nop
L1:
mov mov mov
ax, 0000h ds, ax bx, 3000h
L2:
mov mov
al, BYTE PTR ds:{bx+10h} ah, BYTE PTR ds:{bx+11h]
; data1 is read ; data2 is read
L3:
add
al, ah
; result in : c, al
L4:
jc
L7
; jump to L7 if carri bit = LH
L5:
mov mov
BYTE PTR ds:[bx+0100h], al BYTE PTR ds:[bx+0101h], 00h
; lower 8-bit of result ; no carry; so 00h is saved
L6:
hlt
L7:
mov mov jmp
BYTE PTR ds:[bx+0100h}, al BYTE PTR ds:[bx+0101h], 01h L6
; lower 8-bit of result ; there is carry; so save 01h
MYCODE
ENDS END
START
Task-2.6
; dsr cannot be directly loaded
Assembling, Downloading, Executing and Seeing Results for Codes of Task-2.5
1.
Open DOS screen in the path MTK8086 (or MDA8086) and type the assembly codes of Task-2.5.
2.
Save the source codes as: P2.asm
3.
Exit the DOS screen.
4.
Assemble the program P2.asm to create the following files: i. P2.obj ii. P2.lst
5.
After error free assembly, open the text file P2.lst file and get familiar with what it contains. The list (lst) file allows us to find the sources of errors when the file P2.asm is not correctly assembled.
6.
Close the P2.lst file.
7.
Create P2.abs file by processing the P2.obj file with the help of LOD186.
8.
Open the text file P2.abs to get familiar with its format. You will get familiar with the structure of this file in Chapter-7. The P2.abs file contains the binary codes of the file P2.obj along with some other information. The P2.abs file is the only text (ASCII) format that can be transmitted form the IBMPC to the RAM of the trainer using the COM1 port of the IBMPC.
9.
Download the P2.abs file from the IBMPC to the trainer starting at RAM location 0000:1000. For downloading procedures, see Experiment-1A for Microtalk-8086 and Experiment-1B for MDA-8086.
10.
After downloading, enter the input data1 and data2 into the specified memory locations of the DSM of Fig-2.1. See relevant steps of Experiment-1A or 1B to open memory locations and enter the data.
11.
Execute the downloaded program.
12
Open the output memory locations of the DSM to see the result.
Task-2.7 Validity Check of Program P2.asm Check that the program P2.asm provides correct results for the following pair of input numbers: i. FFh and FFh ii. CDh and 25h iii. 00h and 00h iv. 01h and 00h
3/Expt-2
Task-2.8 Adding Three 8-bit Unsigned Numbers 578bc Entry
START: L1:
(03010) --> al (03011) --> ah (03012h) --> dl L2: al + ah --> c, al L3: Y
Carry = 1 ? L3A:
L8:
01h ----> 04001h
N 00h ---> 04001h
L4 : al + dl ---> c , al L5:
L5A:
Y
Carry = 1 ? N
L 9:
01h+(04001h)--->04001h
00h+(04001h) --> 04001h L6: al --- > 04000h L7: Halt
Figure-2.3: Flow Chart for Adding Three 8-bit Numbers Procedures: 1. Draw memory based data structure for the input/output data of the Flow Chart of Fig-2.3. 2.
Convert the Flow Chart of Fig2.3 into Pseudo Codes.
3.
Convert the Flow Chart of Fig2.3 into 8086 assembly codes. And save as P2B.asm
4.
Assemble the P2B.asm to get P2B.obj, P2B.lst files.
5.
Process P2B.obj file to get P2B.abs file.
6.
Download P2B.abs file into the trainer.
7.
Enter three 8-biitnumbers into the specified input memory locations of the DSM
8.
Execute the program at the address specified by the ORG directive in the P2B.asm program.
9.
Open the output memory locations of the DSM and check that they contain correct result for the given input numbers.
4/Expt-2
Experiment – 3 Familiarization with Assembly Instructions of 8086 Microprocessors by Multiplying Two 8-bit Unsigned Hex Numbers by Repetitive Additions Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-3.1 Theory In unsigned number system, all bits of a given binary number carry positive positional values. In signed number system, the MS-bit of the given number bears negative positional values and all other bits carry positive positional values. In 80x86 architectures, the negative numbers are represented using 2’s compliment form and follows different ways while performing multiplication process on unsigned and signed numbers. In this experiment, we will be focusing on the multiplication of unsigned binary numbers. The two 8-bit unsigned numbers data1 and data2 could be multiplied together in two ways, which are: i.
Using the mul instruction of the 8086 like: mov al, data1 mov bl, data2 mul bl
ii. By Repetitive Addition Process (RAP) like: Multiplier (MLPR) = data1 Multiplicand (MPLC) = data2 Product = add MLPC with initial partial result (IPR = 00h) cumulatively for as many times as the MLPR is.
We intend to practice RAP method for multiplication in order to get familiar with the basic instructions that the MPU carry out to multiply numbers. In practical application, while dealing with large numbers (For example: computing Cost from Product Rate and Weight in Chapter-7), we will be using the mul instruction. Expanded Data Segment Memory(DSM)
Task-3.2 Data Structure Let us assume that we have the following two numbers to multiply. i. ii. iii.
FFFFF = F000:FFFF
Memory Location
The MLPR (range: 00h – FFh The MPLC (range: 00h – FFh) The Product (range: 0000h – FE01h). The upper part of the result, is in fact, the accumulation of the carry bits that had been generated during addition process.
Table
Output 04001 = 0000:4001 04000 = 0000:4000 03FFF = 0000: 3FFF
03012 = 0000:3012 03011 = 0000:3011 03010 = 0000:3010
00000 = 0000:0000
1/Expt-2
Content
(20-Bit) seg:off 04FFF = 0000: 4FFF
Rubyte Rlbyte
MLPC MLPR
Inputs
12
Task-3.3
Pseudo Code for Addition
START: L1:
L2:
nop Initialize based address of DSM Initialize initial value for the bx-pointer to point locations in DSM 0000h → dsr 3000h → bx Read MLPR and keep in al-register Read MLPC and save in ah-register al ← (03010h) ; al = MLPR ah ← (03011h) ; ah = MLPC cl ← 00h (IPR = 00) 00h → ch (Ccounter)
L3: L4:
cl + MLPC → C, cl if (Carry = 1) Goto L9
L5:
MLPR- 01h → MLPR
L6:
if (MLPR !=0) Goto L3
L7:
Result Lower Byte (Rlbyte) → 04000h Result Upper Byte (Rubyte) → 04001h halt
L8:
; multiplication process begins on RPA method.
L9:
Ccounter + 01h → Ccounter Goto L5
Task-3.4 Task-3.5
Draw Flow Chart for the above Pseudo Codes and show it to the teacher. Write 8086 assembly codes in your Lab Khata for the above pseudo codes and show to the teacher. Carry out the following steps:
Task-3.6
a. b. c. d. e.
Save the assembly codes as P3.asm with ORG at 2500h. Assemble P3.asm to get P3.obj and P3.lst files. Process p3.obj file to get p3.abs file. Download P3.abs file into the RAM of the trainer. Enter the MLPR and MLPC into the specified memory location of the DSM using the keyboard of the trainer. f. Execute the downloaded program. g. Open the output memory locations and check that they contain correct result for the given numbers. h. Check the validity of the program P3.asm by giving different numbers for the MLPR and MLPC.
Task-3.7
Check that the execution of the following codes (P3B.asm) provide the same result as has been provided by the program P3.asm. L1: L2: L3: L4:
mov mov mul mov hlt
bx, 3000h ax, WORD PTR [bx+10h] ah WORD PTR [bx+0400h]
2/Expt-2
; reading MLPR and MLPC ; result
3/Expt-2
Experiment – 4 Familiarization with the Procedures of Programming the 8255 PIO Controller Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-3.1 Get Familiar with the 40-pins of the 8255 See Fig-4.3 (a) of this book.
Task-3.2 Get Familiar with the Bus-structured Diagram of 8255 PIO Controller See Fig-4.3 (b) of this book.
If you are using MicroTalk-8086 trainer, then performs the Tasks-3.3 to 3.6. If you are using MDA-8086 trainer, then start from Task-3.7. Task-3.3 Programming the 8255 (U23) of MicroTalk-8086 for Data IO Operations The following 8086-8255-LED based interface circuit of Fig-4.1 has been taken from the User Technical Reference Manual of MicroTalk-8086 trainer. With the help of this circuit, we will get familiar with the architectures and programming of the 8255 controller for data IO operations. GM:672: 08/04 PCR: 3604h PC7 – PC0 (J7)
A
A
D7- D0
D
RD/ WR/ M -IO/
PB0 R/ W/ IO/ PAR: 3600h
LED8
PA7
LED7
PBR: 3602h PB7
CS/
CR 3606h
8086: U2
PA0
LED15
LED0
8255: U23
Figure-4.1: 8255-based Interfacing Circuit for Experiments using MicroTalk-8086 Trainer
Task-3.4 Adding Two Numbers and Show Result in Bit Form on LED15 – LED0 1. Open the addition program of Experiment-2 and save it as P4.asm 2. Put the following Pseudo/ASM codes at Label L6 in order to send the result on the LEDs of 8255. L6: Set the direction of the IO lines of variable ports PAR and PBR as output. Consult Section-4.2 (a) of his book for the required Cbyte. mov dx, 3606h mov al, 92h ; PAR, PBR as output; PCR as input out dx, al
1/Expt-2
L7: L8:
L9:
Read result from the DSM of experiment-2. mov cx, BYTE PTR [bx+0100h] Send the lower byte of into PAR Send the upper byte of result into PAB mov al, cl mov dx, PAR out dx, al mov al, ch mov dx, PBR out dx, al hlt
3. Assemble the program P4.asm and then download the P4.abs file. 4. Enter 45h and FCh as input numbers via the memory locations of the DSM of Experiment-2. 5. Execute the program and check that the LEDs show correct result. 6. Check the functionality of the program giving various sets of input numbers.
Task-3.5 Blinking only LED0 for 10 Times Convert the following Text Codes into 8086 ASM codes and save as: P4B.asm. Execute the program and check that the LED0 blinks for 10 times. 1. Set Direction of PAR as output by sending appropriate Cbyte into CR 2. Set a Counter for 10 counts corresponding to 10 times blinking. 3. Ignite LED0 by sending LH to PA0 Insert Time by calling the following subroutine.: TDEL: mov cx, 0FFFFh ADEC: loop ADEC ; again decrement ret 4. Extinguish LED0 by sending LL to PA0 Insert time delay by calling the subroutine TDEL:
; Time Delay
5. Decrement Counter if (Counter !=0) goto Step-3 6. End
Task-3.6 Detect a Particular Bit (PC0 for LH) via PCR and then Blink PA0 for 10 Times 1. Use a telephone hook up wire and connect PC0 at LL. 2. Open file P4B.asm and save as P4C.asm 3. Declare all the codes of P4C.asm as a subroutine named BLED0. 4. Configure PCR as input. 5. Read PCR 6. If (PC0 != LH) Goto Step-5 7. Blink LED0 for 10 times by calling subroutine BLED0.
2/Expt-2
Task-3.7 8255 Programming using MDA-8086 Trainer The following 8086-8255-CA7SDD interface circuit of Fig-4.2 has been taken and redrawn from the MDA-8086 manual. 8086 : U1
8255 : U29
P3/P4
PAR (19h)
AD15 AD14 AD13 AD12 AD11 AD10 AD09 AD08
39 02 03 04 05 06 07 08
27 28 29 30 31 32 33 34
D7 D6 D5 D4 D3 D2 D1 D0
RD/ WR/
32 29
05 36
RD/ WR/
A .M-IO/
06
CS/
A2 A1
08 09
A1 A0
RST
35
RST
+5V 0V
26 07
Vcc GND
PA0 PA1 PA2 PA3 PA4 PA5 PA6 PA7
04 03 02 01 40 39 38 37
02 03 04 05 06 07 08 09
PBR(1Bh)
CA7SDD 8x330R
R26-R33
07 06 04 02 01 09 10 05
a b c d e f g p
a f b g e
c
p
d CA 08
PCR (1Dh)
CR (1Fh) +5V 538
Figure-4.2: 8255-based Interfacing Circuit for Experiments using MDA-8086 Trainer
Task-3.8 Blink Character 5 for Seven Times on the CA7SDD Device MYCODE
SEGMENT ASSUME cs:MYCODE ORG 1000h
START:
nop
L1:
Set direction of fixed port PAR as output. Consult Section-4.2 (a) of this book for Control Byte. mov al, 80h Out CR, al mov ah, 07h ; Counter for 7 time blink
L2:
mov out call
al, CA5 PAR, al TDEL
; declare CA5 (Common Anode Code of 5) by EQU
L3:
mov out call
al, CAB PAR, al TDEL
; CAB is equal to CA-code of Blank = FFh
L4:
dec jnz
ah L2
; Insert time delay to see the character
3/Expt-2
L5:
TDEL: ADEC:
MYCODE
mov mov mov jmp mov loop ret
bx, 0400h ; blinking done; now going to prompt WORD PTR [bx], 0000h WORD PTR [bx+02h], 0F000h DWORD PTR [bx] ; control transfers at F000:0000= F0000h cx, 0FFFFh ADEC
ENDS END
START
Task-3.9 Draw Flow Chart for the ASM Codes of Section-3.8 and show it to the teacher. Task-3.10
Ignite the LED, G00 of the following interface circuit of Fig-4.3.
[About Dot Matrix LED] Let us have a look on the component side of the MDA-8086 trainer and we find that there is an 8-by-8 ‘Dot Matrix LED (DOTLED)’. Each dot of the device contains two separate common cathode type ‘Light Emitting Diodes’ of RED and GREEN colors. This two-diode structure has been depicted in Fig-42.1. Thus there are in total 64 LEDs. These diodes are connected across rows and columns in such a way so that a user program can access a single LED. GM:624: 04/04
Col7 Col0 10 PC7
14 PC 0
12
22
1C h PA: 18h PB7 PA7
A
A
D7-D0
D
RD/ WR/ M-IO/
R/ W/ IO/ PB: 1Ah
25 37
R ow7
R70 G70
R77 G77
R00 G00
R07 G07
CS/
CR 1Eh
8086: U1
PB0 PA0
18 4
R ow0
8255: U30
DOTLED
Figure-4.3: Interconnecting Diagram of 8086, 8255 and the DOTLED
Solution: L1: Set directions of the IO lines of Port-A, B and C as outputs [Cbyte (80h) → CR (1Eh)] L2: All columns are OFF except Coolumn-0 [ 01h → Port-C] L3: All port lines of Port-A, B are at LH except PA0 [ FFh → Port-B; FEh → Port-A] L4: Done
4/Expt-2
5/Expt-2
Ahsanullah University of Science and Technology (AUST) Dhaka-1212: Bangladesh Recommended Course Outline 8086 Microprocessor, Interfacing and System Design Faculty: Golam Mostafa, B.Sc.Engg (EE-BUET), M.Sc.Engg (CSE-BUET), PTrng (UK, USA), EX-BCIC, GEC and Schlumberger, Assoc Prof. AUST Week
Lecture
Topics
Quiz
1–4
1 – 12 (12)
Chapter - 1: Fundamental Concepts (a) Basic Tasks of a MPU and Building Blocks of a MPU-based System; (b) RAM Structure, Data Read from a RAM Location, Development of Pseudo Code and Assembly Code to accomplish Data Read/Write Operation with Memory Locations. (c) Use of Data Structure, Pseudo Code, Flow Chart and ASM (assembly) Instructions to Program 8086 for: (i) Adding two 8-bit Hexadecimal Numbers, (ii) for Multiplying two 8-bit Hexadecimal Numbers by Repetitive Additions; (d) Data Read/Write Operations with Fixed and Variable Ports. Chapter - 2: Architecture (a) Physical Pin Diagram, Pin Classification, Bus-structured Diagram. (b) Internal Register Set, Function of Flag Register. (c) Memory Organization showing ODD/EVN Banks, Truth table of RD/, WR/, M-IO/, BHHE/, A0. Chapter – 3: Instruction Set (a) Definitions and Classifications of Instructions, Addressing Modes. (b) Various Format of JMP and CALL Instructions. Chapter – 4: IO Controller Programming (a) Parallel IO Programming using 8255, LCD Display System and Programming. (b) Keyboard and CC7SDD Programming using 8279, Serial IO Programming using 8251 Chapter – 4: Interrupt Structure (a) Meaning of Interrupting the CPU, Events that occur during Interrupt, Interrupt Pins of 8086, IPD (b) Conditions to be satisfied before Interrupt, Use of ITC code to Know Beginning Address of ISR. (c) Use of SSM and SP to save/retrieve Exit Data during Interrupt, RET and IRET Instructions. Chapter – 6: Data Conversion Algorithm (a) 2s-Complemet Code, BCD2BIN Conversion by (i) Counting Rule (ii) by Horner Rule. (b) BIN2BCD Conversion by (i) Counting Rule (ii) by Horner Rule. (c) Rules to Adjust Incorrect BCD, daa Instruction Chapter – 7: System Design (8086 Based Digital Weighing Machine: DWM) (a) Block Diagram of an 8086-based DWM, Weight Acquisition, Multiplexed ADC, Rate Acquisition (b) Cost Computation Flow Chart, 16-bit x 16-bit Multiplication Chapter – 8: Microcontroller (a) Definition of MCU, Physical Pin of 89S51, Block Diagram showing Internal Resources (b) Block Diagram of Port-mode, Mixed-mode and Bus-mode Operation (c) Instruction Set, Block Diagram of 8051-based (i) DWM (ii) RTC, (iii) CARMET , (iv) PENERMET
1
5
13 - 15 (3)
6
16 - 18 (3)
7- 8
19 - 24 (6)
9
25 - 27 (3)
10 - 11
28 - 33 (6)
12
34 - 36 (3)
13– 14
37 - 42 (6)
Text Book Reference Book Lab Book
Lab Works using MicroTalk-8086 and MDA-8086 Experiment – 1A, 1B Experiment – 2 Experiment - 3 Selected Exercises from Ch-1
1
Experiments: Same as Above Selected Exercises from Ch-2
1
Experiments: Same as Above Selected Exercises from Ch-3
1
Experiment – 4 Experiment – 5A Selected Exercises from Ch-4 Experiment – 6A, 6B Selected Exercises from Ch-5
1
1
Experiment – 7 Experiment – 8, 9 Selected Exercises from Ch-8
1
Experiment - 10A, 10B Selected Exercises from Ch-7
1
Experiment – 10A Experiment – 10B Selected Exercises from Ch-8
: 8086/Microprocessor/Interfacing and System Design/using MicroTalk-8086 MPU Learning/Dev. System/ By: Golam Mostafa : Microprocessors/Interfacing/ By: Douglas V. Hall: McGraw-Hill Book Company : 8086 Microprocessor/Laboratory Experiments Manual/ using MicroTalk-8086 and MDA-8086 Trainers/ : By: Golam Mostafa
Experiment – 5A Familiarization with the Procedures of Interfacing the Text Mode LCD Panel with MicroTalk-8086 Trainer Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-5A.1 Familiarization with the Architecture and Working Principles of Text LCD Panel See Section-4.4 (a) of this book. Task-5A.2 Familiarization with the Instruction Set of 2-Line LCD Panel See Section-4.4 (c) of this book. Task-5A.3 Familiarization with the Connection of LCD Panel with MicroTalk-8086 Trainer A LCD panel can be interfaced with the 8086 buses using the existing hardware of the MicroTalk8086 trainer. The connection diagram is shown below in Fig-5A.1. The base address for the registers of the LCD is taken from the decoded SEP2/-pin of the MicroTalk-8086 trainer. The SEP2/-pin assumes LL-state for any 16-bit even port address that is chosen from the band 3E00h – 3FFEh and is asserted on the 8086 bus. 2x16 Charracter LCD
MicroTalk -8086
+5V 0V 0V RD/ WR/
16
+5
A2 A1 0V +5V 0V
SEP2/: 3E00h -
Vss L+ L-
T o See at Dark
AD7 AD6 AD5 AD4 AD3 AD2 AD1 AD0
Vdd
15
VA
1
D-I/
2
R-W /
3
6
D0
14 13 12 11 10 9 8 7
E
4
DP1F
5
DPF
DP10
D7 D6 D5 D4 D3 D2 D1
DP0
R1:1k5
Viewing Angle 0V
6 5 4 3 2 1
Y2/ Y1/ Y0/
13 14 15
U1: 74LS138
2 1
3
U2: 7486
722ab
Figure-5A.1: Connection Diagram between 2-Line LCD panel and 8086 Buses
1/Expt-5A
Operational Truth Table-1: Function
8086 Instruction
Write into Instruction Register: LCDIR (3E00h) Read from Status Register: LCDSR (3E04h) Write into Data Register: LCDDR (3E02h)
out LCDIR, al in al, LCDSR out LCDDR, al
WR/ 0 1 0
Signal Activities RD/ E A2 1 1 0 0 1 1 1 1 0
A1 0 0 1
From the above operational truth table, we can easily verify that the addresses assigned to the registers are indeed correct! When the address bits A2A1 = 00, the Instruction Register (because D-I/=LL) is selected for write (because R-W/=LL) operation. The decoder has been designed in such way so that the E-pin of the LCD assumes LH-state while the 8086 asserts LL signal on its WR/-pin during the execution of the out LCDIR, al instruction. Similarly, when the address bits A2A1=10, the Status Register is selected for read (because R-W/ = LH) operation. For address bits A2A1=01, the LCDDR register is selected for write operation. Task-5A.4
Display Character A at DP0 Position of Top Line of the LCD
Convert the following Text Codes into ASM code. Save the program as P5A4.asm. Assemble the program, download it and execute it. Check that the LCD shows the desired character.
i. Clear Display by sending: call TDEL Cbyte1 (01h) into LCDIR ii. Entry Mode Set by sending: call TDEL Cbyte2 (04h) into LCDIR: iii. Display ON/OFF Control by sending call TDEL Cbyte3 (0Ch) into LCDIR. vi. Cursor Shift Mode by sending: call TDEL Cbyte4 (18h) into LCDIR. v. Function Set by sending: call TDEL Cbyte5 (38h) into LCDIR vi. Sending Character A to LCD call TDEL Dbyte (41h for A) into LCDDR. TDEL: KJ:
mov loop ret
cx, 00FFh KJ
2/Expt-5A
Task-5A.5
Show the following Message on the Center of the LCD Panel ***Chittagong***
Assemble the following program (P5A5.asm), download it and then execute. The LCD should show the message. Before sending any data to LCD, we must insert some fixed time delay by calling the BUSY subroutine. The Time Delay is required to allow the LCD for digesting the last data byte written into it. MYCODE
SEGMENT ASSUME cs:MYCODE ORG 1000h
LCDIR LCDSR LCDDR
EQU EQU EQU
START:
nop
L1:
call
LCDINIT
L2:
call mov mov out
BUSY al, 82h ; cursor position at DP2 of Line-0 dx, LCDIR dx, al
L3:
mov mov
si, OFFSET MSG ; knowing how far the message Chittagong is! bx, 0000h ; pointing the 1st character (C) of the message
L3A:
mov cmp jz call mov mov out inc jmp
ah, BYTE PTR [si+bx] ah, 00h ; to check if printing of the message is done L4 ; message printing done BUSY al, ah dx, LCDDR dx, al bx ; pointing at the next character L3A ; collect and print the next character
L4:
mov mov mov jmp
bx, 0474h WORD PTR [bx], 0000h WORD PTR [bx+02h], 0F000h DWORD PTR [bx] ; the trainer goes to the prompt: 8086 CPU
MSG
DB
'***Chittagong***', 00h
BUSY: KJ:
mov loop ret
cx, 00FFh KJ
3E00h 3E04h 3E02h
LCDINIT: ; ; ; ; ; MYCODE
Send send send send send
ENDS END
Cbyte1 Cbyte2 Cbyte3 Cbyte4 Cbyte5
(01h) (04h) (0Ch) (18h) (38h)
into into into into into
LCDIR LCDIR LCDIR LCDIR LCDIR
START
3/Expt-5A
Task-5A.6
Instruction Set of LCD
4/Expt-5A
Experiment – 5B Familiarization with the Procedures of Programming the Text Mode LCD Panel using MDA-8086 Trainer Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-5B.1 Familiarization with the Architecture and Working Principles of Text LCD Panel See Section-4.4 (a) of this book. Task-5B.2 Familiarization with the Instruction Set of 2-Line LCD Panel See Section-4.4 (c) of this book. Task-5B.3 Familiarization with the Connection of 8086-LCD of MDA-8086 Trainer The following 8086-LCD interface circuit of Fig-5B.1 has been taken and redrawn from the MDA8086 manual. 540
8086 : U1
16x2 LCD DP10DP0
AD07 AD06 AD05 AD04 AD03 AD02 AD01 AD00 R D/ WR/
09 10 11 12 13 14 15 16
14 13 12 11 10 9 8 7
32 29 A M -IO/
Decoder
A2 A1 +5V Viewing Angle
VA1 10k 0V
D7 D6 D5 D4 D3 D2 D1 D0
6
E
4 5
D-I/ R -W /
2
Vdd
3
VL
1
Vss
DP1F
DPF
Figure-5B.1: Bus Structured Connection Diagram between 8086-LCD of MDA-8086 Trainer
[Operational Truth Table-1] Function Write into Instruction Register: LCDIR (00h) Read from Status Register: LCDSR (02h) Write into Data Register: LCDDR (04h) Read from DDR/CGR Register: LCDCR (06h)
8085 Instruction out LCDIR, al in al, LCDSR out LCDDR, al in al, LCDCR
1/Expt-2
WR/ 0 1 0 1
Signal Activities RD/ E A2 1 1 0 0 1 0 1 1 1 0 1 1
A1 0 1 0 1
Task-5B.4
Display Character A at DP0 Position of Top Line of the LCD
Convert the following Text Codes into ASM code. Save the program as P5B4.asm. Assemble the program, download it and execute it. Check that the LCD shows the desired character. 1.
Initialize the LCD Panel by the codes of Section-4.4 (d) of this book.
2.
Set the cursor position at DP0 of Top Line by sending Cbyte-7 [see Instruction Set at Section-4.4 (c)].
3.
Collect ASCII code of A from Section-4.4 (e) of this book and send it into LCDDR.
5.
The character A should appear on the LCD.
Task-5B.5
Show the following Message on the Center of the LCD Panel ***Ahsanullah*** ***University***
Convert the following pseudo codes into ASM codes and save as P5B5.asm. Assemble the program, download it and then execute. The LCD should show the message. Before sending data to LCD call TDEL. MYCODE
START: L1: L2: L3:
L4: L5:
L6: L7: L8: L9:
SEGMENT ASSUME cs:MYCODE ORG 1000h nop Initialize the LCD Set the Cursor Position at DP0 of Top Line Get the OFFSET of the MSG1 (***Ahsanullah***) into bx-register Get the displacement of the characters if MSG1 into si-register. mov bx, OFFSET MSG1 mov si, 0000h ; displacement of the 1st character of MSG1 st Collect the ASCII code of 1 character from MSG1 and send it to LCD mov dl, BYTE PTR cs:[bx+si] ; MSG1 is in the current Code Segment Check that the character so read is not the end-of-MSG1 character cmp al, 00h jz L6 ; end-of-MSG1 character call BUSY ; to see that LCD is ready mov al, dl mov LCDDR, al inc si ; ready to read next character of MSG1 jmp L4 Set the Cursor Position at DP0 of Bottom Line mov bx, OFFSET MSG2 mov si, 0000h ; displacement of the 1st character of MSG1 st Collect the ASCII code of 1 character from MSG2 and send it to LCD mov dl, BYTE PTR cs:[bx+si] ; MSG1 is in the current Code Segment cmp al, 00h jz L10 ; end-of-MSG2 character call BUSY ; to see that LCD is ready mov al, dl mov LCDDR, al inc jmp hlt
si L7
MSG1 MSG2 TDEL: ADEC:
DB DB mov lopp ret
‘***Ahsanullah***’, ‘***University***’, cx, 00FFh ; ADEC ;
MYCODE
ENDS END
L10:
; ready to read next character of MSG1
00h ; 00h marks the end of MSG1 00h fixed time delay given to LCD to digest the last character written inti it.
START
2/Expt-2
3/Expt-2
Experiment – 6A Familiarization with the Functionality Check Of the NMI-interrupt of 8086 using MicroTalk-8086 Trainer Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-6A.1 Get familiar with the following circuit, which will be used for functional check of the NMIinterrupt of the 8086 microprocessor. U2 : 8086
U23: 8255
31 INTA/ +5V
K2
+5V
K1
18
PBR:3602h CS/
INTR
17 NMI
B
LED15… ...LED8 8
B
R2
R1
PAR:3600h 8 CR:3606h 0V MPU
PIO
LED7…...LED0
1406x : GM: 1/2008
Figure-6A.1: Circuit for Functionality Check of NMI-interrupt
Task-6A.2 1. Write ASM code for the following Main Line Program (MLP). Save it as: mlpnmi.asm 2. Download it into the code area starting at 01000h of the MicroTalk-8086 and test it. MLP = To blink LED15-LED8 of Fig-6A.1 continuously. START1: ML1: ML2: ML3: ML4: TDEL1:
nop Cbyte → CR ; to set direction of PBR, PAR as output Ignite LED15-LED0 Insert Time Delay by calling the SUT TDEL1 Extinguish LED15-LED8 Insert Time Delay by calling TDEL1 Goto ML1 ; repeat the cycle load cx-register with FFFFh Keep decrementing until cx = 0 Return from SUR
Task-6A.3 1. Reset the trainer. 2. Write ASM codes for the following ISRNMI (Interrupt Subroutine due to NMI Interrupt). Save it as: isrnmi.asm
1/Expt-6A
3. Download it starting into the code area of MicroTalk-8086 starting at 02000h. ISRNMI = To blink LED0 only for 7 times. START2: ISR1: ISR2: ISR3: ISR4: ; ISR5: TDEL2: AGND2:
nop set direction of PAR and PBR by sending Cbyte into CR Mov ah, 07h ; counter of 7 LH → LED0 Call TDEL2 LL → LED0 Call TDEL2 dec ah Jnz ISR2 iret ; return from interrupt subroutine hlt mov cx, 0FFFFh Loop AGND2 ; again decrement ret
Task-6A.4 1. Reset the trainer002E q 2. Write the following ASM lines at the top of the MLP under the label START1. These ASM codes establish the link between the ISRNMI address and the ITC code of NMI-interrupt. mov bx, 0000h mov WORD PTR [bx+08h], 2000h ; Offset part of the ISRNMI address mov WORD PTR [bx+0Ah], 0000h ; Segment part of the ISRNMI address 3. Reassemble the MLP. Down load the corresponding absolute file into MicroTalk-8086. Task-6A.5 1. Reset the trainer. 2. Insert the following ASM lines at the top of the ISRNMI under the label START2. These lines will reset the ‘Interrupting Device’. The interrupting device generates the IRQ-signal for NMI-interrupt (Taks-6A.6). mov dx, 0000h in al, dx 3.
Remove the comment directive (;) from the label ISR5 and keep the hlt instruction under comment.
3.
Reassemble ISRNMI and download it.
Task-6A.6 1. Execute the MLP at 01000h by using the DOP key of the trainer. 2. Observe that the LED15-LED0 is blinking. 3. Take a telephone hookup wire (Jumper Wire) and insert its one end at J6-3 (KIRQ-pin). Insert the 2nd end at J2-19 (NMI-pin). This wire will carry short pulse as an interrupt signal at the NMI-pin of the 8086. The pulse will be generated when a key is pressed down on the key pad of the trainer. 4. Gently hit a key on the keyboard of the trainer. Notice that LED15-LED8 is not blinking. 5. Observe that LED0 blinks for 7 times. 6. Observe that the MLP has resumed after a while. 7. Repeat the process by pressing any key on the keyboard of the trainer.
2/Expt-6A
3/Expt-6A
Experiment – 6B Familiarization with the Functionality Check Of the NMI-interrupt of 8086 using MDA-8086 Trainer Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-6A.1 Get familiar with the following circuit, which will be used for functional check of the NMIinterrupt of the 8086 microprocessor. 8086 : U1
+5V
NMI MON Key
CA7SD
8255 : U29
AD15 AD14 AD13 AD12 AD11 AD10 AD09 AD08
39 02 03 04 05 06 07 08
27 28 29 30 31 32 33 34
D7 D6 D5 D4 D3 D2 D1 D0
RD/ WR/
32 29
05 36
RD/ WR/
A.M-IO/
06
CS/
A2 A1
08 09
A1 A0
RST
35
RST
+5V 0V
26 07
Vcc GND
PAR (19h) PA0 PA1 PA2 PA3 PA4 PA5 PA6 PA7
04 03 02 01 40 39 38 37
8x330R
02 03 04 05 06 07 08 09
PBR(1Bh) PB0
R26-R33 LED11
07 06 04 02 01 09 10 05
a
a b c d e f g p
f
g
e
b c
p
d CA 08
0V
CR (1Fh) +5V
538
Figure-6B.1: Circuit for Functionality Check of NMI-interrupt
Task-6A.2 1. Write ASM code for the following Main Line Program (MLP). Save it as: mlpnmi.asm 2. Download it into the code area starting at 01000h of the MDA-8086 and test it. MLP = To blink character 3 on the CA7SD device of Fig-6B.1 continuously. START1: ML1: ML2: ML3: ML4: TDEL1:
nop Cbyte → CR ; to set direction of PBR, PAR as output CA_3 → CA7SD Insert Time Delay by calling the SUT TDEL1 Send CA_Blank → CA7SD Insert Time Delay by calling TDEL1 Goto ML2 ; repeat the cycle load cx-register with FFFFh Keep decrementing until cx = 0 Return from SUR
1/Expt-6B
Task-6A.3 1. Reset the trainer. 2. Write ASM codes for the following ISRNMI (Interrupt Subroutine due to NMI Interrupt). Save it as: isrnmi.asm 3. Download it starting into the code area of MDA-8086 starting at 02000h. ISRNMI = To blink LED11 only for 7 times. START2: ISR1: ISR2: ISR3: ISR4: ; ISR5: TDEL2: AGND2:
nop set direction of PAR and PBR by sending Cbyte into CR Mov ah, 07h ; counter of 7 LH → LED11 Call TDEL2 LL → LED11 Call TDEL2 dec ah Jnz ISR2 iret ; return from interrupt subroutine hlt mov cx, 0FFFFh Loop AGND2 ; again decrement ret
Task-6A.4 1. Reset the trainer. 2. Write the following ASM lines at the top of the MLP under the label START1. These ASM codes establish the link between the ISRNMI address and the ITC code of NMI-interrupt. mov bx, 0000h mov WORD PTR [bx+08h], 2000h ; Offset part of the ISRNMI address mov WORD PTR [bx+0Ah], 0000h ; Segment part of the ISRNMI address 3. Reassemble the MLP. Down load the corresponding absolute file into MDA-8086 trainer. Task-6A.5 1. Reset the trainer. 2.
Remove the comment directive (;) from the label ISR5 and keep the hlt instruction under comment.
3.
Reassemble ISRNMI and download it.
Task-6A.6 1. Execute the MLP at 01000h (0000:1000) by using the GO key of the trainer. 2. Observe that the character 3 is blinking. 3. Gently press the MON-key of the trainer. This key applies a LH-signal on the NMI-pin of the 8086 (see Fig-6B.a). The pulse will be generated when a key is pressed down on the key pad of the trainer. 4. Observe that the character 3 is not blinking. 5. Observe that LED11 blinks for 7 times. 6. Observe that the MLP has resumed after a while. If not, then multiple interrupts have occurred due to de-bouncing of the MON-key. 7. Repeat the process by pressing any key on the keyboard of the trainer.
2/Expt-6B
3/Expt-6B
Experiment – 7 Converting BCD Number into Equivalent Binary Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-7.1 Converting Two-digit BCD number (range: 00 – 99) into equivalent BINary number (range: 00h – 63h) using Counting Method (Slow Process). 1. Draw Input/Out Data Structure. Keep Input BCD at location 03010h and the Output Binary at location 04010h. 2. Convert the following conversion Pseudo Codes into 8086 ASM codes and save as: bcd2binc.asm. MYCODE
START: L1:
L2:
L3: L4: MYCODE
3. 4. 5. 6. 7. 8.
9.
SEGMENT ASSUME cs:MYCODE ORG 1000h nop Bring BCD into ah-register Extract UPF Mov al, 00h ; IPR1 = 00h While (UPF !=0) IPR1 + UPW → IPR1 Bring BCD into ah-register Extrcat TPF Mov cl, 00h ; IPR2 = 00h While (TPF !=0) IPR2 + TPW → IPR2 Binary = (IPR1 + IPR2) → 04010h halt ENDS
Assemble and down load the absolute program. Enter the input BCD number as: 23 at location 03010h Execute the program. Open memory location 04010h and we must see 17. Enter different values for the BCD and check that the program produces correct Binary. If your are using the MicroTalk-8086 trainer, then insert additional codes at label L4 to see only the data part of the following on the CC7SD as follows (download bcd2bin7.abs): Input BCD at: DP0DP1 Output Binary at: DP6DP7 If you are using MDA-8086 trainer, then insert ASM codes at label L4 to see the following message on the LCD panel as follows (download bcd2binl.abs): Input BCD: DPE DPF positions of Line-1 Output BCD: DPE DPF positions of Line-2
1/Expt-7
Task-7.2 Converting 4-digit BCD number (range: (0000 – 9999) into equivalent BINary number (range: 0000h – 270Fh) using Horner Method (Fast Process). 1.
2.
3. 3.
Review the following Horner Rule foe conversion. BCD = d3d2d1d0 = d3x103 + d2 x 102 + d1 x 101 + d0 x100 = (((d3)10 + d2) 10 + d1 ) 10 + d0 BIN = (((d3)0Ah + d2) 0Ah + d1 ) 0Ah + d0 = (((IPBIN x 0Ah + d3)0Ah + d2) 0Ah + d1 ) 0Ah + d0 where: IPBIN = Initial Partial Binary = 0000h Computation Philosophy a. Extract d3 and compute: (IPBIN x 0Ah + d3) → IPBIN b. Carry out Step-a, for all the digits of the input BCD number. Draw DSM-based Data Structure for the Input/Output numbers. Draw the following Register-based Data Structure for the Input/Output Numbers. bh
bl
dh
bx = BCD
dl dx = IPBIN
538
4.
Convert the following Pseudo Codes into ASM codes. Save as: bcd2binh.asm. Download and execute it. The DSM locations: 04011h and 04010h would contain the Binary number. L1: L2:
L3:
0000h → dx (IPBIN) mov bh, BYTE PTR [di+11h] ; getting the input BCD from DSM ; Extrcat d3 mov cl, 04h shr bh, cl call BINC ; Binary Computation mov bh, BYTE PTR [di+11h] and bh, 0Fh ; getting d2 call BINC
L4: mov mov shr call L5: mov And call L6: mov
bh, BYTE PTR [di+10h] cl, 04h bh, cl ; getting d1 BINC bh, BYTE PTR [di+10h] bh, 0Fh ; getting d0 BINC WORD PTR [di+1010h], dx ; BINary number at: 04011, 04010
BINC: mov mul mov add ret
ax, 000Ah dx dl, bh dx, ax
; result at: dx, ax = 00, ax
2/Expt-7
Familiarization with the Architecture and Working Principles of Text LCD Panel See Section-4.4 (a) of this book. Task-5A.2 Familiarization with the Instruction Set of 2-Line LCD Panel See Section-4.4 (c) of this book. Task-5A.3 Familiarization with the Connection of LCD Panel with MicroTalk-8086 Trainer A LCD panel can be interfaced with the 8086 buses using the existing hardware of the MicroTalk8086 trainer. The connection diagram is shown below in Fig-5A.1. The base address for the registers of the LCD is taken from the decoded SEP2/-pin of the MicroTalk-8086 trainer. The SEP2/-pin assumes LL-state for any 16-bit even port address that is chosen from the band 3E00h – 3FFEh and is asserted on the 8086 bus.
3/Expt-7
Figure-5A.1: Connection Diagram between 2-Line LCD panel and 8086 Buses
Operational Truth Table-1: Function
8086 Instruction
Write into Instruction Register: LCDIR (3E00h) Read from Status Register: LCDSR (3E04h) Write into Data Register: LCDDR (3E02h)
out LCDIR, al in al, LCDSR out LCDDR, al
WR/ 0 1 0
Signal Activities RD/ E A2 1 1 0 0 1 1 1 1 0
A1 0 0 1
From the above operational truth table, we can easily verify that the addresses assigned to the registers are indeed correct! When the address bits A2A1 = 00, the Instruction Register (because D-I/=LL) is selected for write (because R-W/=LL) operation. The decoder has been designed in such way so that the E-pin of the LCD assumes LH-state while the 8086 asserts LL signal on its WR/-pin during the execution of the out LCDIR, al instruction. Similarly, when the address bits A2A1=10, the Status Register is selected for read (because R-W/ = LH) operation. For address bits A2A1=01, the LCDDR register is selected for write operation. Task-5A.4
Display Character A at DP0 Position of Top Line of the LCD
Convert the following Text Codes into ASM code. Save the program as P5A4.asm. Assemble the program, download it and execute it. Check that the LCD shows the desired character.
i.
Clear Display by sending: call TDEL Cbyte1 (01h) into LCDIR ii. Entry Mode Set by sending: call TDEL Cbyte2 (04h) into LCDIR: iii. Display ON/OFF Control by sending call TDEL Cbyte3 (0Ch) into LCDIR. vi. Cursor Shift Mode by sending: call TDEL Cbyte4 (18h) into LCDIR. v. Function Set by sending: call TDEL Cbyte5 (38h) into LCDIR vi.
Sending Character A to LCD call TDEL Dbyte (41h for A) into LCDDR.
TDEL:
mov
cx, 00FFh
4/Expt-7
KJ:
loop
KJ ret
Task-5A.5
Show the following Message on the Center of the LCD Panel ***Chittagong***
Assemble the following program (P5A5.asm), download it and then execute. The LCD should show the message. Before sending any data to LCD, we must insert some fixed time delay by calling the BUSY subroutine. The Time Delay is required to allow the LCD for digesting the last data byte written into it. MYCODE
SEGMENT ASSUME cs:MYCODE ORG 1000h
LCDIR LCDSR LCDDR
EQU EQU EQU
START:
nop
L1:
call
LCDINIT
L2:
call mov mov out
BUSY al, 82h dx, LCDIR dx, al
L3:
mov mov
si, OFFSET MSG bx, 0000h
L3A:
mov cmp jz call mov mov out inc jmp
ah, BYTE PTR [si+bx] ah, 00h ; to check if printing of the message is done L4 ; message printing done BUSY al, ah dx, LCDDR dx, al bx ; pointing at the next character L3A ; collect and print the next character
L4:
mov mov mov jmp
bx, 0474h WORD PTR [bx], 0000h WORD PTR [bx+02h], 0F000h DWORD PTR [bx] ; the trainer goes to the prompt: 8086 CPU
MSG
DB
'***Chittagong***', 00h
BUSY: KJ:
mov loop
cx, 00FFh KJ
3E00h 3E04h 3E02h
; cursor position at DP2 of Line-0
; knowing how far the message Chittagong is! ; pointing the 1st character (C) of the message
ret LCDINIT: ; Send Cbyte1 (01h) into LCDIR ; send Cbyte2 (04h) into LCDIR ; send Cbyte3 (0Ch) into LCDIR
5/Expt-7
; send Cbyte4 (18h) into LCDIR ; send Cbyte5 (38h) into LCDIR MYCODE
ENDS END
Task-5A.6
START
Instruction Set of LCD
6/Expt-7
Experiment – 1A
Familiarization with Components Organization and the Operating Procedures of the MicroTalk-8086 Microprocessor Learning/Dev. System Read Every Step of a Task and then Work accordingly. Whenever, a Step is Done, put Tick Mark (√ ) on that Step using a Wood Pencil. Ask Teacher for Help when necessary. Task-1.1 Familiarization with Components Layout In this task you will be locating and getting familiar with the following functional units of the MicroTalk-8086 trainer. These units are considered as the building blocks of a microprocessor based system. The MicroTalk-8086s is an 8086 microprocessor learning system, which has been designed, developed and built in Bangladesh by the author. i. 8086 Microprocessor ii. RAM (Random Access Read and Write Memory) iii. EPROM (Ultraviolet Erasable and Electrically Programmable Random Access Read Only Memory) iv. Input Device (The Keyboard) v. Keyboard Interface Controller vi. Output Device (CC7SD = Common Cathode 7-Segment Display Device) vii. Output Device Interface Controllers viii. Primary Memory Decoder ix. Primary Port Decoder
Procedures: 1. Collect the MicroTalk- 8086 trainer from the lab attendant. 2. Open the top cover of the trainer. 3. Look at the PCB (Printed Circuit Board) of the trainer for component layout (Task-1.13). 4. Now, on the PCB, locate the circuit designation U2. This is the 8086 microprocessor chip. 5. Look very carefully on the top of the U2-chip and you will find the inscription ‘8086’. 6. Locate the keyboard on the trainer. The keyboard interface controller is the chip, U24 (8279). 7. Locate the following output devices on the PCB of the trainer. a. The LED15-LRD8, LED7-LED0. The interface controller of the LCD devices is U23 (8255). b. The 7-segment display device, which has the circuit designation, DP0-DP15. These are of common cathode type display devices. Let us agree to call it by the symbolic name CC7SD. The interface controller for these devices is U24 (8279). c. The 8x8 Bicolor dot matrix LED, DOT1. The interface controller is the chip U30 (8255). 8. Locate the RAM chips U11, U12 on the PCB. Bit capacity of each RAM is: 32x1024x8 (32Kbyte) 9. Locate the EPROM chips U9 and U10 on the PCB. These chips contain the Monitor Program of the MicroTalk-8086 trainer. Bit capacity of each EPROM is: 32x1024x8.
1/Expt-1
Task-1.2
Familiarization with the Hardware Block Diagram of MicroTalk-8086
There are many more interface controllers on the PCB of the MicroTalk--8086, which we could not describe in Task-1.1. The following Hardware Block Diagram of Fig-1.1 contains the total IO scenario of the trainer. Complete schematics are attached at the end of this experiment. J6
J10
IR2-IR7
J5
RxRS
TxRS
RxT
TxT
609:GM:03-04
J8
GT CK OT
16 LEDs 4xPh
8x8 LED MAT
RS TTL U18, U19 6.144 MHz
U29 CKG CK
SMI
J7
J6
Display 22h-27h
RST RDY
1000-1FFE CS/
U4, U5 DBUFF DEN/ DT-R/
(20h)IR0 (21h)IR1
RxRDY TxE 2000-2FFE CS/
ADC
U14 IPC
ADC
3000-31FE CS/
ADC
U17 USART
PA PB PC
PA PB PC
3600-37FE
3800-39FE
CS/
ADC
ADC
U23 LED PIO
U13 PIT
A D C
EN/ DIR
CS/
U30 DM PIO
D15-D0 AD
A
C
U6,U7,U8 ALATCH C
M-IO/ A BHE/
CS/-User CS/-U14 CS/-U17 CS/-U13 CS/-U23 CS/-U30 CS/-U24 CS/-U10 CS/-U09 CS/-U12 CS/-U11 CS/-U15 CS/-U16
U1, U3 MEMPORT DECODER
A D C
CK
Data Field
DP0 DP2 DP4 DP1 DP3
DP6 DP8 DP5 DP7
DP9 DPB DPA
DPC DPE DP DPF D
UD
D
ALE
Addr Field
4 to 16 Decoder SL
3 to 8 Decoder
U1 MPU
(3)
J1
DLD
F D E DOP EXA FRW
WAIT
A B C AUT BKW CHG
F3
7 8 9 EXW EXB FLR
0000 - 0FFE CS/
Row
F4
4 CS
5 PC
6 FB
F5
1 IP
2 AX
3 Al
RST CS/
ADC 3400h
CS/
ADC 3200h
U16 DAC
U15 ADC
AnOut
AnIn
J5
J5
CS/
ADC
CS/
ADC
CS/
ADC
CS/
ADC
00001h 0FFFFh
00000h 0FFFEh
F0001h FFFFFh
F0000h FFFFEh
U11 RAMODD (32K)
U12 RAMEVN (32K)
U9 ROMODD (32K)
U10 ROMEVN (32K)
608
U24 KBDC
Figure-1.1: Hardware Block Diagram of McroTalk-8086 Trainer
2/Expt-1
0 BKS RST PRT S/S Keyboard
Task-1.3
Getting Familiar with Keyboard Layout of MicroTalk-8086 Trainer
Study the following template for the keyboard of the MicroTalk-8086 trainer. Also, give a quick glance on the descriptions that relate to the functions of these keys.
DNLD
D E F DOP EXA FRW
F2
B C A AUT BKW CHG
F3
7 8 EXW EXB
9 FLR
F4
4 CS
5 PC
6 FB
F5
1 IP
2 AX
3 AL
RST
0 BKS RST PRT S/S 608
Figure-1.2: Keyboard Layout of MicroTalk-8086 System
The 24 keys of the keypad may be classified into the following categories: A: 1.
CPU Control Key RST (System ReSeT) : When this key is pressed down and then released, the 8086 are reset and starts from the cold state. The PC looks for the ‘Opcode’ of a valid instruction at memory location: FFFF (CS):0000 (IP) = FFFF0h. Activation of the RST key displays the following message on the 7-segment CC-type display device (CC7SD).:
8086 CPU B: 1.
Command Keys EXA (Memory EXAmination): Command to open the 20-bit address of a memory location.
2.
AUT (AUTo Increment): Command to enter data into memory locations on auto incrementing the address field.
3.
DOP (DO a Program): Commanding the CPU to execute a program.
4.
DNLD (DowN LoaD): Command the CPU to automatically initialize the ‘ROM-Based’ serial link routine prior to down loading the program code/data from the IBM-PC.
3/Expt-1
5.
PC (Program Counter): Command to enter the starting address of the 1st instruction of user program, which is to be single stepped. Also, this key works as a ‘home key’ to bring the display showing the address of the instruction to be single stepped.
6.
EXB (Examine Byte data): Command to examine/edit the content of one memory location.
7.
EXW (Examine Word): Command to examine/edit the contents of two consecutive memory locations.
8.
FRW (FoRWard): Command to examine the contents of the next memory locations or next Register or the next Port.
9.
BKW (BacKWard): Command to examine the contents of the previous memory locations or next Register or the next Port.
10.
CHG (ChanGe): Command to alter the contents of memory locations or Registers or Ports.
11.
PRT (PORT): Command to examine the content of a Port location (yet to be implemented)
12.
FLR (FLag Register): Command to examine the contents of the flag register in hex format.
13.
FB (Flag register in Bit form): Command to examine the contents of flag register in bit format.
14.
CS (Code Segment): Command to examine the content of the Code Segment Register. FRW key should be used to examine the contents of the DS, ES and SS registers.
15.
IP (Instruction Pointer): Command to examine the content of the Instruction Pointer Register. FRW key should be used to examine the contents of the DI, SI, SP and BP registers.
16.
AX (AX register): Command to examine the content of the AX register, FRW key should be used to examine the contents of the BX, CX, DX registers.
17.
AL (AL register): Command to examine the contents of the AL register. FRW key should be used to examine the contents of the AH, BL, BH, CL, CH, DL, DH registers.
18.
BKS (BacKSpace): Command to correct typing mistakes in the address and the data field. S/S (Single Step): Command the CPU to execute only one instruction during the single stepping mode.
19.
F2, F3, F4, F5 (Function Keys): Actions to be defined by the user.
C:
Data Keys Keys with labels: 0, 1,2,3,4,5,6,7,8,9,A, B,C,D,E,F are the hexadecimal data keys.
4/Expt-1
Task-1.4
Familiarization with the Operation of MicroTalk-8086 Trainer by Adding Two Numbers.
In this task, we will learn the operation of the MicroTalk-8086 trainer. The learning involves: 1.
2. 3. 4. 5.
Getting familiar with the ‘4’ memory segments, which the CPU uses during the execution of a program. These are: (a) Code Segment Memory (CSM), (b) Data Segment memory (DSM) (c) Extra Segment Memory (ESM) and (d) Stack Segment Memory (ESM). See Fig-1.3 (a) below. Getting familiar with the procedures of entering program code/data into memory (RAM) locations. Getting familiar with the procedures of executing a program, the code/data of which has already been stored into memory (RAM) locations. An example program will be taken to demonstrate the practice of the above steps. The program is: “Adding two 8-bit numbers and show the result on the ‘LED7 – LED0’ of the trainer.”
Procedures: 1. Assume that we have two numbers to add and these are: 2Ch and 47h. The expected result is: 73h (0111 0011). The input data must be kept in the ‘Data Segment Memory (DSM)’ of Fig-1.3 (b). 2. Let us use the keyboard of the trainer and deposit these two numbers into two memory locations of the ‘Data Segment Memory (DSM)’. The particulars of the DSM are: a. b. c.
The Base Address is: 00000h The Beginning Address of DSM is: 03000h The offset (how far) of the beginning address of DSM from the Base Address is: 3000hs.
ALl Four Memory Segments of User-1
Expanded Data Segment Memory(DSM) FFFFF = F 000:FFFF
(0 8F FF = 0000:8FFF)
SSM
Memory Location
Content
Table
(20-Bit) seg:off 04FFF = 0000:4FFF
(07000 = 0000:7000) (06000 = 0000:6000)
Output
ESM
04001 = 0000: 4001 04000 = 0000: 4000 03FFF = 0000:3FFF
(05000 = 0000:5000) (0 4F FF = 0000:4FFF)
Result = 73
Inputs
DSM
03012 = 0000: 3012 03011 = 0000: 3011 03010 = 0000: 3010
Data2=47 Data1= 2C
(03000 = 0000:3000) 02 FF F = 0000:2FFF)
CSM 01000 = 0000 : 1000)
Figure-1.3 (a): Four Memory Segments
Beginning Address
Base Addres
03001 = 0000: 3001 03000 =0000:3000 00000 = 0000: 0000
45
Figure-1.3 (b): The Enlarged View of the DSM of Fig-1,3 (a)
3. Power on the trainer and then press the RST key. The display should show: 8086 CPU 4. Use the keypad of the trainer and deposit the input data 21h and F7h at the indicated memory locations of the DSM of Fig-1.3 (b). The procedures of data entry are given in the next page. a. b.
Data1 (2Ch) will be kept at memory location: 03010h (0000:0310). Data2 (47h) will be kept at memory location: 03011h (0000:0311)
5/Expt-1
Table-A Procedures to Enter 21h and F7h into Memory Locations 03010h and 03011h Press Key 7Seg Display Remarks RST 8086 CPU Trainer is ready EXA - - - - - Ad Address Field is opened to accept 20-bit memory address 030 030 - - Ad Three digits are entered for the Address Field 5 0305 – Ad Next digit but ‘Wrong’ for the memory address. (Typing Error) BKS 030 - - Ad Typing error is corrected. 10 03010 Ad 20-bit address is entered. Now, the CPU is waiting to know if Byte or Word examine is requested EXB 03010 XX Display shows the 8-bit data of memory location: 03010h CHG 03010 - Data field is ready to accept new data 2C 03010 2C The data 2Ch has been stored in location: 03010h FRW 03011 XX Address field shows the content of the next memory location CHG 03011 - Data field is ready to accept new data 47 03011 47 Data 47h has been deposited at location: 03011h RST 8086 CPU Data entry done. The data are in the specified RAM locations.
Sn. 1 2 3 4 5 6 7 8 9 10 11 12 13
5. Now, we need a program, which will bring the input numbers from DSM into the internal registers of the 8086 for addition. The result will be shown on the LED7-LED0 of the trainer. The result will also be deposited at memory locations 04000h of the DSM. Let us assume that we have this program, which is listed below in Table-B. Label: START: L1:
Memory Location 01000 (0000:1001)
L2: L3: L4:
0100A 0100C 01010
L5:
01018
L6:
0101E
Table-B Assembly Instructions - nop - mov bx, 3000h mov al, BYTE PTR [bx+10h] mov ah, BYTE PTR [bx+11h] - add al, ah - mov BYTE PTR [bx+1000h], al - mov ah, al mov al, 80h mov dx, 3606h out dx, al - mov al, ah mov dx, 3600h out dx, al - hlt
Machine Codes - 90 - BB 00 30 8A 47 10 8A 67 11 02 C4 88 87 00 10 - 8A E0 B0 80 BA 06 36 EE - 8A C4 BA 00 36 EE - F4
Meaning ; must be here for the ; bx Register is a pointer ; 2Ch comes into CPU ; 44h comes into CPU ; data are added ; result is stored in DSM ; result is sent to LEDs
; CPU is halted
6. Now enter the machine codes of the above Table-B in the ‘Code Segment Memory (CSM)’ of Fig-1.4 of the next page. Note that: a. b.
c.
The 1st byte of our program is ‘90’ and it must be stored at memory location: 01000 (0000:1000). The 1st byte of an instruction is known as ‘Operation Code’ or ‘Opcode’. The next byte of our program is at label L2 and it is BB. The code will be stored in location 01001. The operand part of this instruction has the data 00 and 30 and they would be stored in locations 01002 and 01003 respectively. The next byte of our program is 8A it must be stored at memory location: 0000:1004. And so on….
6/Expt-1
d.
Follow the steps of Table-A to enter the Machine Codes of the program of Table-B into CSM part of memory. This time use the ‘AUT’ command to open the address field. In AUT mode, the data field will automatically be opened and the address field would also be advance automatically. Expanded Code Segment Memory(CSM) FFFFF = F000:FFFF Memory Location
Content
Table
(20-Bit) seg:off 02FFF = 0000:2FFF
01003 = 0000:1003 01002 = 0000:1002 01001 = 0000:1001 01000 = 0000:1000
Beginning Address of CSM
BB 90
30 00
Operand Opcode Opcode
00000 = 0000:0000
Base Addres
46
Figure-1.4: Code Segment Memory for the Program Codes of Table-B
7. Reset the trainer. Use the EXA and RRW commands to open the addresses starting at 01000h and check that the codes have been correctly entered into the specified memory locations. 8. Now is the turn to execute the program of Table-B, which we have already loaded into the CSM of Fig-1.4. Remember that the program execution will always begin from the starting location of the program. To execute the program follow the steps of Table-C.
Sn. 1 2
Press Key RST DOP
3
01000
Table-C Steps to be followed to Execute the Program of Table-B 7Seg Display Remarks 8086 CPU Trainer is ready - - - - - do Address Field is opened to accept the 20-bit starting address of the CSM (This is the beginning address of your program). run The program is executed.
9. It is hoped that the program of Table-B has been executed correctly. Let us look for the result: a. Look at the LED assembly of the trainer. The LED assembly should have the following ON/OFF conditions: [‘Black Fill’ means ‘LH’ and ‘No Fill’ means ‘LL’]. LED Assemly LED15
LED8
LED7
LED0 608
b. Reset the trainer. Open the memory location: 04000h of the DSM of Fig-1.3 (b). We will find a data value of 73h. To open a memory location, follow the steps of Table-A.
7/Expt-1
Task-1.5
Execute the program of Table-B for the following set of data. Check that the LEDs indicate the correct results and the memory location 04000h also contain the correct result. Data1 ABh 67h FF
Task-1.6
Data2 10h 89h FF
Expected Result BBh F0h 01FE
LED Status (LED7-LED0) 1011 1011 1111 0000 1111 1110
Memory Content (03012h) BBh F0h FE (01 is missing!)
Working Principles of Number Addition Program of Table-B
The diagram of Fig-1.5 depicts the ‘Signal Flow’ structure for the problem of adding two numbers 2Ch and 47h of Task-1.4. 610
043FF
CPU
73 47 2C
CR (3606h)
Result
al 03012 03011 03010
LEDPIO(U23) ah
ALU
D 03000
al
PA R (3600h)
DSM
LD7
LD0
D Result
Figure-1.5: Signal Flow Diagram of the Addition Problem of Task-1.4 Working Principles: The CPU brings the data1 (2Ch) into its al-register. It then brings data2 (47h) into its ah-register. The contents of the al and ah registers are added in the ALU of the 8086 CPU. The result (73h) is be shown in the output LEDs: LD7-LD0. In Fig-1A.1, we see that the LEDs are connected with the CPU via the interface controller LEDPIO (U23: 8255). Thus, we may say that the CPU sends the result from its alregister into the LEDPIO and from PIO the result automatically goes into the LEDs. The result is also saved at memory location: 03012h of the DSM.
Task-1.7
Getting Machine Codes
In this task, we will get familiar with the procedures of getting the machine codes for the number addition program of Table-B of Task-1.4. We shall use MASM (Macro Assembler) program and the IBM-PC to obtain the machine codes for the assembly instructions of Table-B of Task-1.4. The procedures are: (a) Check that the D drive of your computer contains the directory (Folder)) named as MTK8086 and then goto Step-b. If the directory doesn’t exit, then copy the folder MTK8086 from the MicroTalkCD into the D drive. The following files (Folders) are the essential components for learning 8086 Assembly Programming. Sno. 1 2 3 4 5 6
(b) (c)
File Name MTK86COM1 LINK.EXE LOD186.EXE MASM.EXE EDIT.EXE EXER
Purpose Serial Communication Interface for MicroTalk-8086 Trainer To create relocatable *.EXE file from *.OBJ file To create ‘Absolute (*.ABS)’ file from *.obj file To create *.LST and *.OBJ files form *.ASM file To create Assembly Program (Source Code) for 80x86 MPUs A Working Directory
Boot the IBM-PC in WIN98/WINXP and then click on the Command Prompt menu by following the path: Start → All Programs → Accessories → Command Prompt. Bring the IBM-PC in the following DOS path: d:\mtk8086>--
8/Expt-1
(c) (d) (e)
The procedures: 1. Type cd \ and then press enter key. The screen shows: c:>_ 2. Type d: and then press enter key. The screen shows: d:>_ 3. Type cd mtk8086 and then press enter key. The screen shows: d:\mtk8086>_ 4. Press Alt-key and then hit Enter-key to enlarge the screen. Type EDIT at the cursor position of the above DOS prompt. Press Enter key. As a result, a screen appears called DOS Screen will appear. Type only the labels and the assembly instructions of Table-B of Task-1.4. Save the screen (what you have typed in the screen) with the file name of: P14.asm. Save the file as: d:\mtk8086\P14.asm The Procedures: 1. Press Alt key and then release. And then press Enter key.
(f)
2. Choose ‘Save As...’ from the menu using the arrow keys. 3. Now type the file name: P14.asm and then press Enter key. Type the following 3 lines (called Assembler Statements) at the top of your program. MYCODE
(g)
cs: MYCODE 1000h
Type the following assembler statements at the end of your assembly program. MYCODE
(h)
SEGMENT ASSUME ORG ENDS END
START
Update your file (P14.asm) in the following ways: The Procedures: 1. Press Alt key and then release. And then press Enter key.
(i)
2. Choose ‘Save’ from the menu using the arrow keys. 3. Now press Enter key. Now leave the screen and come back to the DOS prompt in the following ways: The Procedures: 1. Press Alt key and then release. And then press Enter key.
(j) (k)
2. Choose ‘Exit’ from the menu using the arrow keys and then press Enter key. Type cls and press Enter key for clearing up the screen. Now, convert the source codes of your program d:\mtk8086\P14.asm into machine codes in the following ways: This is known as assembling. The Procedures: 1. Type MASM at the cursor position of the DOS prompt. Press Enter key. 2. Type P14.asm (assembly) and press Enter key 3. Type P14.obj (object) and then Press Enter key 4. Type P14.lst (list) and press Enter key. 5. Press Enter key
(l)
(m)
You are back to the DOS prompt. Your assembly program has already been converted into machine codes and has been saved in the path: d:\mtk8086\P14.lst. Show the error messages (if any) to the teacher. Remember that there should not be any error in the program. If there are errors, take help from teacher and correct these and go to Step-k. Open the P14.lst file in the following ways to see its contents: The Procedures: 1. Type ‘EDIT’ at the DOS prompt. And then press Enter key.
2. Press Alt key and then press Enter key. 3. Choose ‘Open...’ from the menu using the arrow keys. Press Enter key.
9/Expt-1
4. Use ‘tab’ key and ‘arrow’ key to choose the file, P14.lst from the menu. Press Enter. 5. Now the machine codes of your program are in the screen and they look like: MYCODE ASSUME
SEGMENT cs:MYCODE ORG 1000h
START:
nop
L1: L2:
mov mov mov add
bx, al, ah, al,
1000 1000
90
1001 1004 1007 100A
BB 8A 8A 02
100C
88 87 1000
L3:
mov
BYTE PTR [bx+1000h], al
1010 1012 1014 1017
8A E0 B0 80 BA 3606 EE
L4:
mov mov mov out
ah, al, dx, dx,
1018 101A 101D
8A C4 BA 3600 EE
L5:
mov mov out
al, ah dx, 3600h dx, al
101E
F4
L6:
hlt
MYCODE END
ENDS START
3000 47 10 67 11 C4
101F
(n) (o) (p)
3000h BYTE PTR [bx+10h] BYTE PTR [bx+11h] ah
al 80h 3606h al
Pick up the machine codes of your program from the screen. Compare these codes with the machine codes of Table-B of Task-1.4. Write down the codes where they differ. Power OFF and then ON of the MicroTalk-8086 trainer and then press the RST key. The 7-segmnet display of the trainer shows the following prompt message: 8086
(q)
(r) (s) (t) (u)
CPU
Use keyboard of the trainer and enter the machine codes of Step-n (P14.lst) in the CSM starting at memory location. 0000:1000. Take help of the lab teacher to know the ways of entering the differing codes in the CSM. Enter the data 2Ch at RAM location 0000:3010 and 47h at RAM location 0000:3011 of the data segment memory. Execute the program at location: 0000:1000 Observe that the LED7 – LED0 show the correct result of 73h (0111 0011). The Task-1.7 is well done.
Task-1.8
In this Task, we will transfer the machine codes of the Step-n of Task-1.7 from the IBM-PC to the CSM of the MicroTalk-8086 trainer. This method is known as Down Loading. To do it, we will be using the COM1 port of the IBM-PC. This method saves a lot of time while developing a large program. We do not need to enter the data and codes manually in the memory locations. The procedures are: 1. Power down the MicroTalk-8086 trainer. Connect the serial cable of the trainer with the COM1 port of the IBM-PC. 2. Bring the IBM-PC in WIN98/WINXP mode. 3. Check that the MTK86COM1 interface is present in the Start menu and then goto Step-4. Otherwise, install it from the MTK8086 folder. MTK86COM1 allows transferring Intel-Hex formatted file from IBMPC into the RAM space of MicroTalk-8086 trainer.
10/Expt-1
4. 5.
Power up the MicroTalk-8086 trainer. From the Start menu locate the MTK86COM1 interface and execute it. The following GUI interface will appear on the screen.
Figure-1A.6: GUI Interface to Download Program Codes from IBMPC to MicroTalk-8086
6. 7.
Go to the DOS path: d:\mtk8086 Now, convert the T14.obj (object) file into T14.abs (absolute) file for onward transmission to the trainer. Type LOD186 at the cursor position of the DOS prompt. And then press Enter key. Answer as follows: (a) Type T14.obj (b) Type d:\mtk8086\T14.abs (c) press Enter key The conversion is completed with the message LOAD COMPLETED and the PC comes to the following DOS path: d:\mtk8086> _ The converted file is located at: d:\mtk8086\T14.abs.
8. 9.
Type EDIT at the cursor position of the DOS prompt. Open the file T14.abs The screen shows the following lines known as Intel-Hex formatted frames. Each frame is composed of many fields and the fields have meanings, which are explained in Task-1.9. :1410000090BB00308A47108A671102C4888700108AE0B080FF :0B101400BA0636EE8AC4BA0036EEF4CD :0400000300001000E9 :00000001FF
10. 11. 12. 13 14 15
Exit the screen and come to the DOS prompt of: d:\mtk8086> _ Go to the MTK86COM1 interface and follow the menu to transfer the P14.abs file. Reset the MicroTalk--8086 trainer. Enter 2Ch and 47h at memory location 03010h and 03011h of the DSM. Execute at 0000:1000 using the DOP command of the trainer. The LED7-LED0 will show the result.
11/Expt-1
Task-1.9 Down load the file U248279.abs and then execute it at: 0000:1000. Observe that the CC7SD devices of the trainer shows: 0,1,2,3,4,5,6,7,8,9,A, B,C,D,E,F,0,1,2............
Taks-1.10 : 10 C100 (a) (b) (c)
Structure of an Intel-Hex Formatted Frame 00 003E9032002116101E110133C10ACD19 (d) (e)---------------------------->
D4 (f)
There are six fields in an Intel-Hex formatted frame as is shown above. The meanings of these fields are given below: (a) indicates that a new data frame to begin (b) indicates number of information bytes to transfer that is contained in (e). (c) indicates the starting location of RAM to store information bytes (d) indicates ‘Not the End of File’, when the value is 00 (e) indicates the actual information byte (In this example it is 16) (f) indicates checksum and is computes ad follows: all data bytes from and including (b) to (e) are added. The carry is discarded. Two's complement of the remaining 8-bit are taken as CHKSUM and is transmitted as the last filed of the frame. For more details, the readers are referred to MicroTalk-8086 User Technical Reference Manual CD for the following resources: 85serlink.asm. This is a ROM-based program of the MicroTalk-8085 trainer program and receives the Intel-Hex frames from the IBMPC. MTK86COM1 is the GUI program of the IBMPC and transmits the Intel-Hex frames. Working Principles of the Receiver Program of MicroTalk-8086 Trainer:
1.
The program receives data from the IBMPC character by character in ASCII format. This means that the data byte of caption (b) is received as 31H and 30H.
2.
The characters are received on software handshake basis. The trainer send an acknowledgment code (06H) after receiving each character, The IBMPC will send the next after getting the ACK code. If the ACK code is not available within the timeout time, the IBMPC will terminate the transmission session.
3.
The trainer receives the data of caption (b) and computes the following information: Total information bytes as contained in the caption (e) Total data bytes in the frame as contained in (b) to (f)
4.
The trainer keeps receiving all the data bytes in a frame. The ASCII codes of the received characters are shown at the DP0DP1 positions of the trainer. After receiving a frame, the trainer does the following: a. The ASCII codes of the frame are save in: 6080H – b. The ASCII codes are converted to HEX and saved in: 60C0H-. c. The CHKSUM is recomputed from the converted Hex and is compared with the received CHKSUM as contained in the caption (f) d. If the CHKSUM agrees, the trainer saves the Hex data stating at the address as contained in the caption (c). e. The trainer then sends the ACK code to the IBMPC. f. The cycle repeats with the reception and process of the next data frames.
12/Expt-1
Task-1.11 Introduction to MicroTalk-8086 Trainer The MicroTalk-8086 is a 16-bit ‘Microprocessor Learning/Development System’ based on Intel’s 8086 architecture. The trainer has been designed, developed and built in ‘Bangladesh’ by ‘Karighar Research and Development Center’ by a one-man team headed by ‘Golam Mostafa (the author)’ during the period: 1992 – 2004. The author greatly acknowledges the hard labor and the patience of ‘M. A. Sarker (author’s ex-student)’ for the preparation of the PCB under the OrcadEDA environment and the accumulation of the logistic support. The Address: Manufacturer:
Karighar Research and Development Center 2/801: Eastern Morshed Apartment, 16/1-2, Segun Bagicha Dhaka-1000, Bangladesh, Phone: 7161846, 01726-341559
Hardware Features:
A. Central Processing Unit Subsystem 1. 8086 Microprocessor running in Minimum Mode 2. ROM-based Composite Memories and Port Decoder
B. Memory Subsystem 1. 64 Kbytes of EPROM 2. 64 Kbytes of RAM
C: Interrupt Structure Subsystem 8259-Based 8-Channel Interrupt Priority Controller with Option for Cascading
D: Input/Output Subsystem 1. Keyboard:
2. 3.
4.
5. 6. 7. 8.
8279 Based Keypad containing 24 keys. It Supports: i. Data Lines, Scan Lines are available at Edge Connectors for further Interfacing ii. Unused Row/Col Lines of the Keyboard are at the Edges for adding extra keys Display: 7-Segment CC-type Display Unit containing 16 Digits Parallel IO: a: Onboard 8255PIO, which interfaces: i. 16 LED suitable for monitoring input/output data in Binary form ii. Driver Electronics for Phase Stepper Motor iii. The Port Lines are at the Edges Connectors for Data Input/Output b. Onboard 82535PIO, which drives an 8x8 Bi-color Dot Matrix Led Serial IO: 8251A-Based RS232 Serial Port. It is: i. Interfaced with IBM-PC by a DB9 connector. ii. Signals are available at the Edge Connector ADC: ADC0804-Based Analog-to-Digital Converter. DAC: AD558-Based Digital-to-Analog Converter. Timer: 8253-Based 3-Channel Programmable Timer/Counter. All 9 Signals are at the Edges. Prototyping: a. Edges (Edge Connectors. It supports). It supports: i. The availability of all the signals that may be required to design a system ii. Acceptance of Hookup Wiring for Circuit Experiments b. 5.5” x 2.5” Bread Board
Software Features: A: Resident Monitor Program 1. 2. 3. 4. 5. 6. 7.
Powerful and Comprehensive Resident Monitor Program Auto/Manual Data Entry for both Byte/Word Operations Program Execution Capability Forward/Backward/Change/Backspace Facilities Byte/Word Examine/Edit Capability Single Instruction Execution Capability for Program Debugging. Registers Contents can be Examined and Changed.
13/Expt-1
8. 9. 10. 11. 12.
Flag Register Contents can be Examined in Bit-form and Hex-form. ROM-Based Test Routine for all the Onboard Peripheral Controllers A good number of Ready Made Stand alone routines A good number of Subroutines to Facilitate System Design ROM-Based Data Conversion Algorithms like: i. BCD-to-Binary Conversion (BCD2BIN) ii. Binary-to-BCD Conversion (BIN2BCD) iii. Binary Multiplication BMULT) iv. Binary Division (BDIV) v. BCD-to-Common-cathode Code (BCD2CC) vi. CCcode-to-BCD Conversion (CC2BCD) vii. Scan Code-to-CCcode Conversion (SC2CC)
13. Complete Software that Converts the MicroTalk-8086 into a Digital Weighing Machine (DWM) 14. Serial Communication Link to down load Intel-Hex frames from IBMPC into the Trainer.
Taks-1.12 Memory Space and Port Space Organization of MicroTalk- 8086 Port Space Map
FFFFF
Reserved 4x 2KByres
Reserved 4x 4KByres
05000 04FFF
03000 02FFF 01000 00FFF
00F00 00EFF
00400 003FF
00000
ROM
Can be Used after Decoding
Decoded at SEP2 ( J1-5)
3E00 3DFE Decoded at SEP1 ( J1-6)
3C00 3BFE Decoded at SEP0 ( J1-7)
3A00 39FE
Shadow
3806 3804 3802 3800 37FE
CR of 8255: U30 PC of 8255: U30 PB of 8255:U30 PA of 8255:U30
3605 3604 3602 3600 35FE
CR of 8255: U23 PC of 8255: U23 PB of 8255:U23 PA of 8255:U23
3400 33FE
DR of DAC : U 16
3200 31FE
DR/CR :ADC:U15
Scratch Pad
3006 3004 3002 3000 2FFE
CR /SR: 8251: U13 C2 of 8251: U13 C1 of 8253: U13 C0 of 8253: U13
Data Structure
2002 2000 1FFE
CR of 8251: U17 DR of 8251: U17
1002 1000 0FFE
CR of 8259 : U 14 DR of 8259 : U 14
0002 0000
CR /SR: 8279: U24 DR of 8279: U24 607a
Space for Stack Segment Space for Extra Segment Space for Data Segment Space for Code Segment
RAM
07000 06000
4000 3FFE
Useable after Decoding
0D000 0CFFF
09000 08000
Can be Used after Decoding
User-3
10000 0FFFF
EVEN Port
FFFE
FFFF
User-2
F0000 EFFFF
Start Up Location
User-1
FFFF:0000
ODD Port
Interrupt Vvector Table 545
0001
Figure-1.6: Memory and Port Space Map of MicroTalk-8086
14/Expt-1
Shadow
Shadow Shadow Shadow
Shadow
Shadow
Shadow
Task-1.13 Component Layout of MicroTalk-8086
15/Expt-1
Figure-1.7: Component Layout Diagram of the MDA-8086 System
Task-1.14 Schematics of the MDA-8086 Learning System
16/Expt-1
Figure-1.8: CPU Subsystem
17/Expt-1
Figure-1.9: Composite Memory and Port Subsystem
18/Expt-1
Figure-110: Memory Subsystem Print:
P19_Expt1A.doc
DB[0:7]
U25 19 1 2OE 1OE
U24 D0 D1 D2 D3 D4 D5 D6 D7
12 13 14 15 16 17 18 19
A1
21
DB0 DB1 DB2 DB3 DB4 DB5 DB6 DB7 A0
24 QA3 25 QA2 26 QA1 27 QA0 28 QB3 29 QB2 30 QB1 31 QB0
DB7 DB6 DB5 DB4 DB3 DB3 DB2 DB2 DB1 DB1 DB0 DB0
DB7 DB6 DB5 DB4
17 15 13 11 8 6 4 2
A8 A7 A6 A5 A4 A3 A2 A1
74LS244 1 2 A 3 B VCC C
32 SL0 33 SL1 34 SL2 35 SL3
6 4 G1 5 G2A G2B
23 BD 4 IRQ
74LS138 3.072MHz PCLK 3 IORC/ RESET
AIOWC/ CS8279
37 10 9 36 11 22
KIRQ SL0 SL1 SL2 SL3
CLK CN/ST RD RESET SHFT WR CS
1 2 A 3 B C 6 4 G1 5 G2A G2B 74LS138
RL0 RL1 RL2 RL3 RL4 RL5 RL6 RL7
38
KR0
5 4 G2B 6 G2A VCC G1 3 2 C 1 B 74LS138 A
S[0:7]
Y0 Y1 Y2 Y3 Y4 Y5 Y6 Y7 Y0 Y1 Y2 Y3 Y4 Y5 Y6 Y7 Y7 Y6 Y5 Y4 Y3 Y2 Y1 Y0
3 5 7 9 12 14 16 18
S7 S6 S5 S4 S3 S2 S1 S0
S7 S6 S5 S4 S3 S2 S1 S0
p g f e d c b a
.
U27 15 cc0 14 cc1 13 cc2 12 cc3 11 cc4 10 cc5 9 cc6 7 cc7
S7 S6 S5 S4 S3 S2 S1 S0
6 1 2 4 5 7 9 10
p g f e d c b a
S7 S6 S5 S4 S3 S2 S1 S0
.
6 1 2 4 5 7 9 10
p g f e d c b a
cc1
cc0
S7 S6 S5 S4 S3 S2 S1 S0
6 1 2 4 5 7 9 10
p g f e d c b a
.
S7 S6 S5 S4 S3 S2 S1 S0
6 1 2 4 5 7 9 10
DP6
.
S7 S6 S5 S4 S3 S2 S1 S0
6 1 2 4 5 7 9 10
p g f e d c b a
.
S7 S6 S5 S4 S3 S2 S1 S0
6 1 2 4 5 7 9 10
p g f e d c b a
.
cc S7SEGCC
3 cc5
cc4
DP7
cc S7SEGCC
3
3
cc3
p g f e d c b a
cc S7SEGCC
cc S7SEGCC
3
6 1 2 4 5 7 9 10
p g f e d c b a
.
S7 S6 S5 S4 S3 S2 S1 S0
6 1 2 4 5 7 9 10
S7 S6 S5 S4 S3 S2 S1 S0
.
6 1 2 4 5 7 9 10
p g f e d c b a
cc8
K10
K11
K12
K13
DNLD K20
D/DOP E/EXA F/FRW K23 K21 K22
F2 K30
A/AUT K31
B/BKW K32
C/CHG K33
6 7/EXW
8/EXB
9/FLR
F3 K40
K41
K42
F4
4/CS
5/PC
6/FB
K50
K51
K52
K53
K43
8 KR7
K60
1/IP K61
2/AX
3/AL
K62
K63
BKS-S/S
RST2
0/PRT RST1
RES/
19/Expt-1
6 1 2 4 5 7 9 10
p g f e d c b a
.
3 cc7
cc6
6 1 2 4 5 7 9 10
p g f e d c b a
.
S7 S6 S5 S4 S3 S2 S1 S0
6 1 2 4 5 7 9 10
p g f e d c b a
.
6 1 2 4 5 7 9 10
p g f e d c b a
.
cc13
DP15 S7 S6 S5 S4 S3 S2 S1 S0
6 1 2 4 5 7 9 10
p g f e d c b a
.
cc S7SEGCC
3
3 cc12
S7 S6 S5 S4 S3 S2 S1 S0
cc S7SEGCC
cc S7SEGCC
3
cc11
DP14
DP13
DP12
S7 S6 S5 S4 S3 S2 S1 S0
cc S7SEGCC
3
cc10
cc9
cc[8:15]
S7 S6 S5 S4 S3 S2 S1 S0
cc S7SEGCC
3
3
3
.
cc S7SEGCC
cc S7SEGCC
cc S7SEGCC
U26 7 KC7 9 KC6 10 KC5 11 KC4 12 13 14 15
p g f e d c b a
DP11
DP10
DP9
DP8
S7 S6 S5 S4 S3 S2 S1 S0
2
7
.
cc S7SEGCC
cc2
39
5
p g f e d c b a
cc[0:7]
U28 15 cc8 14 cc9 13 cc10 12 cc11 11 cc12 10 cc13 9 cc14 7 cc15
1
6 1 2 4 5 7 9 10
3
3
3
.
S7 S6 S5 S4 S3 S2 S1 S0
DP5
DP4
DP3
cc S7SEGCC
cc S7SEGCC
cc S7SEGCC
F5 8279
6 1 2 4 5 7 9 10
DP2
DP1
DP0
Y8 Y7 Y6 Y5 Y4 Y3 Y2 Y1
3 cc14
cc15
Figure-1.11: Keyboard and Display Subsystem
20/Expt-1
Figure-1.12: LED Assembly and Stepper Motor Interface Subsystem
21/Expt-1
Figure-1.13: Bicolor 8x8 Dot Matrix LED Display Subsystem
22/Expt-1
Figure-1.14: Serial Communication Subsystem
23/Expt-1
Figure-1.15: IPC, ADC, DAC and Timer Subsystem
24/Expt-1
Figure-1.16: Power Supply Subsystem
25/Expt-1
8086 Microprocessor Laboratory Experiments Manual Using MicroTalk-8086 and MDA-8086 Trainers MicroTalk-8086 ( Bangladesh )
MDA-8086 ( Korea )
Golam Mostafa
Ahsanullah University of Science and Technology
Experiment – 10A
Conversion and Operation of MicroTalk-8086 Trainer into a Digital Weighing Machine (DWM) (You must Finish all the Tasks of this Experiment. Exercises, Examples and Questions are given as topics for additional studies to enhance your Knowledge & Understanding) Task-10A.1: [Aim of the Experiment] To get familiar with the procedures of converting the MicroTalk-8086 microprocessor trainer into a Digital Weighing Machine (DWM). Task-10A.2: [Converting the MicroTalk- 8086 Trainer into DWM] Let us carry out the following steps to convert the MicroTalk-8086 trainer into a DWM (Digital Weighing Machine). 1. Look into the following block diagram of Fig-71.1, which could be used to represent the MicroTalk-8086 based DWM. Load cell is shown in fig-71.2. Amplifier is shown in elsewhere. 713-04
Load Cell
CC7S Type Display of MicroTalk-8086 Tr ainer
Breadboard
Weight Field
Rate Field
DP1 DP3 DP0 DP2 DP4
+5 -5 0V
DP9 D P11 D P10
A m p
A D C
J7
U23 8255
U2 8086
DS1 DS2 DS3 DS4
U24 8279
DP5
DP6
DP7
DP8
D P13 D P15 D P12 D P14
Cost Field
E
Q3 Q2 Q1 Q0
7
8
9
4
5
6
1
2
3
0 BKSRST
Figure-71.1: Block Diagram of DWM Based on the MicroTalk-8086 Trainer Weight + Sense (Blue) + Excitation (Green)
+5V + Output 20mV / 20Kg. Wt. + Output (White) - Excitation (Black) -5V + Output (Red)
- Sense (Yello)
Load Cell
Figure-71.2: Pictorial View of Load Cell
GM: loadcellcircuit323: 15/12/01: 714-04
Figure-71.3: Electrical Circuit of the Load Cell
1/Expt-10A
2. Assume that the ‘Load Cell’ is connected (Practically it is not connected). We will be performing the load cell exercises in Experiment-7.2. 3. Also assume that the ‘Breadboard, the Instrument Amplifier (See Fig-72.1) and the ADC (See Fig-72.2) are also present (Practically they not connected). 4a. Assume that the Load Cell has produced a signal of 12.37mV corresponding to 12.370kg of loads. This signal has been amplified and digitized to upBCD format by the ADC. Also assume that the WTupBCD (Weight as Unpacked BCD as: 01, 02, 03, 07 for 12.37 Kg) signals have been acquired via the interface controller U23 (8255) and are saved into the following four memory locations (Fig-71.4) of Table-T7 of the ‘DWM Data Structure (Fig-71.11). For the weight of 12.370Kg, we have: (05050) (05051) (05052) (05053)
= = = =
01 02 03 07
for 10kg for 2kg for 300 gm for 70gm 05053 05052 05051 05050
UpBCD UpBCD UpBCD UpBCD
Wt: 1/100 Wt: 1/10 Wt: 1 Wt: 10
upBCD Wt
Goods T7
Figure-71.4: Table Containing upBCD Weight Data
Also assume that the upBCD weight data are converted to pBCD and CC-codes and are saved into following memory locations of Table-3 (Fig-71.5) and Table-T1 (Fig-71.6) respectively. For the weight of 12.370kg, we have: (05020) (05021)
= 12 = 37
for 12 kg for 370 gm 05021 05020
Wt Field
pBCD: 1/10, 1/100 pBCD: 10, 1
BCD
Figure-71.5: Table Containing BCD Weight
For the weight of 12.370kg, we have: (05000) (05001) (05002) (05003) (05004)
= = = = =
06 5B 4F 07 3F
for the digit- 1 for the digit-2 for the digit-3 for the digit-7 for the digit-0 05004
4b. Assemble, convert, download and execute p712a.asm. The DP0-DP4 shows: 12.370 kg.
05000
always 3Fh for 0 CC-C ode: 1/100 CC-C ode: 1/10 CC-C ode: 1 (UNI) CC-C ode: 10 (TEN)
DP4 DP3 DP2 DP1 DP0
Wt Field T1a
Figure-71.6: Table Containing CC-code Weight
5 We will be using the keyboard of the MicroTalk-8086 trainer to enter the product rate. The rate will be entered one digit at a time and will be instantly processed by the CPU. The keyboard of the trainer will be supplying an 8-bit Scan Code for a digit that has been pressed. Let us assume that the rate of the product is: Tk 27.95/kg. Now, when the user presses the key with label-2, the CPU will receive the code 0Dh. Let us assume that the specified memory locations of Table-T5 (Fig-71.7) will contain the RTSCAN (product Rate in SCAN Code format). The specified memory locations of Table-T3 (Fig-71.8) will contain the BCD (product rate in BCD format).
2/Expt-10A
For the product rate of Tk 27.95/kg, we have: next next next
(0504B) (0504B) (0504B) (0504B)
= = = = 0504D 0504C 0504B 0504A 05049 05048 05047
15 0B 1B 14
for digit-2 for digit-7 for digit-9 for digit-5 Rate
Key Scan Code C ursor Type No of Digits to Print C ursor Position ASCII for 1/100 DP1F
T5
Figure-71.7: Table Containing Scan Code Rate
For the product rate of Tk 27.95/kg, we have: (05022) (05023)
= 27 = 95
for Tk 27 for Paisa 95
5b. Assemble, Download and Execute: P712b.asm The DP0-DP4 shows: 12.370 kg. The DP5-DP8 shows: 27.95 Tk
05023 05022
pBC D: 1/10, 1/100 pBC D: 10, 1
Rate Field
BCD
Figure-71.8: Table Containing BCD Rate
6 We assume that the MicroTalk-8086 trainer contains the product cost computation routine (See Fig-74.1) and it has already computed the cost by multiplying the weight and rate. Let us assume that the COSTBCD (product Cost in Packed BCD Format) has been saved in the specified memory locations of Fig-71.9. The COSTCC (Product Cost in CC-code Format) has also been saved in the specified memory locations of Fig-7.10. For the product cost of : Tk 345.74 (rate of Tk 27.95/kg x weight of 12.370kg), we have: (05025) (05026) (05027)
= 03 = 45 = 74
for Tk 0300 for Tk 45 for Paisa 74 05027 05026 05025
pBC D: 1/10, 1/100 pBC D: 10, 1 pBC D: 1000, 100
Cost Field
BCD
Figure-71.9: Table Containing BCD Cost
For the product cost of : Tk 345.74 (rate of Tk 27.95/kg x weight of 12.370kg), we have: (0500A) (0500B) (0500C) (0500D) (0500E) (0500F)
= = = = = =
3F 4F 66 6D 07 66
for digit-0 for digit-3 for digit-4 for digit-5 for digit7 for digit-4 0500F
6b. Assemble, download and execute: p712c.asm The DP0-DP4 shows : 12.370 kg (weight) The DP5-DP8 shows: 27.95 Tk (rate) The DP10-DP15 shows: 0345.74 Tk (Cost).
0500B 0500A 05009
CC -Code: 1/100 CC -Code: 1/10 CC -Code: 1 (UNI) CC -Code: 10 (TEN) CC -Code:100 (HUN) CC -Code: 1000 (K) no Use
DP15 DP14 DP13 DP12 DP11 DP10
Cost Field T1c
Figure-71.10: Table Containing CC-code Cost
3/Expt-10A
GM:04/04: 632
05015 05014 05013 05010 0500F
0500B 0500A 05009 05008 05005 05004
05000
T5 DP1F
ASCII Type LCD Display of MDA-8086 amd MTS-86C
Rate Field T4c
DP0 DP1 DP2 DP3 DP4 DP5 DP6 DP7 DP8 DP9 DPA DPB DPC DPD DPE DPF Wt Field T4b
DP10 DPF
COS T : 0 0 0 0 . 0 0 5 93
DP18 DP17
LCD Display
pBCD: 1/10, 1/100 pBCD: 10, 1 pBCD: 1/10, 1/100 pBCD: 10, 1 upBCD: X0 :1/ 100 upBCD: X0 : 1/10 upBCD: X0 : 1 upBCD: X0 : 10 upBCD: X0 : 100 upBCD: X0 : 1000 no Use upBCD: X0 : 1/100 upBCD: X0 : 1/10 upBCD: X0 : 1 upBCD: X0 : 10 no Use upBCD: X0 :1/100 upBCD: X0 :1/10 upBCD: X0 : 1 upBCD: X0 : 10 CC-Code: 1/100 CC-Code: 1/10 CC-Code: 1 (UNI) CC-Code: 10 (TEN) CC-Code:100 (HUN) CC-Code: 1000 (K) no Use CC-Code: 1/100 CC-Code: 1/10 CC-Code: 1 (UNI) CC-Code: 10 (TEN) always 3Fh for 0 CC-Code: 1/100 CC-Code: 1/10 CC-Code: 1 (UNI) CC-Code: 10 (TEN)
Rate
7-Segment and LCD
Key Scan Code Cursor Type No of Digits to Print Cursor Position ASCII for 1/100 ASCII for 1/10 ASCII for . ASCII for 1 ASCII for 10 ASCII for : ASCII for R ASCII for Blank ASCII for 0 ASCII for 1/100 ASCII for 1/10 ASCII for . ASCII for 1 ASCII for 10 ASCII for : ASCII for W ASCII for Blank ASCII for Blank ASCII for 1/100 ASCII for 1/10 ASCII for . ASCII for 1 ASCII for 10 ASCII for 100 ASCII for 1000 ASCII for : ASCII for T ASCII for S ASCII for O ASCII for C ASCII for Blank ASCII for Blank pBCD: 1/10, 1/100 pBCD: 10, 1 pBCD: 1000, 100
T6
R : _ _ . _ _
W : 1 2 . 3 7 0
DP10 DP11 DP12 DP13 DP13 DP!4 DP15 DP16 DP17 DP18 DP1A DP1B DP1C DP1D DP1E DP1F
Cost Field T4a
DP0
DP15
DP10 DP8 DP5 DP3 DP0 DP15 DP14 DP13 DP12 DP11 DP10 DP8 DP7 DP6 DP5 DP4 DP3 DP2 DP1 DP0
Cost Field Rate Field Wt Field Cost Field T2c Rtae Field T2b Wt Field T2a Cost Field T1c Rtae Field T1b Wt Field T1a
CC7S Type Display of MicroTalk-8086 Trainer Weight Field DP1 DP3 DP0 DP2 DP4
7-Sement Display Devices
0501A 05019 05018
Scratch Pad Memory
Goods
T7
ASCII Table: T4
0502A 05029 05028 05027 05026 05025 05024 05023 05022 05021 05020 0501F
upBCD Wt
pBCD Table: T3
05038 05037
Wt: 1/100 Wt: 1/10 Wt: 1 Wt: 10
upBCD Table: T2
05040 0503F
UpBCD UpBCD UpBCD UpBCD
CC-Code Table: T1
05053 05052 05051 05050 0504F 0504E 0504D 0504C 0504B 0504A 05049 05048 05047
Rate Field DP5
DP6
DP7
DP8
1 2. 3 7 0
2 7. 9 5
0 3
4 5. 7 4
DP9 DP11 DP10
DP13 DP15 DP12 DP14
Cost Field
Figure-71.11: Data Structure for the Digital Weighing Machine
4/Expt-10A
Example Data 1. Weight: 12.370 kg 2. Rate: 27.95 Tk 3. Cost : 345.74 Tk
7 We also assume that the MicroTalk-8086 trainer has routines to convert data from one format to another like BCD2CC. It is also assumed that the trainer contains a routine that transfers the CC-code data to the 7-sement display devices. 8 We are now ready to operate the MicroTalk- 8086 trainer as a Digital Weighing Machine. Task-10A.3: [Operating the MicroTalk-8086 as DWM: p713.asm] We may follow the steps as outlined below: Take a hookup wire and short: J6-3(KIRQ) and J6-11 (IR2). 1 Connect the IBM-PC and the MicroTalk- 8086 trainer using the serial cable of COM1 port. Apply power to the IBM-PC and the Microtalk-8086 trainer. 2 Now open the file p713.asm program from the path: c:\mtk8086\p713.asm. This is the program, which converts the MicroTalk-8086 trainer into a DWM. 3 Assembly the program p713.asm. Convert it to p713.abs and down load into MicroTalk-8086. 4 Execute the downloaded program starting at location: 01000 (0000:1000). 5 Observe that the following message (Fig-71.12) appears at the 7-segment panel of the trainer. 715-04
CC7S Type Display of MicroTalk-8086 Trainer Weight Field
Rate Field
DP1 DP3 D P0 D P2 DP4
DP5
D P6
DP7
D P8
1 2. 3 7 0
0 0. 0 0
0 0
0 0. 0 0
D P9 D P11 DP10
DP13 D P15 DP12 DP14
Cost Field
Figure-71.12: 7-Segment Display Panel after the Execution of p713.asm
6 We have assumed a weight of 12.370 kg. The rate is seen to be Tk 00.00. So, the Cost is Taka: 0000.00 7 The execution of the p713.asm program has configured the ‘E’-key (E stands for Rate Entry) of the trainer as a command key and it can be used to tell the trainer to accept rate from the keyboard. Let us press the E-key, the display appears as Fig-71.13 with the rate field opened. 715-04
CC7S Type Display of MicroTalk-8086 Trainer Weight Field D P1 D P3 D P0 D P2 D P4
Rate Field D P5
D P6
D P7
D P8
1 2. 3 7 0
_ _. _ _
0 0
0 0. 0 0
D P9 D P11 D P10
D P13 D P15 D P12 D P14
Cost Field
Figure-71.13: 7-Segment Display Panel after Pressing the Rate Entry Key ‘E’
5/Expt-10A
8 Enter the product rate of Tk 27.95 by pressing down the digits: 2 7 9 and 5. When the entry of all the 4-digits are done, the display appears as Fig-7.14 which shows the Cost of the product. 715-04
CC7S Type Display of MicroTalk-8086 Trainer Weight Field DP1 DP3 DP0 DP2 DP4
Rate Field DP5
DP6
DP7
DP8
1 2. 3 7 0
2 7. 9 5
0 3
4 5. 7 4
DP9 DP11 DP10
DP13 DP15 DP12 DP14
Cost Field
Figure-71.14: 7-Segment Display Panel after Entering of the Product Rate
9 This is the end of the conversion and operation of the MDA-8086 as a Digital Weighing Machine. Check that the DWM is working all right by entering different product rates. Task-10A.4 [Exercises] [p714.asm] Open p713.asm and save as p714.asm 1 Change the simulated weight to 15.750Kg by editing the program p714.asm at the relevant memory locations. Reassemble the program and down load it to the trainer. Enter the rate as: Tk 34.50. The display must show correct input/output values (Cost: 0543.37 Tk). 2 Press the E-key to enter a new rate (say: Tk 57.69). The rate field of the display is opened. 3 Type 5 and then ‘F2’. The rate field shows: 5 _ . _ _. This indicates that the program has not accepted the ‘F2’ key as a valid digit key. Type all other non-digit key and check that the program has correctly filtered out them. If any of the non-digit keys is found having not been filtered out, then bring necessary change in the program p714.asm to get it filtered. 4 Do you know what type of data the keyboard generates when you press the keys (3 4 6 and 9) one after another as product rate? Ans: When the key-3 is pressed down, the electronics of the keyboard (see Fig-73.1] generates an 8-bit code called ‘Scan Code’. Thus there are 4-packets of ‘8-bit’ scan codes for the above four digits. What are the values of these scan codes? To get the values of these scan codes execute the ROM-based program of the trainer at: F05B0h and press keys. 5 Let us take that the scan codes for the above four (of Step-4) digits are: 1Dh, 0Ch, 1Ch and 1Bh respectively. 6 Now, write 8086 ASM program to convert the above scan codes into their corresponding CCcodes codes 4Fh, 66h, 7Dh and 6Fh) and store them at the appropriate memory locations of the data structure of Fig-71.11.
6/Expt-10A
Task-10A.5: Complete Code Listing for DWM Program: P713.asm MYCODE
SEGMENT ASSUME cs:MYCODE ORG 1000h ; 0000:1000
START: L1:
nop ; init to enter Rate Data from keyboard mov di, 5000h mov BYTE PTR [di+48h], 05h ; cursor position mov BYTE PTR [di+49h], 04h ; 4-digits to print mov BYTE PTR [di+4Ah], 08h ; cursor type _ ; 8259 initialization ;call far ptr F000:0890 mov bx, 504Ch mov WORD PTR [bx], 0890h mov WORD PTR [bx+02h], 0F000h call DWORD PTR [bx] ; IR2 for KIRQ enabled sti ; 8086's interrupt is enabled ; vector set for int 22h for KIRQ at: ; 0000:2000h ; 00088h mov ax, 0000h mov es, ax mov bx, 0000h mov WORD PTR es:[bx+88h], OFFSET INT22; 2000h mov WORD PTR es:[bx+8Ah], SEG INT22; 0000h ; correct ; 8279 initialization mov al, 08h mov dx, 0002h out dx, al mov al, 34h out dx, al
L2:
L3:
; 16-digit ; poit at CR of 8279 ; clock scaling
; storage of WTupBCD at T7 mov bx, 5000h mov WORD PTR [bx+50h], mov WORD PTR [bx+52h], mov WORD PTR [bx+22h], ptr WTACQ 02h 5050h 5020h ptr up2BCD
of Fpg-71.11 0201h 0703h 0000h
; 12.37 kg ; 27.95 Tk/kg
call mov mov mov call
far ch, si, di, far
mov call mov
si, 5020h ; point at BCDWT ; 1237d = 04D5h far ptr BCD2BIN ; converting BCD wt into Binary Wt WORD PTR [si+2Ch],ax ; saving BINWT at: 504D,504C
mov call mov
si, 5022h ; point at BCDRATE ; 2795d = 0AEBh far ptr BCD2BIN ; converting BCD wt into Binary Wt WORD PTR [si+2Ch],ax ; saving BINRT at: 504F, 504E
mul
WORD PTR [si+2Ah]
; BINCOST in [dx][ax] 32-bit
mov mov mov
di, 5000h WORD PTR [di+4Ch], ax WORD PTR [di+4Eh], dx
; saving lowerr 16-bit of BINCOST ; saving upper 16-bit of BINCOST
call
far ptr BIN2BCD ; convert BIN Cost to BCD Cost by Horner Rule
mov mov mov call
ch, si, di, far
mov mov mov
ch, 04h si, 5022h di, 5005h
04h 5020h 5000h ptr BCD2CC
; Acquisition of Weight as 0X: 0000:1050 ; number of packed bytes to obtain ; pointing at upBCD table, T7 ; pointing at pBCD table, T3 ; to convert unpacked BCD to Packed BCD
; number of CCCodes to obtain ; point at BCD table, T3a ; point at CCcode table, T1a ; number of CCCodes to obtain ; point at BCD table, T3a ; point at CCcode table, T1a
7/Expt-10A
WTACQ WTACQ
call
far ptr BCD2CC
mov mov mov call
ch, si, di, far
mov mov mov mov mov or or or call jmp
ch, 10h ; number pf cccode bytes to transfer ah, 90h ; Display Position of 8279 si, 5000h ; point at ccode table, T1a BYTE PTR [si+04h], 3Fh ; place 0 at DP4 BYTE PTR [si+09h], 00h ; blank BYTE PTR [si+01h], 80h ; placing decimal point 12.37kg BYTE PTR [si+06h], 80h ; plce . 27.95 BYTE PTR [si+0Dh], 80h far ptr CCX79 L3
06h 5024h 500Ah ptr BCD2CC
; number of CCCodes to obtain ; point at BCD table, T3c ; point at CCcode table, T1a
PROC FAR ; read from ADC and save the upBCD (0X) in table, T7 of Fig-71.11 ret ENDP
BCD2BIN PROC mov mov and cmp jz L41d: add dec jz jmp
FAR ax, 0000h ;initial partial result bl, BYTE PTR [si+01h] ; begin of BCD2BIN conversion =37(12) bl, 0Fh ; bl=00 bl, 00h L41e ax, 0001h bl L41e L41d
L41e:
mov mov ror and cmp jz add dec jz jmp
bl, BYTE PTR [si+01h] cl, 04h bl, cl bl, 0Fh ; bl = 05 bl, 00h L41h ax, 000Ah bl L41h L41g
mov and cmp jz add dec jz jmp
bl, BYTE PTR [si] bl, 0Fh ; bl = 07 bl, 00h L41j ax, 0064h bl L41j L41i
L41g:
L41h:
L41i:
L41j:
mov mov ror and cmp jz L41k: add dec jz jmp L41l: ret BCD2BIN ENDP
; 12 (37)
bl, BYTE PTR [si] cl, 04h bl, cl bl, 0Fh ; bl=04 bl, 00h L41l ax, 03E8h bl L41l L41k ; 16-bit BINary result in: ax-register
8/Expt-10A
BIN2BCD PROC LV1: mov mov mov mov mov
LV2:
LV2a: LV3:
LV4:
LV5:
LV6:
LV7:
LV8:
mov mov mov mov rcl rcl jc mov add daa mov mov adc daa mov mov adc daa mov mov adc daa mov dec jnz jmp mov adc jc jmp daa mov stc jmp
LV9:
FAR bx, 5000h ; converting 32-bit BIN2BCD by Horner Rule di, WORD PTR [bx+4Eh] ; di=upper 16-bit of BINCOST si, WORD PTR [bx+4Ch];si=lower 16-bit (di, si) = 32-BIT BINCOST WORD PTR [bx+4Eh], 0000h WORD PTR [bx+4Ch], 0000h;(0504F,0504E,0504D,0504C)=00000000 ; initial 8-digit BCDCOST) bx, 0000h ; converting 32-bit BIN2BCD using Horner Rule cx, 0000h; (cx,bx) = 00000000 = initial partial BCDCOST ah, 20h ; number of rotation al, 00h ; result: (ch,cl,bh,bl) si, 01h di, 01h LV7 al, bl al, al bl, al al, bh al, al bh, al al, cl al, al cl, al al, ch al, al ch, al ah LV2 LV9 al, bl al, al LV8 LV2a bl, al LV3
mov mov mov mov mov ret BIN2BCD ENDP
di, 5000h ; [cx][bx]=03457415;mov di, 5000h BYTE PTR [di+24h], ch ; upper part of BBCD COST BYTE PTR [di+25h], cl ; BYTE PTR [di+26h], bh BYTE PTR [di+27h], bl ; lower part of BCDCOST
up2BCD L1SR1:
PROC mov mov rol and or mov dec jz inc inc inc jmp ret ENDP
FAR cl, 04h al, BYTE PTR [si] al, cl al, 0F0h al, BYTE PTR [si+01h] BYTE PTR [di], al ch L2SR1 si si di L1SR1
PROC mov mov mov mov
FAR ax, es, al, dl,
L2SR1: up2BCD BCD2CC L1SR2:
; saving the pBCD at table T3a
0F000h ax ; point at the base of LUT3 BYTE PTR [si] ; 03 , 45, 74, 15 al
9/Expt-10A
L2SR2: BCD2CC CCX79
L1SR3:
L2SR3: CCX79 XT8279
XT8279 ; INT22
INTL1:
AGNKB:
INTL2:
and mov mov mov mov mov mov rol and mov mov inc mov dec jz inc inc jmp ret ENDP
al, 0F0h ah, 0FEh bx, ax al, BYTE BYTE PTR cl, 04h al, dl al, cl al, 0F0h bx, ax al, BYTE di BYTE PTR ch L2SR2 si di L1SR2
; making X0 = 00
PROC mov mov out mov mov out dec jz inc jmp ret ENDP
FAR dx, 0002h ; point at CR al, ah dx, al dx, 0000h ; point at DR of 8279 al, BYTE PTR [si] dx, al ch L2SR3 si L1SR3
PROC mov mov mov mov mov or or or call ret ENDP
far ch, 10h ; number pf cccode bytes to transfer ah, 90h ; Display Position of 8279 si, 5000h ; point at ccode table, T1a BYTE PTR [si+04h], 3Fh ; place 0 at DP4 BYTE PTR [si+09h], 00h ; blank BYTE PTR [si+01h], 80h ; placing decimal point 12.37kg BYTE PTR [si+06h], 80h ; plce . 27.95 BYTE PTR [si+0Dh], 80h far ptr CCX79
ORG PROC mov mov out mov in cmp jz iret
2000h FAR al, 40h dx, 0002h dx, al dx, 0000h al, dx al, 11h INTL1
mov mov mov call mov in rcr jc jmp mov mov
di, 5000h WORD PTR [di+05h], 8808h WORD PTR [di+07h], 0808h far ptr XT8279 dx, 0002h al, dx al, 01h INTL2 AGNKB dx, 0002h al, 40h
PTR es:[bx] [di], al
; getting the CCcode ; save cccode at T1a
; making X0 PTR es:[bx] [di], al
; getting CCcode ; saving cccode in T1a
; reading Scan Code
10/Expt-10A
out mov in mov cmp jz cmp jz cmp jz cmp jz ;cmp ;jz cmp jz cmp jz
dx, al dx, 0000h al, dx BYTE PTR [di+4Bh], al al, 0Eh L1RS al, 0Dh L1RS al, 0Ch L1RS al, 0Bh L1RS al, 0Ah L1RS al, 15h L1RS al, 14h L1RS
cmp jz cmp jz cmp jz cmp jz jmp
al, 13h L1RS al, 1Dh L1RS al, 1Ch L1RS al, 1Bh L1RS AGNKB
L1RS:
; mov mov mov mov mov mov mov mov mov mov mov call dec jz inc jmp
L2RS:
; cc---> upBCD jmp
; saving the Scan Code
al = scan CC-code di, 5000h dx, 0F000h es, dx bp, 0FFD0h ah, 00h si, ax al, BYTE PTR es:[bp+si] ; getting CCcode cl, BYTE PTR [di+48h] ch, 00h bp, cx BYTE PTR [di+bp], al ; saving the Cccode at T1b far ptr XT8279 ; T1b ---> 8279 with decimal point BYTE PTR [di+49h] ; number of digits to print L2RS BYTE PTR [di+48h] AGNKB L2RS
; 4-digits of Weight are acquired
mov ch, 04h ; bytes to convert mov si, 5005h ; and BYTE PTR [si+01h], 07Fh ; 0111 1111 ; remove point mov di, 5015h call far ptr CC2uBCD ; upBCD ---> pBCD mov ch, 02h ; number of bytes to obtain mov si, 5015h mov di, 5022h call far ptr uB2BCD mov di, 5000h mov BYTE PTR [di+48h], 05h mov BYTE PTR [di+49h], 04h ;test OK ;mov al, 80h ;mov dx, 3606h ;out dx, al ;mov al, 01h ;mov dx, 3600h ;out dx, al ;hlt sti
11/Expt-10A
;iret mov mov mov iret INT22
ENDP
uB2BCD LY1:
PROC mov mov mov ror and or mov dec jz inc inc inc jmp ret ENDP
LY2: uB2BCD
CC2uBCD PROC mov mov LX1: mov mov mov add mov mov dec jz inc inc jmp
bp, sp WORD PTR [bp+00h], 1050h ; OFFSET of L3 of MLP WORD PTR [bp+02h], 0000h ; SEG of L3 of MLP
FAR al, BYTE PTR [si] cl, 04h ah, BYTE PTR [si+01h] ah, cl ah, 0Fh al, ah BYTE PTR [di], al ch LY2 si si di LY1
FAR dx, 0F000h es, dx bp, 0FF00h ; FF00 ; 1234 : 06, 5b, 4F, 6D ah, 00h al, BYTE PTR [si] ; getting CCcode 0D bp, ax ; FF00 + 0006 = FF06 al, BYTE PTR es:[bp] ; getting 10 from FFF0D BYTE PTR [di], al ; saving upBCD ch LX2 si di LX1
LX2: ret CC2uBCD ENDP MYCODE
ENDS END
START
12/Expt-10A
Experiment – 10B
Conversion and Operation of the MDA-8086 Microprocessor Trainer as a Digital Weighing Machine (DWM) (You must Finish all the Tasks of this Experiment. Exercises, Examples and Questions are given as topics for additional studies to enhance your Knowledge & Understanding) Task-10B.1: [Aim of the Experiment] To get familiar with the procedures of converting the MDA-8086 microprocessor trainer into a Digital Weighing Machine (DWM). Task-10B.2: [Converting the MDA-8086 Trainer into DWM] Let us carry out the following steps to convert the MDA-8086 trainer into a DWM. 1. Look into the following block diagram of Fig-71.1, which could be used to represent the MDA-8086 based DWM. 647
Load Cell +5 -5 0V
Breadboard
MDA-8086
A m p
P3
LCD
U29 8255
COST: 1998.80 W: 19.990
DS1 DS2 DS3 DS4
A D C
R: 99.99
E
Q3 Q2 Q1 Q0
8
9
4
5
6
7
0
1
2
3
Figure-71.1: Block Diagram of DWM Based on the MDA-8086 Trainer
2. Assume that the ‘Load Cell’ is connected (Practically they not connected). You will be performing the load cell exercises in Experiment-7.2. 3. Also assume that the ‘Breadboard, the Instrument Amplifier and the ADC’ is also present (Practically they not connected). 4. Assume that the Load Cell has produced a signal of 12.37mV corresponding to 12.370kg of loads. This signal has been amplified and digitized to upBCD format by the ADC. Also assume that the WTupBCD signals have been acquired via the interface controller U29 (8255) and are saved in the following memory locations of the ‘DWM Data Structure’ of Fig-7.4 (see text). 05053 05052 05051 05050
UpBCD UpBCD UpBCD UpBCD
Wt: 1/100 Wt: 1/10 Wt: 1 Wt: 10
upBCD Wt
Goods
T7
Figure-71.2: Table Containing upBCD Weight Data
Also assume that the upBCD weight data are converted to pBCD and ASCII and saved in the following memory locations of the data structure.
1/Expt-10B
Wt Field
pBCD: 1/10, 1/100 pBCD: 10, 1
05021 05020
BCD
Figure-71.3: Table Containing BCD Weight 0503F
05038
ASC II ASC II ASC II ASC II ASC II ASC II ASC II ASC II
for for for for for for for for
0 1/100 1/10 . 1 10 : W
DP17
ASCII Wt Field T4b DP10
Figure-71.4: Table Containing ASCII Weight
5 We will be using the keyboard of the MDA-8086 trainer to enter the product rate. The rate will be entered one digit at a time. Let us assume that the following memory locations of the following data structure contain the RTASCII (product Rate in ASCII format) and RTBCD (product rate in BCD format). 05047
ASCII ASCII ASCII ASCII ASCII ASCII ASCII
05041
for for for for for for for
1/100 1/10 . 1 10 : R
DP1F
DP19
ASCII Rate Field T4c
632a
Figure-71.5: Table Containing ASCII Rate 05023 05022
pBC D: 1/10, 1/100 pBC D: 10, 1
Rate Field
BCD
Figure-71.6: Table Containing BCD Rate
6 We assume that the MDA-8086 trainer contains the product cost computation routine and it has already computed the cost by multiplying the weight and rate. Let us assume that the COSTBCD and COSTAS are stored in the following memory locations of the data structure. 05027 05026 05025
pBCD: 1/10, 1/100 pBCD: 10, 1 pBCD: 1000, 100
Cost Field
BCD
Figure-71.7: Table Containing BCD Cost 05037
0502A 05029 05028
ASCII ASCII ASCII ASCII ASCII ASCII ASCII ASCII ASCII ASCII ASCII ASCII ASCII ASCII ASCII ASCII
for for for for for for for for for for for for for for for for
Blank Blank 1/100 1/10 . 1 10 100 1000 : T S O C Blank Blank
DPF
ASCII Cost Field T4a
DP0
Figure-71.8: Table Containing ASCII Cost
7 We also assume that the MDA-8086 trainer has routines to convert data from one format to another like BCD2ASCII. It is also assumed that the trainer contains a routine that transfers the ASCII data to the LCD display panel. 8 We are now ready to operate the MDA-8086 trainer as a Digital Weighing Machine.
2/Expt-10B
Task-10B.3: [Operating the MDA-8086 as DWM: p713.asm] We may follow the steps as outlined below: 1 Connect the IBM-PC and the MDA-8086 trainer using the serial cable of COM1 port. Apply power to the IBM-PC and the MDA-8086 trainer. 2 Now open the file p713.asm program from the path: c:\mda8086\p713.asm. This is the program, which converts the MDA-8086 trainer into a DWM. 3 Assembly the program p713.asm. Convert it to p713.abs and down load into MDA-8086. 4 Execute the downloaded program starting at location: 01000 (0000:1000). 5 Observe that the following message appears at the LCD panel of the trainer. DP0 DP1 DP2 DP3 DP4 DP5 DP6 DP7 DP8 DP9 DPA D PB DPC DPD DPE DPF
W : 1 2 . 3 7 0
R : 0_ 0_ . 0_ 0_
5 93
C O S T : 0 0 0 0 . 0 0
DP10 DP11 DP12 DP13 DP13 DP!4 DP15 DP16 DP17 DP18 DP1A D P1B DP1C DP1D DP1E DP1F
Figure-71.9: LCD Panel after the Execution of p713.asm
6 In step-4 of Task-71.2, we have assumed a load of 12.370 kg. The rate is seen to be Tk 00.00. So, the Cost is: 0000.00 Tk. 7 The execution of the p713.asm program has configured the ‘E’-key (E stands for Rate Entry) of the trainer as a command key and now we may use this key to tell the trainer to accept rate from the keyboard. Let us press the E-key, the display shows: DP0 DP1 DP2 DP3 DP4 DP5 DP6 DP7 DP8 DP9 DPA D PB DPC DPD DPE DPF
W : 1 2 . 3 7 0
R : _ _ . _ _
5 93
C O S T : 0 0 0 0 . 0 0
DP10 DP11 DP12 DP13 DP13 DP!4 DP15 DP16 DP17 DP18 DP1A D P1B DP1C DP1D DP1E DP1F
Figure-71.10: LCD Panel after Pressing the Rate Entry Key ‘E’
8 Enter the product rate of Tk 27.65 by pressing down the digits: 2 7 6 and 5. When the entry of all the 4-digits are done, the display appears as below: DP0 DP1 DP2 DP3 DP4 DP5 DP6 DP7 DP8 DP9 DPA D PB DPC DPD DPE DPF
W : 1 2 . 3 7 0
R : 2_ 7_ . 6_ 5_
5 93
C O S T : 0 30 40 20 . 0 30
DP10 DP11 DP12 DP13 DP13 DP!4 DP15 DP16 DP17 DP18 DP1A D P1B DP1C DP1D DP1E DP1F
Figure-71.11: LCD Panel after Entering of the Product Rate
9 This is the end of the conversion and operation of the MDA-8086 as a Digital Weighing Machine. Check that the DWM is working all right by entering different product rates.
3/Expt-10B
Task-10B.4 [Exercises] 1 Change the simulated weight to 15.750Kg by editing the program p713.asm at the relevant points. Reassemble the program and down load it to the trainer. Enter the rate as: Tk 34.50. The LCD panel must show correct input/output values. 2 Press the E-key to enter a new rate (say: Tk 57.69). The rate field of the LCD is opened. 3 Type 5 and then ‘GO’. The rate field shows: R: 5 _ . _ _. This indicates that the program has not accepted the ‘GO’ key as a valid digit key. Type all other non-digit key and check that the program has correctly filtered out them. If any of the non-digit keys is found not been filtered out, then bring necessary change in the program p713.asm to get it filtered. 4 Do you know what type of data the keyboard generates when you press the keys (3 4 6 and 9) one after another as product rate? Ans: When the key-3 is pressed down, the electronics of the keyboard (see Fig-44.4] generates an 8-bit code called ‘Scan Code’. Thus there are 4-packets of ‘8-bit’ scan codes for the above four digits. What are the values of these scan codes? To get the values of these scan codes execute the program, p446.asm. 5 Assume that the scan codes for the above four (of Step-4) digits are: 03h, 04h, 06h and 09h respectively. Now, write 8086 ASM program to convert these codes into their corresponding ASCII codes 33h, 34h, 36h and 39h) and store them at the memory location of Fig-71.5. Program to Read Scan Codes and Saving: [Execute and Check the Result] ST: L1:
L2:
L3: L4:
L5:
nop mov Mov out in test jnz and mov out dec jz inc jmp jmp
5000h ah, 04h KRS(01H), 00h al, KRD(01h) al, 10000000B L2 al, 00011111B BYTE PTR [bx+4Ch], al KRS(01h), 00h ah L5 bx L2 F000:FFFFh (EA FF FF 00 F0)
; pointing a table that will hold the scan codes ; keyboard is reset ; read the raw scan code ; checking if B7-bit is 0 ; no key is pressed down ; closed key found and save in KBUF [upper 3-bits 0] ; scode is saved at memory location : 0000:504C..504F ; reset the keyboard
; read the scan code of the next key ; the goes to the prompt (the ready mode).
Program to Convert Scan Code to ASCII (SC2AS): [Execute and Check the Result] -
mov mov L: mov - mov xlat - mov dec jz inc jmp
ah, 04h si, 5000h al, BYTE PTR [si+4Ch] bx, OFFSET ASCII BYTE PTR [si+41h] ah M si L
; pointing the table that contain the Scan Code ; getting the 1st Scan Code, 2nd scan code …… ; bx-register knows how far the ASCII table is. ; now al-register contains the ASCII code ; ASCII code for the 1st digit is saved
ASCII DB 30h, 31h, 32h, 33h, 34h, 35h, 36h, 37h, 38h, 39h
M: conversion is done!
4/Expt-10B
Task-10B.5 – Complete ASM Code Listing for DWM : MYCODE LCDIR LCDSR LCDDR LCDCG KRR KDR START:
L1:
L2:
L3:
SEGMENT ASSUME EQU EQU EQU EQU EQU EQU ORG nop mov mov mov mov
cs:MYCODE 00h 02h 04h 06h 01h 01h 1000h ax, ss, ds, sp,
0000h ax ax 8000h
call mov out
far ptr BUSY al, 38h LCDIR, al
; LCD initialization (L12 -L26)
call mov out
far ptr BUSY al, 0Ch LCDIR, al
call mov out
far ptr BUSY al, 10h LCDIR, al
call mov out
far ptr BUSY al, 01h LCDIR, al
mov mov mov mov mov mov
bx, 5000h ; ASCII table initialization (L28-33) WORD PTR [bx], 3130h ; 0 1 WORD PTR [bx+02h], 3332h ; 2 3 WORD PTR [bx+04h], 3534h ; 4 5 WORD PTR [bx+06h], 3736h ; 6 7 WORD PTR [bx+08h], 3938h ; 8 9
mov mov mov mov mov mov
WORD WORD WORD WORD WORD WORD
PTR PTR PTR PTR PTR PTR
[bx+28h], [bx+2Ah], [bx+2Ch], [bx+2Eh], [bx+30h], [bx+32h],
2020h ; blank blank ; init Message (L35-L51) 4F43h ; O C 5453h ; T S 303Ah ; 0 : 3030h ; 0 0 2E30h ; . 0
mov mov mov mov mov mov mov mov mov mov
WORD WORD WORD WORD WORD WORD WORD WORD WORD WORD
PTR PTR PTR PTR PTR PTR PTR PTR PTR PTR
[bx+34h], [bx+36h], [bx+38h], [bx+3Ah], [bx+3Ch], [bx+3Eh], [bx+40h], [bx+42h], [bx+44h], [bx+46h],
3030h 2020h 3A57h 3231h 332Eh 3037h 5220h 303Ah 2E30h 3030h
mov mov mov call mov out call
si, 5000h ; xfer meggage to LCD (L53 -L66) bx, 0028h cl, 10h far ptr BUSY al, 80h LCDIR, al far ptr T42LCD ; xferring ASCII code from T4 to LCD
inc mov call mov out call
bx cl, 10h far ptr BUSY al, 0C0h LCDIR, al far ptr T42LCD
; ; ; ; ; ; ; ; ; ;
0 0 blank blank : W 2 1 3 . 0 7 R blank 0 : . 0 0 0
5/Expt-10B
L4: L31: L31a:
L41: L41a:
L41b:
nop mov mov mov out in test jnz and mov nop nop out cmp jnz mov mov mov
; flag init (L67 -L69) bx, 5000h WORD PTR [bx+4Ch], 0000h ; flags al, 00h ; ckecking if key close (L70-L74) KRR, al al, KDR al, 80h L31a al, 0Fh ; closed key found (L75-L81) BYTE PTR [si+4Bh], al
mov mov mov call mov out call
si, 5000h ; xfer message to LCD (L86-L99) bx, 0028h cl, 10h far ptr BUSY al, 80h LCDIR, al far ptr T42LCD ; xfer ASCII of T4 of Fig-44.8 to LCD
inc mov call mov out call
bx cl, 10h far ptr BUSY al, 0C0h LCDIR, al far ptr T42LCD
mov mov mov mov out nop in test jnz mov and mov nop nop out call cmp jnz mov mov mov mov mov call mov ;out mov
si, 5000h ; now digit printing at Rate Filed (L114-L162) dl, 04h ; for 4 digits to print bp, 0043h ; pointer al, 00h KRR, al ; keyborad reset
mov mov mov call mov out call
si, 5000h bx, 0028h cl, 10h far ptr BUSY al, 80h LCDIR, al far ptr T42LCD
inc mov
bx cl, 10h
KRR, al ; keyboard is al, 0Eh L31a bx, 5000h ; closed key is WORD PTR [bx+43h], 5F5Fh WORD PTR [bx+46h], 5F5Fh
reset 'E' and init message (L82-L84) ; _ _ at DP1B and DP1C ; _ _ at DP1E and DP1F
; 2nd line of LCD
al, KDR al, 80h L41a ; key has not been pressed ah, al al, 0Fh ; key has been pressed down BYTE PTR [si+4Bh], al ; scan code is saved KRR, al ; keyboard is reset far ptr DIGIT ; filtering out no-digit BYTE PTR [si+4Dh], 01h; L41a BYTE PTR [si+4Dh], 00h ; flag is reset, valid digit (0-9) si, 5000h bh, 50h bl, BYTE PTR [si+4Bh] ah, BYTE PTR [bx] ; ASCII code for digit in ah-register far ptr BUSY al, ah LCDDR, al BYTE PTR [si+bp], al
; xfer ASCII of T4 of
6/Expt-10B
Fig-44.8 to LCD
L41c:
HERE:
LV1:
call mov out call dec jz cmp jnz inc inc jmp
far ptr BUSY al, 0C0h ; 2nd line of LCD LCDIR, al far ptr T42LCD dl HERE ; 4-digit Rtae Entry is complete dl, 02h ; to find position for (.) to avoid printing L41c bp bp L41a
mov mov mov rol and and or mov
si, 5000h ; converting RATE ASCII into BCD (L165-L196) ax, WORD PTR [si+43h] ; al=34 ; ah=37 ASCII2BCD cl, 04h al, cl ; al, 0F0h ; al=40 ah, 0Fh ; ah=07 al, ah ;al=47 BYTE PTR [si+4Dh], al ;(0504D)= 47 ; upper Byte of BCDRATE
mov mov rol and and or mov
ax, WORD cl, 04h al, cl al, 0F0h ah, 0Fh al, ah BYTE PTR
mov mov rol and and or mov
ax, WORD PTR [si+3Ah] ; al=31 ; ah=32 ASCII2BCD cl, 04h al, cl al, 0F0h ah, 0Fh al, ah BYTE PTR [si+4Fh], al ; upper byte of BCDWT
mov mov rol and and or mov
ax, WORD PTR [si+3Dh] ; al=37 ; ah=37 ASCII2BCd cl, 04h al, cl al, 0F0h ah, 0Fh al, ah BYTE PTR [si+4Eh], al ; lower byte of BCDWT
call
far ptr BCD2BIN
mov mov mov call mov mov
dx, ax ; BINRATE in dx-register ax, WORD PTR [si+4Eh] ; converting BCDWT into BIN WORD PTR [si+4Ch],ax ; (0504D)(0504C) = BCDWT far ptr BCD2BIN ; WORD PTR [si+4Eh], ax ; (0504F)(0504E) = BINWT WORD PTR [si+4Ch], dx ; (0504D)(0504C) = BINRATE
mov mul
ax, WORD PTR [si+4Ch] WORD PTR [si+4Eh]
; multgiplication ; multiplier ; (dx)(ax) = 32-bint BINCOST
mov mov
WORD PTR [si+4Ch], ax WORD PTR [si+4Eh], dx
; lower 16-bit BINCOST ; upper 16-bit BINCOST
mov mov mov mov mov
bx, 5000h ; converting 32-bit BIN2BCD by Horner Rule di, WORD PTR [bx+4Eh] si, WORD PTR [bx+4Ch];(di, si) = 32-BIT BINCOST WORD PTR [bx+4Eh], 0000h WORD PTR [bx+4Ch], 0000h;(0540F,0540E,0540D,0540C)=00000000 ; initial 8-digit BCDCOST) bx, 0000h ; converting 32-bit BIN2BCD using Horner Rule
mov
PTR [si+46h] ; al=35 ; ah=36 ; ASCII2BCD ; al=50 ;ah=06 ;al=56 [si+4Ch], al ;(0504C) = 56 ; lower byte of BCDRATE
; converting BCD-RATE into BIN
7/Expt-10B
LV2:
LV2a: LV3:
LV4:
LV5:
LV6:
LV7:
LV8:
LV9:
LV9a:
LX2:
mov mov mov rcl rcl jc mov add daa mov mov adc daa mov mov adc daa mov mov adc daa mov dec jnz
cx, ah, al, si, di, LV7 al, al,
0000h; (cx,bx) = 00000000 = initial partial BCDCOST 20h ; number of rotation 00h 01h 01h
jmp mov adc jc jmp daa mov stc jmp
LV9 al, bl al, al LV8 LV2a
mov mov mov
si, 5000h WORD PTR [si+4Eh], cx WORD PTR [si+4Ch], bx
mov mov mov
ah, 03h ; 3-bytes to convert dx, 002Fh ; pointer bp, 004Fh ; converting BCDCOST into ASCIICOST
mov mov mov ror and xlat mov mov mov mov and mov xlat inc mov mov mov dec jz dec cmp jnz inc inc jmp
bx, al, cl, al, al,
mov mov
si, 5000h ; xfer meggage to LCD (L53 -L66) bx, 0028h
bl al
bl, al al, bh al, al bh, al al, cl al, al cl, al al, ch al, al ch, al ah LV2
bl, al LV3
OFFSET ASCII BYTE PTR [si+bp] ; al= 05 04h cl 0Fh ; al = 00 ; al=30h bx, dx ; bx=002Fh BYTE PTR [si+bx], al dx, bx al, BYTE PTR [si+bp] al, 0Fh bx, OFFSET ASCII dx bx, dx BYTE PTR [si+bx], al dx, bx ah LX3; HERE1 bp dx, 0032h LX2 dx dx LV9a
LX3:
8/Expt-10B
mov call mov out call
cl, 10h far ptr BUSY al, 80h LCDIR, al far ptr T42LCD
inc mov call mov out call
bx cl, 10h far ptr BUSY al, 0C0h LCDIR, al far ptr T42LCD
HERE1:
jmp
L31;HERE1
ASCII BUSY
DB PROC in and jnz ret ENDP
30h,31h,32h,33h,34h,35h,36h,37h,38h,39h FAR al, LCDSR al, 80h BUSY
PROC mov call mov out dec jz inc jmp ret ENDP
FAR ah, BYTE PTR [si+bx] far ptr BUSY al, ah LCDDR, al cl L3b bx L3a
PROC cmp jz cmp jz cmp jz cmp jz cmp jz cmp jz cmp jz cmp jz cmp jz cmp jz cmp jz cmp jz cmp jz cmp jz mov mov ret ENDP
FAR al, 12h ;GO EXIT al, 11h ; STP EXIT al, 0Ch ; C EXIT al, 0Dh ; D EXIT al, 0Eh ; E EXIT al, 0Fh ; F EXIT al, 15h ; + EXIT al, 13h ; REG EXIT al, 0Ah ; A EXIT al, 0Bh ; B EXIT al, 14h ; EXIT al, 16h ; DA EXIT al, 10h ; : EXIT al, 17h ; 'AD' EXIT BYTE PTR [si+4Bh], al BYTE PTR [si+4Dh], 01h ; valid digit is found
BUSY T42LCD L3a:
L3b: T42LCD DIGIT
EXIT: DIGIT
; xferring ASCII code from T4 to LCD
9/Expt-10B
BCD2BIN PROC mov mov mov and cmp jz L41d: add dec jz jmp
FAR si, 5000h ax, 0000h bl, BYTE PTR [si+4Ch] bl, 0Fh ; bl=00 bl, 00h L41e ax, 0001h bl L41e L41d
L41e:
mov mov ror and cmp jz add dec jz jmp
bl, BYTE PTR [si+4Ch] cl, 04h bl, cl bl, 0Fh ; bl = 05 bl, 00h L41h ax, 000Ah bl L41h L41g
mov and cmp jz add dec jz jmp
bl, BYTE PTR [si+4Dh] bl, 0Fh ; bl = 07 bl, 00h L41j ax, 0064h bl L41j L41i
L41g:
L41h:
L41i:
L41j:
mov mov ror and cmp jz L41k: add dec jz jmp L41l: ret BCD2BIN ENDP BCD2ASC PROC nop
; begin of BCD2BIN conversion
bl, BYTE PTR [si+4Dh] cl, 04h bl, cl bl, 0Fh ; bl=04 bl, 00h L41l ax, 03E8h bl L41l L41k ; 16-bit BINary result in: ax-register FAR
BCD2ASC ENDP MYCODE
ENDS END
START
10/Expt-10B
Experiment – 11A
Study of the Asynchronous Serial Communication Link Between IBMPC and MicroTalk-8086 Trainer (You must Finish all the Tasks of this Experiment. Exercises, Examples and Questions are given as topics for additional studies to enhance your Knowledge & Understanding) Task-11A.1 Lab Works on COM1 Port of IBMPC and MicroTalk-8086 Trainer using DOS and ASM Codes The diagram shown below depicts the interconnection between the 8086 (microprocessor), 8259 (Interrupt Priority controller), 8251A (Serial IO Controller), 8279 (Keyboard/Display Controller), 488/489 (TTL ↔ RS232 Converter) of MicroTalk-8086 trainer and the IBMPC. Study this diagram carefully and then carry out the steps that follow: A
D7-D0
D
R D/ WR/ M -IO/
R/ W/ IO/
8259 : U14 IR 7
C S/
INTR INTA/
INT INTA/ DR CR
J6-11
IR 2(22h) IR 1(21h) IR 0(20h)
KIR Q
4
IR Q
J6-3
1000h 1002h
0000h 0002h
8086: U2 BUS
6.144M Hz 307.2KHz
677
C LK TxC R xC 2000h 2002h
USART:
R xR DY TxR DY
TTL RS232 TxT
DR R xD CR
8251: U17
R xT
J6-18 J6-17
7SCCD
KBDIC
BUS
DRAM
IPC:
A
2 3
488 489
DP0 DP7 DP8
C ol
Key Buffer
MPU
R ow
DR CR
8279 : U24
3
TxR S
J10-2
1
R xR S
J10-3
489,488: U18,U19
Keypad
IBM-PC
Figure-11A.1: Hardware Connection Diagram among 8086, 8251, 8259, ‘Keyboard-Display’ and IBMPC
When this test is carried out, we shall see that: a. The message ‘dO’ keeps flashing at the DP7DP8 positions of the trainer. b. You press a key on the keyboard of the IBM-PC; the PC transmits the corresponding ASCII code. The trainer receives the ASCII code, displays it on the DP7DP8 positions of the trainer. The trainer also transmits back the same ASCII code to the PC. The PC receives the ASCII code and displays the corresponding character on the monitor. And then, the message ‘dO’ comes back. c. Press a key on the keypad of the trainer. The character ‘A’ appears on the monitor of PC. Procedures: i. Power down the IBM-PC and the MicroTalk-8086 trainer.. ii. Use a 9-pin serial cable to connect the trainer and the COM1 port of IBMPC. iii. Power up the trainer. Use a hookup wire and short: J6-3(KIRQ) and J6-11 (IR2). iv Execute at: F1940h. The message ‘dO’ starts blinking at DP7DP8 positions of the trainer.
1/Expt-11A
v. vi.
Power up the IBM-PC. In the IBM-PC, execute the program, c:\MTK8086\DVH463.EXE Listing of DVH463.ASM Program
MYSTACK SEGMENT para stack 'stack' DW 100 dup (0) STKTOP LABEL word MYSTACK ENDS MYDATA MYDATA
SEGMENT para public 'data' DB 00h ENDS
MYCODE
SEGMENT para public 'code' ASSUME cs:MYCODE,ss:MYSTACK, ds:MYDATA
START:
mov mov mov
ax,MYSTACK ss,ax sp,offset STKTOP
mov mov
ax, MYDATA ds, ax
mov mov mov int
ah,00h dx,0000h al,11000111B 14h
sti dx,0000h ah,03h 14h ah,01h RDCHAR KYBD
;points at COM1 ;ROM BIOS function value for int 14h ;ROM BIOS function call ,get COM1's status ;ah-B0 = 1 means data ready at UART ;data has just arrived at COM1 ;see if any command from Keyboard
RDCHAR: mov int
ah,02h 14h
;fuction value for ROM BIOS `int 14h' call ;ROM BIOS function call, data in al register
mov mov int
dl,al ah,02h 21h
;DOS BIOS function call, display data at CRT
KYBD:
mov int jnz jmp
ah,01h 16h RDKY CHKAGN
;function value ;ROM BIOS functioncall,ZF=1 means no char ;ZF=0,scan and ascii codes in type-ahead buff ;
RDKY:
mov int cmp jne mov int
ah,00h 16h al,51h NEXT ax,4C00h 21h
mov mov int
ah,01h dx,0000h 14h
MYCODE
ix.
;enable interrupts
CHKAGN: mov mov int test jnz jmp
NEXT:
viii.
;initialising COM1 ;pointing at COM1 ;4800-Bd,2-SB,NP,8-DB ; 11100111 ; 9600Bd ;ROM BIOS function call
;ROM BIOS function call, sc=ah,ac=al ;see if Quit command (capital Q) ;function value to return to DOS prompt ;DOS fuction call ;function value ;point at COM1 ;ROM BIOS function call
jmp CHKAGN ENDS END START
Press a key on the keypad of the trainer. The character ‘A’ appears on the monitor of the PC. Press Capital-Q to exit the program. Press a key on the keyboard of the PC. We observe that the corresponding ASCII code has appeared at the DP7DP8 positions of the trainer. The character also appears on the monitor.
2/Expt-11A
3/Expt-11A
Experiment – 11B
Study of the Asynchronous Serial Communication Link Between IBMPC and MDA-8086 Trainer (You must Finish all the Tasks of this Experiment. Exercises, Examples and Questions are given as topics for additional studies to enhance your Knowledge & Understanding) Task-11B.1
Lab Works on COM1 Port of IBMPC and MDA-8086 Trainer using DOS and ASM Codes The schematic diagram for the serial interface of the MDA-8086 (Korean made 8086 trainer) trainer is given below. Write complete program both for the IBMPC and the 8251A controller of the mmda-8086 trainer to establish communication between these two equipments at the setting of: 4800 Bd, 1 start bit, 8 character bits, even parity and 2 stop bits. And then carry out the following functional checks. IPC:
8086: U1 : MPU
8259 : U14
LCD
BUS
BUS
00h 02h 04h
IR7
INTR INTA/
IR0(43h) IR2(42h) IR1(41h) IR0(40h)
INT INTA/ DR CR
IR SR DR
Keyboard 01h 01h
10h 12h
DR CR
2.4576MHz
GT0 CK0 OT0
09h 0Fh
C0 CR
8253 : U41: PIT
a. b. c.
+5
BUS
CLK TxC RxC 08h 0Ah
RxR DY TxRDY
DR R xD CR
TTL RS232 TxT
10
7
TxR S
R xT
12
13
RxR S
MAX232: U15
USART: 8251: U17
IBM-PC
Download the codes of your program starting at 0000:1000 and then execute at 01000h Type a character in the keyboard of the IBMPC, its ASCII, Scan and Label would appear on LCD Type a character in the keyboard of MDA-8086, its Label would appear on the monitor of IBMPC.
Solution Hints: a. Open a DOS screen in the IBMPC under WIN98. Save the screen as p4513a.asm. This program would read a character from the Rx-register by polling the RxRDY-bit and then write it back on the Tx-register by polling the TxRDY-bit.
1/Expt-11B
Determine TxC for 4800 Bd (assume BRF = x16) and then configure the PIT chip 8253 accordingly. TxC = BRF x Bd = 16 x 4800 = 76800 Hz Configure Counter-0 of PTI chip 8253 (U41) to work as a frequency divider of: CK0/TxC = 2.4576MHz/0.076800 MHz = 32(20h) in order to output a frequency of 76800Hz Configure 8251A (U17): i. ii.
To operate for the settings of: 4800 Bd, 1 start bit, 8 character bits, even parity and 2 stop bits by sending appropriate MICB (Mode Instruction Control Byte) into CR For activating the modem control lines and Rx/Tx enabling; send appropriate CICB (Command Instruction Control Byte) into CR.
Now keep polling the RxRDY-bit of the status register of the 8251A to find the presence of a valid character that has come form the IBMPC. Read it and write it back into the Tx-register by polling the TxRDY-bit. Assemble the program; make an Intel-Hex (p4513a.abs) formatted file. Download the Intel-Hex file into the MDA - 8086 trainer starting at RAM location: 000:1000h b.
Open a second DOS screen in the IBMPC under WIN98. Save the screen as p4513b.asm. This is a ‘Terminal Emulator Program’, which reads a character from the keyboard of the IBMPC by polling and writes on the Tx-register of the COM1 port of the IBMPC. The program also reads a character form the Rx-register of COM1 and displays it on the monitor. i. Set the COM1 port setting as: “4800 Bd, 1 start bit, 8 character bits, even parity and 2 stop bits” by calling ROMBIOS ‘ ah=00h, dx=0000h, al=BRCB, int 14h’. ii. Configure the modem control lines by writing appropriate bits into MCR-register of 8250 iii. Read the ASCII code of a pressed down in the keyboard of the IBMPC by polling. Use ROMBIOS ‘ah=00h, int 16h’ for this purpose. Detection of ‘Q’ would terminate the program. iv. Write the ASCII code of the pressed down key on the Tx-register by polling the TxRDYbit. v. Poll the RXRDY-bit and read character from the Rx-register of COM1 port. vi. Use DOSBIOS ‘ ah=02h, dl=ASCII, int 21h’ to send the receiver character on the monitor. vii. Assemble the program and link it to make the file p4513b.exe.
c.
Reset the MDA-8086 trainer and then execute at: 0000:1000
d.
In the IBMPC, execute the program p4513b.
e.
Type the character A from the keyboard. The monitor must show it.
f.
This verifies that the IBMPC and the MDA-8086 trainer are communicating using the customized serial link.
g.
Now, add addition code with program p4513a.asm so that the MDA-8086 trainer could display on the LCD display, the ASCII code, Scancode and Label of the key that has been pressed down on the keyboard of the IBMPC.
h.
Now, add addition code with program p4513a.asm so that the MDA-8086 trainer could receive the 8-bit code of a pressed down of it keypad and then send its Label to IBMPC.
i.
Now, add additional codes with p4513a.sam so that the MDA-trainer could read character from the Rx-register on interrupt.
j.
Now, add necessary codes with the program p4513b.asm, so that the IBMPC could read character from the Rx-register on interrupt.
2/Expt-11B
Experiment – 12 Programming of the 8279-Based Display Unit of the MicroTalk-8086 Learning System (You must Finish all the Tasks of this Experiment. Exercises, Examples and Questions are given as topics for additional studies to enhance your knowledge & understanding)
Task-12.1:
Display the message ‘Good’ at the data field of the display unit of the MicroTalk-8085 trainer. The Procedures: 1. Fill up the following Common Cathode Codes Table for all Possible Characters Displayable on 7Segment Display Devices Character 0 1 2 3 4 5 6 7 8 9 A B C D E F G o (small O) D R L U S T
Displayable Form 0 1
Segment Bits p g f e d c b a 0 0 1 1 1 1 1 1 0 0 0 0 0 1 1 0
Figure-12.11 : CC-code Table for Experiment: Task-43.1
1/Expt-12
Data Value 3FH 06H
2. Update the following Memory Resident Data Table for the Message ‘Good’ Memory Location in RAM Content CC-Code for Character 0A000 G 0A001 O 0A002 O 0A003 D Figure-12.2 : CC-code Table for Experiment: Task-43.1 3. Study the following Circuit Diagram of the 8279 and Display Unit of MicroTalk-8086
D9 D8 D7 D6 D5 DP0 DP1 DP2 DP3 DP4
8279 : U10 DDR
Q3
1024KHz
In Out
0 1
4-Bit Counter
Frequency Divider
100KH
Fin
Q2 Q1 Q0
Display RAM DP0
2
D C B A
Data
8
DP1 DP2 DP3 DP4 DP5
D4 D3 D2 D1 DP5 DP6 DP7 DP8
p g f e
p g f e
d c b a cc
d c b a cc
cc
cc
cc
cc
cc
cc
4 to 16
0000, 0002
CS/
A1
A0 (C-D/)
D E C O D E R F
DECODER
DPF
SL3 SL2 SL1 SL0
DR
CR SR
D C B A
S0/ S1/ S2/ S3/ S4/ S5/ S6/ S7/ S8/
U11, U13, U14 82798086 : GM : 1199
Figure-12.3: Circuit Diagram of the Display Subsystem of MicroTalk-8086
4. Programming Table – 1 Register Name Control Register Status Register Display Data Register Keyboard Data Register
Abbreviation CR SR DDR
Address 0000h 0002h 0000h
Mapping Standard & Variable Standard & Variable Standard & Variable
Read/Write Mode Write Only Read Only Read/Write
KDR
0000h
Standard & Variable
Read/Write
2/Expt-12
cc
5. Programming Table – 2 Control Byte 000 00 000B = 08H 000 10 000B = 18B 010 00 000B = 40H 011 0 0000B = 60H 011 1 0000B = 70H
100 0 0000B = 80H 100 1 0010B = 90H
Purpose 16 Digit Display; Character Entry from Left 16 Digit Display; Character Entry from Right To read data from the KDR Read data from DDR (display RAM0 pointed by the lower 4-bits of Cbyte) Read data from DDR (display RAM0 pointed by the lower 4-bits of Cbyte) Next read will be automatically from RAM1 of DDR and so on…… Write data into DDR (Display RAM0 pointed by the lower 4-bits of CByte) Write data into DDR (Display RAM2 pointed by the lower 4-bits of CByte) Next write will be automatically at RAM3 of DDR and so on………..
6. Code, Store and Execute the following Pseudo Codes that describes the solution of TaskF.1. L1:
do nothing;
L2:
Cbyte (08H) → CR (0002h); Cbyte (90H) → CR (0002h) Register, cx as a Counter for 04 characters SI-register to Point the beginning of the data source table;
L3:
(ds: [di]) → al
L4:
al → DDR (0000h)
L5 :
if ( cx == 0) goto L6 else { (SI) + 01H → SI goto L3 }
L6:
halt
3/Expt-12
L1:
Entry L2:
Initialization DDR for 16-Digits Display,Left Entry L3: Read Data from Read Data Memory Table from Port-B byte-by-byte L4:
Write Label-c Data to DDR L5: Write Done ? L6:
Exit 111-00:GM:1199
Figure-12.4:: Flow Chart for Expt-4.31
Assembly Codes: L1: 05100 - nop L2: - mov al, 08h mov dx, 0002h out dx, al mov al, 90h out dx, al mov cx, 0004h mov si, 0A000h L3: - mov al, BYTE PTR ds:[si] (default ds=0000h) L4: - mov dx, 0000h out dx, al L5: - dec cx jz L6 inc si jmp L3 L6: - hlt
4/Expt-12
Machine Codes: L1: 05100 - 90 L2: - B0 08 BA 02 00 EE B0 90 EE B9 04 00 BE 00 0A L3: - 8A 04 L4: - BA 00 00 EE L5: - 49 74 03 46 EB F4 L6: - F4
5/Expt-12
Experiment – 13 Programming of the 8279-Based Keyboard Unit of the MicroTalk-8086 Learning System (You must Finish all the Tasks of this Experiment. Exercises, Examples and Questions are given as topics for additional studies to enhance your knowledge & understanding) Task-13.1 Onboard 8279 Based Keyboard Programming
Scanning Keyboard of Microtalk-8086 trainer and Recording the Corresponding Scan Codes. Objectives of the Experiment: 01. Verify that the Scan Codes are generated as per Scan Code Format of the 8279 (Fig-44.3 ) 02. Display of the Scan Codes at DP7DP8 position of the display unit of the trainer. The procedures: 1. Study the following Keyboard Circuit Diagram of the MicroTalk-8086 Trainer DP7
8279 4-Bit Coun ter F req . D iv ide r
1024KHz
DP8
8
Q3
100K
Q0
Scan C o de D isplay
4-to-8 Decoder
Display Section
74138
Keyboard Section +5V
0000, 0002
C
CS/
KDR
S0/
`
A1
A0(C-D/)
D7-D0 4 IRQ
SR 112a: GM: 0701 : 06/2005
S3/ B S2/ A S1/
8x5K
E L E C T R O N I C S
CR
RL0
C1 C2
K11
RL1
ROW-1
RL2
ROW-2
RL3
ROW-3
RL4
ROW-4
RL5
ROW-5
RL6
ROW-6
RL7
ROW-7
C3
K13
K63
RESET
Figure-13.1: Keyboard Diagram for the MicroTalk-8086 Trainer
2. Programming Table – 1 Keyboard Scan Code Format: CONTROL B7 0
SHIFT B6 0
COLUMN LINES B5 B4 B3 X X X
Figure-13.2: Keyboard Scan Code Format for 8279 Chips
1/Expt-13
ROW LINES B2 B1 B0 X X X
3. Follow Fig-44.3 and Fill up the following table for the Keypad of the MicroTalk-8086 Key Designation K11 K21 …… K51 K61
Key Label D/DOP ----------------------
Scan Codes (Binary) 00 001 001 ---------------------
Scan Codes (Hex) 09H ----------------------
-------------------------------------------
-----------------------------------------------
-------------------------------------------
K12 – K62
-----------------------
------------------------
---------------------
K13 K23 K33 K43 K53 K63
_______________ ----------------------------------------------------------------------------------------------------------
______________ --------------------------------------------------------------------------------------------------------------
_______________ ----------------------------------------------------------------------------------------------------------
4. Programming Table-2 Control Byte 40H
Written to Control Register
Purpose To make read access to KDR
5. Pseudo Codes for the solution of the problem (p441.asm) Flow Chart for the Pseudo Codes: L1: L2: L3:
L4: L5: L6:
L7:
L8:
nothing SR0 → al if (al0 = 1) Closed Key is there; Go to L4 Else no closed key; goto L2 Scan_Code → al [Cbyte(40H) → CR(0002h); KDR(0000h) → al] go to L6 convert 1-Byte Scan Code to 2-Bytes 7-Segment codes for the purpose of display (al → 0044Eh; call F000:F47C) display the converted data of label-6 on the D2D1 position; blank D7D6D5D4D3 positions (00h → 00444h – 0044Ah s call F000:FFB6) go to L2
113-00: GM: 0701
L1:
Entry L2: Read Status Register
L3: S R0 Bit =1 ?
N
Y
L4:
Read S can Code L5:
L8: Display the S can Code at D2D1 of Trainer
L7: Convert 1-Byte S can Code to 2-Bytes 7-seg
L6:
6. Code, store and execute the pseudo codes. 7. Press the keys of the keypad of the trainer. Observe the corresponding 2-digit code in the display. 8. The readers may readily find the scan codes of the keys by executing an EPROM based program at address F05B0h. 9. The readers may also assemble and download the program p441.asm, which similar to F05B0h
2/Expt-13
Figure-44.2:: Flow Chart to Acquire/Display Scan Code
3/Expt-13
Experiment – 13B
Programming the Keyboard Unit of the MDA-8086 System (You must Finish all the Tasks of this Experiment. Exercises, Examples and Questions are given as topics for additional studies to enhance your knowledge & understanding) Task-13B.1: [Aim of the Experiment] Acquiring the ‘Scan Codes’ for the keys of the keypad of the MDA-8086 trainer and displaying those on the LCD panel of the trainer. Example-13B.2: [Objectives of the Experiment] This experiment is presented with the intention that the readers, while conducting the experiment, will be familiar with: 1. 2. 3. 4.
Various terminologies relating with keyboard design. Design of ‘Bus Compatible’ keyboard using discrete ICs. Design of bus compatible keyboard using programmable IC like 8279. The procedure of converting scan codes into ASCII codes.
Example-13B.3: [Terminologies] Scan Code: A key has two pins and it becomes an operational key when its two terminals are placed between a row and a column as is shown in Fig-44.1. When a key is pressed down, the associated electronics around that key generates an 8-bit code, which is termed as ‘Scan Code = scode)’. The value of the scode depends on the row and column across which the key is placed. Thus, the scan codes of the keys of a keypad are always different from each other. Example-44.4: [Hardware Block Diagram of the MDA-8086 Keyboard] Decoder: U16 CS/: 01h WR/ RD/ BHE/ M-IO/
KRS/ KRD/
U25 S/
Q
Status Signal DB-sig: 33m S
R/
IRQ
U24
Key Pad
OE/
D15-D8
B7 B6 B5 Q7-Q0 B4 B3 B2 B1 B0
DB-Sig 0V
541
Q4 Q3 Q2 Q1 Q0
G0 12 + 15 14 : 10
STP 11 REG 13
DA 16 AD 17
C 0C 8 08 4 04 0 00
D 0D 9 09 5 05 1 01
E 0E A 0A 6 06 2 02
F 0F B 0B 7 07 3 03
Figure—13B.1: Hardware Block Diagram for the Keyboard of the MDA-8086 Trainer
6/Expt-13B
Example-13B.5: [Working Principles of the Keyboard of Fig-13B.1] The decoder (U16), which has conditioned the signals CS/, RD/, WR/, BHE/ and M-IO/ signals are not the part of the keyboard circuit. This is shown here as a reference. The U’s numbers correspond to the actual U’s of the circuit diagram of the keyboard as depicted in the MDA-8086 user’s manual. The keypad contains 24 keys with the labels as indicated. The 2-digit hex number shown below the key label is the 8-bit scan code for that key. There are electronics circuitry to the left and the top of the key array of the keypad. The B7-B0 bits at the input of U24 represent the 8-bit scan code of a pressed down key. The Fig-58.1 indicates that the values of the B4-B0 and B7 bits are dependent on the positions of the keys in the key matrix. The detailed study of the keyboard circuit of Fig-58.1 is available in Exercise-1. The keyboard is designed in such a way so that whenever none of the keys in the keypad is pressed down, the B7-bit of the scan code is at LH. Thus, the B7-bit works as a status, which carries the closed condition of a key in the keypad. Before the keyboard is put into operation, the B7-bit is made LH by executing the instruction: out KRS(01H), 00h. This instruction activates the KRS/ signal of the decoder, which in turn sets the flip-flop U25. The result is that the B7-bit at the input of U24 assumes LH. When a key is pressed in the keypad, the internal electronics to the left of the key array activates and generates a bit pattern for the bits: B4-B0. At the same time, the top electronics of the key array generates a low going pulse, ‘DB-sig’. The DB-sig resets the flip-flop U25 making B7-bit LL. The DB-sig may be inverted using a gate as shown in Fig-44.1 and can be used to interrupt the CPU. Alternately, the CPU may poll the B7-bit for LL and then can read the scan code from the input of the buffer U24 by executing the instruction: in al, KRD (01h). The complete cods for the polling and reading of the keyboard is given below: L1: L2:
L3: L4:
out in test jnz and mov out jmp
KRS(01H), 00h al, KRD(01h) al, 10000000B L2 al, 00011111B BYTE PTR KBUF, al KRS(01h), 00h --------
; keyboard is reset ; read the raw scan code ; checking if B7-bit is 0 ; ne key is pressed down ; closed key found and save in KBUF ; KBUF is a memory location of DSM (say, 03010h) ; reset the keyboard ; take action as needed against the closed key.
Scan Code Table for the Keyboard of MDA-8086: Key Designation K11 K12 K13 K14 K15 K16 K21 K22 K23 K24 K25 K26
Key Label GO STP C D E F + REG 8 9 A B
Scan code 12h 11h 0Ch 0Dh 0Eh 0Fh 15h 13h 08h 09h 0Ah 0Bh
Key Designation K31 K32 K33 K34 K35 K37 K41 K42 K43 K45 K46 K47
6/Expt-13B
Key Label DA 4 5 6 7 : AD 0 1 2 3
Scan Code 14hh 16h 04h 05hh 06h 07h 10h 17hh 00h 01h 02h 03h
Task-13B.6: [Reading and Saving Scan Code] Write a small program to read the scode of a pressed down key of the keypad. Save the scode at memory location: 03100h (0000:3100). After the execution of the program, manually check the content of the memory location 03100h and look for the correct scode for the key that have pressed down. Solution: L1: L2:
L3: L4:
out in test jnz and mov out jmp
KRR(01H), 00h al, KDR(01h) al, 10000000B L2 al, 00011111B BYTE PTR ds: [3100h], al KRS(01h), 00h F000:FFFFh (EA FF FF 00 F0)
; keyboard is reset ; read the raw scan code ; checking if B7-bit is 0 ; no key is pressed down ; closed key found and save in KBUF [upper 3-bits 0] ; scode is saved at memory location : 0000:3100 ; reset the keyboard ; the goes to the prompt (the ready mode).
Example-13B.7: The scode of the Task-44.6 has been stored at memory location 0000:1100 by executing the instruction: mov BYTE PTR ds:[3100h], al. Verify that the following instruction can also be used to store the scode at the memory location: 0000:3100. mov bx, 3100h mov BYTE PTR ds:[bx] Exercise-13B.8: Modify the program of Task-44.6 so that the CPU will respond (it will go to Ready Prompt) when and only when you press the ‘REG’ key. All other keys will be ignored. Scode is saved at: 03100h. Solution Hints: The solution of Exercise-44.8 is given below in the form of Pseudo Code and Flow Chart. Convert it into machine codes. Enter the program codes into the CSM starting at 0000:1000 and execute it. Pseudo Codes: Flow Chart: L0: entry L1: xxh → KRS (01h) ; reset keyboard L0: L2: al ← KRD (01h) ; read raw scan code Entry L3: if (a7 = 1) ; checking the status bit L1: goto L2 ; key not closed Reset the Keyboard L4: if (al != 13h) ; is it REG key? goto L2 ; it is not REG key L2: L5: al → 03100h ; saving Scan code for REG. Read Scan Code L6: goto F000:FFFFh (EA FF FF 00 F0) L3:
Assembly Codes: L0: nop L1: out 01h, al L2: in al, 01h L3: mov ah, al …………… jnc L2 L4: cmp al, 13h jnz L2 L5: mov 03100h, al L6: jmp far PTR F000: FFFF
Y
B7 = 1 N
N
L4:
Scode=13h ? Y
L5:
Condition Scode and save at 01100h L6:
Exit to Prom pt
542
Figure-44.2: Flow Chart for Exercise-44.8 Exercise-13B.9: Modify the program of Exercise-44.8 so that the CPU will now exit to the Ready Prompt when either the ‘GO’ or ‘STP’ key is pressed down.
6/Expt-13B
Exercise-13B.10: Rewrite and execute the program of Task-44.6 by assigning variable port addresses for the devices KRS and KRD.
Taks-13B.11: Write, code and execute an 8086 assembly program, which will show the message ‘Closed key Found’ on the top line of the LCD when the key ‘GO’ is pressed down: Solution: 1. Configure the LCD for 8-data lines, 16x2 line, 5x7 dots, display ON and cursor OFF. 2. Manually initialize the message ‘Closed Key Found’ in the following data structure of DSM: 0000:3200 ASCII Cde of 'C' 0000:3201 ASCII Cde of 'l' 0000:3202 ASCII Cde of 'o' ASCII Cde of 's' ASCII Cde of 'e' ASCII Cde of 'd' Space ASCII Cde of 'K' ASCII Cde of 'e' ASCII Cde of 'y' Space ASCII Cde of 'F' ASCII Cde of 'o' ASCII Cde of 'u' ASCII Cde of 'n' 0000:320F ASCII Cde of 'd' 0000:3210 Mark of End (24h) 543
Figure-44.3 Data Structure for Task-44.10
3. The Program Codes: RPT:
if (closed key is GO) { transfer the content of the above data structure into LCD stay HERE } else goto RPT
Exercise-13B.12: Write, code and execute an 8086-based assembly program in the MDA-8086 system to accomplish the following: a. The LCD panel is cleared up. There is no character on the LCD. b. When you press the ‘REG (Rate Entry for Goods)’ key, a cursor like ‘_’ will be blinking at the DP0 position of the LCD. c. You press any key from 0-9 on the keypad, the corresponding image of the pressed key will appear at the current cursor position. The blinking cursor will shift to the right. c. Your program will accept any four digits from the keyboard. d. At the end of four digits entry, the CPU will again recognize the ‘REG’ command. Your program will transfer control back to Step-b. Solution Hints: Given below a solution hints in the form of Pseudo Code. Draw the flow chart, the assembly codes and then execute the program. Check strictly, the correctness of every step of the pseudo code program. Pseudo Codes: L0: initialize the LCD for the required ‘Mode of Operation’ L1: initialize a Counter (register, cl) for total number of digits to be printed. initialize a flag (initial value 00h) to indicate that the LCD shows blinking cursor ‘_’. L2: reset the keyboard L3: read raw scan code of the keyboard
6/Expt-13B
if (B7-bit of the raw scan code is LH) goto L3 if (flag = 00h) if (scode = 13h) { show: blinking cursor ‘_’ at the DP0 position of the LCD 1 → flag [ at the end of 4-digit entry flag will be made LL) } else goto L2 else { reset keyboard if (scode != 13h) goto L2 else { print the digit on the LCD at the present cursor position decrement counter if (counter = 0) goto L1 else goto L2 } Exercise-13B.13: Draw the complete circuit diagram for the keyboard of the MDA-8086 system. And also write down the working principles of this keyboard circuit. Schematic Diagram: The complete schematic diagram is shown in Fig-58.4 below, which is a redrawn version of the original schematic given in the user’s manual of the MDA-8086. The only new thing in this diagram is that the diagram of Fig-58.4 has much better readability than the one of the user’s manual. Working Principles: The heart of the keyboard circuit is the component U27, which is a ‘Priority Encoder’ chip. This is the chip, which actually generates the scan codes for the keys of the keypad. However, the transistors, TR1-TR3 also play a great role for generating the scan codes by providing the column lines for the keyboard matrix. The keyboard works in very interesting way. When none of the keys of the keyboard is pressed down, the row lines are isolated from the column lines and the inputs to the U27 are: 00000000B. According to the truth table of the U27 (4532), when the inputs are at 0s, the output E0=LH and GS=0. It is assumed that prior to the operation of the keyboard, the keyboard has been reset by asserting LH at B7 with the execution of the instruction: out KRS(01H), 00h. The LH value of the B7-bit is an indication that none of the keys in the keyboard has been pressed down. When any of the keys of the keypad is pressed down, the b7-bit immediately goes to LL. Thus, the CPU can easily know whether a key has been pressed or not just by monitoring the value of the b7-bit. Say, the key-8 is pressed down. The column line provided by TR2 is shorted with the D7 line of the U27. The voltage at D7 of U27 becomes: 5V – VEBTR2 (0.7V) = 4.3V, which is Logic-H. Because, the TR2 is ON, its collector voltage is very close to +5V (LH), which constitutes Bit-3 of the scan code. With the bit pattern as 10000000 at the inputs of U27, the output of U27 would be 111 (Q2Q3Q1). The EO-pin assumes LL and the GS-pin assumes LH. The activity of the EO signal triggers the 33mS-oneshot U26. The 33mS pulse width is intentionally chosen to allow the complete extinction of the denouncing pulses of the mechanical key, key-8. The inverted output of U26 clocks the GS-bit into the latch, U25 after 33mS time delay. This results in putting LL at B7-bit of the scan code. Thus, the scan code for the key-8 stands as: 00001000 (08h). At this moment, if the CPU reads the scan code out of U24, it will find a valid scan code by seeing LL at B7-bit.
6/Expt-13B
544
R8 3.3k
R10 3.3k
R12 3.3k
TR1
R9 3.3k
TR2
R11 3.3k
0V
0 1 2 3 4 5 6 7
8 9 A B C D E F
TR3
R13 3.3k
: STP GO + REG DA AD
RA1: 8x3.3k
WR/
CS/ (01h) BHE/ M-IO/
U21 7432
+5V
0V
17 15 13 11 8
0V
U27 4532 +5V
5
04 03 02 01 13 12 11 10
+5V
EI
0V
EO D7 D6 D5 D4 D3 D2 D1 GS D0 Q2 Q1 Q0
15
14
R7 : 33k
Q
6
5
B
Q/
1
3
CK
Q
5
2
D
Q/
6
Reset Enable
U24 74244
C8: 1uF
11 + 3 4
6 7 9
B7 B6 B5 B4 B3
R/
10 U26
1
Q7 Q6 Q5 Q4 Q3 Q2 Q1 Q0
74121 33m S
U25: 7474
6 4 2
B2 B1 B0
3 5 7 9 12 14 14 18
D15 D14 D13 D12 D11 D10 D09 D08
OE/
1,19 IRQ
Read Enable
RD/
Needs to be Installed by the User
D15-D0
Figure-13B.4: Complete Schematic Diagram for the Keyboard of the MDA-8086 System Exercise-13B.14: The CPU can read the scan code of a closed key by reading the status of Bit-7 of the input value of U24. The CPU will keep reading the data out of U24 until it finds that Bit-7 is at LL. This way of reading a data is called ‘Polling Method’. Polling method gives the guarantee that a valid data will always be found but at the expense of time. The alternate way of reading scan code without wastage of time is the ‘Interrupt Method’. In this method, the keyboard will inform the CPU by way of interruption when there has been a key closed in the keypad. Refer to the diagram of Fig-44.4, we notice that having the occurrence of a key closure, and at the expiry of 33mS denouncing time, the IRQ output goes LH. This signal may be connected with the INTR pin of the 8086 for interruption. Exercise-13B.15: Explain the reason of connecting the output data of U24 with the D15-D8 lines of the 8086 instead of D7-D0 lines. Answer: In the diagram of Fig-44.4, we notice that the address assigned to the keyboard is 01h, which is an odd numbered fixed ort address. The architecture of 8086 dictates that the CPU can perform data read/write operations with the odd numbered port and memory locations should their data lines are tied with the upper byte (D15-D8) of the data bus. More over, the execution of the instruction, mov al, KRD (01h) automatically asserts LL at the BHE/ pin of the CPU due to the presence of an odd numbered port address in the instruction. The activation of BHE/ signal connects only the upper byte of the data bus with the accumulator register of the CPU. As a reference study, we may include here that the data bits of the even numbered-address ports and memory locations are always connected with the lower byte of the data bus.
6/Expt-13B
Experiment – 14A
Converting MicroTalk-8086 Trainer into a 24-Hr Clock (You must Finish all the Tasks of this Experiment. Exercises, Examples and Questions are given as topics for additional studies to enhance your knowledge & understanding) Task-14A.1: 24-Hr Clock [1-sec Time Tick is obtained from 50Hz Line Frequency] Procedures: 1. Download program …\mtk8086\P14Aclk.abs starting at RAM location 0000:1000 (01000h). 2. Use keyboard of the trainer and update the following memory locations with current time. (00474) = Second : 00 - 59 (00475) = Minutes : 00 – 59 (00476) = Hours : 00 – 23 3. Use the DOP command and execute the down loaded program at: 01000h 4. Take a jumper wire and gently short PZC (J3-26) and NMI (J2-19) points. 4. The display of the trainer should show the Time as per format of Fig-14A.1 as shown below. U2 : 8086
U24 : 8279
CS/ Jumper
B
20mS J3-26
B
NMI J2-19
PZC
DRAM0
DP0
DRAM1
DP1
DRAM2 DRAM3
DP2 DP3
DRAM4
DP4
DRAM5 DRAM6
DP5 DP6
DRAM7
DP7
DRAM8
DP8
CC-type 7-Segment Display Unit
DP0 DP1 DP2 DP3 DP4
HRS
DP5 DP6 DP7 DP8
Data
MIN
Min
Hr
Sec
SEC
739abx
Figure-14A.1: Hardware Structure for the 24-Hr Clock
Task-14A.2: Working Principles of the 24-Hr Clock System T11
00476 HRS 00475 MIN 00474 SEC Initial BCD Time
T13
T12 00450 0044F 0044E Running
HRS D3D4 MIN D5D6 SEC D7D8 BCD Time
BCD2CC F000:F47C
D3 00447 HRS D4 00446 D5 00445 MIN D6 00444 D7 00443 SEC D8 00442 Running CC Time
7-Seg Display CCX8279 F000:FFB8
HRS MIN SEC
739abx
Figure-14A.2: Software Data Structure for the 24-Hr Clock
1. 2. 3. 4.
Initial BCD Time is entered into the indicated memory locations of T11 using the keyboard of the MicroTalk-8086 trainer. The CPU is interrupted at every 20-mS. The COU goes to ISRNMI and checks if 500 interrupts have occurred, which is equivalent to 1-Sec elapsed time (50x20 = 1000mS). At every 1-sec, the CPU updated the ‘Running BCD Time’ and is converted to ‘Running CC Time’ using ROM-based subroutine BCD2CC. The ‘CC Time’ is transferred into the display RAM of the 8279 using ROM-based subroutine CCX8279. The ‘CC Time’ automatically enters into the 7-Segment display unit.
1/Expt-14A
Task-14A.3 : Listing of the ASM Codes for the 24-Hr Clock System […..\P14Aclk.asm] ; Converting MicroTalk-8086 into a 24-Hr Clock System: Dated: 8/1/2009 by Golam Mostafa START: nop mov cl, 00h ; counter L1:
mov mov mov
bx, 0000h ; Link ISRNMI with NMIITC WORD PTR [bx+08h], OFFSET ISRNMI WORD PTR [bx+0Ah], SEG ISRNMI
L2:
mov mov mov mov mov call
bx, 0400h ax, WORD PTR [bx+74h] WORD PTR [bx+4Eh], ax al, BYTE PTR [bx+76h] BYTE PTR [bx+50h], al BCD2CC
mov mov or or call
WORD PTR WORD PTR BYTE PTR BYTE PTR CCX8279
jmp
L3
L3:
;Transfer Initial BCD Time from T11 into T12
; converting BCDTIME into CCTIME
[bx+48h], 0000h [bx+4Ah], 0000h [bx+44h], 80h ; place point [bx+46h], 80h ; xfering CCTIME into 8279
; wait for interrupt
ISRNMI: ; beginning of ISR due to NMI ISR1: inc cl cmp cl, 100 ; 3Ch = 48+2 = 100x20 = 1000mS = 1Sec je ISR2 ; looks like NMI senses both Redge and LH of PZC iret ISR2:
mov mov add daa cmp je mov jmp
cl, 00h ; counter Reset al, BYTE PTR [bx+4Eh] al, 01h
mov mov add daa cmp je mov jmp
BYTE PTR [bx+4Eh], 00h al, BYTE PTR [bx+4Fh] al, 01h
mov mov add daa cmp je mov jmp
BYTE PTR [bx+4Fh], 00h al, BYTE PTR [bx+50h] al, 01h
ISR5:
mov mov
WORD PTR [bx+4Eh], 0000h BYTE PTR [bx+50h], 00h
ISR6:
call
BCD2CC
mov mov or or call iret
WORD PTR WORD PTR BYTE PTR BYTE PTR CCX8279
ISR3:
ISR4:
al, 60h ISR3 BYTE PTR [bx+4Eh], al ISR6
al, 60h ISR4 BYTE PTR [bx+4Fh], al ISR6
al, 24h ISR5 BYTE PTR [bx+50h], al ISR6
[bx+48h], [bx+4Ah], [bx+44h], [bx+46h],
0000h 0000h 80h 80h
BCD2CC: mov mov mov call ret
di, 0F00h WORD PTR [di], 0F47Ch WORD PTR [di+02h], 0F000h DWORD PTR [di]
CCX8279:mov mov mov call ret
di, 0F00h WORD PTR [di], 0FFB6h WORD PTR [di+02h], 0F000h DWORD PTR [di]
; placing decimal point
1/Expt-14A
MYCODE
ENDS END
START
1/Expt-14A
Experiment - 9
Multiplication of Two Unsigned 16-Bit Numbers Task - 9.1[16-bitx16-bit Multiplication by Counting: p91a.asm] In this task, we shall multiply two unsigned 16-bit numbers by ‘full repetitive addition’ method using the MicroTalk-8086/MDA-8086 microprocessor learning system. There will be absolutely no use of either of the following two instructions: -
i.
mul
al, byte_data
ii. mul
ax, word_data
Let us assume that we have the following two 16-bit numbers: 04FFF
519
x3x2 x1x0 y3y2 y1y0 r3'r2'
r7r6
r1r0
: Multiplicand : Multiplier
= (x1x0) x (y1y0) : L1
r5''r4''
r3''r2''
= (x3x2) x (y1y0) : L2
r5'''r4'''
r3'''r2'''
= (x1x0) x (y3y2) : L3
r5''''r4'''' --
-Carry
03006 03006 03005 03004 03003 03002 03001 03000 02FFF
= (x3x2) x (y3y2) :L4 --
--
r1r0
Product (R esult) Multiplicand Multiplier
00000
L1:
L2:
nop 00h → r7r6, r5r4, r3r2, r1r0 ; initial results 00h → r3’r2’, r3’’r2’’, r3’’’r2’’’, r5’’r4’’, r5’’’r4’’’, r5’’’’r4’’’’ - compute [x1x0]x[y1y0] by repetitive addition mov al, 00h ; al is the working register and also holds IPR mov ah, y1y0 ; ah holds the multiplier L1A: add al, x1x0 jc L1C L1B: dec ah jnz L1A jmp L1D L1C: r3’r2’ + C → r3’r2’ Jmp L1B L1D: al → r1r0 ; we have : [r3’r2’ r1r0] for L1: [x1x0)]x [y1y0] - compute [x3x2]x[y1y0] by repetitive addition mov al, 00h ; al is the working register s mov ah, y1y0 ; ah holds the multiplier L2A: add al, x3x2 jc L2C L2B: dec ah jnz L2A jmp L2D L2C: r5’’r4’’ + C → r5’’r4’’
1/Expt-9
DSM
Inputs
CSM
559b
Figure-9.2: Input/Output Data Structure
Program: p631a.asm: Mixed Codes START:
Output
01000
Carry Carry
Figure-9.1: Computation Mechanism
r7r6 r5r4 r3r2 r1r0 x3x2 x1x0 y3y2 y1y0
L2D:
Jmp L2B al → r3’’r2’’
; we have : [r5’’r4’’ r3’’r2’’] for L2: [x3x2]x [y1y0]
L3:
- compute {[x1x0]x[y3y2]} by repetitive addition mov al, 00h ; al is the working register and also holds IPR mov ah, y3y2 ; ah holds the multiplier L3A: add al, x1x0 jc L3C L3B: dec ah jnz L3A jmp L3D L3C: r5’’’r4’’’ + C → r5’’’r4’’’ jmp L3B L3D: al → r3’’’r2’’’ ; we have : [r5’’’r4’’’ r3’’’r2’’’] for L3: [x1x0] x [y3y2]
L4:
- compute {[x3x2]x[y3y2]} by repetitive addition mov al, 00h ; al is the working register mov ah, y3y2 ; ah holds the multiplier L4A: add al, x3x2 jc L4C L4B: dec ah jnz L4A jmp L4D L4C: r7r6 + C → r7r6 jmp L4B L4D: al → r5’’’’r4’’’’ ; we have : [r7r6 r5’’’’r4’’’’] for L4: [x3x2] x [y3y2]
L5:
- now add the three components of r3r2 of L1, L2 and L3 mov ah, 00h ; ah-register will accumulate the carries [r3’r2’ + r3’’r2’’] → al jc L5A jmp L5B L5A: ah + 01h → ah L5B: al + r3’’’r2’’’ → al jc L5C jmp L5D L5C: ah + 01 → ah L5D: al → r3r2 ; the value of ah-register will be added with r5r4 components
L6:
- now add the three r5r4 components of L2, L3 and L4. mov cl, 00h; ; cl-register will accumulate the carries [r5’’r4’’ + ah ] → al jc L6A jmp L6B L5A: cl + 01h → cl L5B: al + r5’’’r4’’’’ → al jc L6C jmp L6D L5C: cl + 01 → cl
2/Expt-9
L6D:
L6E: L6F:
al + r5’’’’r4’’’’ → al Jc L6E Jmp L6F cl + 01h → cl al → r5r4 ; the value of cl-register will be added with r7r6
L7:
- now add r7r6 with cl-register r7r6 + cl → r7r6
L8:
- the multiplications is done-
Implementation: 1. Assume the input numbers as: Multiplicand = 1234h Multiplier = ABCDh 2. Expected Result : Product = 0C374FA4h 3. Use keyboard and store the multiplicand and the multiplier in the specified RAM locations of the input/output data structure of Fig-63.2. 3. Use keyboard and store 00h to all four-memory locations of the data structure holding the results. 4. Write the complete 8086-assembly program for the above mixed codes and save as: drive:\mda86\p631a.asm. In the meantime execute the following test program (p91a.c). #include #include #include void bmult(); unsigned char r1r0=0, r3r2=0, r5r4=0, r7r6=0; unsigned char r3r2_1=0, r3r2_2=0, r3r2_3=0; unsigned char r5r4_2=0, r5r4_3=0, r5r4_4=0; void main() { union buff { unsigned long size; unsigned char ch [4]; } y; clrscr(); bmult(); y.ch[0] = r1r0; y.ch[1] = r3r2; y.ch[2] = r5r4; y.ch[3] = r7r6; printf("\n%lx ", (y.size)); getch(); }
3/Expt-9
void bmult() { // x3x2 = 12; x1x0 = 34h, y3y2 =AB; y1y0=CDh BM: asm asm asm L1A: asm asm L1B: asm asm asm L1C: asm asm L1D: asm asm
mov mov mov add jc dec jnz jmp inc jmp mov mov
bl, 0x00 al, 0x00 ah, 0x34 // y1y0 ; y3y2y1y0=1234h al, 0xCD // x1x0; X3x2x1x0=ABCDh L1C ah L1A L1D bl L1B r1r0, al // r3r2_1, r1r0 r3r2_1, bl // 29A4h
asm asm asm L2A: asm asm L2B: asm asm asm L2C: asm asm L2D: asm asm
mov mov mov add jc dec jnz jmp inc jmp mov mov
bl, 0x00 al, 0x00 ah, 0x34 // y1y0; y3y2y1y0=1234 al, 0xAB //x3x2 ; x3x2x1x0=ABCD L2C ah L2A L2D bl L2B r3r2_2, al // r5r4_2, r3r2_2 r5r4_2, bl // 22BCh
asm asm asm L3A: asm asm L3B: asm asm asm L3C: asm asm L3D: asm asm
mov mov mov add jc dec jnz jmp inc jmp mov mov
bl, 0x00 al, 0x00 ah, 0x12 // y3y2; y3y2y1y0 = 1234h al, 0xCD // x1x0l x3x2x1x0=ABCDh L3C ah L3A L3D bl //r5r4_3 L3B r3r2_3, al // r5r4_3, r3r2_3 r5r4_3, bl // 0E6Ah
asm asm asm L4A: asm asm L4B: asm
mov mov mov add jc dec
bl, 0x00 al, 0x00 ah, 0x12 // y3y2 ; y3y2y1y0=1234h al, 0xAB // x3x2; x3x2x1x0=ABCDh L4C ah
4/Expt-9
asm asm L4C: asm asm L4D: asm asm
jnz jmp inc jmp mov mov
L4A L4D bl //r7r6 L4B r5r4_4, al // r7r6, r5r4_4 r7r6, bl //0C06h
L5:
asm asm asm asm asm asm L5A: asm L5B: asm asm asm asm L5C: asm L5D: asm
mov mov mov add jc jmp inc mov add jc jmp inc mov
ah, 0x00 bl, r3r2_1 al, r3r2_2 al, bl L5A L5B ah bl, r3r2_3 al, bl L5C L5D ah r3r2, al // r3r2=5Ah;
L6:
mov mov mov add jc jmp inc mov add jc jmp inc mov add jc jmp inc mov add
al, ah ah, 0x00 bl, r5r4_2 al, bl L6A L6B ah bl, r5r4_3 al, bl L6C L6D ah bl, r5r4_4 al, bl L6E L6F ah r5r4, al r7r6, ah
asm asm asm asm asm asm L6A: asm L6B: asm asm asm asm L6C: asm L6D: asm asm asm asm L6E: asm L6F: asm L7: asm }
5. Assemble the program: p631a.asm and enter the machine codes in the CSM starting at slocation: 01000h. 6. Execute the program at : 01000h. 7. Open the following memory locations for the result and we must find the correct result: 010404 = A4 010405 = 4F
5/Expt-9
010406 = 37 010407 = 0C 7. Test your program for another set of values. Also test that the program works for the input data: 0000h and 0000h.
Task - 9.2[16-bitx16-bit Multiplication by ‘8-bit mul Instruction’: p91b.asm] In this task, we shall multiply two unsigned 16-bit numbers by ‘partial repetitive addition’ method using the MTS-86C microprocessor learning system. . There will be a use of the mul instruction.s [
Let us assume that we have the following two 16-bit numbers: Mixed Codes: START: L1:
L2:
L2A: L3:
L3A:
L4:
L4A:
nop al ← y1y0 al x BYTE PTR [1402h] al → r1r0 ah → r3r2 al ← y1y0 al x BYTE PTR [1403h] al + r3r2 → r3r2 jnc L2A inc ah ah → r5r4 al ←y3y2 al x BYTE PTR [1402h] al + r3r2 → r3r2 jnc L3A inc ah ah + r5r4 → r5r4 jnc L4 r7r6 + 01h → r7r6 al ← y3y2 al x BYTE PTR [1403h] al + r5r4 → r5r4 jnc L4A inc ah ah + r7r6 →r7r6
; (x1x0) x (y1y0)
; (x3x2) x (y1y0)
; (x1x0) x (y3y2)
; (x3x2) x (y3y2)
Task - 9.3[16-bitx16-bit Multiplication by ‘Double Precision mul Instruction’: p631c.asm] START: L1: L2:
nop mov mul mov mov
ax, multiplicand WORD PTR [bx+03000h] WORD PTR [bx+03004h], ax WORD PTR [bx+03006h], dx
; lower 16-bit of result ; upper 16-bit of results
6/Expt-9
Product Advertisement Microprocessor/Microcontroller Learning/Development Systems (Accompanied with Rich Documentation)
8-Bit Microprocessor Learning /Dev System using Intel 8085 Architecture
I92, D93, B97, M04
I88, D90, B92, M05
Designed to Meet the Learning and Research Needs of the Students, Teachers, Scientists, Technocrats and Engineers MicroTalk-8085 MicroTalk-8086
16-Bit Microprocessor Learning /Dev System using Intel 8086 Architecture
MicroTalk-80286 I96, D99, B99, M?
I93, D95, B99, M05
MicroTalk-8x51
16-Bit Protected Virtual Address Mode Microprocessor Learning /Dev System using Intel 80286 High Perfomance Arch.
8-Bit Microcontroller Learning /Dev System using Intel /Atmel 8x51 Architecture
I02, D03, B?, M?
MicroTalk-80386
32-Bit Protected Virtual Address Mode Microprocessor Learning /Dev System using Intel 80386DX High Perfomance Architecture
Users List: BUET, KUET, RUET, DUET, ITU, DU, JU, AUST, IUBAT, QU, AIUB, AUB, Mohila Polytechnic, Ctg. Polytechnic, Zamuna Fertilizer, Cybernetic Systems …
Designed, Developed and Built in Bangladesh By Golam Mostafa B.Sc.Engg (EE-BUET), M.Sc.Engg (CSE-BUET): Ex-Schlumberger, GEC and BCIC Associate Professor, Ahsanullah University of Science and Technology, Dhaka
Karighar Research and Development Center 16/1-2 (Apt: 2/801), Segun Bagicha: Dhaka-1000: Bangladesh Phone: 02-7161846, 01726-341559 Email:
[email protected]
