548Mathcad - Mathcad Resources Gradient, Divergence, And Curl
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Mathcad Resources Gradient, Divergence, And Curl...
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CALCULUS AND DIFFERENTIAL EQUATIONS quicksheets Gradient, Divergence, and Curl
This QuickSheet illustrates how to define and evaluate the vector operators gradient, divergence, and curl. Gradient
The gradient of a scalar-valued function
x0 f ( x) = f x1 x 2 is defined by
∂ f ( x) ∂x0 ∂ f ( x) ∇ x f ( x) = ∂x1 ∂ f ( x ) ∂x2 You can compute the gradient using the Mathcad gradient operator. For example, suppose you define the following scalar-valued function: f ( x) := ( x0) 2 ⋅ x1 ⋅ ( x2) 3 To insert the gradient operator, press [Ctrl] [Shift] G: ∇
Type the variable vector x in the lower placeholder, and type the function f(x) in the upper placeholder. ∇ x f ( x) Finally, type [Ctrl] [.] to insert the symbolic equal sign and press [Enter].
2 ⋅ x0 ⋅ x1 ⋅ ( x2) 3 ∇ x f ( x) → ( x0) 2 ⋅ ( x2) 3 3 ⋅ x 2 ⋅ x ⋅ x 2 ( 0) 1 ( 2) If you define the vector x numerically, the gradient is a numerical vector:
1 x := 3 −1 −6 ∇ x f ( x) = − 1 9 Divergence
The divergence of a vector-valued function A(x,y,z) = (A(x,y,z)0, A(x,y,z)1, A(x,y,z)2) is defined by div ( A , x , y , z) :=
d d d A ( x , y , z) 0 + A ( x , y , z) 1 + A ( x , y , z) 2 dx dy dz
This can also be written as div = ∇ ⋅ A where ∇ =
d dx
d dy
d is the "del" operator. dz
For example, if you define
x := x
x⋅z A( x , y , z) := −y2 2 2⋅x ⋅y you can evaluate the divergence symbolically by: div ( A , x , y , z) → z − 2 ⋅ y After substituting values for x, y, and z, you can evaluate the divergence numerically: div ( A , 1 , 1 , 1) = −1 Curl
The curl of a vector-valued function A is defined by
d A ( x , y , z) 2 − d A ( x , y , z) 1 dz dy d d curl ( A , x , y , z) := A( x , y , z) 0 − A( x , y , z) 2 dx dz d d dx A ( x , y , z ) 1 − dy A ( x , y , z ) 0 In terms of the del operator, this can be written as curl = ∇ × A
To symbolically evaluate the curl of the function A defined previously, use the symbolic equal sign:
2 ⋅ x2 curl ( A , x , y , z) → x − 4 ⋅ x ⋅ y 0 Or, you can define values for x, y, and z, and evaluate the curl numerically: 2 curl ( A , 1 , 1 , 1) = −3
0
Here are some more examples: f ( x , y , z) := x ⋅ y ⋅ z 2
3
B ( x , y , z) := f ( x , y , z) ⋅ A( x , y , z)
x 3 ⋅ y ⋅ z 4 B ( x , y , z ) → − x 2 ⋅ y3 ⋅ z 3 2 ⋅ x 4 ⋅ y2 ⋅ z 3 div ( B , x , y , z) → 6 ⋅ x 4 ⋅ y2 ⋅ z 2 − 3 ⋅ x 2 ⋅ y2 ⋅ z 3 + 3 ⋅ x 2 ⋅ y ⋅ z 4
4 ⋅ x 4 ⋅ y ⋅ z 3 + 3 ⋅ x 2 ⋅ y3 ⋅ z 2 curl ( B , x , y , z) → 4 ⋅ x 3 ⋅ y ⋅ z 3 − 8 ⋅ x 3 ⋅ y2 ⋅ z 3 − x 3 ⋅ z 4 − 2 ⋅ x ⋅ y3 ⋅ z 3
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