3era Tarea de Algoritmos
December 17, 2022 | Author: Anonymous | Category: N/A
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U@ISEVQIHGH XEA@BNÑOIAG HEN ZEVÔ
AUVQB4
ZVI@AIZIBQ HE GNOBVIXKBQ
GNUK@BQ4
ABHIOB4
NIKG ‑ ZEVÔ
KGYB - 6:6:
XGVEG #1
Ederaiaibs prbpuestbs 7. Zrbaesb he açnaunb he prbkehib he 8 `btgs. Zrbaesb prpkehib Hec`ir `7,`6,`1,`8 abkb e`terb Hec`ir prbk abkb regn Esarifir „i`orese ngs 8 `btgs‛ Neer `7,`6,`1,`8 Zrbk >- (`7,`6,`1,`8)/8
Esarifir „i`orese en prbkehib he ngs 8 `btgs‛,prbk
Ci`prbaesb
6. Zrbaesb pgrg guke`tgr u` `ôkerb e` su 33%. Zrbaesb i`areke`tb Hec`ir `uk abkb esterb Hec`ir extrg,rptg abkb regn Hec`ir „i`orese u` `ukerb‛ Neer `uk Extrg >- `uk *:.33 Vptg >- `uk +extrg Esarifir „i`orese ng respuestg hen i`areke`tb‛, rptg Ci`prbaesb
1. Zseuhbañhiob que agnaung en prbkehib he u` estuhig`te ab`siherg`hb4 @btg Zesb ZA:7 7:% ZA:6 6:% ZA:1 1:% EC 8:%
Qbnuaiñ`
Zrbaesb prbkehib c`gn Hec`ir @btgREx7 abkb regn Hec`ir @btgREx6 abkb regn hec`ir @btgREx1 abkb regn Hec`ir @btgRZbr7 abkb regn Hec`ir @btgRZbr6 abkb regn hec`ir @btgRZbr1 abkb regn hec`ir Zrbkehib abkb regn Esarifir ' Eskghb usugrib pbr gvbr i`orese ng `btg hen exgke` exgke` 7 ' neer @btgREx7 Esarifir ' Eskghb Eskghb usugrib usugrib pbr gvbr i`orese i`orese ng `btg hen exgke` 6 ' neer @btgREx6 Esarifir ' Eskghb usugrib pbr gvbr i`orese ng `btg hen exgke` exgke` 1 ' neer @btgREx1 @btgRZbr7 >- ( @btgREx7 * :.65 ) @btgRZbr6 >- ( @btgREx6 * :.65 ) @btgRZbr1 >- ( @btgREx1 * :.5: ) Zrbkehib >- ( @btgRZbr7 @btgRZbr7 + @btgRZbr6 + @btgRZbr1 ) prbkerhib >- ( prbkehib / 1) Esarifir ' En prbkehib hen estuhig`te estuhig`te es 4 ' Zrbkehib Ci`Zrbaesb
8. Neer u`g kehihg e` orghbs ae`orghb y nueob kbstrgrnb e` orghbs Cgmre`meit. Hgtb4
; 9 /5 *
+ 16
Hb`he4 • C es ng kehih e` orghbs Cgmre`meit • A es ng kehihg e` orghbs Aensius. I`iaib Hec`ir vgrigfnes regn4 ae`, gre` Neaturg he hgtbs Esarifir („I`oresgr orghbs ae`orghbs‛) Neer (ae`) Zrbaesb he açnaunb4 ab`versiñ` he tekpergturg gre` 9 / 5 * ae` +16 Qgnihg he resuntghbs Esarifir (ae`, „ ae`orghb equivgne g ‛, gre`, „ Cgre`meit„) Ci`
5. I`oresgr ng ag`hgh he gnuk`bs gprbfghbs y hesgprbfghbs he u` aursb. Nueob kbstrgr en pbrae`tgde he estuhig`tes gprbfghbs y en pbrae`tgde he estuhig`tes estuhig`tes hesgprbfghbs. Zrbaesb gsio`gturg Hec`ir gprbfghb, hesgprbfghb, `btgfne, sbfresgnie`te, tbtgn, tbtQup abkb e`terb Hec`ir psup, pgprb, phesgp, p`btg, psbfre abkb regn Esarifir „I`oresgr ag`hgh he gprbfghbs‛ Neer gprbfghb Esarifir „I`oresgr ag`hgh he hesgprbfghbs‛ Neer hesgprbfghb Esarifir „I`oresgr ag`hgh he `btgfnes‛ Neer `btgfne Esarifir „I`oresgr ag`hgh he sbfresgnie`tes‛ Neer sbfresgnie`te tbtgngprbfghb+hesgprbfghb+`btgfne+sbfresgnie`te tbtsup gprbfghb+`btgfne+sbfresgnie`te gprbfghb+`btgfne+sbfresgnie`te psup(tbtsup*7::)/tbtgn pgprb(gprbfghb*7::)/tbtgn phesgp(hesgprbfghb*7::)/tbtgn p`btg(`btgfne*7::)/tbtgn psbfre(sbfresgnie`te*7::)/tbtgn Esarifir „Zbrae`tgde he nbs que supergrb`‛, psup Esarifir „Zbrae`tgde he gprbfghbs‛, pgprb Esarifir „Zbrae`tgde he hesgprbfghbs‛, phesgp Esarifir „Zbrae`tgde he `btgfnes‛, p`btg Esarifir „Zbrae`tgde he sbfresgnie`tes‛, psbfre Ci`Zrbaesb
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