STATIS MOMEN
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CONTOH SOAL: Carilah sais !"!#$ %#$a!%a$& %#rs#&i %a$'a$& %a(a &a!)ar (i )a*ah i$i (#$&a$ +ara r!s !! (a$ +ara i$#&ral s#hi$&&a (i(a%a-a$ r!s $- )a$&$ %#$a!%a$& %#rs#&i %a$'a$& #rs#).
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INERSIA PENAMPANG BY :
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P#rhi$&a$ (#$&a$ Ta)#l E4EL :
INERSIA PENAMPANG BY :
CONTOH SOAL: 6i-#ahi s#)ah )al"- (#$&a$ %#$a!%a$& )#r)#$- I s#%#ri #r&a!)ar (i )a*ah i$i. A%a)ila (i-#ahi (i!#$si %#$a!%a$& (#$&a$ l#)ar 7)8 9 1/ +!, i$&&i )a(a$ 7h*9 5 +!, #)al sa;a% aas 719 3 +!, #)al )a(a$ 729 2 +! (a$ #)al sa;a% )a*ah 7 39 / +!. Hi$&lah las %#$a!%a$& (a$ ii- )#ra %a(a %#$a!%a$& #rs#) < Penyelesaian : U$- !#!(ah-a$ !a-a %#$a!%a$& (i)a&i !#$'a(i i&a )a&ia$ ;ai, sa;a% aas, )a(a$ (a$ sa;a% )a*ah. 6i-#ahi: 7)8 9 1/ +! 7h*9 5 +! 719 3 +! 729 2 +! 739 / +!
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Luas penampang (A) : 3
A ∑ A
i
i =1
7)8 × 19 = 7h* × 29 = 7)8 × 39 71/ × 39 = 75 × 29 = 71/ × /9 / = 5 = / 255 +!2
Momen statis terhaap sum!u " : 3
S> ∑ A i .y i i =1
?7)8 × 19.71@2.1 = h* = 39 = ?7h* ×
[email protected]* = 39 = ?7)8 × 39. 71@2.39 ?71/ ×
[email protected] = 5 = /9 = ?75 × 29.71@2.5 = /9 = ?71/ × /9. 71@2./9 7/ × 0,/9 = 75 × 2/9 = 7/ × 2,/9 252,/ = 2555 = 1,/ 25 +!3 11
Momen statis terhaap sum!u y : 3
S;
∑ A .x i
i
i =1
?7)8 × 19.71@2.)8 9 = ?7h* × 29.71@2.)8 9 = ?7)8 × 39. 71@2.)8 9 ?71/ ×
[email protected]/9 = ?75 ×
[email protected]/9 = ?71/ × /9.
[email protected]/9 7/ × ,/9 = 75 × ,/9 = 7/ × ,/9 33,/ = 055 !erat = /02,/ Leta# titi# pusat !erat Leta# titi# pusat 3 1/55 +! penampang terhaap sum!u penampang terhaap sum!u y: ": 3
∑ A .x i
Sx
3
i
3
A
;5
4280
∑ A i =1
i
∑ A i .yi
Sy
i =1
;5
200
A 1500
i =1 3
200
,/5 +!
21,5 +! 12
∑ A i i =1
P#rhi$&a$ (#$&a$ Ta)#l E4EL :
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MOMEN INERSIA 7I9
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GAMBAR PENAMPANG
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INERSIA PENAMPANG BY :
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INERSIA PENAMPANG BY :
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INERSIA PENAMPANG BY :
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INERSIA PENAMPANG BY :
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INERSIA PENAMPANG BY :
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INERSIA PENAMPANG BY :
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UNTUK LEBIH ELASNYA 6APAT 6ILIHAT PA6A TABEL BERIKUT INI :
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CONTOH SOAL :
INERSIA PENAMPANG BY :
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INERSIA PENAMPANG BY :
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INERSIA PENAMPANG BY :
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INERSIA PENAMPANG BY :
2