231109891-Spreader-Bar-Calculation.pdf

CALCULATION FOR SPREADER BEAM Tag No: V-211-004 Pipe 24 " OD = Thickness of Pipe ID = C/S Area

Service:AGSU Stripper

mm mm mm mm^2

609.6 14 581.60 26195.86 2

PIPE PROPERTIES Material SA 283 Min. Yield Strength (Fy) 2080.17 kg/cm^2

2

 ( OD  + ID ))/4 Radius of Gyration ( r ) =   = 210.63 Moment of inertia(I)=( PI()/64)*(D^4-Di^4) Section modulus(Z)= Pi()/32*(OD^4-ID^4)/OD Distance in between lifting plate ( l ) =

E=

2059770

kg/cm^2

mm mm^4 mm^3

1162229456 3813088.77

 

Slenderness Ratio=

=

2

Cc = sqrt(2∏ *E / Fy)

=

139.81

6580.00 mm mm

K

1

K*l / r =

31.24

R

 

 Allowable Compressive stress -Fa (as per Equation E2-1 of AISC ASD) 2

Fa=

2

L

[1-(Kl/r) / 2Cc ]*Fy 3

3

5/3 + (3*(Kl/r)/8Cc) - ((Kl/r) /8Cc ) 2

2

(Kl/r) / 2Cc  =

0.024963925

(3*(Kl/r)/8Cc) =

0.083792028

3

3

(Kl/r) /8Cc = Therefore

   D    O    E    P    I    P

0.001394519 1159.61 Kg/cm^2

Fa =

I ) Check for axial compressive stress : -

Total Equipment weight be lifted = W

= 286000

Kg

a =

Load Load at each each end = W/2 = 143000 143000 Shock factor = 2 In state of equilibrium , Design load at each lifting plate = Pv = W/2 x Shock Factor =

60 Pt

286000

Kgs

P axial axial ( P a )= Pv / Tan a

Pa

=

165122

60 minimu minimum m angle angle Pa Kgs

Compressive Stress Induced ( Pc ) = P a / Area of cross section Pv Pc

= =

As Pc < Fa, Provided size of Spreder bar is

6.3 Kg/mm^2 630.3 Kg/cm^2

OK

CALCULATION FOR SPREADER BEAM Tag No: V-211-004

Service:AGSU Stripper

II ) Check for Lifting Plate Matl : A 516 Gr.65 Yield stress = a) Shear at lifting eye : allowable Tensile stress St = Allowable stress due to Bending =Sb = 2/3 x Yield = 330 mm End Radius ( R )= 220 mm Eye pad Radius ( Re )= Re=

Kg/cm^2 1615.185 Kg/cm^2 1615.185 Kg/cm^2

2447.25

P t = P v / Sin a  

= 330244

Kgs

Lift Hole Dia ( di ) = 155

mm Lift Plate Thk ( t l )=

Eye plate Size =    420 / 

Therefore Shear stress = Pt/(2*(Re-(di/2))*(tl+2*te)) fs =

7.9914 #######

Eye plate thk =

65

mm

40

mm

Allowable Shear stress = 0.5* yield = 1223.625 Kg/cm^2 Ss= Kg/mm^2 Kg/cm^2 Since fs